You want to create a number with two decimal places less than 6. How many can you make if you can only use 2, 4, 6 and the decimal point once?
[OP_LIST_SOL] 2 4 6 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 6 10 3 1 [OP_SUB] [OP_POW] [OP_MUL] [OP_LIST_LESS] [OP_LIST_LEN]
var_a = 2
var_b = 4
var_c = 6
list_a= []
if "/" in str(var_c):
    var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
    var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
    var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_d))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_e = 6
var_f = 10
var_g = 3
var_h = 1
var_i = var_g - var_h
var_j = var_f ** var_i
var_k = var_e * var_j
list_c = []
for i in list_b:
    if i < var_k:
        list_c.append(i)
var_l = len(list_c)
print(int(var_l))