When performing multiplication between two-digit numbers, when the tens digit of the multiplier is mistakenly considered as 6 instead of 2, the calculated value is 2496. However, the correct calculation yields 936. What is the sum of these two two-digit numbers?
[OP_LIST_SOL] 2496 936 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] 936 2496 936 [OP_SUB] 6 2 [OP_SUB] 10 [OP_MUL] [OP_DIV] [OP_DIV] [OP_LIST_EOL] [OP_LIST_SUM]
var_a = 2496
var_b = 936
var_c = var_a - var_b
var_d = 6
var_e = 2
var_f = var_d - var_e
var_g = 10
var_h = var_f * var_g
var_i = var_c / var_h
var_j = 936
var_k = 2496
var_l = 936
var_m = var_k - var_l
var_n = 6
var_o = 2
var_p = var_n - var_o
var_q = 10
var_r = var_p * var_q
var_s = var_m / var_r
var_t = var_j / var_s
list_a= []
if "/" in str(var_t):
    var_t = eval(str(var_t))
list_a.append(var_t)
if "/" in str(var_i):
    var_i = eval(str(var_i))
list_a.append(var_i)
list_a.reverse()
list_a = [float(i) for i in list_a]
var_u = sum(list_a)
print(int(var_u))