A has 21 coins, B has 9 coins fewer than A's, and C has 17 more than B's. If the number of coins added to A and B is 5 less than the number of coins added to C and D, how many coins does D have?
21 21 9 [OP_SUB] [OP_ADD] 21 9 [OP_SUB] 17 [OP_ADD] [OP_SUB] 5 [OP_ADD]
var_a = 21
var_b = 21
var_c = 9
var_d = var_b - var_c
var_e = var_a + var_d
var_f = 21
var_g = 9
var_h = var_f - var_g
var_i = 17
var_j = var_h + var_i
var_k = var_e - var_j
var_l = 5
var_m = var_k + var_l
print(int(var_m))