Univalued Binary Tree
<p>A binary tree is <strong>uni-valued</strong> if every node in the tree has the same value.</p>

<p>Given the <code>root</code> of a binary tree, return <code>true</code><em> if the given tree is <strong>uni-valued</strong>, or </em><code>false</code><em> otherwise.</em></p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/0900-0999/0965.Univalued%20Binary%20Tree/images/unival_bst_1.png" style="width: 265px; height: 172px;" />
<pre>
<strong>Input:</strong> root = [1,1,1,1,1,null,1]
<strong>Output:</strong> true
</pre>

<p><strong class="example">Example 2:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/0900-0999/0965.Univalued%20Binary%20Tree/images/unival_bst_2.png" style="width: 198px; height: 169px;" />
<pre>
<strong>Input:</strong> root = [2,2,2,5,2]
<strong>Output:</strong> false
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li>The number of nodes in the tree is in the range <code>[1, 100]</code>.</li>
	<li><code>0 &lt;= Node.val &lt; 100</code></li>
</ul>
Tree; Depth-First Search; Breadth-First Search; Binary Tree
/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
 *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
 *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
 * };
 */
class Solution {
public:
    bool isUnivalTree(TreeNode* root) {
        int x = root->val;
        auto dfs = [&](this auto&& dfs, TreeNode* root) -> bool {
            if (!root) {
                return true;
            }
            return root->val == x && dfs(root->left) && dfs(root->right);
        };
        return dfs(root);
    }
};
