What is the space complexity of a Trie?
The space complexity of a Trie is O(n * m), where n is the number of words and m is the length of the longest word, because each character in every word needs to be stored in the Trie.
Thatâ€™s correct. Tries require space proportional to both the number of words and the length of the longest word due to the storage of characters in the nodes.
Can you explain how the space complexity of a Trie compares to that of a hash map when storing a large number of strings?