In a calculation that adds a two-digit number to a four-digit number, the digit in the ones place of the four-digit number is incorrectly seen as 5. Also, when we mistook and switched the digits in the tens and ones place of a two-digit number, we got 63. If the incorrect calculation resulted in 2708, and the original four-digit number has 8 in the ones place, what is the correct result of the calculation?
2708 8 5 [OP_SUB] [OP_ADD] 63 36 [OP_SUB] [OP_ADD]
var_a = 2708
var_b = 8
var_c = 5
var_d = var_b - var_c
var_e = var_a + var_d
var_f = 63
var_g = 36
var_h = var_f - var_g
var_i = var_e + var_h
print(int(var_i))