Find how many 3-digit natural numbers that can be formed by repeating odd numbers from 1 to 9 are greater than 500.
1 9 [OP_LIST_ODD] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_MORE] [OP_LIST_LEN]
var_a = 1
var_b = 9
list_a = []
if var_a%2==0:
    for i in range(var_a+1, var_b+1, 2):
        list_a.append(i)
else:
    for i in range(var_a, var_b+1, 2):
        list_a.append(i)
var_c = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_c))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
var_d = 500
list_c = []
for i in list_b:
    if i > var_d:
        list_c.append(i)
var_e = len(list_c)
print(int(var_e))