title: MOV [EBX], AX - Pointer to a register?
body: <p><code>MOV [1234H], AX</code> means that the value of AX is copied to 1234 hexadecimal address in memory.
  So, please correct me if what I am saying is wrong, the [] operator functions as a pointer to, right?</p>
  
  <p>This being said, I can't understand the following instruction: <code>MOV [EBX], AX</code> why the use of the [ ]? EBX is a general purpose register inside the processor, not a memory cell, so there is no pointer to it, right?</p>
  
  <p>P.S. I am programming under masm32.</p>
  
  <p>Thanks</p>