title: Aide with error when trying to get email poplib
body: <p>This what ive tried so far :</p>
  
  <pre><code># view and delete e-mail using the POP3 protocol
  
  import sys, getpass, poplib, re
  
  # change according to your needs
  POPHOST = "pop3.126.com"
  POPUSER = "Username"
  POPPASS = "pass"
  
  # the number of message body lines to retrieve
  MAXLINES = 10
  HEADERS = "From To Subject".split()
  
  # headers you're actually interested in
  rx_headers  = re.compile('|'.join(HEADERS), re.IGNORECASE)
  
  try:
      # connect to POP3 and identify user
      pop = poplib.POP3(POPHOST)
      pop.user(POPUSER)
  
      if not POPPASS or POPPASS=='=':
          # if no password was supplied, ask for it
          POPPASS = getpass.getpass("Password for %s@%s:" % (POPUSER, POPHOST))
  
      # authenticate user
      pop.pass_(POPPASS)
  
      # get general information (msg_count, box_size)
      stat = pop.stat(  )
  
      # print some information
      print "Logged in as %s@%s" % (POPUSER, POPHOST)
      print "Status: %d message(s), %d bytes" % stat
  
      bye = 0
      count_del = 0
      for n in range(stat[0]):
  
          msgnum = n+1
  
          # retrieve headers
          response, lines, bytes = pop.top(msgnum, MAXLINES)
  
          # print message info and headers you're interested in
          print "Message %d (%d bytes)" % (msgnum, bytes)
          print "-" * 30
          print "\n".join(filter(rx_headers.match, lines))
          print "-" * 30
  
          # input loop
          while 1:
              k = raw_input("(d=delete, s=skip, v=view, q=quit) What?")
              k = k[:1].lower(  )
              if k == 'd':
                  # Mark message for deletion
                  k = raw_input("Delete message %d? (y/n)" % msgnum)
                  if k in "yY":
                      pop.dele(msgnum)
                      print "Message %d marked for deletion" % msgnum
                      count_del += 1
                      break
              elif k == 's':
                  print "Message %d left on server" % msgnum
                  break
              elif k == 'v':
                  print "-" * 30
                  print "\n".join(lines)
                  print "-" * 30
              elif k == 'q':
                  bye = 1
                  break
  
          # done ...
          if bye:
              print "Bye"
              break
  
      # summary
      print "Deleting %d message(s) in mailbox %s@%s" % (
          count_del, POPUSER, POPHOST)
  
      # close operations and disconnect from server
      print "Closing POP3 session"
      pop.quit(  )
  
  except poplib.error_proto, detail:
  
      # possible error
      print "POP3 Protocol Error:", detail
  </code></pre>
  
  <p>this give me the error:</p>
  
  <pre><code>POP3 Protocol Error: -ERR Unable to log on
  </code></pre>
  
  <p>Does anyone know what the problem is? I'm using a gmail account and all the login information is correct.</p>
  
  <p><strong>Edit</strong>:</p>
  
  <p>ive changed the code up a bit and now i get his error...here the code and the error:</p>
  
  <pre><code>import poplib
  user = "username@gmail.com"
  passs = "password"
  pop = poplib.POP3("pop.gmail.com",995)
  pop.user(user)
  pop.pass_(passs)
  </code></pre>
  
  <p>and i get this error:</p>
  
  <pre><code>  File "C:\Python27\lib\poplib.py", line 86, in __init__
      self.welcome = self._getresp()
    File "C:\Python27\lib\poplib.py", line 124, in _getresp
      resp, o = self._getline()
    File "C:\Python27\lib\poplib.py", line 108, in _getline
      if not line: raise error_proto('-ERR EOF')
  error_proto: -ERR EOF
  </code></pre>