title: Bash: Replacing "" with newline character, using sed or tr
body: <p>I'm trying to format output in a way that inserts newline characters after each 'line', with lines denoted by double quotes (""). The quotes themselves are temporary and to be stripped in a later step.</p>
  
  <p>Input:</p>
  
  <pre><code>"a",1,"aa""b",2,"bb"
  </code></pre>
  
  <p>Output:</p>
  
  <pre><code>a,1,aa
  b,2,bb
  </code></pre>
  
  <p>I've tried: </p>
  
  <pre><code>sed 's/""/\n/'
  sed 's/""/\/g'
  tr '""' '\n'
  </code></pre>
  
  <p>But tr seems to replace every quote character and sed seems to insert \n as text instead of a newline. What can I do to make this work?</p>