title: How to extract filename from askopenfile result?
body: <p>I do my first stumbling in Python/Tkinter. When I choose a file to be opened, I do:</p>
  
  <pre><code>filein = askopenfile(initialdir=initial_dir, filetypes=mask, mode='r')
  </code></pre>
  
  <p>It's ok, but my filein consists the string below:</p>
  
  <pre><code>open file '/home/steve/projects/python/test/myfile', mode 'r' at 0xb7494a70
  </code></pre>
  
  <p>Is any method to get the choosen filename without the garbage I do not need?</p>