title: xml.parsers.expat.ExpatError on parsing XML
body: <p>I have been trying to retrieve information through HTTP queries, as an example </p>
  
  <p><a href="http://www.opencellid.org/cell/get?key=xxxxxxxxxxxxx&amp;mnc=1&amp;mcc=228&amp;lac=101&amp;cellid=7283" rel="nofollow">http://www.opencellid.org/cell/get?key=xxxxxxxxxxxxx&amp;mnc=1&amp;mcc=228&amp;lac=101&amp;cellid=7283</a></p>
  
  <p>returns me a response in XML format, like</p>
  
  <pre><code>&lt;rsp stat="ok"&gt;
  &lt;cell nbSamples="1" mnc="1" lac="101" lat="46.52079" lon="6.56676" cellId="7283" mcc="228" range="6000"/&gt;
  &lt;/rsp&gt;
  </code></pre>
  
  <p>I have tried using the <code>response</code> and <code>urllib</code> modules to open the URL, and then parse using  <code>elementtree.ElementTree</code>.</p>
  
  <p>Code snippet:</p>
  
  <pre><code>url = 'http://www.opencellid.org/cell/get?key=xxxxxxxxxx&amp;mnc=1&amp;mcc=228&amp;lac=101&amp;cellid=7283 '
  rss = parse(requests.get(url = url)).getroot()
  pprint(rss)
  </code></pre>
  
  <p>I however get the following error:</p>
  
  <pre><code>xml.parsers.expat.ExpatError: junk after document element: line 5, column 0
  </code></pre>
  
  <p>Just printing the response yields the HTML success code. Some help please!</p>