title: Compression Program in C
body: <p>I want to compress a series of characters. For example if i type</p>
  
  <p>Input : FFFFFBBBBBBBCCBBBAABBGGGGGSSS (27 x 8 bits = 216 bits)
  Output: F5B7C2B3A2B2G5S3 (14 x 8 bits = 112bits)</p>
  
  <p>So far this is what i have, i can count the number of Characters in the Array. But the most important task is to count them in the same sequence. I can't seem to figure that out :(
  Ive stared doing C just a few weeks back, i have knowledge on Array, pointers, ASCII value
  but in any case can't seem to count these characters in a sequence. Ive try a bit of everything. This approach is no good but it the closest i came to it.</p>
  
  <pre><code>#include &lt;stdio.h&gt;
  #include &lt;conio.h&gt;
  
  int main()
  {
  
   int charcnt=0,dotcnt=0,commacnt=0,blankcnt=0,i, countA, countB;
   char str[125];
  
  
  
   printf("*****String Manipulations*****\n\n");
   printf("Enter a string\n\n");
  
   scanf("%[^'\n']s",str);
  
  
   printf("\n\nEntered String is \" %s \" \n",str);
  
  
   for(i=0;str[i]!='\0';i++)
   {
  
   // COUNTING EXCEPTION CHARS                         
   if(str[i]==' ')
      blankcnt++;
  
   if(str[i]=='.')
      dotcnt++;
  
   if(str[i]==',')
      commacnt++;
  
   if (str[i]=='A' || str[i]=='a')
  
    countA++;
  
        if (str[i]=='B' || str[i]=='b')
  
    countA++;
  
   }
  
   //PRINT RESULT OF COUNT
   charcnt=i;
   printf("\n\nTotal Characters : %d",charcnt);
   printf("\nTotal Blanks     : %d",blankcnt);
   printf("\nTotal Full stops : %d",dotcnt);
   printf("\nTotal Commas     : %d\n\n",commacnt);
   printf("A%d\n", countA);
  
   }
  </code></pre>