How many natural numbers from 100 to 9999 are multiples of 25 and the sum of each digit is 17?
100 9999 1 [OP_LIST_ARANGE] 25 [OP_LIST_DIVISIBLE] [OP_LIST_NUM2SUM] 17 [OP_LIST_FIND_NUM]
var_a = 100
var_b = 9999
var_c = 1
list_a = [i for i in range(var_a, var_b + 1, var_c)]
var_d = 25
list_b = []
var_d = int(var_d)
for i in list_a:
    i = int(i)
    if i % var_d == 0:
        list_b.append(i)
list_c=[]
for i in list_b:
    var_e = 0
    i = int(i)
    while i//10 > 0:
        var_e = var_e + i%10
        i = i//10
    var_e = var_e + i%10
    list_c.append(var_e)
var_f = 17
var_g = 0
var_f = int(var_f)
for i in list_c:
    i = int(i)
    if i == var_f:
        var_g = var_g + 1
print(int(var_g))