title: Coin Flip Streaks Challenge - Al Sweigart's Automate The Boring Stuff with python
body: <p>Looking around the internet for the expected result to this challenge I have found different answers so that I'm not sure what is correct. I think my code looks ok and results in <strong>1.5%</strong> but differs from others. So I am looking for the correct answer to this.</p>
  <p>Here's the challenge:</p>
  <p><strong>Coin Flip Streaks</strong></p>
  <p><em>For this exercise, we’ll try doing an experiment. If you flip a coin 100 times and write down an “H” for each heads and “T” for each tails, you’ll create a list that looks like “T T T T H H H H T T.” If you ask a human to make up 100 random coin flips, you’ll probably end up with alternating head-tail results like “H T H T H H T H T T,” which looks random (to humans), but isn’t mathematically random. A human will almost never write down a streak of six heads or six tails in a row, even though it is highly likely to happen in truly random coin flips. Humans are predictably bad at being random. Write a program to find out how often a streak of six heads or a streak of six tails comes up in a randomly generated list of heads and tails. Your program breaks up the experiment into two parts: the first part generates a list of randomly selected 'heads' and 'tails' values, and the second part checks if there is a streak in it. Put all of this code in a loop that repeats the experiment 10,000 times so we can find out what percentage of the coin flips contains a streak of six heads or tails in a row. As a hint, the function call random.randint(0, 1) will return a 0 value 50% of the time and a 1 value the other 50% of the time. You can start with the following template:</em></p>
  <pre><code>import random
  numberOfStreaks = 0
  for experimentNumber in range(10000):
      # Code that creates a list of 100 'heads' or 'tails' values.
      # Code that checks if there is a streak of 6 heads or tails in a row.
  print('Chance of streak: %s%%' % (numberOfStreaks / 100))
  </code></pre>