title: awk combine conditions and search to print?
body: <p>There may be something on here like this but I haven't found it.</p>
  <p>I have two conditions I'm trying to meet in order to print: one specific, one kind of open ended:</p>
  <p>First,</p>
  <pre><code>$1 == &quot;SCR&quot;
  </code></pre>
  <p>Second, that the search string exists anywhere from <code>$7</code> until the end of the line.</p>
  <p>an example of the searchstring might be _RS1c80952b46129fc3bbf7b6d35e52f581d5d96edf</p>
  <p>So, in no particular syntax, I guess what I'm looking for is something like:</p>
  <pre><code>awk '$1 == &quot;SCR&quot; &amp;&amp; _RS1c80952b46129fc3bbf7b6d35e52f581d5d96edf exists anywhere in $7 to end of line {print $6}' inputfile.txt
  </code></pre>
  <p>Any help is welcomed. thanks.</p>