title: awk + one line awk syntax to print only once the second field if "true" word matched
body: <p>I don't know how to do this with awk
  But my target is to create awk one line syntax in order to print the second field ($2) if 
  all first field ($1) are true </p>
  
  <p>for example</p>
  
  <p>I have the file:</p>
  
  <pre><code>   true my_name_is_lenon
     true my_name_is_lenon
     true my_name_is_lenon
     false my_name_is_lenon
     true my_name_is_lenon
  
     false my_dog_is_fat
     true my_dog_is_fat
     true my_dog_is_fat
  
     true I_am_very_tall
     true I_am_very_tall
     true I_am_very_tall
  
     true my_ball_is_fine
     true my_ball_is_fine
  </code></pre>
  
  <p>the awk will print only the following:</p>
  
  <pre><code> I_am_very_tall
   my_ball_is_fine
  </code></pre>
  
  <p>Because I_am_very_tall , my_ball_is_fine get true on the first field without false</p>
  
  <p>my_dog_is_fat , my_name_is_lenon not printed because the false word on the first field</p>
  
  <p>The rule is to print the second field if no false word on the first field! (Of all the same sentence on the second field)</p>
  
  <p>lidia</p>