A total of 108 coins consists of 10-won coins, 50-won coins, and 100-won coins. The amount of the 50-won coins is 1/3 of the amount of the 10-won coins, and the amount of the 100-won coins is 1/2 of that of the 50-won coins. What kind of won-coins do you have the least?
[OP_LIST_SOL] 10-won 50-won 100-won [OP_LIST_EOL] [OP_LIST_SOL] 1 1 3 [OP_DIV] 1 3 [OP_DIV] 2 [OP_DIV] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
var_a = '10-won'
var_b = '50-won'
var_c = '100-won'
list_a= []
if "/" in str(var_c):
    var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
    var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
    var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_d = 1
var_e = 1
var_f = 3
var_g = var_e / var_f
var_h = 1
var_i = 3
var_j = var_h / var_i
var_k = 2
var_l = var_j / var_k
list_b= []
if "/" in str(var_l):
    var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_g):
    var_g = eval(str(var_g))
list_b.append(var_g)
if "/" in str(var_d):
    var_d = eval(str(var_d))
list_b.append(var_d)
list_b.reverse()
var_m = 1
list_c=list_b.copy()
list_c.sort()
var_n = list_c[var_m-1]
var_o = list_b.index(var_n)+1
var_p = list_a[var_o-1]
print(var_p)