title: How to open an URL with Selenium in python?
body: <p>Problem:</p>
  <p>I just want to open a URL with selenium in python but it didn't work.</p>
  <p>This is my current code:</p>
  <pre><code>from selenium import webdriver 
  
  path='C:\Program Files (x86)\chromdriver.exe'
  url='https://anywebpage.de'
  browser = webdriver.Chrome(path)
  </code></pre>
  <p>Technical specification:</p>
  <p>Windows 10 Pro 64 bit Python Version 3.9</p>
  <p>I get this error message:</p>
  <p>&quot;Message: 'chromdriver.exe' executable needs to be in PATH. Please see <a href="https://sites.google.com/a/chromium.org/chromedriver/home%22" rel="nofollow noreferrer">https://sites.google.com/a/chromium.org/chromedriver/home&quot;</a></p>
  <p>I cannot find a solution out in the documentation</p>
  <p>Has anyone else an idea?</p>
  <p>The exe.file is in the correct path stored.</p>