title: Right split using awk
body: <p>I have a txt file filled with file sizes and full paths.</p>
  <p>ex:</p>
  <pre><code>1 3788160 /nfs/extracted/UNENCRYPTED.bin.extracted/_0.extracted/vmlinux.img
  2 5971656 /nfs/extracted/extracted/out_v2.1.3.zip.extracted/firmware.tar.extracted/_uImage.extracted/vmlinux.bin.30071
  3 4202630 /nfs/extracted/v2.0.0.10/extracted/v2.0.0.10.zip.extracted/_install.img.extracted/package2/vmlinux.develop.avhdd.mars.nand.bin
  4 117 /nfs/extracted/v1.0.0.14/extracted/1.0.0.14.zip.extracted
  </code></pre>
  <p>I'd like to print the second column and the filename (rsplit on &quot;/&quot;) so that a[0] is the file name.</p>
  <pre><code>3788160 vmlinux.img
  5971656 vmlinux.bin.30071
  4202630 vmlinux.develop.avhdd.mars.nand.bin
  117 1.0.0.14.zip.extracted
  </code></pre>
  <p>Is there an awk equilient to rsplit?</p>
  <p>ex:</p>
  <pre><code>awk '{rsplit($2,a,&quot;/&quot;); print $1, a[0]}'
  </code></pre>