title: Converting Integers to Characters in Common Lisp
body: <p>Is there a way to parse integers to their char equivalents in Common Lisp?</p>
  
  <p>I've been looking all morning, only finding <code>char-int</code>...</p>
  
  <pre><code>* (char-int #\A)
  
  65
  </code></pre>
  
  <p>Some other sources also claim the existance of <code>int-char</code></p>
  
  <pre><code>* (int-char 65)
  ; in: INT-CHAR 65
  ;     (INT-CHAR 65)
  ; 
  ; caught STYLE-WARNING:
  ;   undefined function: INT-CHAR
  ; 
  ; compilation unit finished
  ;   Undefined function:
  ;     INT-CHAR
  ;   caught 1 STYLE-WARNING condition
  
  debugger invoked on a UNDEFINED-FUNCTION:
    The function COMMON-LISP-USER::INT-CHAR is undefined.
  
  Type HELP for debugger help, or (SB-EXT:EXIT) to exit from SBCL.
  
  restarts (invokable by number or by possibly-abbreviated name):
    0: [ABORT] Exit debugger, returning to top level.
  
  ("undefined function")
  </code></pre>
  
  <p>What I'm really looking for, however, is a way of converting <code>1</code> to <code>#\1</code> </p>
  
  <p>How exactly would I do that?</p>