title: using python urlopen for a url query
body: <p>Using <code>urlopen</code> also for url queries seems obvious. What I tried is:</p>
  
  <pre><code>import urllib2
  query='http://www.onvista.de/aktien/snapshot.html?ID_OSI=86627'
  f = urllib2.urlopen(query)
  s = f.read()
  f.close()
  </code></pre>
  
  <p>However, for this specific url query it fails with HTTP error 403 forbidden
  When entering this query in my browser, it works.
  Also when using <a href="http://www.httpquery.com/" rel="nofollow">http://www.httpquery.com/</a> to submit the query, it works.</p>
  
  <p>Do you have suggestions how to use Python right to grab the correct response?</p>