title: Android: unable to maintain session after logging in the application
body: <p>I am trying to open up a URL in <code>WebView</code> but i am unable to do so and i think that is because the session is not maintained.
  I am sending the username, password and the id of user to the server in an activity. here's the code ..</p>
  
  <pre><code>public class ServiceActivity extends Activity {
  private Button button_back;
  
  private Button button_submit_user_pass;
  private EditText edit_id_code;
  private String contents;
  private String format;
  private String username;
  private String password;
  private String id;
  public static HttpClient client;
  
  @Override
  public void onCreate(Bundle savedInstanceState) {
      super.onCreate(savedInstanceState);
      setContentView(R.layout.qr_code_view);
  
      edit_id_code = (EditText) findViewById(R.id.editText_id);
  
      button_back = (Button) findViewById(R.id.button_back);
      button_submit_user_pass = (Button) findViewById(R.id.button_submit_user_pass);
  
      Intent user_pass = getIntent();
  
      username = user_pass.getStringExtra("user");
      password = user_pass.getStringExtra("pass");
  
  
      button_submit_user_pass
              .setOnClickListener(user_pass_qr_submit_listener);
      button_back.setOnClickListener(back_listener);
  
  }
  
  private View.OnClickListener user_pass_qr_submit_listener = new View.OnClickListener() {
  
      @Override
      public void onClick(View v) {
          // TODO Auto-generated method stub
          try {
              id = edit_id_code.getText().toString();
  
              client = new DefaultHttpClient();
              HttpPost post1 = new HttpPost(
                      "xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx");
              List&lt;NameValuePair&gt; nvp = new ArrayList&lt;NameValuePair&gt;();
              nvp.add(new BasicNameValuePair("uname", username));
              nvp.add(new BasicNameValuePair("password", password));
              nvp.add(new BasicNameValuePair("id", id));
              post1.setEntity(new UrlEncodedFormEntity(nvp));
              HttpResponse resp = client.execute(post1);
              String responseText = inputStreamTOString(
                      resp.getEntity().getContent()).toString();
              Log.i("response", responseText);
              int num = Integer.parseInt(responseText);
  
              if (num == 0) {
                  Toast.makeText(getApplicationContext(),
                          "Response" + responseText, 0).show();
              } else if (num == 1) {
                  Intent survey = new Intent(ServiceActivity.this,
                          WebViewActivity.class);
                  startActivity(survey);
              }
          } catch (Exception e) {
              Log.e("error", "ERROR" + e);
          }
  
      }
  
  };
  private View.OnClickListener back_listener = new View.OnClickListener() {
  
      @Override
      public void onClick(View v) {
          // TODO Auto-generated method stub
      }
  };
  
  private StringBuilder inputStreamTOString(InputStream is) {
      String line = "";
      StringBuilder total = new StringBuilder();
  
      // read response until the end
      try {
          BufferedReader rd = new BufferedReader(new InputStreamReader(is,
                  "iso-8859-1"), 8);
          while ((line = rd.readLine()) != null) {
              total.append(line);
  
          }
      } catch (Exception e) {
          // TODO: handle exception
      }
      return total;
  
  }
  }
  </code></pre>
  
  <p>After this if the response from the server side is "1" i am opening a new activity in which I need to display the content of the user in the <code>WebView</code> here's the code</p>
  
  <pre><code>public class WebViewActivity extends Activity{
  private WebView web;
  @Override
  public void onCreate(Bundle savedInstanceState){
      super.onCreate(savedInstanceState);
      setContentView(R.layout.web_view);
  
      web = (WebView) findViewById(R.id.webView);
  
  
      web.getSettings().setJavaScriptEnabled(true);
  
  
      web.loadUrl("xxxxxxxxxxxxxxxxxxxxxxxxxxxx");
  }
  
  }
  </code></pre>
  
  <p>but i am unable to load the URL corresponding o the user, I get php errors over the webviewactivity and that is because i am unable to maintain the session of the user who has logged in. Please suggest me some solution to this. </p>