title: How default exception handler work
body: <p>When we try to run the following program then we get the error that  <code>Exception in thread "main" java.lang.ArithmeticException: / by zero</code></p>
  
  <pre><code>class excp {
    public static void main(String args[]) {
      int x = 0;
      int a = 30/x;
    }
  }
  </code></pre>
  
  <p>but when we ask somebody how these works, then he tell me that this exception is cautch by the default exception handler, So i could't understand how this defualt exception handler works.
  Plz elaborate this.</p>