When the given numbers 2, 3, 7, and 8 are used once to form the second large three-digit number, which number is not used?
[OP_LIST_SOL] 2 3 7 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] [OP_LIST_POP] [OP_NUM2LIST] [OP_SET_DIFFERENCE] 1 [OP_LIST_GET]
var_a = 2
var_b = 3
var_c = 7
var_d = 8
list_a= []
if "/" in str(var_d):
    var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
    var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
    var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
    var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 2
list_c=list_b.copy()
list_c.sort()
var_g = list_c[-var_f]
list_d = []
var_g = int(var_g)
while var_g//10 > 0:
    list_d.append(var_g%10)
    var_g = var_g//10
list_d.append(var_g%10)
list_d = list_d[::-1]
list_e = list(set(list_a) - set(list_d))
var_h = 1
var_i = list_e[var_h-1]
print(int(var_i))