title: How to skip the first row when reading a csv file?
body: <p>I have an awkward csv file and I need to skip the first row to read it.</p>
  
  <p>I'm doing this easily with python/pandas</p>
  
  <pre><code>df = pd.read_csv(filename, skiprows=1)
  </code></pre>
  
  <p>but I don't know how to do it in Go.</p>
  
  <pre><code>package main
  
  import (
      "encoding/csv"
      "fmt"
      "log"
      "os"
  )
  
  type mwericsson struct {
      id     string
      name   string
      region string
  }
  
  func main() {
  
      rows := readSample()
  
      fmt.Println(rows)
      //appendSum(rows)
      //writeChanges(rows)
  }
  
  func readSample() [][]string {
      f, err := os.Open("D:/in/20190629/PM_IG30014_15_201906290015_01.csv")
      if err != nil {
          log.Fatal(err)
      }
      rows, err := csv.NewReader(f).ReadAll()
      f.Close()
      if err != nil {
          log.Fatal(err)
      }
      return rows
  }
  </code></pre>
  
  <p>Error:</p>
  
  <pre><code>2019/07/01 12:38:40 record on line 2: wrong number of fields
  </code></pre>
  
  <p><code>PM_IG30014_15_201906290015_01.csv</code>:</p>
  
  <pre><code>PTN Ethernet-Port RMON Performance,PORT_BW_UTILIZATION,2019-06-29 20:00:00,33366     
  DeviceID,DeviceName,ResourceName,CollectionTime,GranularityPeriod,PORT_RX_BW_UTILIZATION,PORT_TX_BW_UTILIZATION,RXGOODFULLFRAMESPEED,TXGOODFULLFRAMESPEED,PORT_RX_BW_UTILIZATION_MAX,PORT_TX_BW_UTILIZATION_MAX
  3174659,H1095,H1095-11-ISM6-1(to ZJBSC-V1),2019-06-29 20:00:00,15,22.08,4.59,,,30.13,6.98
  3174659,H1095,H1095-14-ISM6-1(to T6147-V),2019-06-29 20:00:00,15,2.11,10.92,,,4.43,22.45
  </code></pre>