Rectangle Area II
<p>You are given a 2D array of axis-aligned <code>rectangles</code>. Each <code>rectangle[i] = [x<sub>i1</sub>, y<sub>i1</sub>, x<sub>i2</sub>, y<sub>i2</sub>]</code> denotes the <code>i<sup>th</sup></code> rectangle where <code>(x<sub>i1</sub>, y<sub>i1</sub>)</code> are the coordinates of the <strong>bottom-left corner</strong>, and <code>(x<sub>i2</sub>, y<sub>i2</sub>)</code> are the coordinates of the <strong>top-right corner</strong>.</p>

<p>Calculate the <strong>total area</strong> covered by all <code>rectangles</code> in the plane. Any area covered by two or more rectangles should only be counted <strong>once</strong>.</p>

<p>Return <em>the <strong>total area</strong></em>. Since the answer may be too large, return it <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>
<img alt="" src="https://fastly.jsdelivr.net/gh/doocs/leetcode@main/solution/0800-0899/0850.Rectangle%20Area%20II/images/rectangle_area_ii_pic.png" style="width: 600px; height: 450px;" />
<pre>
<strong>Input:</strong> rectangles = [[0,0,2,2],[1,0,2,3],[1,0,3,1]]
<strong>Output:</strong> 6
<strong>Explanation:</strong> A total area of 6 is covered by all three rectangles, as illustrated in the picture.
From (1,1) to (2,2), the green and red rectangles overlap.
From (1,0) to (2,3), all three rectangles overlap.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> rectangles = [[0,0,1000000000,1000000000]]
<strong>Output:</strong> 49
<strong>Explanation:</strong> The answer is 10<sup>18</sup> modulo (10<sup>9</sup> + 7), which is 49.
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= rectangles.length &lt;= 200</code></li>
	<li><code>rectanges[i].length == 4</code></li>
	<li><code>0 &lt;= x<sub>i1</sub>, y<sub>i1</sub>, x<sub>i2</sub>, y<sub>i2</sub> &lt;= 10<sup>9</sup></code></li>
	<li><code>x<sub>i1 &lt;= </sub>x<sub>i2</sub></code></li>
	<li><code>y<sub>i1 &lt;=</sub> y<sub>i2</sub></code></li>
	<li>All rectangles have non zero area.</li>
</ul>
Segment Tree; Array; Ordered Set; Line Sweep
class Node {
    int l, r, cnt, length;
}

class SegmentTree {
    private Node[] tr;
    private int[] nums;

    public SegmentTree(int[] nums) {
        this.nums = nums;
        int n = nums.length - 1;
        tr = new Node[n << 2];
        for (int i = 0; i < tr.length; ++i) {
            tr[i] = new Node();
        }
        build(1, 0, n - 1);
    }

    private void build(int u, int l, int r) {
        tr[u].l = l;
        tr[u].r = r;
        if (l != r) {
            int mid = (l + r) >> 1;
            build(u << 1, l, mid);
            build(u << 1 | 1, mid + 1, r);
        }
    }

    public void modify(int u, int l, int r, int k) {
        if (tr[u].l >= l && tr[u].r <= r) {
            tr[u].cnt += k;
        } else {
            int mid = (tr[u].l + tr[u].r) >> 1;
            if (l <= mid) {
                modify(u << 1, l, r, k);
            }
            if (r > mid) {
                modify(u << 1 | 1, l, r, k);
            }
        }
        pushup(u);
    }

    private void pushup(int u) {
        if (tr[u].cnt > 0) {
            tr[u].length = nums[tr[u].r + 1] - nums[tr[u].l];
        } else if (tr[u].l == tr[u].r) {
            tr[u].length = 0;
        } else {
            tr[u].length = tr[u << 1].length + tr[u << 1 | 1].length;
        }
    }

    public int query() {
        return tr[1].length;
    }
}

class Solution {
    private static final int MOD = (int) 1e9 + 7;

    public int rectangleArea(int[][] rectangles) {
        int n = rectangles.length;
        int[][] segs = new int[n << 1][4];
        int i = 0;
        TreeSet<Integer> ts = new TreeSet<>();
        for (var e : rectangles) {
            int x1 = e[0], y1 = e[1], x2 = e[2], y2 = e[3];
            segs[i++] = new int[] {x1, y1, y2, 1};
            segs[i++] = new int[] {x2, y1, y2, -1};
            ts.add(y1);
            ts.add(y2);
        }
        Arrays.sort(segs, (a, b) -> a[0] - b[0]);
        Map<Integer, Integer> m = new HashMap<>(ts.size());
        i = 0;
        int[] nums = new int[ts.size()];
        for (int v : ts) {
            m.put(v, i);
            nums[i++] = v;
        }

        SegmentTree tree = new SegmentTree(nums);
        long ans = 0;
        for (i = 0; i < segs.length; ++i) {
            var e = segs[i];
            int x = e[0], y1 = e[1], y2 = e[2], k = e[3];
            if (i > 0) {
                ans += (long) tree.query() * (x - segs[i - 1][0]);
            }
            tree.modify(1, m.get(y1), m.get(y2) - 1, k);
        }
        ans %= MOD;
        return (int) ans;
    }
}