I am trying to create a function in python that takes a Roman numeral as its argument and then returns the value as a numeric integer. Keep in mind it does not need to validate the form of the Roman numeral
system
I am trying to create a function in python that takes a Roman numeral as its argument and then returns the value as a numeric integer. Keep in mind it does not need to validate the form of the Roman numeral
user
Here is a function that converts a Roman numeral to an integer:

def solution(roman):
    nums = []
    ans = 0
    for char in roman:
        if char == 'M':
            nums.append(1000)
        elif char == 'D':
            nums.append(500)
        elif char == 'C':
            nums.append(100)
        elif char == 'L':
            nums.append(50)
        elif char == 'X':
            nums.append(10)
        elif char == 'V':
            nums.append(5)
        elif char == 'I':
            nums.append(1)
    for i, n in enumerate(nums[:-1]):
        if n >= nums[i + 1]:
            ans += n
        else:
            ans -= n
    return ans + nums[-1]

Here's the step-by-step breakdown of the code.
1.) First, the code loops through each character in the parameter "roman".
2.) If the character is a valid Roman numeral value, the code appends the corresponding value to "nums".
3.) The enumerate is used to loop over all the pairs of adjacent integers in the "nums" variable, except for the last one.
4.) For each pair of integers, the code compares them to determine whether to add or subtract variable "n" from the result. 
5.) If "n" is greater than or equal to "nums[i+1]" then "n" is added to the "ans" variable. Otherwise, "n" is subtracted.
6.) The last integer value is always added to "ans" regardless of the value because there are no more pairs of integers to compare it to.
assistant
<|system|>
</s>
<|user|>
I am trying to create a function in python that takes a Roman numeral as its argument and then returns the value as a numeric integer. Keep in mind it does not need to validate the form of the Roman numeral</s>
<|assistant|>
Here is a function that converts a Roman numeral to an integer:

def solution(roman):
    nums = []
    ans = 0
    for char in roman:
        if char == 'M':
            nums.append(1000)
        elif char == 'D':
            nums.append(500)
        elif char == 'C':
            nums.append(100)
        elif char == 'L':
            nums.append(50)
        elif char == 'X':
            nums.append(10)
        elif char == 'V':
            nums.append(5)
        elif char == 'I':
            nums.append(1)
    for i, n in enumerate(nums[:-1]):
        if n >= nums[i + 1]:
            ans += n
        else:
            ans -= n
    return ans + nums[-1]

Here's the step-by-step breakdown of the code.
1.) First, the code loops through each character in the parameter "roman".
2.) If the character is a valid Roman numeral value, the code appends the corresponding value to "nums".
3.) The enumerate is used to loop over all the pairs of adjacent integers in the "nums" variable, except for the last one.
4.) For each pair of integers, the code compares them to determine whether to add or subtract variable "n" from the result. 
5.) If "n" is greater than or equal to "nums[i+1]" then "n" is added to the "ans" variable. Otherwise, "n" is subtracted.
6.) The last integer value is always added to "ans" regardless of the value because there are no more pairs of integers to compare it to.</s>
