title: Find column that meets Criteria and Copy Row to another Sheet
body: <p>I'm trying to create a Macro that will find a Value in a column and if a criteria is met, then copies the entire row to another sheet. So far I have failed.</p>
  
  <p>I have a Sheet called "DB" which has all the raw data with headers and it ranges from A to BG. The column that has the values to meet the criteria is "AJ" and it goes from no data (blank cell on AJ) up to number 10.</p>
  
  <p>I have three other sheets where the data will be copied to. "BlankResults", "0to8" and "9to10" (they all have the same headers as "DB")</p>
  
  <p>What I need is for the macro to check on "DB" column "AJ" for the following:</p>
  
  <pre><code>&gt;= 9 then copy the entire row and paste it on the sheet "9to10" 
  &lt;= 8 then copy and paste the row on "0to8" 
  Blank Cells under AJ and copy the row to "BlankResults".
  </code></pre>
  
  <p>I know that the blank cells part might be kinda tricky because of the amount of cells empty below the last row and the blank cell on AJ could be anywhere on AJ but just as FYI, the entire row from "A to BG" will have data even if the cell on AJ is blank.</p>
  
  <p>I was going to paste the code I was running but it's rather worthless because it only searches for the ">=9" criteria and copies the row but I can't figure out how to do it all in one single macro, nor how to work around the blank cells on AJ since I still need the row on another sheet.</p>
  
  <p>I'm trying to automate a report which that I need to load to a pivot table and I want to sort the data needed since I have to do lots of calculations based on the criterias mentioned above.</p>
  
  <p>If you need me to provide more information, I'd gladly do it.</p>