title: Python: UnicodeDecodeError: 'utf8' codec can't decode byte 0x91
body: <p>I'm parsing a CSV as follows:</p>
  
  <pre><code>with open(args.csv, 'rU') as csvfile:
          try:
              reader = csv.DictReader(csvfile, dialect=csv.QUOTE_NONE)
              for row in reader:
              ...
  </code></pre>
  
  <p>where <code>args.csv</code> is the name of my file.  One of the rows in my file is an e with two dots on top.  My script breaks when it encounters this.  </p>
  
  <p>I get the following stack trace:</p>
  
  <pre><code>File "/usr/local/Cellar/python/2.7.11/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/__init__.py", line 244, in dumps
      return _default_encoder.encode(obj)
    File "/usr/local/Cellar/python/2.7.11/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/encoder.py", line 207, in encode
      chunks = self.iterencode(o, _one_shot=True)
    File "/usr/local/Cellar/python/2.7.11/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/encoder.py", line 270, in iterencode
      return _iterencode(o, 0)
  </code></pre>
  
  <p>and the following error:</p>
  
  <pre><code>UnicodeDecodeError: 'utf8' codec can't decode byte 0x91 in position 5: invalid start byte
  </code></pre>
  
  <p>FWIW, I'm running Python 2.7 and upgrading isn't an option (for a few reasons).</p>
  
  <p>I'm pretty lost about how to fix this so any help is much appreciated.</p>
  
  <p>Thanks!</p>