In order to find the sum of three numbers, when three different numbers less than 10 are drawn, how many ways are there that the value is equal to 12?
1 10 1 [OP_SUB] 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 12 [OP_LIST_LESS_EQUAL] 12 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]
var_a = 1
var_b = 10
var_c = 1
var_d = var_b - var_c
var_e = 1
list_a = [i for i in range(var_a, var_d + 1, var_e)]
var_f = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_f))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_c=[]
for i in list_b:
    var_g = 0
    i = int(i)
    while i//10 > 0:
        var_g = var_g + i%10
        i = i//10
    var_g = var_g + i%10
    list_c.append(var_g)
var_h = 12
list_d = []
for i in list_c:
    if i <= var_h:
        list_d.append(i)
var_i = 12
list_e = []
for i in list_d:
    if i >= var_i:
        list_e.append(i)
var_j = len(list_e)
print(int(var_j))