Convert to Base -2
<p>Given an integer <code>n</code>, return <em>a binary string representing its representation in base</em> <code>-2</code>.</p>

<p><strong>Note</strong> that the returned string should not have leading zeros unless the string is <code>&quot;0&quot;</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> n = 2
<strong>Output:</strong> &quot;110&quot;
<strong>Explantion:</strong> (-2)<sup>2</sup> + (-2)<sup>1</sup> = 2
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> n = 3
<strong>Output:</strong> &quot;111&quot;
<strong>Explantion:</strong> (-2)<sup>2</sup> + (-2)<sup>1</sup> + (-2)<sup>0</sup> = 3
</pre>

<p><strong class="example">Example 3:</strong></p>

<pre>
<strong>Input:</strong> n = 4
<strong>Output:</strong> &quot;100&quot;
<strong>Explantion:</strong> (-2)<sup>2</sup> = 4
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>0 &lt;= n &lt;= 10<sup>9</sup></code></li>
</ul>
Math
func baseNeg2(n int) string {
	if n == 0 {
		return "0"
	}
	ans := []byte{}
	k := 1
	for n != 0 {
		if n%2 != 0 {
			ans = append(ans, '1')
			n -= k
		} else {
			ans = append(ans, '0')
		}
		k *= -1
		n /= 2
	}
	for i, j := 0, len(ans)-1; i < j; i, j = i+1, j-1 {
		ans[i], ans[j] = ans[j], ans[i]
	}
	return string(ans)
}