title: calling php file fron another php file while passing arguments
body: <p>i need to call a php inside another php file and pass some arguments also. how can i do this??
  i tried</p>
  
  <pre><code>include("http://.../myfile.php?file=$name");
  </code></pre>
  
  <ul>
  <li>but gives access denied. i read like v must not set allow_url_open to OFF.</li>
  </ul>
  
  <p>if i write like</p>
  
  <pre><code>$cmd = "/.../myfile.php?file=".$name";
  $out =exec($cmd. " 2&gt;&amp;1");
  echo $out;
  </code></pre>
  
  <ul>
  <li>gives error as /.../myfiles.php?file=hello: no such file or directory.</li>
  </ul>
  
  <p>how can i solve this???</p>