title: Using signal to pop-up a screen
body: <p>I'm having a little trouble using a signal to make a little screen appear.
  Shortening all i have so far, this following code should show my problem.</p>
  
  <pre><code>import sys
  from PyQt4 import QtGui, QtCore
  
  qApp = QtGui.QApplication(sys.argv) 
  
  class InformatieVenster(QtGui.QMainWindow):
      def __init__(self):
          QtGui.QMainWindow.__init__(self)
          self.setWindowTitle('Informatie')
          self.setGeometry(100,100,300,200)
  
  informatie = InformatieVenster()  
  
  class MenuKlasse(QtGui.QMainWindow):
      def __init__(self):
          QtGui.QMainWindow.__init__(self)
  
          about = QtGui.QAction('About...', self)
          about.setShortcut('Ctrl+A')
          about.setStatusTip('Some text, haha')
          self.connect(about, QtCore.SIGNAL('clicked()'), QtCore.SIGNAL(informatie.show()))
  
          menubar = self.menuBar()
          self.Menu1 = menubar.addMenu('&amp;File')
          self.Menu1.addAction(about)
  
  Menu = MenuKlasse()
  Venster = QtGui.QMainWindow() 
  Venster.menuBar().addMenu(Menu.Menu1)
  Venster.setGeometry(200, 200, 300, 300); 
  size =  Venster.geometry()
  Venster.show()
  qApp.exec_()
  </code></pre>
  
  <p>When this program is runned, the 'informatie' window automatically pops-up.
  However... i only want this to happen every time I click on 'about...' in the menu, or when i use the assigned shortcut.</p>
  
  <p>How may i improve my code such that my problem will be made history?</p>
  
  <p>Greets!</p>