title: JQuery reverse each() with find()
body: <p>I know this kind of question has been asked before, but the general solution of </p>
  
  <pre><code>$($("input").get().reverse()).each(function() { /* ... */ });
  </code></pre>
  
  <p>is not working for me. I have an xml document that contains a list of concerts that I'd like to display on a webpage. So, in JQuery:</p>
  
  <pre><code>$.ajax({
      type: "GET",
      url: "concerts.xml",
      dataType: "xml",
      cache: false,
      success: function(xml) {
          $(xml).find('concert').each(function() {
              /*do stuff*/
          });
      }
  });
  </code></pre>
  
  <p>However, I'd like to display the concerts in reverse order. So, I tried the following, but it did not work:</p>
  
  <pre><code>$.ajax({
      type: "GET",
      url: "concerts.xml",
      dataType: "xml",
      cache: false,
      success: function(xml) {
          $($(xml).find('concert').reverse()).each(function() {
              /*do stuff*/
          });
      }
  });
  </code></pre>
  
  <p>Any assistance would be much appreciated. Thanks.</p>