Sum of Mutated Array Closest to Target
<p>Given an integer array <code>arr</code> and a target value <code>target</code>, return the integer <code>value</code> such that when we change all the integers larger than <code>value</code> in the given array to be equal to <code>value</code>, the sum of the array gets as close as possible (in absolute difference) to <code>target</code>.</p>

<p>In case of a tie, return the minimum such integer.</p>

<p>Notice that the answer is not neccesarilly a number from <code>arr</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> arr = [4,9,3], target = 10
<strong>Output:</strong> 3
<strong>Explanation:</strong> When using 3 arr converts to [3, 3, 3] which sums 9 and that&#39;s the optimal answer.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> arr = [2,3,5], target = 10
<strong>Output:</strong> 5
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> arr = [60864,25176,27249,21296,20204], target = 56803
<strong>Output:</strong> 11361
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= arr.length &lt;= 10<sup>4</sup></code></li>
	<li><code>1 &lt;= arr[i], target &lt;= 10<sup>5</sup></code></li>
</ul>
Array; Binary Search; Sorting
func findBestValue(arr []int, target int) (ans int) {
	sort.Ints(arr)
	n := len(arr)
	s := make([]int, n+1)
	mx := slices.Max(arr)
	for i, x := range arr {
		s[i+1] = s[i] + x
	}
	diff := 1 << 30
	for value := 0; value <= mx; value++ {
		i := sort.SearchInts(arr, value+1)
		d := abs(s[i] + (n-i)*value - target)
		if diff > d {
			diff = d
			ans = value
		}
	}
	return
}

func abs(x int) int {
	if x < 0 {
		return -x
	}
	return x
}