title: create temp file in android
body: <p>In my android application i am trying to create a music file using  create temp and trying to read that.Now i am able to create but its giving an error saying video cannot be played.</p>
  
  <pre><code>    public void onCreate(Bundle savedInstanceState) {
  
      super.onCreate(savedInstanceState);
      requestWindowFeature(Window.FEATURE_NO_TITLE);  
     //File newfile=new File("/data/data/com.ayansys.samplevideo/Music.3gp");
  
      //String xyz=newfile.getAbsolutePath();
      getWindow().setFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN,WindowManager.LayoutParams.FLAG_FULLSCREEN); // Sets the window in full screen
      setContentView(R.layout.main);
     // path.g
     // Log.i("Raw folder path:", R.raw.music);
     String path= musicFile();
      try{
      Thread.sleep(5000);
      }
      catch(InterruptedException e)
      {
          e.printStackTrace();
          Log.i("exception raised",e.toString());
      }
      mVideoView = (VideoView) findViewById(R.id.surface_view);
      // mVideoView.setVideoURI(Uri.parse("android.resource://com.ayansys.samplevideo/"+R.raw.music));
  
     // File infile=new File("/data/data/com.ayansys.samplevideo/Video.3gp");
      mVideoView.setVideoPath(path);
  
      mVideoView.requestFocus();
      mVideoView.start();
  
  }
  
  public   String  musicFile()
  {
      String temPath = null;
      try{
          File outFile=File.createTempFile("music", ".3gp", getDir(temPath, MODE_PRIVATE));
          temPath=outFile.getAbsolutePath();
          FileOutputStream f=new FileOutputStream(outFile);
          //FileOutputStream fos = openFileOutput("music.3gp", Context.MODE_PRIVATE);
          URL u = new URL("http://59.162.166.211/aptv-web/VODAFONE/STARONE/SarabhaivsSarabhai/J2ME/SarabhaivsSarabhai_05.3gp");
      HttpURLConnection c = (HttpURLConnection) u.openConnection();
      c.setRequestMethod("GET");
      c.setDoOutput(true);
      c.connect();
      //FileOutputStream f = new FileOutputStream(new File("/sdcard/videooutput.mp4"));
  
  
      InputStream in = c.getInputStream();
  
      byte[] buffer = new byte[1024];
      int len1 = 0;
      while ( (len1 = in.read(buffer))!= -1 ) {
           f.write(buffer,0,len1);
      }
  
      f.close();
      String str=outFile.getAbsolutePath();
      //outFile..close();
      in.close();
  
  }
      catch(Exception e)
      {
          e.printStackTrace();
          System.out.println("Exception raised in creating a file: "+e.toString());
      }
      return temPath;
  }
  </code></pre>
  
  <p>}</p>
  
  <p>I would like to play this.
  Please share your valuable suggestions.</p>
  
  <p>Thanks in advance</p>