title: Have two dictionaries and would like to combine them in a certain way
body: <p><strong>Desired Dictionary Format:</strong></p>
  
  <pre><code>foo = {'a': [{'Arizona': [Partner(state='Arizona', name='shmo', logo='123.png', link=''), Partner(state='Arizona', name='joe', logo='png', link='')] }, 'c':[{'california': [stuff, more_stuf]}]}
  </code></pre>
  
  <p>Dictionaries which I currently have:</p>
  
  <p>The first one:</p>
  
  <pre><code>{'o': [Partner(state='Ohio', name='hi', logo='pic.png', link='http'), 
  Partner(state='Ohio', name='ayo', logo='int.png',)], 
  'a':[Partner(state='alaska', name='hi', logo='pic.png', link='http'), 
  Partner(state='arkansas', name='ayo', logo='int.png',)]})
  </code></pre>
  
  <p>The second one:</p>
  
  <pre><code> {'Ohio': [Partner(state='Ohio', name='shmo', logo='123.png', 
  link=''), Partner(state='Ohio', name='joe', logo='png', link='')], 
  'Alaska': [Partner(state='Alaska', name='yo',logo='321.png', 
  link='')], 
  'arkansas'[Partner(state='arkansas',name='yo',logo='321.png', link='')]
  </code></pre>
  
  <p>I even have a dict with letters that have states within! </p>
  
  <pre><code>{'i': None, 'm': 'm', 'f': None, 'j': None, 'b': None, 'p': None, 'n': None, 't': 't', 'v': None, 'k': None, 'e': None, 'g': None, 'q': None, 'h': None, 'y': None, 'c': None, 'w': None, 'a': 'a', 'u': None, 'x': None, 'l': None, 'o': 'o', 'd': None, 'z': None, 's': None, 'r': None}
  </code></pre>
  
  <p>And even a list!</p>
  
  <pre><code>dict_keys(['a', 'm', 'o', 't'])
  </code></pre>
  
  <p><strong>What I have tried to play around with</strong></p>
  
  <pre><code>partners_by_states = defaultdict(list)
  for partner in partner_list:
      raw_state_state_name = partner.state
      state_key = raw_state_state_name.lower()
      partners_by_states[state_key].append(partner)
  
  used_letters = partners_by_state.keys()
  
  for key, value in partners_by_states.items():
      partners = sorted(value, key=lambda x: x.name)
      partners_by_states[state_key] = partners
  </code></pre>