title: Errno 22 Invalid argument...python3.exe: can't open file print.py
body: <p>I have these two scripts within the same folder, I'm working in Windows 10:</p>
  
  <p>File <code>job.sh</code></p>
  
  <pre><code>python3 print.py
  </code></pre>
  
  <p>File <code>print.py</code></p>
  
  <pre><code>#!/usr/bin/python3
  print('Hello World')
  </code></pre>
  
  <p>When I run <code>job.sh</code> I get the error, </p>
  
  <p><code>[Errno 22] Invalid argument7-32\python3.exe can't open file print.py</code></p>
  
  <p>But, after a lot of ways that I tried, I just noticed that only the first line is generating this error. So, If I modify the file <code>job.sh</code></p>
  
  <pre><code>python3 print.py
  python3 print.py
  </code></pre>
  
  <p>then the first line is generating the same error, whereas the second is showing the result. </p>
  
  <p>Btw, if I write directly in cmd <code>python3 print.py</code> everything is fine.</p>
  
  <p>I have no idea what is wrong with my <code>job.sh</code> script. Thanks for any help!</p>