title: django {% url %} tag without parameters
body: <p>I have a url defined as follows:</p>
  
  <pre><code>url(r'^details/(?P&lt;id&gt;\d+)$', DetailView.as_view(), name='detail_view'),
  </code></pre>
  
  <p>In my templates, I want to be able to get the following url: <code>/details/</code> from the defined url.</p>
  
  <p>I tried <code>{% url detail_view %}</code>, but I get an error since I am not specifying the <code>id</code> parameter.</p>
  
  <p>I need the url without the ID because I will be appending it using JS.</p>
  
  <p>How can I accomplish this?</p>