There are five types of shapes: triangular-prism, quadrangular-prism, triangular-pyramid, quadrangular-pyramid, and truncated-quadrangular-pyramid. Given that you place a sticker on the center of each face of each shape, which shape needs the least number of stickers?
[OP_LIST_SOL] triangular-prism quadrangular-prism triangular-pyramid quadrangular-pyramid truncated-quadrangular-pyramid [OP_LIST_EOL] [OP_LIST_SOL] 3 2 [OP_ADD] 4 2 [OP_ADD] 3 1 [OP_ADD] 4 1 [OP_ADD] 4 2 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]
var_a = 'triangular-prism'
var_b = 'quadrangular-prism'
var_c = 'triangular-pyramid'
var_d = 'quadrangular-pyramid'
var_e = 'truncated-quadrangular-pyramid'
list_a= []
if "/" in str(var_e):
    var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
    var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
    var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
    var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
    var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_f = 3
var_g = 2
var_h = var_f + var_g
var_i = 4
var_j = 2
var_k = var_i + var_j
var_l = 3
var_m = 1
var_n = var_l + var_m
var_o = 4
var_p = 1
var_q = var_o + var_p
var_r = 4
var_s = 2
var_t = var_r + var_s
list_b= []
if "/" in str(var_t):
    var_t = eval(str(var_t))
list_b.append(var_t)
if "/" in str(var_q):
    var_q = eval(str(var_q))
list_b.append(var_q)
if "/" in str(var_n):
    var_n = eval(str(var_n))
list_b.append(var_n)
if "/" in str(var_k):
    var_k = eval(str(var_k))
list_b.append(var_k)
if "/" in str(var_h):
    var_h = eval(str(var_h))
list_b.append(var_h)
list_b.reverse()
var_u = 1
list_c=list_b.copy()
list_c.sort()
var_v = list_c[var_u-1]
var_w = list_b.index(var_v)+1
var_x = list_a[var_w-1]
print(var_x)