Find the number of cases to put A and B next to each other in a situation where 6 people A, B, C, D, E, and F are lined up in a line.
[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_SOL] A [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]
var_a = 'A'
var_b = 'B'
var_c = 'C'
var_d = 'D'
var_e = 'E'
var_f = 'F'
list_a= []
if "/" in str(var_f):
    var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
    var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
    var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
    var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
    var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
    var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_g = 'A'
list_b= []
if "/" in str(var_g):
    var_g = eval(str(var_g))
list_b.append(var_g)
list_b.reverse()
list_c = list(set(list_a) - set(list_b))
var_h = len(list_c)
var_i = len(list_c)
var_j = 1
var_h = int(var_h)
var_i = int(var_i)
for i, elem in enumerate(range(var_i)):
    var_j = var_j * (var_h-i)
var_k = 'A'
var_l = 'B'
list_d= []
if "/" in str(var_l):
    var_l = eval(str(var_l))
list_d.append(var_l)
if "/" in str(var_k):
    var_k = eval(str(var_k))
list_d.append(var_k)
list_d.reverse()
var_m = len(list_d)
var_n = len(list_d)
var_o = 1
var_m = int(var_m)
var_n = int(var_n)
for i, elem in enumerate(range(var_n)):
    var_o = var_o * (var_m-i)
var_p = var_j * var_o
print(int(var_p))