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1) That looks right. 2) Step 1: Moles=Mass/Mr, so it's 144/72= 2mol. Step 2: Stoichiometry means the ratio of oxygen to pentane is 1:8 so moles of oxygen is moles of pentane times 8. 2*8=16mol of oxygen. Step 3: 16= 9.6*10^24. 3) The ratio of oxygen to carbon in CO2 is 1:2. so it's 192/3 = 64.
12.2g of magnesium reacts completely with oxygen gas. Calculate the mass of oxygen consumed during the reaction and the mass of magnesium oxide produced. 1  Wite the balanced chemical equation: 2Mg (s) + O 2(g) â 2MgO (s). 2  Determine the mole ratio from the equation, Mg: O 2: MgO is 2:1:2.3  Use the mole ratios to calculate the mass of each reactant and product as shown below:iven a mass of m grams of magnesium: 1  mass O 2 = moles(O 2) x molar mass(O 2). & 2 nbsp &nbsp &nbsp &nbsp &nbsp &nbsp &nbsp Calculate moles Mg = mass(Mg) &divide molar mass(Mg) = m &divide 24.31. & 3 nbsp &nbsp &nbsp &nbsp &nbsp &nbsp &nbsp Use the balanced chemical equation to determine the mole ratio O 2 :Mg 1:2.