Count Submatrices with Top-Left Element and Sum Less Than k
<p>You are given a <strong>0-indexed</strong> integer matrix <code>grid</code> and an integer <code>k</code>.</p>

<p>Return <em>the <strong>number</strong> of <span data-keyword="submatrix">submatrices</span> that contain the top-left element of the</em> <code>grid</code>, <em>and have a sum less than or equal to </em><code>k</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/3000-3099/3070.Count%20Submatrices%20with%20Top-Left%20Element%20and%20Sum%20Less%20Than%20k/images/example1.png" style="padding: 10px; background: #fff; border-radius: .5rem;" />
<pre>
<strong>Input:</strong> grid = [[7,6,3],[6,6,1]], k = 18
<strong>Output:</strong> 4
<strong>Explanation:</strong> There are only 4 submatrices, shown in the image above, that contain the top-left element of grid, and have a sum less than or equal to 18.</pre>

<p><strong class="example">Example 2:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/3000-3099/3070.Count%20Submatrices%20with%20Top-Left%20Element%20and%20Sum%20Less%20Than%20k/images/example21.png" style="padding: 10px; background: #fff; border-radius: .5rem;" />
<pre>
<strong>Input:</strong> grid = [[7,2,9],[1,5,0],[2,6,6]], k = 20
<strong>Output:</strong> 6
<strong>Explanation:</strong> There are only 6 submatrices, shown in the image above, that contain the top-left element of grid, and have a sum less than or equal to 20.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>m == grid.length </code></li>
	<li><code>n == grid[i].length</code></li>
	<li><code>1 &lt;= n, m &lt;= 1000 </code></li>
	<li><code>0 &lt;= grid[i][j] &lt;= 1000</code></li>
	<li><code>1 &lt;= k &lt;= 10<sup>9</sup></code></li>
</ul>
Array; Matrix; Prefix Sum
class Solution {
public:
    int countSubmatrices(vector<vector<int>>& grid, int k) {
        int m = grid.size(), n = grid[0].size();
        int s[m + 1][n + 1];
        memset(s, 0, sizeof(s));
        int ans = 0;
        for (int i = 1; i <= m; ++i) {
            for (int j = 1; j <= n; ++j) {
                s[i][j] = s[i - 1][j] + s[i][j - 1] - s[i - 1][j - 1] + grid[i - 1][j - 1];
                if (s[i][j] <= k) {
                    ++ans;
                }
            }
        }
        return ans;
    }
};