 f be n(z). Solve 2 = f*a - 8 for a.
5
Let u(w) be the first derivative of 4*w**2 - 28*w - 3. Let y be u(4). Solve y*i - 10 = 2 for i.
3
Let u = 1063 + -1038. Suppose 4*z - 3*s - 22 = 0, 0 = 4*z + 3*s - 0*s - 10. Solve r = -z*r + u for r.
5
Suppose -35*i + 23*i + 396 = 0. Solve -6*s + 3 = i for s.
-5
Suppose 34*v - 32*v - 10 = 0. Solve v = -3*x + 8 for x.
1
Suppose -6*x = -2*x. Suppose 2 = q + 4*a - 13, x = 5*a - 15. Solve 2*h + 1 = q for h.
1
Let s be ((-9)/2 + 6)/((-2)/72). Let r = 54 + s. Solve 5*u + r*u = -15 for u.
-3
Suppose 3*b - 2*b = 54. Suppose 0 = 5*s - 2*g - b, 3*g - 36 + 2 = -4*s. Solve -3*z = 2*z - s for z.
2
Let s(a) be the third derivative of -a**5/20 - 29*a**4/24 - 3*a**3 - 16*a**2. Let p be s(-9). Solve p = -3*m - m + 8 for m.
2
Suppose t = -2*t - 84. Let n = -28 - t. Solve n = 8*y - 3*y + 5 for y.
-1
Let d(y) = 3*y**2 - 12*y + 20. Let r be d(6). Let m be (-21)/r - 38/(-16). Solve s - 12 = -m*s for s.
4
Let c be (-6 + 0)*-1 + -2. Let z be -2*((-9)/4 - 3/12). Solve -c - 6 = z*o for o.
-2
Let h = -62 - -64. Solve -2*j + h = -j for j.
2
Suppose 3*h - 828 = -h. Let j be (-4)/16 + h/12. Let r be j/(-85) + 72/10. Solve -5*x = -18 - r for x.
5
Let u(p) = -p**2 + 8*p. Let t = -18 - -26. Let q be u(t). Let d = 7 + -5. Solve -d*g + g = q for g.
0
Let d(c) = -c**3 + 8*c**2 - 5*c - 8. Let a be d(7). Suppose 3 = a*o - 5*o. Suppose -o = 4*q - 19. Solve q*z + 16 + 0 = 0 for z.
-4
Suppose -2*b = 3*b. Suppose -d - 5*m - 16 = 0, 20 = 2*d - b*d - 3*m. Suppose d*i + i = 10. Solve -i*f + 3 = 9 for f.
-3
Let h be (1 - 3 - -9)*(-38)/(-133). Solve -3*g = -h*g + 1 for g.
-1
Let f = 79 - 75. Suppose -2*d - 2*w = -10, -f*d - 4*w + 2*w + 10 = 0. Solve g - 5*g + 12 = d for g.
3
Let l(j) = j**2 - 5 - j + 8*j + 4 + j. Let w be l(-9). Solve -4*t + 0 = w for t.
-2
Suppose 0 = 13*m - 773 - 98. Solve 71*y - m*y - 20 = 0 for y.
5
Let p(f) = 14*f**2 + 2*f. Let w be p(-1). Solve 0*r - w = 4*r for r.
-3
Let b(q) = -2*q**2 + 2*q + 7. Let u be b(0). Solve 6*r - u = -r for r.
1
Let l = 6 + -3. Let x(z) = z - 1 + 3 + 5 + l. Let s be x(-9). Solve -s = -2*g + g for g.
1
Let c = 346 + -339. Solve -d - c = -4 for d.
-3
Suppose -489 = 13*k - 788. Solve 24*o - k*o + 3 = 0 for o.
-3
Suppose 0 = -11*q + 46 + 20. Solve -12*i = -q*i + 12 for i.
-2
Suppose -35*j = -7*j - 28. Solve 75*m = 74*m - j for m.
-1
Suppose -6 = 2*q + 4*k - 4, -4*k - 12 = 0. Suppose -q*p = -9 - 31. Solve -5*c = p + 2 for c.
-2
Suppose 276 = v + 2*v. Solve -v = 4*t - 76 for t.
-4
Suppose -2*f + 4*d + 9 + 15 = 0, -f = 3*d - 17. Let s be 4/(-14) + 172/f. Solve 2*h + s = -h for h.
-4
Suppose 0 = -5*g + 1 + 29. Let v(m) = -m + 6. Let w be v(g). Let s be w - 0/(-1) - 0. Solve -u = -1 - s for u.
1
Let q be -2 + 19 + (34 - 40). Solve 9*w - 6 = q*w for w.
