Maximum Students Taking Exam
<p>Given a <code>m&nbsp;* n</code>&nbsp;matrix <code>seats</code>&nbsp;&nbsp;that represent seats distributions&nbsp;in a classroom.&nbsp;If a seat&nbsp;is&nbsp;broken, it is denoted by <code>&#39;#&#39;</code> character otherwise it is denoted by a <code>&#39;.&#39;</code> character.</p>

<p>Students can see the answers of those sitting next to the left, right, upper left and upper right, but he cannot see the answers of the student sitting&nbsp;directly in front or behind him. Return the <strong>maximum </strong>number of students that can take the exam together&nbsp;without any cheating being possible.</p>

<p>Students must be placed in seats in good condition.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img height="200" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/1300-1399/1349.Maximum%20Students%20Taking%20Exam/images/image.png" width="339" />
<pre>
<strong>Input:</strong> seats = [[&quot;#&quot;,&quot;.&quot;,&quot;#&quot;,&quot;#&quot;,&quot;.&quot;,&quot;#&quot;],
&nbsp;               [&quot;.&quot;,&quot;#&quot;,&quot;#&quot;,&quot;#&quot;,&quot;#&quot;,&quot;.&quot;],
&nbsp;               [&quot;#&quot;,&quot;.&quot;,&quot;#&quot;,&quot;#&quot;,&quot;.&quot;,&quot;#&quot;]]
<strong>Output:</strong> 4
<strong>Explanation:</strong> Teacher can place 4 students in available seats so they don&#39;t cheat on the exam. 
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> seats = [[&quot;.&quot;,&quot;#&quot;],
&nbsp;               [&quot;#&quot;,&quot;#&quot;],
&nbsp;               [&quot;#&quot;,&quot;.&quot;],
&nbsp;               [&quot;#&quot;,&quot;#&quot;],
&nbsp;               [&quot;.&quot;,&quot;#&quot;]]
<strong>Output:</strong> 3
<strong>Explanation:</strong> Place all students in available seats. 

</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> seats = [[&quot;#&quot;,&quot;.&quot;,&quot;<strong>.</strong>&quot;,&quot;.&quot;,&quot;#&quot;],
&nbsp;               [&quot;<strong>.</strong>&quot;,&quot;#&quot;,&quot;<strong>.</strong>&quot;,&quot;#&quot;,&quot;<strong>.</strong>&quot;],
&nbsp;               [&quot;<strong>.</strong>&quot;,&quot;.&quot;,&quot;#&quot;,&quot;.&quot;,&quot;<strong>.</strong>&quot;],
&nbsp;               [&quot;<strong>.</strong>&quot;,&quot;#&quot;,&quot;<strong>.</strong>&quot;,&quot;#&quot;,&quot;<strong>.</strong>&quot;],
&nbsp;               [&quot;#&quot;,&quot;.&quot;,&quot;<strong>.</strong>&quot;,&quot;.&quot;,&quot;#&quot;]]
<strong>Output:</strong> 10
<strong>Explanation:</strong> Place students in available seats in column 1, 3 and 5.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>seats</code>&nbsp;contains only characters&nbsp;<code>&#39;.&#39;<font face="sans-serif, Arial, Verdana, Trebuchet MS">&nbsp;and</font></code><code>&#39;#&#39;.</code></li>
	<li><code>m ==&nbsp;seats.length</code></li>
	<li><code>n ==&nbsp;seats[i].length</code></li>
	<li><code>1 &lt;= m &lt;= 8</code></li>
	<li><code>1 &lt;= n &lt;= 8</code></li>
</ul>
Bit Manipulation; Array; Dynamic Programming; Bitmask; Matrix
class Solution {
    private Integer[][] f;
    private int n;
    private int[] ss;

    public int maxStudents(char[][] seats) {
        int m = seats.length;
        n = seats[0].length;
        ss = new int[m];
        f = new Integer[1 << n][m];
        for (int i = 0; i < m; ++i) {
            for (int j = 0; j < n; ++j) {
                if (seats[i][j] == '.') {
                    ss[i] |= 1 << j;
                }
            }
        }
        return dfs(ss[0], 0);
    }

    private int dfs(int seat, int i) {
        if (f[seat][i] != null) {
            return f[seat][i];
        }
        int ans = 0;
        for (int mask = 0; mask < 1 << n; ++mask) {
            if ((seat | mask) != seat || (mask & (mask << 1)) != 0) {
                continue;
            }
            int cnt = Integer.bitCount(mask);
            if (i == ss.length - 1) {
                ans = Math.max(ans, cnt);
            } else {
                int nxt = ss[i + 1];
                nxt &= ~(mask << 1);
                nxt &= ~(mask >> 1);
                ans = Math.max(ans, cnt + dfs(nxt, i + 1));
            }
        }
        return f[seat][i] = ans;
    }
}