title: What does "the following packages will be superseded by a higher priority channel" mean?
body: <p>I am trying to install fuzzywuzzy onto my Anaconda distribution in 64 bit Linux. When I do this, it tries to change my <code>conda</code>, and <code>conda-env</code> to <code>conda-forge</code> channels. As follows:</p>
  
  <p>I search anaconda for fuzzy wuzzy by writing:</p>
  
  <pre><code>anaconda search -t fuzzywuzzy
  </code></pre>
  
  <p>This showed that the most up to date version available for anaconda on 64 bit Linux is 0.13 provided on the channel <code>conda-forge</code>.</p>
  
  <p>To install, within the command line, I type:</p>
  
  <pre><code>conda install -c conda-forge fuzzywuzzy=0.13.0
  </code></pre>
  
  <p>I get the following output:</p>
  
  <pre><code>The following packages will be downloaded:
  
  package                    |            build
  ---------------------------|-----------------
  conda-env-2.6.0            |                0         1017 B  conda-forge
  python-levenshtein-0.12.0  |           py27_0         138 KB  conda-forge
  conda-4.2.13               |           py27_0         375 KB  conda-forge
  fuzzywuzzy-0.11.0          |           py27_0          15 KB  conda-forge
  ------------------------------------------------------------
                                     Total:         528 KB
  
  
  The following new packages will be INSTALLED:
  
      fuzzywuzzy:            0.11.0-py27_0 conda-forge
      python-levenshtein:    0.12.0-py27_0 conda-forge
  
  The following packages will be SUPERCEDED by a higher-priority channel:
  
      conda:        4.2.13-py27_0      --&gt; 4.2.13-py27_0 conda-forge 
      conda-env:    2.6.0-0            --&gt; 2.6.0-0       conda-forge 
  
  Proceed ([y]/n)?
  </code></pre>
  
  <p>I do not understand what this is telling me.</p>
  
  <p>What does this mean? Am I right in thinking that this is changing my default package manager channels? Can this be reversed if I go ahead and install it? Is there any way to complete the installation without changing the default channel? Or is favouring the superceding channels something that I should be doing? </p>
  
  <p>I don't want to change my distribution just for one module, or cause further headaches.</p>
  
  <p>This question: <a href="https://github.com/conda/conda/issues/2898" rel="noreferrer">https://github.com/conda/conda/issues/2898</a> sounds like its telling me that I should just let it happen. What do?</p>
  
  <p>(I am using anaconda version: 4.2.13 and Python 2.7.12)</p>