title: CSV - display rows in which specified column is empty
body: <p>i have an csv file that goes like this:</p>
  <pre><code>department_id,department_name,manager_id,location_id
   10,Administration,200,1700
   20,Marketing,201,1800
   30,Purchasing,114,1700
   40,Human Resources,NaN,2400
   50,Shipping,NaN,1500
  ......
  </code></pre>
  <p>the task is to print rows in which column <code>manager_id</code> is empty, and <code>no headers</code> are displayed.</p>
  <p>The closest approach i achieved is :</p>
  <pre><code>import pandas as pd
  df = pd.read_csv ('data.csv', header=None, index_col = 0 )
  null_data = df[df.isnull().any(axis=1)]
  print(null_data)
  </code></pre>
  <p>but it prints weird</p>
  <pre><code>Your code output:
  1    2     3
  0                                   
  120              Treasury  NaN  1700
  ....
  </code></pre>
  <p>at the beggining.
  I would be grateful with any help, not really with pandas, all approaches  would be great.</p>