Max Consecutive Ones II
<p>Given a binary array <code>nums</code>, return <em>the maximum number of consecutive </em><code>1</code><em>&#39;s in the array if you can flip at most one</em> <code>0</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,0,1,1,0]
<strong>Output:</strong> 4
<strong>Explanation:</strong> 
- If we flip the first zero, nums becomes [1,1,1,1,0] and we have 4 consecutive ones.
- If we flip the second zero, nums becomes [1,0,1,1,1] and we have 3 consecutive ones.
The max number of consecutive ones is 4.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums = [1,0,1,1,0,1]
<strong>Output:</strong> 4
<strong>Explanation:</strong> 
- If we flip the first zero, nums becomes [1,1,1,1,0,1] and we have 4 consecutive ones.
- If we flip the second zero, nums becomes [1,0,1,1,1,1] and we have 4 consecutive ones.
The max number of consecutive ones is 4.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>
	<li><code>nums[i]</code> is either <code>0</code> or <code>1</code>.</li>
</ul>

<p>&nbsp;</p>
<p><strong>Follow up:</strong> What if the input numbers come in one by one as an infinite stream? In other words, you can&#39;t store all numbers coming from the stream as it&#39;s too large to hold in memory. Could you solve it efficiently?</p>
Array; Dynamic Programming; Sliding Window
/**
 * @param {number[]} nums
 * @return {number}
 */
var findMaxConsecutiveOnes = function (nums) {
    let [l, cnt] = [0, 0];
    for (const x of nums) {
        cnt += x ^ 1;
        if (cnt > 1) {
            cnt -= nums[l++] ^ 1;
        }
    }
    return nums.length - l;
};
