title: In App Inventor Make TCP IP Client
body: <p>Hi Guy's I'm new to programming Android device's I do have python, java, C#, C, C++, PHP, Bash and Visual Basic Experience but I'm new to this block programming, and I haven't done much work with forms. I'm trying to get make an application that posts data to an external IP. I have successsfully wrote a server and a windows based client, clicking buttons in my windows client posts data to the ip 192.168.1.9 port 9999. This is just in the testing phase to remote control a bunch of beaglebone gpio's. So far I've had great success with the windows side. In app inventor for android, However, I've created a series of buttons and tabs, different buttons post text or post and poll for response. The problem I have is that I can directly attach the web connector to 192.168.1.9 but when I add in the port 9999 it tells me the address is incorrect. The method I'm using is</p>
  
  <pre><code>when Screen1.initialize
  do set Web1.Url to "http://192.168.1.9:9999"
  
  when Button1.Click
  do call Web1.PostText
               text &gt; 0
  </code></pre>
  
  <p>Again, if I type in just the IP of the beaglebone I see its ethernet port go crazy when I click button1. It does nothing when I add in the port. Of course my server is running on 9999 since port 80 is reserved for the internet. Any suggestions?</p>