title: In java, what is the best way to sort an integer array if only the last number item is displaced?
body: <p>It's an array of integers. 
  It was created this way:
  No element is repeated. Every time an element is added, its number is the next available integer, from 0 onwards. This way, if you add 6 elements in a row, they will be 0, 1, 2, 3, 4, 5, in that order. If you delete an element, the array shrinks, and a 'hole' is left between two of the elements, they are no longer consecutive because of that gap: 0, 1, 3, 4, 5. Then comes the problem: if you add a new element, it gets added to the end, but has the next available integer. So, the array is now 0, 1, 3, 4, 5, 2. It needs to be sorted, so the 2 can occupy its place between the 1 and the 3.
  What is the best way to do it? I have thought of several methods. The list is nearly ordered, and it has the property that, when it is ordered, every element is equal to or greater than its index in the array. I am currently doing a bubble sort (don't laugh), i think quick sort is overkill, i dont want to go recursive or use temporary arrays, and i dont want to change the add-element method (which adds the element at the end), so it must be sorted immediately after adding an element (so only the last element is out of place)</p>