title: Python- creating a text file with a variable as a name
body: <p>So im doing a project where my program creates a textfile named "Ten Green Bottles" and writes the 10 green bottles song in it, I have successfully got it working but i want to make it better. I started by making the amount of bottles optional to the user and it worked fine. Now i just want the name to be relevent with the amount of bottles input by the user. ie, if I put in 20 bottles i want the name of the text file to be "Twenty Green Bottles" rather than "Ten Green Bottles"
  Code:</p>
  
  <pre><code>num1=int(input('Pick a number between 10 and 30: '))
  
  def main():
      numbers =[ 'no', 'One', 'Two', 'Three', 'Four', 'Five', 'Six', 'Seven',      'Eight', 'Nine', 'Ten', 'Eleven', 'Twelve', 'Thirteen', 'Fourteen', 'Fifteen',     'Sixteen', 'Seventeen', 'Eighteen', 'Nineteen', 'Twenty', 'Twentyone',      'Twentytwo', 'Twentythree', 'Twentyfour', 'Twentyfive', 'Twentysix',         'Twentyseven', 'Twentyeight', 'Twentynine', 'Thirty' ]
  text_one = 'green bottle%s\nHanging on the wall'
  text_two = "\nAnd if one green bottle\nShould accidentally fall\nThere'll be"
  text_three =' \n'
  
  
  with open( 'Green Bottles.txt', 'w') as a:
      for l in range(num1, 0, -1):
          a.write(numbers[l]+ ' ')
          if l == 1:
              a.write(text_one % '' +'\n')
          else:
              a.write(text_one % 's' +'\n')
  
          a.write(numbers[l] + ' ')
          if l == 1:
              a.write(text_one %  '' + '\n') 
          else:
              a.write(text_one % 's' +  '\n')
          a.write(text_two + ' ')
          a.write(numbers[l-1] + ' ')
          if (l - 1) ==1 :
              a.write(text_one % ''+'\n')
          else:
              a.write(text_one % 's'+'\n')
          a.write('\n' + '\n')
  
  
  
  if __name__ == '__main__':
  main()
  </code></pre>