Round up the second largest five-digit number you can make by using the five number cards 0, 1, 5, 7, and 9 once to the tens digit.
[OP_LIST_SOL] 0 1 5 7 9 [OP_LIST_EOL] 5 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 2 [OP_CEIL]
var_a = 0
var_b = 1
var_c = 5
var_d = 7
var_e = 9
list_a= []
if "/" in str(var_e):
    var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
    var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
    var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
    var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
    var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 5
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_g = 2
list_c=list_b.copy()
list_c.sort()
var_h = list_c[-var_g]
var_i = 2
var_j=int(((var_h+9*10**(var_i-2))//(10**(var_i-1)))*10**(var_i-1))

print(int(var_j))