There are three numbers A, B and C. A is 10 multiplied by 2 plus 9. A is 16 greater than B. B multiplied by 3 is C. What is the largest minus the smallest number?
[OP_LIST_SOL] 10 2 [OP_MUL] 9 [OP_ADD] 10 2 [OP_MUL] 9 [OP_ADD] 16 [OP_SUB] 10 2 [OP_MUL] 9 [OP_ADD] 16 [OP_SUB] 3 [OP_MUL] [OP_LIST_EOL] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_SUB]
var_a = 10
var_b = 2
var_c = var_a * var_b
var_d = 9
var_e = var_c + var_d
var_f = 10
var_g = 2
var_h = var_f * var_g
var_i = 9
var_j = var_h + var_i
var_k = 16
var_l = var_j - var_k
var_m = 10
var_n = 2
var_o = var_m * var_n
var_p = 9
var_q = var_o + var_p
var_r = 16
var_s = var_q - var_r
var_t = 3
var_u = var_s * var_t
list_a= []
if "/" in str(var_u):
    var_u = eval(str(var_u))
list_a.append(var_u)
if "/" in str(var_l):
    var_l = eval(str(var_l))
list_a.append(var_l)
if "/" in str(var_e):
    var_e = eval(str(var_e))
list_a.append(var_e)
list_a.reverse()
var_v = 1
list_b=list_a.copy()
list_b.sort()
var_w = list_b[-var_v]
var_x = 3
list_c=list_a.copy()
list_c.sort()
var_y = list_c[-var_x]
var_z = var_w - var_y
print(int(var_z))