title: flutter firebase deeplinks params not getting
body: <p>I am creating a flutter application. I am using Deeplink. It is creating success but the clicking part of the app not working well. The app is retrieving the url but not retrieving the params. I don't know what is the reason?
  My codes are shown below.</p>
  <pre><code>    final DynamicLinkParameters parameters = DynamicLinkParameters(
      uriPrefix: 'https://mydomain.page.link',
      link: Uri.parse(
          // 'https://pachiradev.page.link/circleinvite?token=' + uid1.toString()
          'https://pachiradev.page.link/circleinvite?token=' + '1234'),
      androidParameters: AndroidParameters(
          packageName: 'io.flutter.plugins.firebasedynamiclinksexample',
          minimumVersion: 0,
      ),
      dynamicLinkParametersOptions: DynamicLinkParametersOptions(
          shortDynamicLinkPathLength: ShortDynamicLinkPathLength.short,
      ),
      iosParameters: IosParameters(
          bundleId: 'com.google.FirebaseCppDynamicLinksTestApp.dev',
          minimumVersion: '0',
      ),
      );
  
      Uri url;
  
    final ShortDynamicLink shortLink = await parameters.buildShortLink();
    url = shortLink.shortUrl;
  
      print(url)
  
      //https://mydomain.page.link/circleinvite?token=1234
      //https://mydomain.page.link/ARTu
  </code></pre>
  <p>Here I printing the url with params. But in retrieving code I am not getting params</p>
  <pre><code>    FirebaseDynamicLinks.instance.onLink(
          onSuccess: (PendingDynamicLinkData dynamicLink) async {
      final Uri deepLink = dynamicLink?.link;
  
  
      print(deepLink);
        //https://mydomain.page.link/circleinvite
        //not showing params
  
      if (deepLink != null) {
          // Navigator.pushNamed(context, deepLink.path);
          final queryParams = deepLink.queryParameters;
          if (queryParams.length &gt; 0) {
          String token = queryParams[&quot;token&quot;];
  
          }
      }
      }, onError: (OnLinkErrorException e) async {
      print('onLinkError');
      print(e.message);
      });
  </code></pre>
  <p>I tried several way but no results. If anyone know the reason please help me.</p>