title: URLOpen Error while combining url with word from wordlist
body: <p>Hey guys im making a Python Webcrawler at the Moment. So i have a link, which last chars are: "search?q=" and after that im using my wordlist which i have loaded before into a list. But when i try to open that with : urllib2.urlopen(url) it throws me an Error (urlopen error no host given) . But when i open that link with urllib normally (so typing the word which is normally automatic pasted in) it just works fine. So can you tell me why this is happening?</p>
  
  <p>Thanks and regards</p>
  
  <p>Full error:</p>
  
  <p><div class="snippet" data-lang="js" data-hide="false">
  <div class="snippet-code">
  <pre class="snippet-code-js lang-js prettyprint-override"><code>  File "C:/Users/David/PycharmProjects/GetAppResults/main.py", line 61, in &lt;module&gt;
      getResults()
    File "C:/Users/David/PycharmProjects/GetAppResults/main.py", line 40, in getResults
      usock = urllib2.urlopen(url)
    File "C:\Python27\lib\urllib2.py", line 127, in urlopen
      return _opener.open(url, data, timeout)
    File "C:\Python27\lib\urllib2.py", line 402, in open
      req = meth(req)
    File "C:\Python27\lib\urllib2.py", line 1113, in do_request_
      raise URLError('no host given')
  urllib2.URLError: &lt;urlopen error no host given&gt;</code></pre>
  </div>
  </div>
  </p>
  
  <p>Code:</p>
  
  <p><div class="snippet" data-lang="js" data-hide="false">
  <div class="snippet-code">
  <pre class="snippet-code-js lang-js prettyprint-override"><code>with open(filePath, "r") as ins:
      wordList = []
      for line in ins:
          wordList.append(line)
  
  def getResults():
  packageID = ""
  count = 0
  word = "Test"
  for x in wordList:
      word = x;
      print word
      url = 'http://www.example.com/search?q=' + word
      usock = urllib2.urlopen(url)
      page_source = usock.read()
      usock.close()
      print page_source
      startSequence = "data-docid=\""
      endSequence = "\""
      while page_source.find(startSequence) != -1:
          start = page_source.find(startSequence) + len(startSequence)
          end = page_source.find(endSequence, start)
          print str(start);
          print str(end);
          link = page_source[start:end]
          print link
          if link:
              if not link in packageID:
                  packageID += link + "\r\n"
                  print packageID
          page_source = page_source[end + len(endSequence):]
  count+=1</code></pre>
  </div>
  </div>
  </p>
  
  <p>So when i print the string word it outputs the correct word from the wordlist</p>