-3
Let k(b) be the third derivative of b**5/60 + b**4/3 + b**3/3 - 3*b**2. Let r be k(-8). Suppose 2*y - 5 - 1 = 0. Solve y*a = r*a for a.
0
Suppose 2*g - 31*g + 174 = 0. Let p be (-3)/15 + (-12)/(-10). Solve -w = g - p for w.
-5
Suppose 4*w + 15 = 35. Suppose -2*l - 4*j = -8, w*j = -l - l + 10. Solve -10 = 5*y - l for y.
-2
Suppose -13 = -2*g + 3. Let h(y) = y**3 - 8*y**2 + y - 3. Let w be h(g). Let x be (3/w)/((-11)/(-165)). Solve -4*q = -x*q + 15 for q.
3
Suppose -4*k = -n - 12, 0 = 4*n - 0*k + 2*k + 48. Let g be n/10*10*5/(-15). Solve -1 = -3*s + g*s for s.
-1
Let u be (6 - 4) + (-1 - 3). Let y = 6 + u. Let k = -2 + y. Solve -5 = k*r + 3*r for r.
-1
Let q be 1/(-4) + (-114)/(-8). Suppose 6 = -3*p + 4*y - q, y - 5 = -p. Solve 12 = 3*v - p for v.
4
Let p = 104 + -93. Let u be (-4)/(-14) + 18/(-14). Let d be u/(-6) - p/(-6). Solve d*f - 3*f + 4 = 0 for f.
4
Suppose 0 = -2*g + 5*g + 45. Let d = g - -19. Solve 12 = c - d*c for c.
-4
Let s be ((-75)/18)/(104/(-48) - -2). Solve 0 = 5*c - 15 + s for c.
-2
Suppose 5*v = -4*u - 4, 4*u - v - 13 = 7. Let f be (u/(-14))/(12/28)*-6. Solve -5*q + f - 24 = 0 for q.
-4
Suppose 8*v = -219 + 915. Let l = 92 - v. Solve 2*a = 3*a + l for a.
-5
Let b = -129 + 68. Let o = b - -76. Solve -4*s - s = -o for s.
3
Let d be 1/(-1) + 0 + -3 + 6. Solve -m = -d + 1 for m.
1
Suppose 5*w - 2*w + 81 = 3*s, -3*w + 29 = 2*s. Suppose 2 = -4*q + s. Suppose -q*p = -2 - 3, -z + 7 = 4*p. Solve 0 = -c + z*c + 10 for c.
-5
Suppose -2*u + 11 + 5 = 0. Suppose -9*w + 5*w + u = 0. Solve 15 = -w*t - 3*t for t.
-3
Suppose 36 = 4*r + 4*g, r + 0*r + 4*g = 24. Suppose -1 = 3*w + w - 3*b, w - 2*b = -r. Solve 3 = 5*h - w for h.
1
Let y(s) be the second derivative of s**5/20 + 17*s**4/12 - 19*s**3/6 - 7*s**2 - 2*s - 9. Let c be y(-18). Solve -3*d = -d + c for d.
-2
Let t(b) = 3*b**2 + 20*b - 2. Let v be t(-7). Suppose -3*o + 4*o - 5 = -5*p, 10 = v*p + 2*o. Solve p*r = r - 5 for r.
5
Let p(k) = k**3 - 4*k**2 - 2*k + 5. Let j be p(4). Let r be j + 15 - (2 + -2). Let y be -5*(-2)/(-3)*(-36)/30. Solve -r = -i + y*i for i.
-4
Let q = -1 - -1. Suppose -r + 3*a + 3 - 12 = q, -5*a = 4*r - 15. Solve r = -c + 5*c + 20 for c.
-5
Suppose -24*n + 23*n + 7 = 0. Let i be (12 + 0)*n/21. Solve 4*c + i + 0 = 0 for c.
-1
Let n be 24/(-48) + (-11)/(-2). Solve 5*a = -n*a + 5*a for a.
0
Let z = 12 - 8. Suppose z*s + 14 = 74. Solve -2*i + 5 = s for i.
-5
Let r(h) = h + 4. Let k be r(0). Let a = 6936 + -6928. Solve k*z + 12 = a*z for z.
3
Suppose 5*i + 5 = z, 3*z + 2*i = -3*i - 5. Suppose 10*l - 5*l = z. Let q be (0 + (-2)/2)*-1. Solve l = 2*r + q - 3 for r.
1
Let j be (-39)/26 + (-7)/(-2). Suppose -3*v = 16*v - 3*v. Solve j*y = -v*y - 4 for y.
-2
Let p = 887 - 885. Let d(k) = -k**3 + 7*k**2 - 7*k + 6. Let o be d(6). Solve o = -0*v - p*v + 2 for v.
