Super Palindromes
<p>Let&#39;s say a positive integer is a <strong>super-palindrome</strong> if it is a palindrome, and it is also the square of a palindrome.</p>

<p>Given two positive integers <code>left</code> and <code>right</code> represented as strings, return <em>the number of <strong>super-palindromes</strong> integers in the inclusive range</em> <code>[left, right]</code>.</p>

<p>&nbsp;</p>
<p><strong class="example">Example 1:</strong></p>

<pre>
<strong>Input:</strong> left = &quot;4&quot;, right = &quot;1000&quot;
<strong>Output:</strong> 4
<strong>Explanation</strong>: 4, 9, 121, and 484 are superpalindromes.
Note that 676 is not a superpalindrome: 26 * 26 = 676, but 26 is not a palindrome.
</pre>

<p><strong class="example">Example 2:</strong></p>

<pre>
<strong>Input:</strong> left = &quot;1&quot;, right = &quot;2&quot;
<strong>Output:</strong> 1
</pre>

<p>&nbsp;</p>
<p><strong>Constraints:</strong></p>

<ul>
	<li><code>1 &lt;= left.length, right.length &lt;= 18</code></li>
	<li><code>left</code> and <code>right</code> consist of only digits.</li>
	<li><code>left</code> and <code>right</code> cannot have leading zeros.</li>
	<li><code>left</code> and <code>right</code> represent integers in the range <code>[1, 10<sup>18</sup> - 1]</code>.</li>
	<li><code>left</code> is less than or equal to <code>right</code>.</li>
</ul>
Math; String; Enumeration
const ps = Array(2e5).fill(0);

const init = (() => {
    for (let i = 1; i <= 1e5; ++i) {
        const s: string = i.toString();
        const t1: string = s.split('').reverse().join('');
        const t2: string = s.slice(0, -1).split('').reverse().join('');
        ps[2 * i - 2] = parseInt(s + t1, 10);
        ps[2 * i - 1] = parseInt(s + t2, 10);
    }
})();

function superpalindromesInRange(left: string, right: string): number {
    const l = BigInt(left);
    const r = BigInt(right);
    const isPalindrome = (x: bigint): boolean => {
        const s: string = x.toString();
        return s === s.split('').reverse().join('');
    };
    let ans = 0;
    for (const p of ps) {
        const x = BigInt(p) * BigInt(p);
        if (x >= l && x <= r && isPalindrome(x)) {
            ++ans;
        }
    }
    return ans;
}
