Hank gave his wife, Delphine, a box of 24 chocolates for Valentine's Day.  On the first day, Delphine ate 4 chocolates.  On the second day, she ate 3 less than twice as many chocolates as she ate the first day.  On the third day, she ate two less than the number she ate on the first day.  And on the fourth day, she ate one less than she ate the previous day.  On the fifth day, how many chocolates remained uneaten?
How many chocolates did Delphine eat the first day? ** Twice as many chocolates as she ate the first day is 2*4=<<2*4=8>>8 chocolates.
How many chocolates did Delphine eat the second day? ** And three less than twice as many chocolates as she ate the first day is 8-3=<<8-3=5>>5 chocolates.
How many chocolates did Delphine eat the third day? ** Two less than the number she ate on the first day is 4-2=<<4-2=2>>2 chocolates.
How many chocolates did Delphine eat the fourth day? ** One less than she ate the third day is 2-1=<<2-1=1>>1 chocolate.
How many chocolates did Delphine eat in total? ** By the end of the fourth day, 4+5+2+1=<<4+5+2+1=12>>12 chocolates had been eaten.
How many chocolates remained uneaten? ** Thus, on the fifth day, 24-12=<<24-12=12>>12 chocolates remained uneaten.
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