title: open a file in a tomcat webapplication
body: <p>i want to open a file and return its content. Although it is in the same directory like the class that wants to open the file, the file can't be found. Would be cool if you could help me solving the problem.</p>
  
  <p>Here is the code:</p>
  
  <pre><code>@GET @Produces("text/html") @Path("/{partNO}/") @Consumes("text/html")
  public String getPartNoResponseHTML(@PathParam("partNO") String parID) throws WebApplicationException {
  PartNoTemplate partNo = getPartNoResponse(parID);
  
  String result = "";
  
  try {
    result = readFile(PART_NO_TEMPLATE_FILE);
  } catch (FileNotFoundException e) {
    e.printStackTrace(System.out);
    return e.getMessage() + e.toString();
    // throw new WebApplicationException(Response.Status.NOT_FOUND);
  } finally {
    result = result.replace("{partNO}", parID);
    result = result.replace("{inputFormat}", partNo.getFormat().toString());
  }
  
  return result;
  }
  </code></pre>
  
  <p>I guess it can't find the file, because its running on tomcat. I'm also using Jersey and JAX-RS. Thank you for your help,</p>
  
  <p>Maxi</p>