title: awk command to print out entire row that contains a certain string
body: <pre><code>output.txt
  Test Results 1 PASSED with 2 minutes to process 0 issues
  Test Results 2 PASSED with 10 minutes to process 0 issues
  Test Results 3 FAILED ERROR 1 issues
  Test Results 4 PASSED with 4 minutes to process 0 issues
  Test Results 5 FAILED ERROR 3 issues
  Test Results 6 PASSED with 19 minutes to process 0 issues
  </code></pre>
  
  <p>I need help coming up with a awk command to parse through this text. I want to list only rows that has more than 0 issue.</p>
  
  <p>So in this case</p>
  
  <p><code>Test Results 1 PASSED with 2 minutes to process 0 issues
   Test Results 5 FAILED ERROR 3 issues</code></p>