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1) That looks right. 2) Step 1: Moles=Mass/Mr, so it's 144/72= 2mol. Step 2: Stoichiometry means the ratio of oxygen to pentane is 1:8 so moles of oxygen is moles of pentane times 8. 2*8=16mol of oxygen. Step 3: 16= 9.6*10^24. 3) The ratio of oxygen to carbon in CO2 is 1:2. so it's 192/3 = 64.
Best Answer: 0.69 mol / 25 eq = 27.6 mmol O2 0.20 mol / 2 eq = 100 mmol octane therefore... a) oxygen is the limiting reagent b) 27.6 mmol x 18 eq = 497 mmol or 0.0497 moles H2O produced. c) 27.6 mmol x 2 eq = 55.2 mmoles octane consumed 200 mmol - 55.2 mmol = 144.8 mmol or 0.145 moles octane remaining.