1
Suppose 0 = 142*u - 52*u. Solve u = 6*t + t + 35 for t.
-5
Let m(a) = a**3 - 4*a**2 - 22. Let h be m(5). Solve -h*j + 0 = -3 for j.
1
Let f(v) = -2*v + 6. Let y be f(4). Let n = 709 + -713. Let q be (n/10)/(y/30). Solve -4*g + 2*g = q for g.
-3
Let v(r) = r**2 + 8*r + 2. Let l be v(-8). Solve -2*x + 0 = -l for x.
1
Suppose -69 = -28*a + 15. Solve 0 = -q + a*q + 8 for q.
-4
Let m(y) = y**3 + y**2 - 2*y + 4. Let h be m(0). Suppose 0 = h*c - 8 - 8. Solve -3*s = -c*s for s.
0
Let p be 0/(5 - 0 - 0). Solve 3*j - 3 = -p*j for j.
1
Suppose 21*b = 140 - 14. Solve 2*l + 16 = b*l for l.
4
Suppose 0*l + 4 = l - 5*s, 2*l + s = 8. Let g(f) = f**3 + 2*f**3 + 4*f**3 - 6*f - 6*f**3 - 5 + l*f**2. Let h be g(-5). Solve h = -6*c + c for c.
0
Suppose 0 = 4*m + h - 152, 4*h = 3*m + m - 132. Solve 5*t = -12 + m for t.
5
Let v = -384 - -396. Solve -8*l - 12 = v for l.
-3
Suppose -78 = -3*z + 3*s, 17*z - 3*s - 102 = 13*z. Solve 10*f - z = 2*f for f.
3
Suppose 19*a = 15*a + 2*q + 8, -15 = -3*a - 3*q. Solve a*t - 5*t = t for t.
0
Let q(v) = v**3 - 26*v**2 + 24*v + 25. Let r be q(25). Solve 17*c - 81 - 4 = r for c.
5
Let n = -587 + 593. Solve 0 = -n*o + 8*o - 8 for o.
4
Let x = 75 - 71. Let t(d) = d**2 + 7*d + 8. Let u be t(-7). Solve u = x*h - 12 for h.
5
Let t = 341 - 339. Solve 2*q - t = -6 for q.
-2
Let p = -760 + 772. Solve 6*c - p = -6 for c.
1
Let o be 2/11 - 5040/(-110). Solve o - 42 = -2*p for p.
-2
Let x be (-1 - 3/(-27))*-9. Solve x*p = -3*p + 55 for p.
5
Let i(j) = j**3 + 6*j**2 - j - 1. Let t be i(-6). Let c be ((-2)/10)/(11/(-33))*t. Let y = -5 - -8. Solve -4*z = -c*z - y for z.
3
Let n be (-261)/(-54) - 2/(-12). Solve -k + 0*k = n for k.
-5
Let d(x) = -4*x - 10. Let n be d(-3). Suppose -2*q + 13 = 3. Suppose 3*t + 2*t + 5*m - 25 = 0, -7 = -n*t - q*m. Solve 3*c = t*c for c.
0
Suppose 0 = -25*n + 53*n - 308. Solve -17*q = -6*q + n for q.
-1
Let r be -4*((-3)/(-4) - 2*1). Suppose -s = -7 + r. Solve s*m = -m for m.
0
Let p be (-45)/(-10) - 6/(-4). Let b(o) = o**3 + 8*o**2 + 7*o. Let g be b(-7). Suppose g = -2*j + 4. Solve -j*m = -p*m - 4 for m.
-1
Suppose -7 = -5*l + 5*z - 12, -2*l - 5*z = -33. Solve -2*q = 3*q + l*q for q.
0
Let s(l) = -l**3 - 50*l**2 + 4*l + 214. Let g be s(-50). Solve 0 = -5*q + g - 4 for q.
2
Suppose 2806*o - 2810*o = -656. Solve 5 = -169*l + o*l for l.
-1
Let u = 25 - 25. Suppose 0 = -k - u*k. Let d be k - (-1)/((-3)/(-15)). Solve -d*v = -3*v for v.
0
Let t(m) = 74*m + 152. Let v be t(-2). Solve 16 = -6*o + v for o.
-2
Let h = -55 - -48. Let g be -5 - h - (-4 - 0). Solve -3*f + g*f = -9 for f.
-3
Let y(g) = -2*g**3 - 43*g**2 - 24*g - 48. Suppose 4*u - 7*u - 39 = 2*c, 88 = -4*c + 4*u. Let r be y(c). Solve 4*x + r = x for x.
-5
Supp


