title: SVN checkout bat file error
body: <p>I have created a batch file as below:</p>
  <pre><code>set SVNExe = &quot;C:\Program Files\TortoiseSVN\bin\svn.exe&quot;
  set SVNURL = &quot;https://server.local/svn/MyProject/&quot;
  set CheckOutLocation = &quot;E:\Projects\MyProject&quot;
  %SVNExe% checkout %SVNURL% %checkOutLocation%
  @pause
  </code></pre>
  <p>When I run this file, I get the following error:</p>
  <blockquote>
  <p>Try svn help checkout for more information.</p>
  <p>Not enough arguments provided.</p>
  </blockquote>
  <p>I don't know which arguments are missing as the definition of svn checkout says:</p>
  <pre><code>svn checkout URL[@REV]... [PATH]
  </code></pre>
  <p>And per this my syntax is correct.</p>