Adding Two Negabinary Numbers
<p>Given two numbers <code>arr1</code> and <code>arr2</code> in base <strong>-2</strong>, return the result of adding them together.</p>

<p>Each number is given in <em>array format</em>:&nbsp; as an array of 0s and 1s, from most significant bit to least significant bit.&nbsp; For example, <code>arr = [1,1,0,1]</code> represents the number <code>(-2)^3&nbsp;+ (-2)^2 + (-2)^0 = -3</code>.&nbsp; A number <code>arr</code> in <em>array, format</em> is also guaranteed to have no leading zeros: either&nbsp;<code>arr == [0]</code> or <code>arr[0] == 1</code>.</p>

<p>Return the result of adding <code>arr1</code> and <code>arr2</code> in the same format: as an array of 0s and 1s with no leading zeros.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> arr1 = [1,1,1,1,1], arr2 = [1,0,1]
<strong>Output:</strong> [1,0,0,0,0]
<strong>Explanation: </strong>arr1 represents 11, arr2 represents 5, the output represents 16.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> arr1 = [0], arr2 = [0]
<strong>Output:</strong> [0]
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> arr1 = [0], arr2 = [1]
<strong>Output:</strong> [1]
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= arr1.length,&nbsp;arr2.length &lt;= 1000</code></li>
	<li><code>arr1[i]</code>&nbsp;and <code>arr2[i]</code> are&nbsp;<code>0</code> or <code>1</code></li>
	<li><code>arr1</code> and <code>arr2</code> have no leading zeros</li>
</ul>
Array; Math
class Solution {
public:
    vector<int> addNegabinary(vector<int>& arr1, vector<int>& arr2) {
        int i = arr1.size() - 1, j = arr2.size() - 1;
        vector<int> ans;
        for (int c = 0; i >= 0 || j >= 0 || c; --i, --j) {
            int a = i < 0 ? 0 : arr1[i];
            int b = j < 0 ? 0 : arr2[j];
            int x = a + b + c;
            c = 0;
            if (x >= 2) {
                x -= 2;
                c -= 1;
            } else if (x == -1) {
                x = 1;
                c += 1;
            }
            ans.push_back(x);
        }
        while (ans.size() > 1 && ans.back() == 0) {
            ans.pop_back();
        }
        reverse(ans.begin(), ans.end());
        return ans;
    }
};