title: Running a thread which doesn't return back anything in Python
body: <p>I am writing a bot for Discord which can create a timer and notify when it runs out. With the code that i have right now the bot sleeps for that amount of time and then messages saying that time is up.
  (uses discord.py)</p>
  <pre><code>@bot.command(name='create')
  async def create_schedule(ctx, title: str, mins: float):
      await ctx.send(f'Created schedule for {title} in {mins} minutes')
      time.sleep(60*mins)
      await ctx.send(f'{title} is starting now!')
  </code></pre>
  <p>But the problem is that i can't create two schedules at the same time since the second one will be put in queue, wait for the first one to finish and then start the timer.
  I have tried to create a new thread and sleep in that thread so that i can accept another create command but that didn't work.</p>
  <pre><code>async def wait(ctx, title, mins):
      time.sleep(int(60*mins))
      await ctx.send(f'{title} is starting now!')
  
  @bot.command(name='create')
  async def create_schedule(ctx, title: str, mins: float):
      await ctx.send(f'Created schedule for {title} in {mins} minutes')
      threading.Thread(target=wait, args=(ctx, title, mins)).start()
  </code></pre>
  <p>I dont want to wait for the <code>wait()</code> function to finish before i accept another command. I just want to start up the timer, set it aside and continue parsing other commands. How can i do this?  BTW The <code>wait()</code> function has a way of displaying that the time is up (<code>ctx.send(f'{title} is starting now!')</code>) so it doesn't have to return anything or call any other part of the program after the timer is done sleeping (and i don't want it to do anything else after the time is up).
  Thanks in advance</p>