Seonho has 1 more marble than Minjeong. Jinyoung has 3 fewer than Joohwan , Minjeong has 6 marbles, and Joohwan has 7 marbles. Which of these has the fewest marbles?
[OP_LIST_SOL] Minjeong Joohwan Seonho Jinyoung [OP_LIST_EOL] [OP_LIST_SOL] 6 7 6 1 [OP_SUB] 7 3 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
var_a = 'Minjeong'
var_b = 'Joohwan'
var_c = 'Seonho'
var_d = 'Jinyoung'
list_a= []
if "/" in str(var_d):
    var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
    var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
    var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
    var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_e = 6
var_f = 7
var_g = 6
var_h = 1
var_i = var_g - var_h
var_j = 7
var_k = 3
var_l = var_j - var_k
list_b= []
if "/" in str(var_l):
    var_l = eval(str(var_l))
list_b.append(var_l)
if "/" in str(var_i):
    var_i = eval(str(var_i))
list_b.append(var_i)
if "/" in str(var_f):
    var_f = eval(str(var_f))
list_b.append(var_f)
if "/" in str(var_e):
    var_e = eval(str(var_e))
list_b.append(var_e)
list_b.reverse()
var_m = 1
list_c=list_b.copy()
list_c.sort()
var_n = list_c[var_m-1]
var_o = list_b.index(var_n)+1
var_p = list_a[var_o-1]
print(var_p)