title: filteredArrayUsingPredicate doesn't filter data
body: <p>I am developing iOS app, in which i have searchBar.</p>
  
  <p>What i want is,</p>
  
  <p><strong>when user types <code>s</code> in the searchBar, i want to get all the <code>Merchant_Name</code> who starting with letter <code>s</code> from my array</strong></p>
  
  <p>Here is my code snippet i have tried but it is not working,</p>
  
  <p>My arr contains:</p>
  
  <pre><code> arr at index 0 = {
          "Merchant_Id" = 1261;
          "Merchant_Name" = "Magazine Mall";
          "Merchant_Url" = "magazine-mall";
      },
       arr at index 1 =   {
          "Merchant_Id" = 1262;
          "Merchant_Name" = MakeMyTrip;
          "Merchant_Url" = makemytrip;
      },
     arr at index 2 =     {
          "Merchant_Id" = 1263;
          "Merchant_Name" = Travelguru;
          "Merchant_Url" = travelguru;
      },
      arr at index 3 =    {
          "Merchant_Id" = 1266;
          "Merchant_Name" = Travelchacha;
          "Merchant_Url" = travelchacha;
      },
        arr at index 4 =  {
          "Merchant_Id" = 1267;
          "Merchant_Name" = Tradus;
          "Merchant_Url" = tradus;
      },
      arr at index 5 =    {
          "Merchant_Id" = 1268;
          "Merchant_Name" = ToyWorld;
          "Merchant_Url" = toyworld;
      },
       arr at index 6 =   {
          "Merchant_Id" = 1269;
          "Merchant_Name" = Topskin;
          "Merchant_Url" = topskin;
      },
     ....
  </code></pre>
  
  <p>Code:</p>
  
  <pre><code>NSPredicate *predicate = [NSPredicate predicateWithFormat:@"Merchant_Name LIKE[cd] %@ ",searchText];
  NSMutableArray *filter1 =[[NSMutableArray alloc] init];
  filter1 = [[arr filteredArrayUsingPredicate:predicate] mutableCopy];
  NSLog(@"predicate  = %@ -------  filter=%@",predicate,filter1);
  </code></pre>
  
  <p>Log Shows:  </p>
  
  <pre><code>predicate  = Merchant_Name LIKE[cd] "s" -------  filter=(
  )
  </code></pre>
  
  <p>Please help me, Where i am doing mistake? </p>
  
  <p><strong><em>Thanks in advance.</em></strong></p>