title: range() but with normal distribution? (no randomness)
body: <p>Looking for a python function that emulates range() but for a normal distribution rather than a set interval.</p>
  
  <p>So instead of <code>range(min, max, interval)</code> I want something like <code>mynormrange(min, max, numberofpoints)</code>. The option to inverse the distribution would be great too.</p>
  
  <p>So <code>mynormrange(0, 100, 9)</code> would output something like <code>[0, 34, 47.5, 49.85, 50, 50.15, 52.5, 66, 100]</code> where the numbers around the average (avg=50 in this case) are closer together.</p>
  
  <p>And the inverse <code>mynormrange(0, 100, 9, inverse=True)</code> would output something like <code>[0, 0.15, 2.5, 16, 50, 84, 97.5, 99.85, 100]</code> where the numbers around the edges (0 and 100 in this case) are closer together.</p>
  
  <p>I don't want randomness though, so random.normal() doesn't work for what I need.</p>
  
  <p>Something like numpy's linspace() but for a normal distribution. </p>
  
  <p>Edit: I'm just going to combine linspace and cosine multiplied by my desired max value. Sine for the inverse.</p>