title: How to concat multiple jQuery files into one using Gulp?
body: <p>I'm wanting to only load one JS file which uses jQuery code, but am confused about how to best do it. The thing I'm worried about is doing something sloppy like the below to solve the issue of loading all the scripts under <code>$(document).ready(function(){});</code></p>
  
  <pre><code>gulp.task('compile-js', function() {
      gulp.src(['./js/initialization.js', './stuff.js'./js/end.js'])
          .pipe(concat('script.js'))
          .pipe(gulp.dest('./public/javascripts/'));
  });
  </code></pre>
  
  <p>where <code>initialization.js</code> and <code>end.js</code> are for the wrapping of the  <code>document.ready</code> function (I know lol, hence asking)</p>
  
  <p>Is there a better way of doing it?</p>