If all divisors of 75 are written once, how many times the number 5 must be written?
75 [OP_LIST_GET_DIVISOR] [OP_LIST2NUM] [OP_NUM2LIST] 5 [OP_LIST_FIND_NUM]
var_a = 75
list_a = []
num_sqrt = int(math.sqrt(var_a))
for i in range(1, num_sqrt+1):
    if var_a % i == 0:
        list_a.append(i)
        list_a.append(int(var_a/i))
list_a = sorted(set(list_a))
var_b=""
for i in list_a:
    i = str(i)
    var_b = var_b + i
list_b = []
var_b = int(var_b)
while var_b//10 > 0:
    list_b.append(var_b%10)
    var_b = var_b//10
list_b.append(var_b%10)
list_b = list_b[::-1]
var_c = 5
var_d = 0
var_c = int(var_c)
for i in list_b:
    i = int(i)
    if i == var_c:
        var_d = var_d + 1
print(int(var_d))