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For H2SO4 we have a total of 32 valence electrons. Put a pair between the atoms. We're forming chemical bonds here. We've used 8, 10, 12, and then around the outside to fill the octets on the Oxygens, 14, and 32.So this looks like a pretty good Lewis structure for H2SO4. In the H 2 SO 4 Lewis structure Sulfur is least electron electronegative atom and goes in the center of the Lewis structure. 2  When we have an H (or H2) in front of a polyatomic molecule (like CO 3, SO 4, NO 2, etc.) we know that it's an acid.
Using the oxidation numbers of the the atoms that constitute the sulfate ion that has a formula of SO4, the oxidation state is determined by adding the oxidation number of sulfur and oxygen.Sulfur has an oxidation number of 6, or it loses 6 atoms when it forms a chemical compound.Oxygen atoms on the other hand accept 2 electrons each when they form a compound. The sulfate anion has a formula of SO4, this gives a net oxidation state of +6 + 4*(-2) = -2.osted on. (Answer #1). The oxidation number refers to the charge on the central atom of a compound when the ligands attached to it are removed and so are the atoms that associated with the ligand. For the sulfate anion it is the oxidation state that can be determined not the oxidation number.