There are four pieces of paper with the numbers 1, 3, 7, and 8 written on them. If two cards are drawn in order and the first number drawn is the tens place, and the second number drawn is the ones place, how many total numbers are less than 40?
[OP_LIST_SOL] 1 3 7 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 40 [OP_LIST_LESS_EQUAL] [OP_LIST_LEN]
var_a = 1
var_b = 3
var_c = 7
var_d = 8
list_a= []
if "/" in str(var_d):
    var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
    var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
    var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
    var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 2
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 40
list_c = []
for i in list_b:
    if i <= var_f:
        list_c.append(i)
var_g = len(list_c)
print(int(var_g))