When the three numbers 1, 2, and 3 are used repeatedly to form a four-digit number, how many ways can the sum be 10?
[OP_LIST_SOL] 0 1 2 3 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PRODUCT] [OP_LIST_NUM2SUM] 10 [OP_LIST_FIND_NUM]
var_a = 0
var_b = 1
var_c = 2
var_d = 3
list_a= []
if "/" in str(var_d):
    var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
    var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
    var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
    var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = len(list_a)
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_c=[]
for i in list_b:
    var_f = 0
    i = int(i)
    while i//10 > 0:
        var_f = var_f + i%10
        i = i//10
    var_f = var_f + i%10
    list_c.append(var_f)
var_g = 10
var_h = 0
var_g = int(var_g)
for i in list_c:
    i = int(i)
    if i == var_g:
        var_h = var_h + 1
print(int(var_h))