title: "Getting started" issue with JOSS JavaSWIFT
body: <p>I'm testing joss javaswift following this <a href="http://joss.javaswift.org/" rel="nofollow">link</a>. I also added JAR files from <a href="http://grepcode.com/snapshot/repo1.maven.org/maven2/org.javaswift/joss/0.9.8" rel="nofollow">here</a> to my project. But it provides an error. What am I doing wrong?</p>
  
  <pre><code>package test;
  
  import org.javaswift.joss.client.factory.AccountConfig;
  import org.javaswift.joss.client.factory.AccountFactory;
  import org.javaswift.joss.model.Account;      
  
  public class Test {
  
      public static void main(String[] args)
      {
          String username = "user";
          String password = "pwd";
          String authUrl  = "http://...";
          String tenantName = "test";
  
          AccountConfig config = new AccountConfig();
          config.setUsername(username);
          config.setPassword(password);
          config.setAuthUrl(authUrl);
          config.setTenantName(tenantName);
  
          Account account = new AccountFactory(config).createAccount();
  
      }
  }
  </code></pre>
  
  <blockquote>
    <p>Exception in thread "main" java.lang.NoClassDefFoundError:
    org/apache/http/conn/scheme/SchemeSocketFactory   at
    org.javaswift.joss.client.factory.AccountFactory.createClientImpl(AccountFactory.java:38)
      at
    org.javaswift.joss.client.factory.AccountFactory.createAccount(AccountFactory.java:28)
      at test.TestSWIFT3.main(TestSWIFT3.java:23)</p>
    
    <p>Caused by: java.lang.ClassNotFoundException:
    org.apache.http.conn.scheme.SchemeSocketFactory   at
    java.net.URLClassLoader$1.run(Unknown Source)     at
    java.net.URLClassLoader$1.run(Unknown Source)     at
    java.security.AccessController.doPrivileged(Native Method)    at
    java.net.URLClassLoader.findClass(Unknown Source)     at
    java.lang.ClassLoader.loadClass(Unknown Source)   at
    sun.misc.Launcher$AppClassLoader.loadClass(Unknown Source)    at
    java.lang.ClassLoader.loadClass(Unknown Source)   ... 3 more</p>
  </blockquote>