title: Display ListPopupWindow on most left of the screen
body: <p>I could display ListPopupWindow on most left of the screen by following code.</p>
  
  <pre><code>@Override
  public View onCreateActionView() {
      LayoutInflater layoutInflater = LayoutInflater.from(mContext);
  
      final View actionItem = layoutInflater.inflate(R.layout.list_table_view_action_provider, null);
  
      final ImageButton button = (ImageButton) actionItem.findViewById(R.id.button);
      button.setOnClickListener(new View.OnClickListener() {
          @Override
          public void onClick(View v) {
              mListPopupWindow = new ListPopupWindow(mContext);
              mListPopupWindow.setAnchorView(actionItem);
              mListPopupWindow.setAdapter(mAdapter);
              mListPopupWindow.setModal(true);
              mListPopupWindow.setContentWidth(150);
  
              // Display mListPopupWindow on most left of the screen
              mListPopupWindow.setHorizontalOffset(-1000);
  
  
              mListPopupWindow.setOnItemClickListener(ListTableViewActionProvider.this);
  
              mListPopupWindow.show();
              mListPopupWindow.setOnDismissListener(ListTableViewActionProvider.this);
          }
      });
  
      return actionItem;
  }
  </code></pre>
  
  <p>"mListPopupWindow.setHorizontalOffset(-1000);" is too bad.
  Is there other solutions?</p>