title: How do I launch multiple batch files from one batch file with dependency?
body: <p>I want to run one batch file, that start the other batch files. I looked at a similar question posted here: <a href="https://stackoverflow.com/questions/1103994/how-to-run-multiple-bat-files-within-a-bat-file">How to run multiple .BAT files within a .BAT file</a></p>
  
  <p>I followed the example (specifically the very last suggestion) and it worked...partially. It did launch the batch files that I needed to. However, in order for the applications to function properly, some of these batch files have to open, and then run their course for a few seconds, before the next the next batch file launches, otherwise they won't be registered. Specifically, the first batch file launches a web applications server (JBOSS 5.1), then the next batch file opens a pool manager, then the other two launch distribution servers. When I run my batch file that calls the others, they all launch nearly simultaneously, and they do not register each other. Can I even do this with a batch file? Or do I have to go into the code of the other batch files and make changes there? I want to avoid that at all costs.</p>
  
  <p>Here is what I have so far:</p>
  
  <pre><code>start cmd /k CALL D:\jboss-5.1.0.GA-jdk6\jboss-5.1.0.GA\bin\run.bat
  
  start cmd /k CALL batch1.bat
  
  start cmd /k CALL batch2.bat
  
  start cmd /k CALL batch3.bat
  </code></pre>