title: IOS - Use Custom UI TableViewCell as TableFooter
body: <p>I have setup a UITableViewController with various custom cells - one of which is a submit button - which I need to appear once at the foot of the table.</p>
  
  <p>the cell has the following identifier - </p>
  
  <pre><code> UITableViewCell *headerView = [tableView dequeueReusableCellWithIdentifier:@"ButtonTableViewCell"];
  </code></pre>
  
  <p>Can anyone advise on how I could apply this cell once at the foot of my table?  It needs to access a segue also.  </p>
  
  <p>I considered using the </p>
  
  <pre><code>  -(void)tableView:(UITableView *)tableView willDisplayFooterView:(UIView *)view forSection:(NSInteger)section { 
  </code></pre>
  
  <p>method, but not sure how or if I could apply my cell in this way as that method doesnt return anything?</p>