A and 24 are different natural numbers. If these two numbers are divisors or multiples of each other, find the third smallest of the two-digit numbers corresponding to A.
24 [OP_LIST_GET_DIVISOR] 24 99 24 [OP_LIST_ARANGE] [OP_SET_UNION] 3 [OP_LIST_MIN]
var_a = 24
list_a = []
num_sqrt = int(math.sqrt(var_a))
for i in range(1, num_sqrt+1):
    if var_a % i == 0:
        list_a.append(i)
        list_a.append(int(var_a/i))
list_a = sorted(set(list_a))
var_b = 24
var_c = 99
var_d = 24
list_b = [i for i in range(var_b, var_c + 1, var_d)]
list_c = list(set(list_a) | set(list_b))
var_e = 3
list_d=list_c.copy()
list_d.sort()
var_f = list_d[var_e-1]
print(int(var_f))