Smallest Number in Infinite Set
<p>You have a set which contains all positive integers <code>[1, 2, 3, 4, 5, ...]</code>.</p>

<p>Implement the <code>SmallestInfiniteSet</code> class:</p>

<ul>
	<li><code>SmallestInfiniteSet()</code> Initializes the <strong>SmallestInfiniteSet</strong> object to contain <strong>all</strong> positive integers.</li>
	<li><code>int popSmallest()</code> <strong>Removes</strong> and returns the smallest integer contained in the infinite set.</li>
	<li><code>void addBack(int num)</code> <strong>Adds</strong> a positive integer <code>num</code> back into the infinite set, if it is <strong>not</strong> already in the infinite set.</li>
</ul>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input</strong>
[&quot;SmallestInfiniteSet&quot;, &quot;addBack&quot;, &quot;popSmallest&quot;, &quot;popSmallest&quot;, &quot;popSmallest&quot;, &quot;addBack&quot;, &quot;popSmallest&quot;, &quot;popSmallest&quot;, &quot;popSmallest&quot;]
[[], [2], [], [], [], [1], [], [], []]
<strong>Output</strong>
[null, null, 1, 2, 3, null, 1, 4, 5]

<strong>Explanation</strong>
SmallestInfiniteSet smallestInfiniteSet = new SmallestInfiniteSet();
smallestInfiniteSet.addBack(2);    // 2 is already in the set, so no change is made.
smallestInfiniteSet.popSmallest(); // return 1, since 1 is the smallest number, and remove it from the set.
smallestInfiniteSet.popSmallest(); // return 2, and remove it from the set.
smallestInfiniteSet.popSmallest(); // return 3, and remove it from the set.
smallestInfiniteSet.addBack(1);    // 1 is added back to the set.
smallestInfiniteSet.popSmallest(); // return 1, since 1 was added back to the set and
                                   // is the smallest number, and remove it from the set.
smallestInfiniteSet.popSmallest(); // return 4, and remove it from the set.
smallestInfiniteSet.popSmallest(); // return 5, and remove it from the set.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= num &lt;= 1000</code></li>
	<li>At most <code>1000</code> calls will be made <strong>in total</strong> to <code>popSmallest</code> and <code>addBack</code>.</li>
</ul>
Design; Hash Table; Ordered Set; Heap (Priority Queue)
class SmallestInfiniteSet:
    def __init__(self):
        self.s = SortedSet(range(1, 1001))

    def popSmallest(self) -> int:
        x = self.s[0]
        self.s.remove(x)
        return x

    def addBack(self, num: int) -> None:
        self.s.add(num)


# Your SmallestInfiniteSet object will be instantiated and called as such:
# obj = SmallestInfiniteSet()
# param_1 = obj.popSmallest()
# obj.addBack(num)