116 B.R. 167 (1989)
In re Willis R. GERTH.
Bankruptcy No. 89-10062.
United States Bankruptcy Court, D. South Dakota.
August 2, 1989.
*168 David L. Nadolski, and Marsha K. Stacey, Sioux Falls, S.D., for FCBO.
Bryan R. Hedman, Brookings, S.D., for Debtor.
Kay Cee Hodson, Sioux Falls, S.D., for U.S. Trustee.
Todd D. Boyd, Clear Lake, S.D., for Creditor Douglas Gantvoort.
Thomas Lloyd, Pierre, S.D., for ASCS.
IRVIN N. HOYT, Chief Judge.
The Court has before it the Agricultural Stabilization and Conservation Service's (ASCS) motion to dismiss the Chapter 12 petition filed by Willis R. Gerth. Farm Credit Bank of Omaha (FCBO) joined in ASCS' motion. Gerth had earlier filed a Chapter 11 case, which has been confirmed and substantially consummated, but for which a final decree has not yet been entered. ASCS and FCBO claim that the open Chapter 11 case precludes Gerth's filing of a subsequent Chapter 12 petition.
Gerth filed a Chapter 11 petition in April of 1985. After an extension, Gerth filed his disclosure statement in November, 1985. FCBO's secured debt was restructured under Gerth's disclosure statement and plan. Gerth's plan, which provided for this Court's retention of jurisdiction until its completion or any modification thereof, was ultimately confirmed in October 1986. A final report and application for a final decree, required by B.R. 2015(A)(6) has not been filed to date.
Gerth defaulted on his Chapter 11 payments to FCBO. An agreement after mediation, as contemplated by SDCL Chapter 51-43, was never reached. FCBO thereafter sought foreclosure of its first mortgage lien. Gerth was timely served with FCBO's summons and complaint, but never answered the same, thus positioning FCBO to seek a default judgment. FCBO's attempt at seeking such judgment was stymied by Gerth's filing for protection under Chapter 12 of the Code in late April of 1989. A review of Gerth's Chapter 12 schedules reveals that he has listed many of the same secured and unsecured creditors as were previously being treated in his Chapter 11 case.
The question presented is whether Gerth's Chapter 12 petition should be dismissed because he is currently operating under a confirmed Chapter 11 plan. Briefs were submitted by Gerth, FCBO, creditor Douglas Gantvoort, and the United States Trustee. ASCS did not submit a brief, but instead relied upon the cases cited herein. The Court concludes that the dismissal of the Chapter 12 petition is warranted.
Gerth may not simultaneously be a debtor in two separate cases under two different chapters of the Bankruptcy Code. Freshman v. Atkins, 269 U.S. 121, 46 S.Ct. 41, 70 L.Ed. 193 (1925). A fortiori, such is the case where, as here, the debtor attempts to inconsistently treat the same debts under two different chapters of the Code. In re Hill, 84 B.R. 623 (Bkrtcy.E.D. Mo.1988); In re Smith, 85 B.R. 872 (Bkrtcy.W.D.Ok.1988); In re Fulks, 93 B.R. 274 (Bkrtcy.M.D.Fla.1988). Smith is particularly instructive. In Smith, the debtor had originally filed under Chapter 11. The court ordered the abandonment of certain property to the mortgagee. Thereafter, the debtor moved to convert the case to one under Chapter 7. The automatic stay was modified in order to transfer title to the property and debtor's Chapter 7 discharge was thereafter granted. A judicial sale of the subject property was held on April 12, 1988, with the required hearing to confirm the sale set for April 25. On April 22, debtor filed a second bankruptcy petition. Chief Judge Bohanon dismissed the second petition, correctly concluding that where one bankruptcy case remains pending, "there cannot be a subsequent one effecting [sic] the same debt." Smith at 873.
As in Smith, Gerth still has pending before this Court his Chapter 11 case. His *169 subsequent Chapter 12 petition attempts to affect the same debts as did his previous case. To allow Gerth to proceed under two separate bankruptcy chapters circumvents the "well established notions of orderly administration of justice, the court's inherent right to protect its own jurisdiction, and the court's duty to preclude, where possible, an abuse of the bankruptcy laws." In re Belmore, 68 B.R. 889, 891 (Bkrtcy.N.D.Pa. 1987). See also Prudential Insurance Co. v. Colony Square Co., 40 B.R. 603 (Bkrtcy. N.D.Ga.1984) and In re Stahl, Asano, Shegetomi & Associates, 7 B.R. 181 (Bkrtcy.D. Hi.1980).
Fulks, supra, also provides relevant insight into this inquiry. While Fulks deals with simultaneous cases under Chapters 7 and 13 of the Code, Judge Bayne's analysis is nevertheless persuasive:
If these debtors are permitted to maintain their second petition while a prior case is pending, an easy avenue for abuse of the bankruptcy system would be sanctioned. It is conceivable that debtors could undertake numerous simultaneous filings when events in one case take a turn to their disliking. There is simply no rule of law which would allow debtors to have two cases pending at the same time.
Fulks at 276 citing Smith, supra.
Gerth's reliance on In re Culbreth, 87 B.R. 225 (Bkrtcy.M.D.Ga.1988) is misplaced. The debtor in Culbreth sought protection under Chapter 11 in 1984, confirmed a plan which was substantially consummated, and which resulted in the entry of a final decree in 1987. Less than a year after entry of the final decree, the debtor sought protection under Chapter 12. Objections to confirmation of the debtor's Chapter 12 plan, which argued that such relief was barred by Section 727 and that the debtor was in essence attempting to modify his substantially consummated Chapter 11 plan, were overruled and the debtor's Chapter 12 case was allowed to proceed.
Culbreth is distinguishable from this case. The debtor in Culbreth had received a final decree from the Bankruptcy Court, rendering such case closed. Here, no such decree has been issued, consequently, this Court retains jurisdiction over Gerth's Chapter 11 plan. The case thus remains open and no subsequent case can be filed under another chapter of the Bankruptcy Code. See Hill and Smith, supra.
The U.S. Trustee, relying on In re Baker, 736 F.2d 481 (8th Cir.1984), claims that this Court may not dismiss one bankruptcy petition simply because the debtor has another case pending under a different Chapter of the Code. Baker (which dealt with a Chapter 13 petition filed after the debtor had received a discharge under Chapter 7) relying on § 727(a)(8), held that there is no prohibition to filing under Chapter 13 within six years after a discharge has been granted. This Court agrees with Smith's analysis of Baker, where Judge Bohanon states that Baker does not "stand for the proposition that a person may be a debtor in two cases pending at the same time." Smith at 873. This Court thus finds the holding in Baker to be inapposite. Accordingly, the motion to dismiss Gerth's Chapter 12 petition is granted.
This letter constitutes the Court's findings of fact and conclusions of law in this matter. This is a core proceeding under 28 U.S.C. § 157(b). The Court will enter an order dismissing the petition.


