title: Replace word with contents of paste buffer?
body: <p>I need to do a bunch of word replacements in a file and want to do it with a vi command, not an EX command such as <code>:%s///g</code>.</p>
  <p>I know that this is the typical way one replaces the word at the current cursor position: <code>cw&lt;text&gt;&lt;esc&gt;</code> but is there a way to do this with the contents of the unnamed register as the replacement text and without overwriting the register?</p>