Why does the jQuery constructor map to jQuery.fn.init?
Help understanding jQuery's jQuery.fn.init Why is init in fn
jQuery fn Property Constructor or init function for an object IE8 `window.fn !== fn` jQuery : Object has no method for $.fn (function fn(){ ... })() not working How does this line work: obj['e'+type+fn] = fn What is fn in this example? Javascript's object constructor's this.fn called without this possible? $.fn.<new_function> 'is not a function' jQuery Difference between fn() and fn.call() in JavaScript $.fn.fixTime not working Why is there a second e or x in e.fn.e.init or x.fn.x.init (jQuery instance name, in chrome debugger)? Why sometimes jQuery selector returns something like "a.fn.init"? jQuery: $().click(fn) vs. $().bind('click',fn); Why jQuery do this: jQuery.fn.init.prototype = jQuery.fn? understanding jquery source code - jquery.fn.init Property '$.fn.toggleHeightAndOpacity' of object [object Object] is not a function Javascript Classes with constructor init if (fn) fn() or "fn && fn()" jQuery $.fn is not a function JQuery function fn() is not defined Difference between $(fn) and $(document).ready(fn) in jQuery? Jquery $.fn not working what does fn.apply(fn, []) do? jQuery $.fn. function not defined Why does jQuery.fn display [] in the console? What does "A.fn.A.init {}" mean? jQuery constructor and init Why does jQuery use "new jQuery.fn.init()" for creating jQuery object but I can't?