Find the K-th Character in String Game II
<p>Alice and Bob are playing a game. Initially, Alice has a string <code>word = &quot;a&quot;</code>.</p>

<p>You are given a <strong>positive</strong> integer <code>k</code>. You are also given an integer array <code>operations</code>, where <code>operations[i]</code> represents the <strong>type</strong> of the <code>i<sup>th</sup></code> operation.</p>

<p>Now Bob will ask Alice to perform <strong>all</strong> operations in sequence:</p>

<ul>
	<li>If <code>operations[i] == 0</code>, <strong>append</strong> a copy of <code>word</code> to itself.</li>
	<li>If <code>operations[i] == 1</code>, generate a new string by <strong>changing</strong> each character in <code>word</code> to its <strong>next</strong> character in the English alphabet, and <strong>append</strong> it to the <em>original</em> <code>word</code>. For example, performing the operation on <code>&quot;c&quot;</code> generates <code>&quot;cd&quot;</code> and performing the operation on <code>&quot;zb&quot;</code> generates <code>&quot;zbac&quot;</code>.</li>
</ul>

<p>Return the value of the <code>k<sup>th</sup></code> character in <code>word</code> after performing all the operations.</p>

<p><strong>Note</strong> that the character <code>&#39;z&#39;</code> can be changed to <code>&#39;a&#39;</code> in the second type of operation.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">k = 5, operations = [0,0,0]</span></p>

<p><strong>Output:</strong> <span class="example-io">&quot;a&quot;</span></p>

<p><strong>Explanation:</strong></p>

<p>Initially, <code>word == &quot;a&quot;</code>. Alice performs the three operations as follows:</p>

<ul>
	<li>Appends <code>&quot;a&quot;</code> to <code>&quot;a&quot;</code>, <code>word</code> becomes <code>&quot;aa&quot;</code>.</li>
	<li>Appends <code>&quot;aa&quot;</code> to <code>&quot;aa&quot;</code>, <code>word</code> becomes <code>&quot;aaaa&quot;</code>.</li>
	<li>Appends <code>&quot;aaaa&quot;</code> to <code>&quot;aaaa&quot;</code>, <code>word</code> becomes <code>&quot;aaaaaaaa&quot;</code>.</li>
</ul>
</div>

<p><strong class="example">Example 2:</strong></p>

<div class="example-block">
<p><strong>Input:</strong> <span class="example-io">k = 10, operations = [0,1,0,1]</span></p>

<p><strong>Output:</strong> <span class="example-io">&quot;b&quot;</span></p>

<p><strong>Explanation:</strong></p>

<p>Initially, <code>word == &quot;a&quot;</code>. Alice performs the four operations as follows:</p>

<ul>
	<li>Appends <code>&quot;a&quot;</code> to <code>&quot;a&quot;</code>, <code>word</code> becomes <code>&quot;aa&quot;</code>.</li>
	<li>Appends <code>&quot;bb&quot;</code> to <code>&quot;aa&quot;</code>, <code>word</code> becomes <code>&quot;aabb&quot;</code>.</li>
	<li>Appends <code>&quot;aabb&quot;</code> to <code>&quot;aabb&quot;</code>, <code>word</code> becomes <code>&quot;aabbaabb&quot;</code>.</li>
	<li>Appends <code>&quot;bbccbbcc&quot;</code> to <code>&quot;aabbaabb&quot;</code>, <code>word</code> becomes <code>&quot;aabbaabbbbccbbcc&quot;</code>.</li>
</ul>
</div>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= k &lt;= 10<sup>14</sup></code></li>
	<li><code>1 &lt;= operations.length &lt;= 100</code></li>
	<li><code>operations[i]</code> is either 0 or 1.</li>
	<li>The input is generated such that <code>word</code> has <strong>at least</strong> <code>k</code> characters after all operations.</li>
</ul>
Bit Manipulation; Recursion; Math
function kthCharacter(k: number, operations: number[]): string {
    let n = 1;
    let i = 0;
    while (n < k) {
        n *= 2;
        i++;
    }
    let d = 0;
    while (n > 1) {
        if (k > n / 2) {
            k -= n / 2;
            d += operations[i - 1];
        }
        n /= 2;
        i--;
    }
    return String.fromCharCode('a'.charCodeAt(0) + (d % 26));
}
