title: print result of comparison operators
body: <pre><code>#! /usr/bin/perl
  
  $var1 = 20;
  $var2 = 15;
  
  print ("var1 = ", $var1, "\n");
  print ("var2 = ", $var2, "\n");
  
  # Comparing numbers
  print ("var1 == var2 : ", ($var1 == $var2), "\n");
  print ("var1 != var2 : ", ($var1 != $var2), "\n");
  print ("var1 &lt; var2 : ", ($var1 &lt; $var2), "\n");
  print ("var1 &lt;= var2 : ", ($var1 &lt;= $var2), "\n");
  print ("var1 &gt; var2 : ", ($var1 &gt; $var2), "\n");
  print ("var1 &gt;= var2 : ", ($var1 &gt;= $var2), "\n");
  print ("var1 &gt;= var2 : ", ($var1 &lt;=&gt; $var2), "\n");
  </code></pre>
  
  <p>When  ran above program, I am getting following output.</p>
  
  <pre><code>$ ./comparisonOperators 
  var1 = 20
  var2 = 15
  var1 == var2 : 
  var1 != var2 : 1
  var1 &lt; var2 : 
  var1 &lt;= var2 : 
  var1 &gt; var2 : 1
  var1 &gt;= var2 : 1
  var1 &gt;= var2 : 1
  </code></pre>
  
  <p>My question, why I am not getting any result for var1 == var2, var1 &lt; var2, var1 &lt;= var2, and why comparison operators returning 1 instead of True/False.</p>