title: jq parsing date to timestamp
body: <p>I have the following script:</p>
  
  <pre><code>curl -s -S 'https://bittrex.com/Api/v2.0/pub/market/GetTicks?marketName=BTC-NBT&amp;tickInterval=thirtyMin&amp;_=1521347400000' | jq -r '.result|.[] |[.T,.O,.H,.L,.C,.V,.BV] | @tsv | tostring | gsub("\t";",") | "(\(.))"'
  </code></pre>
  
  <p>This is the output:</p>
  
  <pre><code>(2018-03-17T18:30:00,0.00012575,0.00012643,0.00012563,0.00012643,383839.45768188,48.465051)
  (2018-03-17T19:00:00,0.00012643,0.00012726,0.00012642,0.00012722,207757.18765437,26.30099514)
  (2018-03-17T19:30:00,0.00012726,0.00012779,0.00012698,0.00012779,97387.01596624,12.4229077)
  (2018-03-17T20:00:00,0.0001276,0.0001278,0.00012705,0.0001275,96850.15260027,12.33316229)
  </code></pre>
  
  <p>I want to replace the date with timestamp.</p>
  
  <p>I can make this conversion with date in the shell</p>
  
  <pre><code>date -d '2018-03-17T18:30:00' +%s%3N
  1521325800000
  </code></pre>
  
  <p>I want this result:</p>
  
  <pre><code>(1521325800000,0.00012575,0.00012643,0.00012563,0.00012643,383839.45768188,48.465051)
  (1521327600000,0.00012643,0.00012726,0.00012642,0.00012722,207757.18765437,26.30099514)
  (1521329400000,0.00012726,0.00012779,0.00012698,0.00012779,97387.01596624,12.4229077)
  (1521331200000,0.0001276,0.0001278,0.00012705,0.0001275,96850.15260027,12.33316229)
  </code></pre>
  
  <p>This data is stored in MySQL.</p>
  
  <p>Is it possible to execute the date conversion with jq or another command like awk, sed, perl in a single command line?</p>