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The electric field strength between two parallel conducting plates separated by 4.00 cm is 7.50Ã104V/m. (a) What is the potential difference between the plates? (b) The plate with the lowest potential is taken to be at zero volts.
The charge cancels, and so the voltage between points A and B is seen to be. V AB = Ed E = V AB d (uniform E - field only), where d size 12{d} {} is the distance from A to B, or the distance between the plates in [link]. Note that the above equation implies the units for electric field are volts per meter. We already know the units for electric field are newtons per coulomb; thus the following relation among units is valid: 1 N/C=1 V/m.