title: Python 2.7: find item in list ignoring case
body: <p>I have a list of strings</p>
  
  <pre><code>["oranges", "POTATOES", "Pencils", "PAper"]
  </code></pre>
  
  <p>I want to find whether the list contains <code>paper</code>, ignoring case; so that the following code snippet should print <code>found</code>. My list only contains simple strings constituted of only the English alphabet -- upper and lower cases.</p>
  
  <pre><code>item = 'paper'
  stuff = ["oranges", "POTATOES", "Pencils", "PAper"]
  if item in stuff:
      print "found"
  else:
     print "Not found"
  
  #How do I get the method to print "found"?
  </code></pre>
  
  <p>CLARIFICATION:</p>
  
  <p>My list is actually a list of lists and my logic is using the following construct:</p>
  
  <pre><code>if not any ( item in x for x in stuff):
     print "Not found"
  else:
     print "found"
  </code></pre>