title: grep command need out put without path to file
body: <p>When I am using following grep command to find specific word in bunch of folders and subfolders it shows me that line with path to that file.</p>
  
  <pre><code>grep -r "key_word = " ./
  </code></pre>
  
  <p>results</p>
  
  <pre><code>./folder1/sub1/file name/keyword line = 12
  ./folder1/sub1/sub12/file name/keyword line = 1.3
  ./.................                                   = 12                      
  ./                                  = 12
  ./                 = 12
  etc.
  </code></pre>
  
  <p>Is there any way to get the out put keyword line without path to file name like below</p>
  
  <pre><code>key word = 12
  key word = 1.3
  key word = 12
  key word = 12
  </code></pre>
  
  <p>Then it is easy to compare that line for my task
  does any one have any idea how to do that?
  I have thousands of files in those directories to read and grab that line.</p>