There are three numbers A, B, and C. A is 8 multiplied by 9 minus 3. B is the quotient of A divided by 3. C is equal to 2 times B plus 4. Find the sum of the largest and smallest numbers.
[OP_LIST_SOL] 8 9 [OP_MUL] 3 [OP_SUB] 8 9 [OP_MUL] 3 [OP_SUB] 3 [OP_DIV] 8 9 [OP_MUL] 3 [OP_SUB] 3 [OP_DIV] 2 [OP_MUL] 4 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]
var_a = 8
var_b = 9
var_c = var_a * var_b
var_d = 3
var_e = var_c - var_d
var_f = 8
var_g = 9
var_h = var_f * var_g
var_i = 3
var_j = var_h - var_i
var_k = 3
var_l = var_j / var_k
var_m = 8
var_n = 9
var_o = var_m * var_n
var_p = 3
var_q = var_o - var_p
var_r = 3
var_s = var_q / var_r
var_t = 2
var_u = var_s * var_t
var_v = 4
var_w = var_u + var_v
list_a= []
if "/" in str(var_w):
    var_w = eval(str(var_w))
list_a.append(var_w)
if "/" in str(var_l):
    var_l = eval(str(var_l))
list_a.append(var_l)
if "/" in str(var_e):
    var_e = eval(str(var_e))
list_a.append(var_e)
list_a.reverse()
var_x = 1
list_b=list_a.copy()
list_b.sort()
var_y = list_b[-var_x]
var_z = 3
list_c=list_a.copy()
list_c.sort()
var_A = list_c[-var_z]
var_B = var_y + var_A
print(int(var_B))