A hay farmer harvested 560 bales of hay from 5 acres of grass per month last year. This year, he planted an additional 7 acres of grass. If the farmer also owns 9 horses and each horse consumes 3 bales of hay a day, how many bales of hay would the farmer have left by the end of December if he starts feeding them this year's hay beginning the first day of September?
How many bales of hay can the farmer harvest from each acre of grass? ** For every acre of grass, the farmer can harvest 560/5 = <<560/5=112>>112 bales of hay each month.
How many acres of grass does the farmer have? ** This year, the farmer has 7 + 5 = <<7+5=12>>12 acres of grass.
How many bales of hay can the farmer harvest from all of his acres of grass? ** He can expect to harvest 12 x 112 = <<12*112=1344>>1344 bales of hay per month.
How many bales of hay will the farmer produce this year? ** The total hay production this year is 1344*12 = <<1344*12=16128>>16128
How many days would the farmer have to feed his horses? ** From September to December, the farmer would have to feed his horses for a total of 30 + 31 + 30 + 31 = <<30+31+30+31=122>>122 days
How many bales of hay does each horse eat in a day? ** Each day his horse eats a total of 3*9 = <<3*9=27>>27 bales of hay.
How many bales of hay will the horses eat in total? ** For the 122 days, the horses will eat a total of 27*122 = <<27*122=3294>>3294 bales.
How many bales of hay will the farmer have left by the end of December? ** The total number of bales remaining will be 16128-3294 = <<16128-3294=12834>>12834.
#### 12834