title: Python - skip if has not pattern of date
body: <p>I have a csv where I have for example this:</p>
  
  <pre><code>Date,Comment
  
  2014-05-29,Last time we will see
  
  What about next time?"
  
  2014-05-29,"""still want to be seen as the good guys..."""
  
  This is my world. 
  
  2014-05-29,And so the game begins... ;)
  
  2014-05-29,"Btw, this is... 
  </code></pre>
  
  <p>And I would like to skip those rows which have not a date format in first column. I have this:</p>
  
  <pre><code>a = []
  csvReader = csv.reader(open(csv_file_to_open, 'rb'), delimiter=',')
  for row in csvReader:
      a.append(row)
  
  for row in a:
      if row[0] == "date format then": &lt;= here I need some pattern filter but I don't know how to do it
          print 'yes'
  </code></pre>
  
  <p>Date is always in format <code>%Y-%m-%d</code>.</p>