title: How do I generate monteCarlopi function in a given circle/square?
body: <p>Write a function monteCarloPi(n, radius) that takes two arguments, the number of simulations n and the radius of the circle, and returns a float, which is the estimated value for pi. This radius should be the same radius that you used to draw your inscribed circle in the previous problem. Generate a set of random points, and test to see if that value is inside the circle or outside the circle. Use turtle to draw a dot at each location. This can be done using the function turtle.dot(size, color). Find the ratio of the points inside the circle to the number of points in the simulation. The latter number is an estimate for the area of the square. Multiple the ratio by four to get your estimate for pi.</p>
  <p>This is what I have and I have no idea why it only draws one dot. Can anybody help me? I am a beginner /:</p>
  <pre class="lang-py prettyprint-override"><code>import turtle as t
  import random
  
  def monteCarloPi(n, radius):
      '''
      Takes two arguments, the number of simulations n and the radius of the circle, and returns a float, which is the estimated value for pi.
      
      '''
      
      t.dot() # Origin (0, 0)
      t.pu()
      t.goto(0, -radius)
      t.pd()
      t.circle(radius)
      t.pu()
      t.goto(-radius ,-radius)
      t.pd()
      
      for square in range(4):
          t.fd(radius * 2) 
          t.lt(90)
          
      points_in_circle = 0
      points_in_square = 0
      x = random.uniform(-radius, radius)
      y = random.uniform(-radius, radius)
      
      for dots in range(n):
          t.pu()
          t.goto(x, y)
          t.dot()
          
          origin = x ** 2 + y ** 2
          if origin &lt;=1 :
              points_in_circle += 1
          else:
              points_in_square +=1
              
          pi = 4 * (points_in_circle / points_in_square)
          return pi
  </code></pre>