In two-digit addition, the number 3 in the tens place of the number added was incorrectly counted as 6. Again, the numbers being added incorrectly read the ones digit as 9 to 2. If the result of the calculation is 119, what is the result of the correct calculation?
119 1 9 2 [OP_SUB] [OP_MUL] [OP_ADD] 10 3 6 [OP_SUB] [OP_MUL] [OP_ADD]
var_a = 119
var_b = 1
var_c = 9
var_d = 2
var_e = var_c - var_d
var_f = var_b * var_e
var_g = var_a + var_f
var_h = 10
var_i = 3
var_j = 6
var_k = var_i - var_j
var_l = var_h * var_k
var_m = var_g + var_l
print(int(var_m))