132 Pattern
<p>Given an array of <code>n</code> integers <code>nums</code>, a <strong>132 pattern</strong> is a subsequence of three integers <code>nums[i]</code>, <code>nums[j]</code> and <code>nums[k]</code> such that <code>i &lt; j &lt; k</code> and <code>nums[i] &lt; nums[k] &lt; nums[j]</code>.</p>

<p>Return <code>true</code><em> if there is a <strong>132 pattern</strong> in </em><code>nums</code><em>, otherwise, return </em><code>false</code><em>.</em></p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,2,3,4]
<strong>Output:</strong> false
<strong>Explanation:</strong> There is no 132 pattern in the sequence.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [3,1,4,2]
<strong>Output:</strong> true
<strong>Explanation:</strong> There is a 132 pattern in the sequence: [1, 4, 2].
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> nums = [-1,3,2,0]
<strong>Output:</strong> true
<strong>Explanation:</strong> There are three 132 patterns in the sequence: [-1, 3, 2], [-1, 3, 0] and [-1, 2, 0].
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>n == nums.length</code></li>
	<li><code>1 &lt;= n &lt;= 2 * 10<sup>5</sup></code></li>
	<li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>
</ul>
Stack; Array; Binary Search; Ordered Set; Monotonic Stack
function find132pattern(nums: number[]): boolean {
    let vk = -Infinity;
    const stk: number[] = [];
    for (let i = nums.length - 1; i >= 0; --i) {
        if (nums[i] < vk) {
            return true;
        }
        while (stk.length && stk[stk.length - 1] < nums[i]) {
            vk = stk.pop()!;
        }
        stk.push(nums[i]);
    }
    return false;
}