Q:

Build options changed, rebuilding all exit status 1 [Error] Exit with code=1 MXChip Azure IoT Dev Kit

I am just building my Device code of my Azure IoT Dev Kit MXChip and deploying to the device, but I am getting the error as below.
Build options changed, rebuilding all
GetStarted:9:21: error: utility.h: No such file or directory

compilation terminated.

exit status 1
[Error] Exit with code=1

It was just working fine and I am not sure what exactly the problem is, anyone else has faced this issue?

A:

It was really a strange behavior, a simple workaround just fixed the issue. I just run clicked F1 again, type and select IoT Workbench: Device, then select Device Upload. And it was working fine again.
If it doesn't work for you,

Disconnect MXChip
Reopen the Workspace in VSCode
Do Azure Provisioning
Do device upload

Once it is done, you will get the message as below.
Programming Finished
Verify Started
target halted due to breakpoint, current mode: Thread
xPSR: 0x61000000 pc: 0x2000002e msp: 0x200073fc
[Done] Uploaded the sketch: GetStarted.ino


#!/usr/bin/env python3

'''
pdd test script

Author: Arun Prakash Jana
Email : engineerarun@gmail.com
Home  : https://github.com/jarun/pdd

NOTES:

1. Before raising a PR,
   a. add relevant test cases
   b. run `python3 -m pytest test.py
'''
import pytest
import subprocess

test = [
    ('./pdd', '-d', '1983', 'jul', '3', '2014', '1', '15'),               # 1
    ('./pdd', '-d', '2014', '1', '15', '1983', 'jul', '03'),              # 2
    ('./pdd', '-t', '45:50', '6:17:33'),                                  # 3
    ('./pdd', '-t', '6:17:33', '45:50'),                                  # 4
    ('./pdd', '-t', '5:80:75', '6:17:33'),                                # 5
    ('./pdd', '-t', '6:17:33', '5:80:75'),                                # 6
    ('./pdd', '-d', '2000', 'FEB', '28', '3', '2', '1', '--add'),         # 7
    ('./pdd', '-d', '2000', 'FEB', '28', '1', '2', '3', '--add'),         # 8
    ('./pdd', '-t', '47:71:37', '1:2:63', '--add'),                       # 9
    ('./pdd', '-d', '2000', 'Mar', '01', '0', '0', '1', '--sub'),         # 10
    ('./pdd', '-d', '2000', 'Mar', '1', '1', '1', '1', '--sub'),          # 11
    ('./pdd', '-t', '00:00:00', '0:0:1', '--sub'),                        # 12
    ('./pdd', '-t', '25:61:61', '0:0:0', '--sub'),                        # 13
    ('./pdd', '-t', '0:0:0', '1:1:1', '--sub'),                           # 14
    ('./pdd', '-t', '0:0:0', '25:61:61', '--sub'),                        # 15
]

