title: Square root loop in python
body: <p>I need to take an input of a number greater than 2, and take the square root until the square root is less than two. I need a print statement that includes the count of the times the square root of the number was taken as well as the output. What I have so far is:</p>
  
  <pre><code>import math
  
  input_num = float(input("Enter a number greater than two: "))
  
  while input_num &lt; 2:
      input_num = float(input("Enter a number greater than two: "))
  else:
      sqrt_num = math.sqrt(input_num)
      count = 1
      while sqrt_num &gt; 2:
          sqrt_num = math.sqrt(sqrt_num)
          count += 1
          print(count, ": ", sqrt_num, sep = '')
  </code></pre>
  
  <p>With the output of:</p>
  
  <pre><code>Enter a number greater than two: 20
  2: 2.114742526881128
  3: 1.4542154334489537
  </code></pre>
  
  <p>I want to include that first iteration of count 1. <strong>How do I write a proper loop so it looks like</strong>:</p>
  
  <pre><code>Enter a number greater than two: 20
  1: 4.47213595499958
  2: 2.114742526881128
  3: 1.4542154334489537
  </code></pre>