title: awk: print first line in which a field condition is met
body: <p>I know it's a ridiculously simple problem, but I'd like to print the first line in many files for which a given field condition is met:</p>
  
  <pre><code>$ awk ' ( $3&gt;=0.2 ) { print $3, $5 } ' Data.out
  </code></pre>
  
  <p>I've tried to insert END in a few places to exit printing, but I can't get it to work...  The above prints ALL the lines for which $3>=0.2...</p>