res = [
    b'30y 6m 12d\n11154d\n',                                              # 1
    b'30y 6m 12d\n11154d\n',                                              # 2
    b'05:31:43\n19903s\n',                                                # 3
    b'05:31:43\n19903s\n',                                                # 4
    b'00:03:42\n222s\n',                                                  # 5
    b'00:03:42\n222s\n',                                                  # 6
    b'Tue 2003 Apr 29\n',                                                 # 7
    b'Tue 2001 May 01\n',                                                 # 8
    b'2 day(s) later, 01:14:40\n177280s\n',                               # 9
    b'Tue 2000 Feb 29\n',                                                 # 10
    b'Sun 1999 Jan 31\n',                                                 # 11
    b'1 day(s) earlier, 23:59:59\n-1s\n',                                 # 12
    b'02:02:01\n93721s\n',                                                # 13
    b'1 day(s) earlier, 22:58:59\n-3661s\n',                              # 14
    b'2 day(s) earlier, 21:57:59\n-93721s\n',                             # 15
]

@pytest.mark.parametrize('item, res', zip(test, res))
def test_output(item, res):
    try:
        out = subprocess.check_output(item, stderr=subprocess.STDOUT)
    except subprocess.CalledProcessError as e:
        # print(e.output)
        assert e.output == res
    else:
        assert out == res


A Westport sewer leak Monday near West Parish Road and Wagon Wheel Lane spilled 5,000 gallons of raw sewage into Muddy Brook and required 1,500-gallon pump trucks to work 10 hours straight hauling effluent from one pump station to the next until new pipe was laid, Public Works Director Stephen Edwards said today.

All was quiet at the Center Street pump station at mid-afternoon today. (CLICK TO ENLARGE) Dave Matlow for WestportNow.com

The leak occurred near the Center Street pump station, which had to be shut down, the effluent trucked to the Green’s Farms pump station.

“In order to stop the leak, we had to shut the pump station off,” said Edwards, adding that had the effluent not been trucked to the Green’s Farms, raw sewage would have backed up into homes.

At peak flow, he said, 500 gallons per minute were coming into the Center Street station.


RANTT

How Misogynistic Male Reporters Shaped The Coverage Of The 2016 Election

November 30, 2017 7:27 pm

By Remy Anne for RANTT 2017 is the year of unmasking. From realizing which of your family members and friends are bigoted racists, to discovering how powerful men really think of women, there’s no more hiding who you truly are…

The Resistance Is Female — It’s Time Our Government Represented That

September 20, 2017 3:24 am

By Remy Anne for RANTT The 2016 Presidential Election generated a huge increase in political activism, the likes of which haven’t been seen in decades. People got involved, joined groups, jammed their senator’s phone lines, and took to the streets.…


Dear brides, hair, makeup and bouquet are key pieces in your bridal look, because these complement and put the finishing touches to the set to becoming the perfect bride.

Once you know the shape of the dress, cleavage, volumes, etc… we can start thinking about the hairstyle that you like to wear. For me, it’s very important that the bride has a natural hairstyle.

The hairstyle you choose must complement your face resulting in a natural effect. Find a straight or slightly wavy hairstyle that defines or highlights in a subtle way the lines of your face. It is clear that every face has specific needs, so let yourself be guided by them. We will find the right hairstyle for you. Try always to seek a natural balance between hair and face.

If you opted to wear your hair in an updo or bun, I recommend something simple, without being too tight or too stiff. A bride represents delicacy and grace, it is therefore important to maintain the harmony of the whole. If you prefer to wear it down or in a half updo, do it in a way that it integrates with the headdress and veil. Do it in a way that it doesn’t seem like you did not have enough time to do your hair and that the veil just fail on top of your head.

Bridal makeup should enhance the natural beauty of each of you.

