Minimum Time Difference
Given a list of 24-hour clock time points in <strong>&quot;HH:MM&quot;</strong> format, return <em>the minimum <b>minutes</b> difference between any two time-points in the list</em>.

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<pre><strong>Input:</strong> timePoints = ["23:59","00:00"]
<strong>Output:</strong> 1
</pre><p><strong class="example">Example 2:</strong></p>
<pre><strong>Input:</strong> timePoints = ["00:00","23:59","00:00"]
<strong>Output:</strong> 0
</pre>
<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>2 &lt;= timePoints.length &lt;= 2 * 10<sup>4</sup></code></li>
	<li><code>timePoints[i]</code> is in the format <strong>&quot;HH:MM&quot;</strong>.</li>
</ul>
Array; Math; String; Sorting
class Solution {
public:
    int findMinDifference(vector<string>& timePoints) {
        if (timePoints.size() > 1440) {
            return 0;
        }
        int n = timePoints.size();
        vector<int> nums(n + 1);
        for (int i = 0; i < n; ++i) {
            int hours = stoi(timePoints[i].substr(0, 2));
            int minutes = stoi(timePoints[i].substr(3, 2));
            nums[i] = hours * 60 + minutes;
        }
        sort(nums.begin(), nums.begin() + n);
        nums[n] = nums[0] + 1440;
        int ans = INT_MAX;
        for (int i = 1; i <= n; ++i) {
            ans = min(ans, nums[i] - nums[i - 1]);
        }
        return ans;
    }
};