title: bash removing part of a file name
body: <p>I have the following files in the following format:</p>
  
  <pre><code>$ ls CombinedReports_LLL-*'('*.csv
  CombinedReports_LLL-20140211144020(Untitled_1).csv
  CombinedReports_LLL-20140211144020(Untitled_11).csv
  CombinedReports_LLL-20140211144020(Untitled_110).csv
  CombinedReports_LLL-20140211144020(Untitled_111).csv
  CombinedReports_LLL-20140211144020(Untitled_12).csv
  CombinedReports_LLL-20140211144020(Untitled_13).csv
  CombinedReports_LLL-20140211144020(Untitled_14).csv
  CombinedReports_LLL-20140211144020(Untitled_15).csv
  CombinedReports_LLL-20140211144020(Untitled_16).csv
  CombinedReports_LLL-20140211144020(Untitled_17).csv
  CombinedReports_LLL-20140211144020(Untitled_18).csv
  CombinedReports_LLL-20140211144020(Untitled_19).csv
  </code></pre>
  
  <p>I would like this part removed: <br>
  <code>20140211144020</code> (this is the timestamp the reports were run so this will vary)</p>
  
  <p>and end up with something like:</p>
  
  <pre><code>CombinedReports_LLL-(Untitled_1).csv
  CombinedReports_LLL-(Untitled_11).csv
  CombinedReports_LLL-(Untitled_110).csv
  CombinedReports_LLL-(Untitled_111).csv
  CombinedReports_LLL-(Untitled_12).csv
  CombinedReports_LLL-(Untitled_13).csv
  CombinedReports_LLL-(Untitled_14).csv
  CombinedReports_LLL-(Untitled_15).csv
  CombinedReports_LLL-(Untitled_16).csv
  CombinedReports_LLL-(Untitled_17).csv
  CombinedReports_LLL-(Untitled_18).csv
  CombinedReports_LLL-(Untitled_19).csv
  </code></pre>
  
  <p>I was thinking simply along the lines of the <a href="https://stackoverflow.com/questions/12174947/removing-a-part-of-filename-of-a-bunch-of-files">mv</a> command, maybe something like this:</p>
  
  <pre><code>$ ls CombinedReports_LLL-*'('*.csv
  </code></pre>
  
  <p>but maybe a <a href="https://unix.stackexchange.com/questions/19166/bash-shell-script-to-locate-and-remove-substring-within-a-filename">sed</a> command or other would be better</p>