Brian goes fishing twice as often as Chris, but catches 2/5 times fewer fish than Chris per trip. If Brian caught 400 fish every time he went fishing, how many fish did they catch altogether if Chris went fishing 10 times?
How many fish did Brian catch in two trips? ** If Brian caught 400 fish in one trip, he caught 2*400=<<400*2=800>>800 fish in two trips.
How many more fish does Chris catch than Brian? ** Since Brian catches 2/5 times less fish than Chris per trip, Chris catches 2/5*400=<<2/5*400=160>>160 more fish in one fishing trip.
How many fish does Chris catch in one trip? ** Chris's total number of fish in one trip is 400+160 = <<400+160=560>>560 fish.
How many fish does Chris catch altogether? ** In 10 trips, Chris catches 560*10=<<560*10=5600>>5600 fish.
How many fish does Brian catch altogether? ** If in his two trips Brian catches 800 fish, and he goes fishing twice as often as Chris, if Chris goes fishing 10 times, Brian will catch 800*10=<<800*10=8000>>8000 fish.
How many fish will they catch altogether? ** The total number of fish they'll catch if Chris goes fishing ten times is 8000+5600=<<8000+5600=13600>>13600
#### 13600