title: How to find and replace contents of a bracket inside notepad++
body: <p>I have a large file with content inside every bracket. This is not at the beginning of the line.</p>
  
  <pre><code>1. Atmos-phere (7800)
  2. Atmospheric composition (90100)
  3.Air quality (10110)
  4. Atmospheric chemistry and composition (889s120)
  5.Atmospheric particulates (10678130)
  </code></pre>
  
  <p>I need to do the following </p>
  
  <ol>
  <li><p>Replace the entire content, get rid of line numbers<br>
  <code>1.Atmosphere (10000)</code> to plain <code>Atmosphere</code></p></li>
  <li><p>Delete the line numbers as well 
  <code>1.Atmosphere (10000)</code> to plain <code>Atmosphere</code></p></li>
  <li><p>make it a hyperlink
  <code>1.Atmosphere (10000)</code> to plain <code>&lt;a href="http://blahqd.com/Atmosphere.htm"&gt;linky study&lt;/a&gt;</code></p></li>
  <li><p>[<em>I added/Edit</em>] Extract the words into a new file, where we get a simple list of key words. Can you also please explain the numbers <em>in replace the \1\2, and escape on some characters</em></p>
  
  <ol>
  <li><p>Each set of key words is a new line<br>
  <code>Atmospheric</code><br>
  <code>Atmospheric composition</code><br>
  <code>Air quality</code> </p></li>
  <li><p>Each set is a on one line separated by one space and commas<br>
  <code>Atmospheric, Atmospheric composition, Air quality</code> </p></li>
  </ol></li>
  </ol>
  
  <p>I tried find with regex like so, <code>\(*\)</code> it finds the brackets, but dont know how to replace this, and where to put the replace, and what variable holds the replacement value.</p>