title: Python Regex Extract Date to New Column in Dataframe
body: <p>I'm scraping a website using Python and I'm having troubles with extracting the dates and creating a new Date dataframe with Regex.</p>
  
  <p><strong>The code below is using BeautifulSoup to scrape event data and the event links:</strong></p>
  
  <pre><code>import pandas as pd
  import bs4 as bs
  import urllib.request
  
  source = urllib.request.urlopen('https://www.techmeme.com/events').read()
  soup = bs.BeautifulSoup(source,'html.parser')
  
  event = []
  links = []
  
  # ---Event Data---
  for a in soup.find_all('a'):
      event.append(a.text)
  
  df_event = pd.DataFrame(event)
  df_event.columns = ['Event']
  df_event = df_event.iloc[1:]
  
  # ---Links---
  for a in soup.find_all('a', href=True): 
      if a.text: 
          links.append(a['href'])
  df_link = pd.DataFrame(links)
  df_link.columns = ['Links']
  
  # ---Combines dfs---
  df = pd.concat([df_event.reset_index(drop=True),df_link.reset_index(drop=True)],sort=False, axis=1)
  </code></pre>
  
  <p>At the beginning of the each event data row, the date is present. Example: (May 26-29Augmented World ExpoSan...). The date follows the following format and I have included my Regex(which I believe is correct).</p>
  
  <pre><code>Different Date Formats:
  May 27: [A-Z][a-z]*(\ )[0-9]{1,2}
  May 26-29:  [A-Z][a-z]*(\ )[0-9]{1,2}-[0-9]{1,2}
  May 28-Jun 2: [A-Z][a-z]*(\ )[0-9]{1,2}-[A-Z][a-z]*(\ )[0-9]{1,2}
  
  Combined
  [A-Z][a-z]*(\ )[0-9]{1,2}|[A-Z][a-z]*(\ )[0-9]{1,2}-[0-9]{1,2}|[A-Z][a-z]*(\ )[0-9]{1,2}-[A-Z][a-z]*(\ )[0-9]{1,2}
  </code></pre>
  
  <p>When I try to create a new column and extract the dates using Regex, I just receive an empty <code>df['Date']</code> column.</p>
  
  <pre><code>df['Date'] = df['Event'].str.extract(r[A-Z][a-z]*(\ )[0-9]{1,2}')
  df.head()
  </code></pre>
  
  <p>Any help would be greatly appreciated! Thank you.</p>