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= 1211 kJ mol-1. Therefore the molar heat of combustion of ethanol is 1211 kJ mol-1 (The molar enthalpy of combustion of ethanol is 1211 kJ mol-1). (Note that the enthalpy change for the reaction is negative because the reaction is exothermic, so the enthalpy change for the reaction is -1211 kJ mol-1, ÎH = - 1211 kJ mol-1)
This is how to do it: First, you have to get the molarity of the solution. Recall that Molarity = mol solute / L solution The unit of molarity is M, which stands for mol/L. You have to convert 0.274 g NaCl to moles by dividing the amount by its molar mass.0.274 g NaCl * 1 mol NaCl / 58.5 g NaCl = 0.00468 mol NaCl Then convert the volume to Liters. 10 mL is equal to 0.01 L. Get the molarity.ecall that Molarity = mol solute / L solution The unit of molarity is M, which stands for mol/L. You have to convert 0.274 g NaCl to moles by dividing the amount by its molar mass. 0.274 g NaCl * 1 mol NaCl / 58.5 g NaCl = 0.00468 mol NaCl Then convert the volume to Liters. 10 mL is equal to 0.01 L. Get the molarity.