title: Explanation of ldd output
body: <p>Can someone explain to me the output of ldd command?
  In the following example (on Gentoo system)   </p>
  
  <pre><code>$ ldd /bin/date
    linux-vdso.so.1 =&gt;  (0x00007fff6ffff000)
    librt.so.1 =&gt; /lib64/librt.so.1 (0x00007f54ba710000)
    libc.so.6 =&gt; /lib64/libc.so.6 (0x00007f54ba384000)
    libpthread.so.0 =&gt; /lib64/libpthread.so.0 (0x00007f54ba167000)
    /lib64/ld-linux-x86-64.so.2 (0x00007f54ba919000)
  </code></pre>
  
  <p>what does the first line mean? The "linux-vdso.so.1 =>  (0x00007fff6ffff000)" The => doesn't point to any shared library file.</p>