title: Return the cube of a number in Python
body: <p>stuck on this exercise. </p>
  
  <p>INSTRUCTIONS </p>
  
  <blockquote>
    <p>First, def a function called <code>cube</code> that takes an argument called
    <code>number</code>. Don't forget the parentheses and the colon!</p>
    
    <p>Make that function return the cube of that number (i.e. that number
    multiplied by itself and multiplied by itself once again).</p>
    
    <p>Define a second function called <code>by_three</code> that takes an argument called
    <code>number</code>. if that number is divisible by 3, <code>by_three</code> should call
    <code>cube(number)</code> and return its result. Otherwise, <code>by_three</code> should return
    <code>False</code>.</p>
  </blockquote>
  
  <p>MY CODE </p>
  
  <pre><code>def cube(number): 
      return number ** number ** number 
  
  def by_three(number)
      if number % 3 == 0:
          return cube(number)
  
      else:
          return False 
  </code></pre>