Partition Equal Subset Sum
<p>Given an integer array <code>nums</code>, return <code>true</code> <em>if you can partition the array into two subsets such that the sum of the elements in both subsets is equal or </em><code>false</code><em> otherwise</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,5,11,5]
<strong>Output:</strong> true
<strong>Explanation:</strong> The array can be partitioned as [1, 5, 5] and [11].
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,3,5]
<strong>Output:</strong> false
<strong>Explanation:</strong> The array cannot be partitioned into equal sum subsets.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 200</code></li>
	<li><code>1 &lt;= nums[i] &lt;= 100</code></li>
</ul>
Array; Dynamic Programming
/**
 * @param {number[]} nums
 * @return {boolean}
 */
var canPartition = function (nums) {
    const s = nums.reduce((a, b) => a + b, 0);
    if (s % 2 === 1) {
        return false;
    }
    const n = nums.length;
    const m = s >> 1;
    const f = Array.from({ length: n + 1 }, () => Array(m + 1).fill(false));
    f[0][0] = true;
    for (let i = 1; i <= n; ++i) {
        const x = nums[i - 1];
        for (let j = 0; j <= m; ++j) {
            f[i][j] = f[i - 1][j] || (j >= x && f[i - 1][j - x]);
        }
    }
    return f[n][m];
};
