title: Draw circle's arc on google maps
body: <p>The idea is to draw an arc centered on a specific point, using angles.
  Note: Not the chord, nor the sector, nor the area between the chord and the arc.</p>
  
  <p>Memento: <a href="http://en.wikipedia.org/wiki/Arc_(geometry)" rel="nofollow noreferrer">http://en.wikipedia.org/wiki/Arc_(geometry)</a></p>
  
  <p>A full circle parameters:</p>
  
  <pre><code>- center at coordinates LatC,LngC
  - radius of 1 609 meters
  - start angle of 0 degrees
  - end angle of 360 degrees
  </code></pre>
  
  <p>example <a href="http://jsfiddle.net/GGvQH/3/" rel="nofollow noreferrer">http://jsfiddle.net/GGvQH/3/</a></p>
  
  <pre><code>new google.maps.Circle({
      center: new google.maps.LatLng(18.4894, 73.910158),
      radius: 1609,
      ...
  });
  </code></pre>
  
  <p>An arc of 180° (PI/2 radiant) oriented to north would be like:</p>
  
  <pre><code> - center at coordinates LatC,LngC
   - radius of 1 609 meters
   - start angle of 270 degrees (9 o'clock)
   - end angle of 90 degrees (3 o'clock)
  </code></pre>
  
  <p>First of all, I do not want to plot a polyline for each arc, using tons of points to get a smooth effect: need to recompute for each scale and may cost resources... or is it?</p>
  
  <p>There is an idea with polygons intersection
  <a href="https://stackoverflow.com/questions/15223739/google-maps-api-v3-circle-sector">Google Maps API v3 - circle sector</a>
  ...do anyone have seen a working jsfiddle?
  Note: <a href="http://jsfiddle.net/Morlock0821/4dRB2/1/" rel="nofollow noreferrer">http://jsfiddle.net/Morlock0821/4dRB2/1/</a> is very close to the arc, but I do not want a closed surface.</p>
  
  <p>Another idea with bearing... but I am reluctant to redefine the earth's radius to get the tiny arc I want.
  <a href="https://developers.google.com/maps/documentation/javascript/examples/geometry-headings" rel="nofollow noreferrer">https://developers.google.com/maps/documentation/javascript/examples/geometry-headings</a>
  (in this case, I want only the purple line, not the red one).</p>
  
  <p>Any help would be greatly appreciated.</p>