title: MIPS: Converting hexadecimal number to 32-bit binary
body: <p>I'm a beginner to MIPS. I'm trying to figure out converting user's inputted hexadecimal values into 32-bit binary number, and store it to an array. Here's what I think: For example, the number is (3ABCD123), then I read this value and split every character and put it in a string array. Then, for every value in the array, convert it to a 4-bit binary number and store it to another array. But I am stuck on splitting the user's inputted string into every character and store it in an array. Please give any suggestions or help, thanks!</p>