title: display image thumbnail by reading path from table and retrieving the image from folder
body: <p>I would be grateful if anybody could help me out with this. </p>
  
  <p>I have a table which stores the filepath of a set of images, e.g col filepath stores values like: ./phpimages/image3.jpg. Note that my images are stored in folder 'phpimages'</p>
  
  <p>Now i want to loop through all the rows in my table and display thumbnails of the images.</p>
  
  <p>Here is my code:</p>
  
  <p>/</p>
  
  <pre><code>*************************Display all records from images table***************/
  //create an instance is Image
  $objImage = new Image;
  
  $result = $objImage -&gt; listImage();
  $num_rows = mysql_num_rows($result);
  //echo $num_rows."records in database";
  
  
  while($row = mysql_fetch_assoc($result)){
  
  $imagepath="'".$row["filepath"]."'"; // note that if i put $imagepath= "dog.jpg", it displays the image just once!
  
  
  //set mime type content
  header('Content-Type: image/jpeg');
  
  
  //create original image
  $image = imagecreatefromjpeg($imagepath);
  
  //get image dimension
  $dim=getimagesize($imagepath);
  
  
  //Set thumb dimension
  $thumbw = 100;
  $thumbh = 130;
  
  //create empty image
  $thumb_image=imagecreatetruecolor($thumbw, $thumbh);
  
  //Resize original image and copy it to thumb image
  imagecopyresampled($thumb_image, $image, 0, 0, 0, 0,
                      $thumbw, $thumbh, $dim[0], $dim[1]);
  
  
  //display thumb image
  imagejpeg($thumb_image);
  }
  
  ?&gt;
  </code></pre>
  
  <p>Please can anyone tell me where my error lies? Many thanks for any help provided</p>