When 6 people A, B, C, D, E, and F are lined up in a line, find the number of ways in which A, B, and C can be placed next to each other.
[OP_LIST_SOL] A B C D E F [OP_LIST_EOL] [OP_LIST_SOL] B C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL]
var_a = 'A'
var_b = 'B'
var_c = 'C'
var_d = 'D'
var_e = 'E'
var_f = 'F'
list_a= []
if "/" in str(var_f):
    var_f = eval(str(var_f))
list_a.append(var_f)
if "/" in str(var_e):
    var_e = eval(str(var_e))
list_a.append(var_e)
if "/" in str(var_d):
    var_d = eval(str(var_d))
list_a.append(var_d)
if "/" in str(var_c):
    var_c = eval(str(var_c))
list_a.append(var_c)
if "/" in str(var_b):
    var_b = eval(str(var_b))
list_a.append(var_b)
if "/" in str(var_a):
    var_a = eval(str(var_a))
list_a.append(var_a)
list_a.reverse()
var_g = 'B'
var_h = 'C'
list_b= []
if "/" in str(var_h):
    var_h = eval(str(var_h))
list_b.append(var_h)
if "/" in str(var_g):
    var_g = eval(str(var_g))
list_b.append(var_g)
list_b.reverse()
list_c = list(set(list_a) - set(list_b))
var_i = len(list_c)
var_j = len(list_c)
var_k = 1
var_i = int(var_i)
var_j = int(var_j)
for i, elem in enumerate(range(var_j)):
    var_k = var_k * (var_i-i)
var_l = 'A'
var_m = 'B'
var_n = 'C'
list_d= []
if "/" in str(var_n):
    var_n = eval(str(var_n))
list_d.append(var_n)
if "/" in str(var_m):
    var_m = eval(str(var_m))
list_d.append(var_m)
if "/" in str(var_l):
    var_l = eval(str(var_l))
list_d.append(var_l)
list_d.reverse()
var_o = len(list_d)
var_p = len(list_d)
var_q = 1
var_o = int(var_o)
var_p = int(var_p)
for i, elem in enumerate(range(var_p)):
    var_q = var_q * (var_o-i)
var_r = var_k * var_q
print(int(var_r))