title: What's the minimum number of weighs required for finding the different weight ball?
body: <p>If there are 9 balls among which if 1 ball is of different weight, it requires minimum of 2 weighs to find the odd ball.
    If there are 27 balls, it requires 3 chances.</p>
  
  <blockquote>
    <p>9 -> 3 pow 2 -> 2 chances.</p>
    
    <p>27 -> 3 pow 3 -> 3 chances.</p>
  </blockquote>
  
  <p>Question: Whats the minimum number of weighs required for finding the odd ball if given</p>
  
  <blockquote>
    <p>3 pow 45 - 3 pow 40 balls</p>
  </blockquote>
  
  <p>?</p>
  
  <p>Can't use calculator. I think, some equation/formula need to be derived.</p>
  
  <p>Can anybody crack this puzzle?</p>