A triangle has a base of 10 centimeters (cm) and a height of 11 centimeters (cm). There is a square with a width of 8 centimeters (cm) and a length of 8 centimeters (cm), and the diameter of a circle is 8 centimeters (cm). Which shape has the widest area? Calculate the circumference ratio as 3.1.
[OP_LIST_SOL] triangle square circle [OP_LIST_EOL] [OP_LIST_SOL] 10 11 [OP_MUL] 2 [OP_DIV] 8 2 [OP_POW] 8 2 [OP_DIV] 2 [OP_POW] 3.1 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
var_a = 'triangle'
var_b = 'square'
var_c = 'circle'
list_a= []
if "/" in str(var_c):
    var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
    var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
    var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 10
var_e = 11
var_f = var_d * var_e
var_g = 2
var_h = var_f / var_g
var_i = 8
var_j = 2
var_k = var_i ** var_j
var_l = 8
var_m = 2
var_n = var_l / var_m
var_o = 2
var_p = var_n ** var_o
var_q = 3.1
var_r = var_p * var_q
list_b= []
if "/" in str(var_r):
    var_r = eval(str(var_r))
list_b.append(var_r)
if "/" in str(var_k):
    var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_h):
    var_h = eval(str(var_h))
list_b.append(var_h)
list_b.reverse()
var_s = 1
list_c=list_b.copy()
list_c.sort()
var_t = list_c[-var_s]
var_u = list_b.index(var_t)+1
var_v = list_a[var_u-1]
print(var_v)