In my opinion it should be natural, giving that feeling of freshness and radiance to the face without looking like you’re wearing a mask. The makeup artist works on the makeup based on the style of each of you and takes into account the wedding dress style and time of the event. The makeup artist will pamper your skin and enhance the gaze. A bride that gets married in the morning should wear a more natural makeup. On the other hand, a bride who gets married during the afternoon may opt for a more intense eye makeup.

The lips have to have a juicy effect and enhance the natural color of your lip. For example, If your natural color is dull, you should give it more intensity. If you like to wear a bolder lip color, go ahead. However, if you do you will have to lower the intensity of the eye makeup. It is better that the intensity focuses only in one point, either the eyes or the lips. The makeup has to be a mix between your personal taste and what the event and the overall scene requires.

Regarding the flowers, I recommend that you take into account the feelings they evoke. For example, if you want to convey the message of a pure bride, look for white flowers. However, if you want to be perceived as a strong and passionate bride, try with more intense flowers such as red or, if you feel that you are pure innocence, blue wildflowers are for you. Keep also in mind, the result of the color test when you look for your flower bouquet. So what about the shape? I recommend you take into account the shape of the dress to balance the effects. What I mean is that the shape and volume of the bouquet and the skirt of the dress must project a harmonious feeling.

As a last tip, I would say do not abuse of the jewelry. If you wear a headdress or tiara that is an important piece, please choose a simple and discreet jewelry.

I would go for long or small earrings depending on the set, the engagement ring and a bracelet at most. Regarding the bracelet, you should take into account whether you are wearing sleeves or not. I would stay away from necklaces or chokers.

The wedding season is here, and some of you brides, will be ready for the big day. However, others are just starting to organize the event and trying to manage all that a wedding details.

Therefore, as an image consultant I will be helping you with the most important decision, the choice of dress. Of course I’m going to make it as easy and comfortable for you, so you choose the perfect dress. As consultant I will be of great help in many other aspects of the big day, but for the moment we will be focusing on the dress. First things first, it is essential to have a clear idea of what kind of dress you would like and most importantly, if it is the one that best fits the needs of your body.

You need to know which color suits you best. We will figure this out with the color test. In previous post I have already explained what this test is. With the test we can see how neutral colors suit you which are the ones that are mostly used in these kind of dresses, such as white, beige, ecru and ivory. But, if you are a creative and unconventional bride, you can bet on any other color, you can even play with the color black, as it was done in other time. Once the color test is done, we can choose the perfect makeup, color bouquet, jewelry and all the color of wedding. By knowing which are your colors we can choose the color that enhances your beauty the most and chromatically harmonize the event around it..

Once we have the right color, we can go to the next step.

This is the morphologic study of your body that I also have explained in previous post. The morphological study will tell us exactly the lines that your dress must follow regarding the neckline, the waist, sleeves and the volume of the skirt. The morphological study will also define the proper placement of the veil, as well as the appropriate length for it.

Having clarified these two points, we are very close to achieving perfection in choosing your wedding dress. Now, we need to evaluate which fabric will better fit those lines that the morphologic study has revealed about your body appearance as the ones that are perfect for your wedding dress. The choice of fabric is as important as the previous two points; after all, we are talking about the material that will cover your body, enhancing your strengths and hiding those parts of your body that are less gracious.

I’ll give a couple of examples that will show you the importance and relevance of the overall balance of these three fundamental points for your wedding dress: Color, Shape and Material.

~ With broad shoulders, you have to avoid bustier necklines, straps and halter or American necklines. The most appropriate in this case would be covering the neckline a little higher than you usually would. For example, with a bateau or off-the-shoulder neckline, but going a little higher than usual and even better if it covers both shoulders a little. I recommend wearing long sleeves because its optical effect is more balanced. We can make a bolder back, narrow the waist and that should bring volume to the skirt –which should be flared or mermaid fit since this helps balance the optical effect creating an hourglass shape, the most balanced silhouette–.

~ If for example, you have a bulky chest, you cannot wear a body of brocade, lace or damask. These materials will always give you a sense of increased volume to your chest. Look for a smooth, fine and matte material like muslin, gazar or chiffon, which create an effect of softness, cleanliness and harmony.

My favorite materials for wedding dress skirts are brocade and damask. Both create skirts with body and volume. This reminds me of the times of the imperial court, with those gorgeous dresses in gold brocade with all the delicacies of that time. Brocade and damask with their drawings and reliefs, are perhaps less common than other materials. In the body I would opt for fine and subtle lace such as Venetian lace, which has different drawings and thicknesses in the drawing or Chantilly lace, which is a much finer and delicate lace and –of course– both natural and wild silk.

Regarding the veil, I would recommend that you choose silk tulle; it is smooth, simple and elegant. You do not need an ornate veil, because the focus will be on the wedding dress.

