Three of the six numbers 0, 1, 2, 3, 4, 5, and 8 have been chosen to form a three-digit number. If you can use the same number more than once, what is the sum of all the possible numbers?
[OP_LIST_SOL] 0 1 2 3 4 5 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] [OP_LIST_SUM]
var_a = 0
var_b = 1
var_c = 2
var_d = 3
var_e = 4
var_f = 5
var_g = 8
list_a= []
if "/" in str(var_g):
    var_g = eval(str(var_g))
list_a.append(var_g)
if "/" in str(var_f):
    var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
    var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
    var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
    var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
    var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
    var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_h = 3
list_b = [str(i) for i in list_a]
list_b = list(itertools.product(list_b, repeat=var_h))
list_b = [''.join(num_list) for num_list in list_b]
list_b = [str_num for str_num in list_b if str_num[0] != '0']
list_b = [float(i) for i in list_b]
list_b = [float(i) for i in list_b]
var_i = sum(list_b)
print(int(var_i))