Range Sum Query 2D - Mutable
<p>Given a 2D matrix <code>matrix</code>, handle multiple queries of the following types:</p>

<ol>
	<li><strong>Update</strong> the value of a cell in <code>matrix</code>.</li>
	<li>Calculate the <strong>sum</strong> of the elements of <code>matrix</code> inside the rectangle defined by its <strong>upper left corner</strong> <code>(row1, col1)</code> and <strong>lower right corner</strong> <code>(row2, col2)</code>.</li>
</ol>

<p>Implement the NumMatrix class:</p>

<ul>
	<li><code>NumMatrix(int[][] matrix)</code> Initializes the object with the integer matrix <code>matrix</code>.</li>
	<li><code>void update(int row, int col, int val)</code> <strong>Updates</strong> the value of <code>matrix[row][col]</code> to be <code>val</code>.</li>
	<li><code>int sumRegion(int row1, int col1, int row2, int col2)</code> Returns the <strong>sum</strong> of the elements of <code>matrix</code> inside the rectangle defined by its <strong>upper left corner</strong> <code>(row1, col1)</code> and <strong>lower right corner</strong> <code>(row2, col2)</code>.</li>
</ul>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/0300-0399/0308.Range%20Sum%20Query%202D%20-%20Mutable/images/summut-grid.jpg" style="width: 500px; height: 222px;" />
<pre>
<strong>Input</strong>
[&quot;NumMatrix&quot;, &quot;sumRegion&quot;, &quot;update&quot;, &quot;sumRegion&quot;]
[[[[3, 0, 1, 4, 2], [5, 6, 3, 2, 1], [1, 2, 0, 1, 5], [4, 1, 0, 1, 7], [1, 0, 3, 0, 5]]], [2, 1, 4, 3], [3, 2, 2], [2, 1, 4, 3]]
<strong>Output</strong>
[null, 8, null, 10]

<strong>Explanation</strong>
NumMatrix numMatrix = new NumMatrix([[3, 0, 1, 4, 2], [5, 6, 3, 2, 1], [1, 2, 0, 1, 5], [4, 1, 0, 1, 7], [1, 0, 3, 0, 5]]);
numMatrix.sumRegion(2, 1, 4, 3); // return 8 (i.e. sum of the left red rectangle)
numMatrix.update(3, 2, 2); // matrix changes from left image to right image
numMatrix.sumRegion(2, 1, 4, 3); // return 10 (i.e. sum of the right red rectangle)

</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>m == matrix.length</code></li>
	<li><code>n == matrix[i].length</code></li>
	<li><code>1 &lt;= m, n &lt;= 200</code></li>
	<li><code>-1000 &lt;= matrix[i][j] &lt;= 1000</code></li>
	<li><code>0 &lt;= row &lt; m</code></li>
	<li><code>0 &lt;= col &lt; n</code></li>
	<li><code>-1000 &lt;= val &lt;= 1000</code></li>
	<li><code>0 &lt;= row1 &lt;= row2 &lt; m</code></li>
	<li><code>0 &lt;= col1 &lt;= col2 &lt; n</code></li>
	<li>At most <code>5000</code> calls will be made to <code>sumRegion</code> and <code>update</code>.</li>
</ul>
Design; Binary Indexed Tree; Segment Tree; Array; Matrix
type BinaryIndexedTree struct {
	n int
	c []int
}

func newBinaryIndexedTree(n int) *BinaryIndexedTree {
	c := make([]int, n+1)
	return &BinaryIndexedTree{n, c}
}

func (this *BinaryIndexedTree) lowbit(x int) int {
	return x & -x
}

func (this *BinaryIndexedTree) update(x, delta int) {
	for x <= this.n {
		this.c[x] += delta
		x += this.lowbit(x)
	}
}

func (this *BinaryIndexedTree) query(x int) int {
	s := 0
	for x > 0 {
		s += this.c[x]
		x -= this.lowbit(x)
	}
	return s
}

type NumMatrix struct {
	trees []*BinaryIndexedTree
}

func Constructor(matrix [][]int) NumMatrix {
	n := len(matrix[0])
	var trees []*BinaryIndexedTree
	for _, row := range matrix {
		tree := newBinaryIndexedTree(n)
		for j, v := range row {
			tree.update(j+1, v)
		}
		trees = append(trees, tree)
	}
	return NumMatrix{trees}
}

func (this *NumMatrix) Update(row int, col int, val int) {
	tree := this.trees[row]
	prev := tree.query(col+1) - tree.query(col)
	tree.update(col+1, val-prev)
}

func (this *NumMatrix) SumRegion(row1 int, col1 int, row2 int, col2 int) int {
	s := 0
	for i := row1; i <= row2; i++ {
		tree := this.trees[i]
		s += tree.query(col2+1) - tree.query(col1)
	}
	return s
}

/**
 * Your NumMatrix object will be instantiated and called as such:
 * obj := Constructor(matrix);
 * obj.Update(row,col,val);
 * param_2 := obj.SumRegion(row1,col1,row2,col2);
 */