title: A try except within a while loop Python 2.7
body: <p>Below is my code for guessing a random number. I had to check the input to make sure it was an integer and within the 1-20 range. Everything is working. It outputs the right response if it is not an integer or is out of range but then it continues through the while loop. I thought the try except would send it back before it continued. What have I done incorrectly here? I cannot figure out the problem. Thank you for any help!</p>
  
  <pre><code>import random
  
  tries = 0
  
  name=(raw_input('Hello! What is your name? '))
  
  number = random.randint(1, 20)
  print('Hello, ' + name + ', I am thinking of a number between 1 and 20.')
  
  
  while tries &lt; 6:
  
      guess = (raw_input('Take a guess.' ))
  
      try:
          guess = int(guess)
      except ValueError:
          print 'You did not enter a valid number, try again.'    
  
      tries = tries + 1
  
      if guess&lt;1 or guess&gt;20:
          print 'Your guess is not between 1 and 20'
  
      if guess &lt; number:
          print 'Your guess is too low.' 
      if guess &gt; number:
          print 'Your guess is too high.'
  
      if guess == number:
          break
  
  if guess == number:
      print 'Good job, ',name,'! You guessed my number in ',tries,' guesses!'
  
  if guess != number:
       print 'Sorry, The number I was thinking of was ',number
  </code></pre>