Intersection of Two Arrays II
<p>Given two integer arrays <code>nums1</code> and <code>nums2</code>, return <em>an array of their intersection</em>. Each element in the result must appear as many times as it shows in both arrays and you may return the result in <strong>any order</strong>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> nums1 = [1,2,2,1], nums2 = [2,2]
<strong>Output:</strong> [2,2]
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> nums1 = [4,9,5], nums2 = [9,4,9,8,4]
<strong>Output:</strong> [4,9]
<strong>Explanation:</strong> [9,4] is also accepted.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= nums1.length, nums2.length &lt;= 1000</code></li>
	<li><code>0 &lt;= nums1[i], nums2[i] &lt;= 1000</code></li>
</ul>

<p>&nbsp;</p>
<p><strong>Follow up:</strong></p>

<ul>
	<li>What if the given array is already sorted? How would you optimize your algorithm?</li>
	<li>What if <code>nums1</code>&#39;s size is small compared to <code>nums2</code>&#39;s size? Which algorithm is better?</li>
	<li>What if elements of <code>nums2</code> are stored on disk, and the memory is limited such that you cannot load all elements into the memory at once?</li>
</ul>
Array; Hash Table; Two Pointers; Binary Search; Sorting
function intersect(nums1: number[], nums2: number[]): number[] {
    const cnt: Record<number, number> = {};
    for (const x of nums1) {
        cnt[x] = (cnt[x] || 0) + 1;
    }
    const ans: number[] = [];
    for (const x of nums2) {
        if (cnt[x]-- > 0) {
            ans.push(x);
        }
    }
    return ans;
}
