Subsets II
<p>Given an integer array <code>nums</code> that may contain duplicates, return <em>all possible</em> <span data-keyword="subset"><em>subsets</em></span><em> (the power set)</em>.</p>

<p>The solution set <strong>must not</strong> contain duplicate subsets. Return the solution in <strong>any order</strong>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> nums = [1,2,2]
<strong>Output:</strong> [[],[1],[1,2],[1,2,2],[2],[2,2]]
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> nums = [0]
<strong>Output:</strong> [[],[0]]
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 10</code></li>
	<li><code>-10 &lt;= nums[i] &lt;= 10</code></li>
</ul>
Bit Manipulation; Array; Backtracking
func subsetsWithDup(nums []int) (ans [][]int) {
	slices.Sort(nums)
	n := len(nums)
	t := []int{}
	var dfs func(int)
	dfs = func(i int) {
		if i >= n {
			ans = append(ans, slices.Clone(t))
			return
		}
		t = append(t, nums[i])
		dfs(i + 1)
		t = t[:len(t)-1]
		for i+1 < n && nums[i+1] == nums[i] {
			i++
		}
		dfs(i + 1)
	}
	dfs(0)
	return
}
