title: String-literals without escaping null-character
body: <p>When I built a function which gives the hexadecimal representation of a nibble (4 bits) and I looked at the binary file, for the lookuptable of the digits, there was an additional 0-char even if it was not used.</p>
  
  <pre><code>const char digits[] = "0123456789abcdef";
  </code></pre>
  
  <p>I know that you can write it in form of an array:</p>
  
  <pre><code>const char digits[] = {'0', '1', '2', '3', '4', '5', '6', '7', '8', '9', 'a', 'b', 'c', 'd', 'e', 'f'};
  </code></pre>
  
  <p>But that would take a while to write and use more disk-space for other numerical-systems with more digits.
  But is there any way to write it as a literal, but without the null-character at the end?</p>
  
  <p>(I am using Clang with <code>-std=c++14</code>)</p>