Friends Of Appropriate Ages
<p>There are <code>n</code> persons on a social media website. You are given an integer array <code>ages</code> where <code>ages[i]</code> is the age of the <code>i<sup>th</sup></code> person.</p>

<p>A Person <code>x</code> will not send a friend request to a person <code>y</code> (<code>x != y</code>) if any of the following conditions is true:</p>

<ul>
	<li><code>age[y] &lt;= 0.5 * age[x] + 7</code></li>
	<li><code>age[y] &gt; age[x]</code></li>
	<li><code>age[y] &gt; 100 &amp;&amp; age[x] &lt; 100</code></li>
</ul>

<p>Otherwise, <code>x</code> will send a friend request to <code>y</code>.</p>

<p>Note that if <code>x</code> sends a request to <code>y</code>, <code>y</code> will not necessarily send a request to <code>x</code>. Also, a person will not send a friend request to themself.</p>

<p>Return <em>the total number of friend requests made</em>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> ages = [16,16]
<strong>Output:</strong> 2
<strong>Explanation:</strong> 2 people friend request each other.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> ages = [16,17,18]
<strong>Output:</strong> 2
<strong>Explanation:</strong> Friend requests are made 17 -&gt; 16, 18 -&gt; 17.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> ages = [20,30,100,110,120]
<strong>Output:</strong> 3
<strong>Explanation:</strong> Friend requests are made 110 -&gt; 100, 120 -&gt; 110, 120 -&gt; 100.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>n == ages.length</code></li>
	<li><code>1 &lt;= n &lt;= 2 * 10<sup>4</sup></code></li>
	<li><code>1 &lt;= ages[i] &lt;= 120</code></li>
</ul>
Array; Two Pointers; Binary Search; Sorting
class Solution {
    public int numFriendRequests(int[] ages) {
        final int m = 121;
        int[] cnt = new int[m];
        for (int x : ages) {
            ++cnt[x];
        }
        int ans = 0;
        for (int ax = 1; ax < m; ++ax) {
            for (int ay = 1; ay < m; ++ay) {
                if (!(ay <= 0.5 * ax + 7 || ay > ax || (ay > 100 && ax < 100))) {
                    ans += cnt[ax] * (cnt[ay] - (ax == ay ? 1 : 0));
                }
            }
        }
        return ans;
    }
}
