title: Count number of digits in array and display them, plus multiply it by given number
body: <p>I have to create an array from an entered value. I also need to display array contents, which I have done and that performs to my liking. I am just having some issues trying to have the program count the amount of digits and display them "digits detected" I also need to multiply the original entered value (number) by 11 and display it at the end of my program.</p>
  
  <p><strong>Problems I need help debugging:</strong>
   1.) Counting and displaying how many digits was entered 
   2.) Multiplying first entered number by 11.</p>
  
  <pre><code>#include &lt;stdio.h&gt;
  
  int main() {
  
  int number, count, mult;
  int numbers[9];
  
      printf("Please enter a number:\n&gt;");
      scanf("%d", &amp;number);
      mult= number * 11;
  
      for(count = 4; count &gt;= 0; count--) {
  
      if(number &lt;= 0)
      numbers[count] = 0;
  
      numbers[count] = number % 10;
      number /= 10;
  
  }
  
      for(count = 0; count &lt; 5; count++)
      printf("Digit Value: %d\t\n", numbers[count]);
  
      count = 0;
      while(number!=0)
      {
              number/=10;
              ++count;
      }
      printf("Digits Detected: %d\n", number);
  return 0;
      }
  </code></pre>