Write me a function in Python that accepts an integer argument and finds the difference between the sum of squares for all numbers in the interval 0 through the integer and the square of the sum of all integers in the same interval
system
Write me a function in Python that accepts an integer argument and finds the difference between the sum of squares for all numbers in the interval 0 through the integer and the square of the sum of all integers in the same interval
user
Here is a Python function that accepts an integer argument, computes the sum of all squares in the interval 0 to the input, computes the sum of all integers in the same interval, and then finds the difference between the sum of the squares and the squared interval sum.

def square_sums_difference(q):
    N = q
    sum_of_squares = sum(i**2 for i in range(1, N + 1))
    interval_sum = sum(i for i in range(1, N + 1))
    return str(sum_of_squares - interval_sum**2)
assistant
<|system|>
</s>
<|user|>
Write me a function in Python that accepts an integer argument and finds the difference between the sum of squares for all numbers in the interval 0 through the integer and the square of the sum of all integers in the same interval</s>
<|assistant|>
Here is a Python function that accepts an integer argument, computes the sum of all squares in the interval 0 to the input, computes the sum of all integers in the same interval, and then finds the difference between the sum of the squares and the squared interval sum.

def square_sums_difference(q):
    N = q
    sum_of_squares = sum(i**2 for i in range(1, N + 1))
    interval_sum = sum(i for i in range(1, N + 1))
    return str(sum_of_squares - interval_sum**2)</s>
