You want to create a three-digit number by drawing three out of 5, 6, 4, and 7 and using them only once. After finding the fourth smallest possible number, find the sum of its digits.
[OP_LIST_SOL] 5 6 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 4 [OP_LIST_MIN] [OP_NUM2LIST] [OP_LIST_SUM]
var_a = 5
var_b = 6
var_c = 4
var_d = 7
list_a= []
if "/" in str(var_d):
    var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
    var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
    var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
    var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.permutations(list_b, var_e))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_f = 4
list_c=list_b.copy()
list_c.sort()
var_g = list_c[var_f-1]
list_d = []
var_g = int(var_g)
while var_g//10 > 0:
    list_d.append(var_g%10)
    var_g = var_g//10
list_d.append(var_g%10)
list_d = list_d[::-1]
list_d = [float(i) for i in list_d]
var_h = sum(list_d)
print(int(var_h))