title: Getting only the values in Array not keys
body: <p>What I'm trying to accomplish is using an array to link to CSS stylesheets.</p>
  
  <p>First I create the function to be executed which is styles()
  The styles() function looks like this..</p>
  
  <pre><code>//CSS Stylesheets Includes
  function styles()
  {
      $linkStyles = array(
      0 =&gt; 'main',
      1 =&gt; 'topBar',
      2 =&gt; 'globals',
      3 =&gt; 'search',
      4 =&gt; 'menu',
      5 =&gt; 'footer',
      6 =&gt; 'banner',
      7 =&gt; 'slideshow',
      8 =&gt; 'graphs',
      9 =&gt; 'contact',
      10 =&gt; 'news',
      11 =&gt; 'products',
      12 =&gt; 'support'
      );
  
      for($i = 0; $i &lt;= count($linkStyles); $i++)
      {
          ?&gt;&lt;link rel="stylesheet" charset="text/css" href="css/style_&lt;?php array($linkStyles[$i]); ?&gt;.css" /&gt;&lt;?php
      }
  }
  </code></pre>
  
  <p>Now what I'm having trouble with is working with the Array within the for() loop. I'm not understanding how to acquire just the value within the key of the array.</p>
  
  <p>For example, If I look up the $linkStyles array under key 0 I want it to return just 'main' without the quotations of course.
  The final output would be something like,</p>
  
  <pre><code>&lt;link rel="stylesheet" charset="text/css" href="css/style_main.css" /&gt;
  </code></pre>
  
  <p>of course since there's a loop, it would have 12 of the links to stylesheets, not just 1.</p>