title: Bash script that writes subdirectories who has more than 5 files
body: <p>while I was trying to practice my linux skills, but I could not solve this question.</p>
  
  <blockquote>
    <p>So its basically saying  "Write a bash script that takes  a name of
    directory as a command argument and printf the name of subdirectories
    that has more than 5 files in it."</p>
  </blockquote>
  
  <p>I thought we will use the <code>find</code> command but ı still could not figure it out. My code is:</p>
  
  <pre><code>find directory -type d -mindepth5 
  </code></pre>
  
  <p>but it's not working.</p>