In 2008, Harvard Stem Cell Institute principal faculty member Kevin Eggan first raised the possibility of using ALS patient-derived stem cells to better understand the disease and identify therapeutic targets for new drugs.
If f(x) is linear, the graph of y = f(x) is a straight line. The parameter m in the first two formulas is the slope of this line. In the general form, the slope is -A/B if B 0 and infinite if B = 0. In the slope-intercept form, the parameter b is the y-intercept. In the point-slope form, the point (x0, y0) is a point on the line y = f(x). Any point (x0, y0) on the line will lead to an equivalent equation. We will frequently have to perform the following calculations with linear equations:
We have to choose what is the equation of the function on the graph. We know the parent function: f(x) = log(2) x ( log base 2 ). The new function should be in the form: f(x) = log(2) ( x - a ) + b. The new vertical asymptote is : x = -3, So: a = -3. Now we have: f (x) = log(2)( x + 3 ) + b. After that we will substitute the values of coordinates of the point ( - 5 , - 2 ) which belong to this function. - 5 = log(2) ( - 2 + 3 ) + b. - 5 = log (2) 1 + b ; - 5 = 0 + b; b = - 5. Answer: The equation of the function shown in the graph is: A ) f (x) = log(2) ( x + 3 ) - 5 .