title: Unix awk command regex problem
body: <p>I have data like this:</p>
  
  <pre><code># data_display  
  
  ab as we hj kl  
  12 34 45 83 21  
  45 56 98 45 09
  </code></pre>
  
  <p>I need just the first column alone, and only the rows starting with numbers.</p>
  
  <p>I now use:</p>
  
  <pre><code># data_display | awk '{ print $1 }' | grep "^[0-9]"  
  </code></pre>
  
  <p>Is there any way to optimise it more,  like using the regex in awk itself?</p>
  
  <p>I am very new to awk.</p>
  
  <p>Thanks.</p>
  
  <p>KK</p>