When 6 people including A, B, and C are lined up, in how many ways can A, B, and C line up next to each other?
6 [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_LEN] 1 [OP_SUB] [OP_SUB] 6 [OP_LIST_LEN] 1 [OP_SUB] [OP_SUB] [OP_PERM] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]
var_a = 6
var_b = 'A'
var_c = 'B'
var_d = 'C'
list_a= []
if "/" in str(var_d):
    var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
    var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
    var_b = eval(str(var_b))
list_a.append(var_b)
list_a.reverse()
var_e = len(list_a)
var_f = 1
var_g = var_e - var_f
var_h = var_a - var_g
var_i = 6
var_j = len(list_a)
var_k = 1
var_l = var_j - var_k
var_m = var_i - var_l
var_n = 1
var_h = int(var_h)
var_m = int(var_m)
for i, elem in enumerate(range(var_m)):
    var_n = var_n * (var_h-i)
var_o = len(list_a)
var_p = len(list_a)
var_q = 1
var_o = int(var_o)
var_p = int(var_p)
for i, elem in enumerate(range(var_p)):
    var_q = var_q * (var_o-i)
var_r = var_n * var_q
print(int(var_r))