The "photoelectrons" emitted as a result of the photoelectric effect have a certain <answer>kinetic</answer> energy, which can be measured. This <answer>kinetic</answer> energy (for each photoelectron) is independent of the intensity of the light, but depends linearly on the frequency; and if the frequency is too low (corresponding to a photon energy that is less than the work function of the material), no photoelectrons are emitted at all, unless a plurality of photons, whose energetic sum is greater than the energy of the photoelectrons, acts virtually simultaneously (multiphoton effect)  Assuming the frequency is high enough to cause the photoelectric effect, a rise in intensity of the light source causes more photoelectrons to be emitted with the same <answer>kinetic</answer> energy, rather than the same number of photoelectrons to be emitted with higher <answer>kinetic</answer> energy.
What type of energy due photoelectrons emitted due to the photoelectric effect have?
kinetic