title: Parse Quartz cron expression with Croniter
body: <p>This code:</p>
  <pre><code>starting_point = datetime.datetime.now() - datetime.timedelta(hours=1)
  cron = croniter.croniter('44 5 19 ? * WED,THU,FRI *', starting_point)
  cron.get_next(datetime.datetime)
  </code></pre>
  <p>Results in:</p>
  <blockquote>
  <p>croniter.croniter.CroniterBadCronError: Exactly 5 or 6 columns has to be specified for iterator expression.</p>
  </blockquote>
  <p>But when using <a href="https://www.freeformatter.com/cron-expression-generator-quartz.html" rel="nofollow noreferrer">https://www.freeformatter.com/cron-expression-generator-quartz.html</a>, the same expression results in</p>
  <blockquote>
  <p>At 19:05:44pm, on every Wednesday, Thursday and Friday, every month</p>
  </blockquote>
  <p>How to parse this cron expression with croniter?</p>