title: print row of integers from csv file Python
body: <p>So, I have a csv file. I just want to print the rows of the file as integers not in [ ].
  My table of numbers looks like:</p>
  
  <p>1 ; 0 ; 5 ; 10 ; 4 ; 3 ; 1 ; 7 ; 6 ; 11 </p>
  
  <hr>
  
  <p>1 ; 10 ; 4 ; 1 ; 1 ; 31 ; 0 ; 11 ; 0 ; 41 </p>
  
  <hr>
  
  <p>10 ; 4 ; 0 ; 12 ; 34 ; 2 ; 13 ; 3 ; 4 ; 4 </p>
  
  <hr>
  
  <p>2 ; 3 ; 6 ; 4 ; 5 ; 7 ; 8 ; 9 ; 11 ; 10 </p>
  
  <hr>
  
  <p>1 ; 2 ; 3 ; 12 ; 23 ; 24 ; 1 ; 2 ; 3 ; 4 </p>
  
  <hr>
  
  <p>1 ; 76 ; 3 ; 43 ; 54 ; 6 ; 5 ; 4 ; 3 ; 4 </p>
  
  <hr>
  
  <p>18 ; 12 ; 13 ; 14 ; 25 ; 34 ; 56 ; 43 ; 23 ; 23 </p>
  
  <hr>
  
  <p>34 ; 2 ; 5 ; 3 ; 3 ; 23 ; 23 ; 3 ; 2 ; 43 </p>
  
  <hr>
  
  <p>34 ; 32 ; 1 ; 5 ; 3 ; 23 ; 21 ; 3 ; 1 ; 3 </p>
  
  <hr>
  
  <p>1 ; 1 ; 2 ; 45  ; 2 ; 23 ; 1 ; 4 ; 1 ; 1</p>
  
  <hr>
  
  <p>Now. My code looks like this.</p>
  
  <pre><code>import csv
  with open('probeMitComma.csv','r+') as fin:
      read= csv.reader(fin, delimiter='\t')
      total = 0
      rows = list(read)
      print (rows[1],"\n",rows[2])
  </code></pre>
  
  <p>what I get is</p>
  
  <pre><code>['1', '10', '4', '1', '1', '31', '0', '11', '0', '41'] 
   ['10', '4', '0', '12', '34', '2', '13', '3', '4', '4']
  </code></pre>
  
  <p>I want to get those without [ ] and without ' '. I have tried with <strong>join</strong> (I get an error because it is with int) </p>
  
  <p>beside this issue I also have another one. 
  My full code looks like:</p>
  
  <pre><code>import csv
  with open('probeMitComma.csv','r+') as fin:
      read= csv.reader(fin, delimiter='\t')
      total = 0
      rows = list(read)    #If I make this line and the one under as a comment it
      print (rows[1],"\n",rows[2])    #shows me the column that I want with the sum
  
      for col in read:
          print (col[0])
          total += int(col[0])
      print ("Total lautet " + str(total))
  </code></pre>
  
  <p>My real objective is to print each column with the respective sum and each row with the respective sum.</p>