title: How to extract the URL of a particular page using selenium/python?
body: <p>I'm building an instagram Bot using selenium.
  How do I extract the URL of a page using python?</p>
  <p>For example Selenium is loading a webpage. I want to extract the url of that particular page .(Suppose : <a href="https://instagram.com/as80df67s4" rel="nofollow noreferrer">https://instagram.com/as80df67s4</a>)</p>
  <p>If you still don't understand what I'm talking about, please check the image below. There, I have highlighted the page link. How do I extract that link?</p>
  <p><a href="https://i.stack.imgur.com/Fr86d.jpg" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/Fr86d.jpg" alt="enter image description here" /></a></p>