title: Unable to use PyJulia with Julia 1.0 and Conda Python 3.6
body: <p>I'm trying to configure Python and Julia to interoperate using <a href="https://github.com/JuliaPy/pyjulia" rel="nofollow noreferrer">these directions</a>.</p>
  
  <p>This is what I've done.</p>
  
  <ol>
  <li>Installed Julia and added <code>julia</code> to my path.</li>
  <li>Installed <code>PyCall.jl</code></li>
  <li>I installed <code>PyJulia</code> using <code>python3 -m pip install julia</code>. This installs pyjulia into my current conda environment's python as well as <code>python-jl</code>.</li>
  </ol>
  
  <p>Now, I think I understand the problems that conda python can cause because of the the <a href="https://github.com/JuliaPy/pyjulia#troubleshooting" rel="nofollow noreferrer">statically linked libpython</a>. According to those directions, you can bypass this problem by running <code>python-jl</code> which is installed with PyJulia and runs using a distribution of python that is separate from the system or any conda install distributions.</p>
  
  <p>However, when I run one of the example tests <code>python-jl -c 'from julia.Base import banner; banner()'</code>, I receive the following error.</p>
  
  <pre><code>ERROR: PyError (PyImport_ImportModule
  
  The Python package julia could not be found by pyimport. Usually this means
  that you did not install julia in the Python version being used by PyCall.
  
  PyCall is currently configured to use the Julia-specific Python distribution
  installed by the Conda.jl package.  To install the julia module, you can
  use `pyimport_conda("julia", PKG)`, where PKG is the Anaconda
  package the contains the module julia, or alternatively you can use the
  Conda package directly (via `using Conda` followed by `Conda.add` etcetera).
  
  Alternatively, if you want to use a different Python distribution on your
  system, such as a system-wide Python (as opposed to the Julia-specific Python),
  you can re-configure PyCall with that Python.   As explained in the PyCall
  documentation, set ENV["PYTHON"] to the path/name of the python executable
  you want to use, run Pkg.build("PyCall"), and re-launch Julia.
  
  ) &lt;class 'ModuleNotFoundError'&gt;
  ModuleNotFoundError("No module named 'julia'")
  
  Stacktrace:
   [1] pyimport(::String) at /Users/austin/.julia/packages/PyCall/0jMpb/src/PyCall.jl:486
   [2] top-level scope at none:0
  </code></pre>
  
  <p>Based off of this, I need to install the PyJulia package <code>julia</code> on to the Julia distribution of Python. There seems to be a hint on how to do this <code>pyimport_conda("julia", PKG)</code> but it's not clear what is meant by <code>PKG</code>...  </p>
  
  <blockquote>
    <p>where PKG is the Anaconda package the contains the module julia</p>
  </blockquote>
  
  <p>From here, I don't know what to try next or if I should report an issue to <code>PyJulia</code>. Any help would be appreciated.</p>