title: HOW to EXIT using "start" in batch files of MSDOS
body: <p>I want to copy some files into diffent USB disks, and want to use START to open several consoles as follows:</p>
  
  <pre><code>start copy a.txt h:
  start copy a.txt i:
  start copy a.txt j:
  </code></pre>
  
  <p>But everytime I run the batch file, there are 3 consoles without exiting.
  How can I realize this EXIT function <strong>WITHOUT</strong> using 3 batch files and "call" commands as:</p>
  
  <p><em>copy.bat:</em></p>
  
  <pre><code>call a.bat
  call b.bat
  call c.bat
  exit
  </code></pre>
  
  <p>and three called batch files as: </p>
  
  <p><em>a.bat:</em></p>
  
  <pre><code>start copy a.txt h:
  exit
  </code></pre>
  
  <p><em>b.bat:</em></p>
  
  <pre><code>start copy a.txt i:
  exit
  </code></pre>
  
  <p><em>c.bat:</em></p>
  
  <pre><code>start copy a.txt j:
  exit
  </code></pre>
  
  <p>I already tried this, but it DOES NOT work:</p>
  
  <pre><code>start copy a.txt h: &amp;&amp; exit
  start copy a.txt i: &amp;&amp; exit
  start copy a.txt j: &amp;&amp; exit
  </code></pre>