Backspace String Compare
<p>Given two strings <code>s</code> and <code>t</code>, return <code>true</code> <em>if they are equal when both are typed into empty text editors</em>. <code>&#39;#&#39;</code> means a backspace character.</p>

<p>Note that after backspacing an empty text, the text will continue empty.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;ab#c&quot;, t = &quot;ad#c&quot;
<strong>Output:</strong> true
<strong>Explanation:</strong> Both s and t become &quot;ac&quot;.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;ab##&quot;, t = &quot;c#d#&quot;
<strong>Output:</strong> true
<strong>Explanation:</strong> Both s and t become &quot;&quot;.
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> s = &quot;a#c&quot;, t = &quot;b&quot;
<strong>Output:</strong> false
<strong>Explanation:</strong> s becomes &quot;c&quot; while t becomes &quot;b&quot;.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code><span>1 &lt;= s.length, t.length &lt;= 200</span></code></li>
	<li><span><code>s</code> and <code>t</code> only contain lowercase letters and <code>&#39;#&#39;</code> characters.</span></li>
</ul>

<p>&nbsp;</p>
<p><strong>Follow up:</strong> Can you solve it in <code>O(n)</code> time and <code>O(1)</code> space?</p>
Stack; Two Pointers; String; Simulation
func backspaceCompare(s string, t string) bool {
	i, j := len(s)-1, len(t)-1
	skip1, skip2 := 0, 0
	for ; i >= 0 || j >= 0; i, j = i-1, j-1 {
		for i >= 0 {
			if s[i] == '#' {
				skip1++
				i--
			} else if skip1 > 0 {
				skip1--
				i--
			} else {
				break
			}
		}
		for j >= 0 {
			if t[j] == '#' {
				skip2++
				j--
			} else if skip2 > 0 {
				skip2--
				j--
			} else {
				break
			}
		}
		if i >= 0 && j >= 0 {
			if s[i] != t[j] {
				return false
			}
		} else if i >= 0 || j >= 0 {
			return false
		}
	}
	return true
}