title: Turning circular gghistogram
body: <p>I am working on a rose diagram using gghistogram.
  Here is what I have so far:
  <a href="https://i.stack.imgur.com/20JEg.png" rel="nofollow noreferrer"><img src="https://i.stack.imgur.com/20JEg.png" alt="enter image description here" /></a></p>
  <p>Data:</p>
  <p><code>structure(list(Dataset = structure(c(1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L, 1L),.Label = &quot;Outcrop 9&quot;, class = &quot;factor&quot;), Orientation = c(205L, 124L, 312L, 212L,196L, 203L, 212L, 155L, 193L, 160L)), class = &quot;data.frame&quot;, row.names = c(NA, -10L))</code></p>
  <p><strong>I'm looking to turn the diagram so 0/360 is at the top (North). Additionally, is there a way to relabel the &quot;0/360&quot; as simply &quot;0&quot;?</strong></p>
  <p>Current code:</p>
  <pre><code>library(ggplot2)
  library(scales)
  colours&lt;-c(&quot;#D52B1E&quot;,&quot;pink&quot;,&quot;black&quot;)
  plot&lt;-ggplot() + 
    geom_line(aes(x = c(0, 360), y = c(4, 4)), colour = &quot;gray75&quot;) +
    geom_line(aes(x = c(0, 360), y = c(8, 8)), colour = &quot;gray75&quot;) +
    geom_line(aes(x = c(0, 360), y = c(12, 12)), colour = &quot;gray75&quot;) +
    geom_line(aes(x = c(0, 360), y = c(16, 16)), colour = &quot;gray75&quot;) +
    geom_line(aes(x = c(0, 360), y = c(20, 20)), colour = &quot;gray75&quot;) +
    geom_vline(aes(xintercept = 0:12 * 30), colour = &quot;gray75&quot;) +
    geom_histogram(data = df, aes(x=Orientation, fill=factor(Dataset)), 
                   position = &quot;stack&quot;, colour = &quot;black&quot;, binwidth = 20,
                   boundary = 0) +theme_bw() + scale_fill_manual(values=colours)+
    coord_polar(start = 3 * pi / 2) + 
    scale_x_continuous(limits = c(0, 360), breaks = 0:12 * 30) +
    scale_y_continuous(limits = c(0, 4)) + theme(panel.border=element_blank(), axis.title.y = element_blank(), axis.title.x = element_blank(),legend.position=&quot;none&quot;)```
  
  (Please ignore the fact that I have added extra colours, I will be adding in two more datasets later)
  </code></pre>