title: Time to send 32KB over 9600 baud serial?
body: <p>I'm wondering if my math here is correct. If my baud rate is 9600 then that means 9600 bits are sent every second, right? If so, then:</p>
  
  <pre><code>9600 bit/sec &lt;=&gt; 1000 ms/ 9600 bit = 0.1042 ms/bit
  </code></pre>
  
  <p>So, sending 32KB should take:</p>
  
  <pre><code>32,000*(8+2) bits = 320,000 bits -- (8+2) because 8 data bits + 1 start bit + 1 stop bit
  320,000 bits*0.1042 ms/bit = 33344 ms = 33.344 sec
  </code></pre>
  
  <p>Is that correct?</p>