title: Addition of any number of columns in each loop
body: <p>Example:</p>
  
  <pre><code>dict1 = ({'ROADS' : ['STREETNAME', 'LEFTFROM', 'LEFTTO', 'RIGHTFROM', 'RIGHTTO'],
              'ITA' :  ['I.ID_BOUND', 'I.BOUND_IDQ']}) 
  </code></pre>
  
  <p><strong>Note</strong></p>
  
  <p><code>ROADS,ITA</code> are the files
  the rest are their columns.</p>
  
  <p>I want to do an addition like concat of all the columns in every file.
  The problem is that each file has different number of columns.</p>
  
  <p>How to make it do it with this?</p>
  
  <p><strong>Update</strong></p>
  
  <p>Explanation:</p>
  
  <p>how to make it add any number of columns that may exist in the dictionary?
  This following example tries to explicitly refer to each column as v[0],etc
  What I want is to do it no matter the number of columns so to just takes independently of the number.</p>
  
  <p>I tried:</p>
  
  <pre><code>for k,v in dict1.items():
      newfield = v[0] + v[1]
  </code></pre>