title: Is there list syntax sugar "[:]" for dictionaries in Python 2.7?
body: <p>We can do the following for lists:</p>
  
  <pre><code>&gt;&gt;&gt; a = [1, 2, 3, 4, 5, 6]
  &gt;&gt;&gt; b = []
  &gt;&gt;&gt; id(a)
  140093169968840
  &gt;&gt;&gt; id(b)
  140093169868528
  &gt;&gt;&gt; b[:] = a
  &gt;&gt;&gt; b
  [1, 2, 3, 4, 5, 6]
  &gt;&gt;&gt; id(b)
  140093169868528
  </code></pre>
  
  <p><code>b</code> retains memory reference</p>
  
  <p>Is there a way to do the same for two dictionaries in Python 2.7?</p>
  
  <pre><code>&gt;&gt;&gt; a = {'one' :1, 'two' :2}
  &gt;&gt;&gt; b = {}
  &gt;&gt;&gt; b[...] = a  # ?
  </code></pre>
  
  <p>UPDATE: The answer is "No, there's no syntax sugar for dictionaries."
  It's not a duplicate. I'm not looking for a way to do it, othere that using syntax sugar.</p>