Why jQuery do this: jQuery.fn.init.prototype = jQuery.fn?
Why is there a second e or x in e.fn.e.init or x.fn.x.init (jQuery instance name, in chrome debugger)?
jQuery fn Property $.fn is not an object while( var row = fn() ); IE8 `window.fn !== fn` jQuery : Object has no method for $.fn Help understanding jQuery's jQuery.fn.init Why is init in fn (function fn(){ ... })() not working How does this line work: obj['e'+type+fn] = fn What is fn in this example? $.fn.<new_function> 'is not a function' jQuery What is fn.bind.apply(fn, arguments) doing? Why does the jQuery constructor map to jQuery.fn.init? Difference between fn() and fn.call() in JavaScript $.fn.fixTime not working jQuery: $().click(fn) vs. $().bind('click',fn); Calling function of $.fn.function What is going on with the javascript and the fn? Object as jQuery.fn prototype? Property '$.fn.toggleHeightAndOpacity' of object [object Object] is not a function if (fn) fn() or "fn && fn()" jQuery $.fn is not a function JQuery function fn() is not defined Difference between $(fn) and $(document).ready(fn) in jQuery? Jquery $.fn not working what does fn.apply(fn, []) do? jQuery $.fn. function not defined Why does jQuery.fn display [] in the console? What does "A.fn.A.init {}" mean? Why does jQuery use "new jQuery.fn.init()" for creating jQuery object but I can't?