Last Substring in Lexicographical Order
<p>Given a string <code>s</code>, return <em>the last substring of</em> <code>s</code> <em>in lexicographical order</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;abab&quot;
<strong>Output:</strong> &quot;bab&quot;
<strong>Explanation:</strong> The substrings are [&quot;a&quot;, &quot;ab&quot;, &quot;aba&quot;, &quot;abab&quot;, &quot;b&quot;, &quot;ba&quot;, &quot;bab&quot;]. The lexicographically maximum substring is &quot;bab&quot;.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;leetcode&quot;
<strong>Output:</strong> &quot;tcode&quot;
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= s.length &lt;= 4 * 10<sup>5</sup></code></li>
	<li><code>s</code> contains only lowercase English letters.</li>
</ul>
Two Pointers; String
function lastSubstring(s: string): string {
    const n = s.length;
    let i = 0;
    for (let j = 1, k = 0; j + k < n; ) {
        if (s[i + k] === s[j + k]) {
            ++k;
        } else if (s[i + k] < s[j + k]) {
            i += k + 1;
            k = 0;
            if (i >= j) {
                j = i + 1;
            }
        } else {
            j += k + 1;
            k = 0;
        }
    }
    return s.slice(i);
}
