title: slice iteration order in go
body: <p>Ok, i think this may be an old question, but i didn't find anything over the stackoverflow. In go , the iteration order over a map is not guranteed to be reproducible. So, the way suggest is to hold the keys in a slice and sort that slice. Then iterate over that slice to retrieve the values from the map, so that we get them in order(since slice composed of keys is sorted, so will be in reproducible order). So this goes to imply that the slice need be sorted else iteration over the slice will also not give reproducible order. But when i tried the below code in playground, i always found the order maintained in iteration, then in the map iteration case, why the slice of keys need to be sorted?</p>
  
  <pre><code>func main() {
      var mySlice = make([]string, 0)
      mySlice = append(mySlice, "abcd")
      mySlice = append(mySlice, "efgh")
      mySlice = append(mySlice, "ijkl")
      mySlice = append(mySlice, "mnop")
      mySlice = append(mySlice, "qrst")
      mySlice = append(mySlice, "uvwxyz")
      for _, val := range mySlice {
          fmt.Println(val)
      }
      fmt.Println(strings.Join(mySlice, "|"))
  
  }
  </code></pre>
  
  <p>Output:</p>
  
  <pre><code>abcd
  efgh
  ijkl
  mnop
  qrst
  uvwxyz
  abcd|efgh|ijkl|mnop|qrst|uvwxyz
  </code></pre>