Silk tulle is soft, has fall and it is not rigid or bulky. It can also be a very suitable choice of material for the confection other parts of the design, not only for the veil. Another option would be the Spanish mantilla, which is a short piece of lace, like a short veil.

Regarding the shoes, obviously you must choose between comfort and design. Ideally, we would combine both. We have seen an increase of conventional brides that opt for a riskier option with shoes, with colors like red, bubblegum pink or golden.

Now, dear brides, after going to your image consultant, you are ready to go out and find your wedding dress or go to a designer or a store specializing in confection and sale of wedding dresses. But, if you really want to stand out and shine on your big day, let yourselves be guided and supervised by an expert consultant. This way everything will be perfect because we can accurately analyze your requirements, adapting them to your own taste and –of course– to the trends.

In the next post I will be giving you hairstyle, makeup and accessory ideas for the big day.

Grooms can find helpful tips on my post of male etiquette. The women invited to the event also have the post on female etiquette. I leave the direct link to each post here below.


Q:

Convert Visual Foxpro dbf to dBaseIII

EDIT: I found out that this error was being thrown due to the new data file being in Visual Foxpor dbf form, while my master file is dBaseIII. Any suggestions on how to programmatically change VFP to dBaseIII?

I am opening two .dbf files. One is a master file and one is a file with new data. I wish to insert the new data into the master file.
I am connecting to the directory that holds the files like so:
 Connection connection = null;
                    String dbString = "jdbc:odbc:Driver={Microsoft dBASE Driver (*.dbf)};DBQ=" + dealerSNS + "\\";

                    try
                    {
                        System.out.println("Opening Database Directory " + dealerSNS );
                        Class.forName("sun.jdbc.odbc.JdbcOdbcDriver");
                        connection = DriverManager.getConnection(dbString, "", "");
                        System.out.println("Connection established!");
                    }
                    catch (ClassNotFoundException cnfEx)
                    {
                        System.out.println("* Unable to load driver! *");
                        System.exit(1);
                    }
                    catch (SQLException sqlEx)
                    {
                        System.out.println(dbString);
                        System.out.println("* Cannot connect to database! * SQL = " + sqlEx);
                        System.exit(1);
                    }

Then I call my prepared statement:
 try
        {
        String update = "INSERT INTO fullSNS SELECT * FROM newSNS";
         PreparedStatement ps = connection.prepareStatement(update);
               ps.executeUpdate();
                  System.out.println("query: " + ps+ " worked!");
                           }
                           catch (SQLException se)
                           {
                                se.printStackTrace();

                           }

Both .dbf's have the exact same fields and are in the same directory, so I'm not sure what I'm doing wrong that it won't link them up.
Any suggestions/ideas?
My stacktrace looks like this:
java.sql.SQLException: [Microsoft][ODBC dBase Driver] External table is not in the expected format.
at sun.jdbc.odbc.JdbcOdbc.createSQLException(JdbcOdbc.java:6964)
at sun.jdbc.odbc.JdbcOdbc.standardError(JdbcOdbc.java:7121)
at sun.jdbc.odbc.JdbcOdbc.SQLExecute(JdbcOdbc.java:3156)
at sun.jdbc.odbc.JdbcOdbcPreparedStatement.execute(JdbcOdbcPreparedStatement.java:215)
at sun.jdbc.odbc.JdbcOdbcPreparedStatement.executeUpdate(JdbcOdbcPreparedStatement.java:137)
at ads.SmooshNMoveFiles.checkNSmoosh(SmooshNMoveFiles.java:116)
at ads.ActiveTimer.reportToWork(ActiveTimer.java:82)
at ads.ActiveTimer.run(ActiveTimer.java:28)
at java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:471)
at java.util.concurrent.FutureTask.runAndReset(FutureTask.java:304)
at java.util.concurrent.ScheduledThreadPoolExecutor$ScheduledFutureTask.access$301(ScheduledThreadPoolExecutor.java:178)
at java.util.concurrent.ScheduledThreadPoolExecutor$ScheduledFutureTask.run(ScheduledThreadPoolExecutor.java:293)
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1145)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:615)
at java.lang.Thread.run(Thread.java:724)

A:

It depends on how "dBaseIII" oriented the table really is.  Some of the earlier versions going way back have different file header information and that may be the issue.  In that case, you might need to do a one-time process of opening and copying the VFP version table to a dBaseIII format, then move that into the production path for your connection.
if you use the Microsoft Visual Foxpro OleDb Provider, you can connect to the path where the table is, and execute a script something like
USE YourTable
COPY to NewVersion TYPE FOXPLUS

Disadvantage of older dBASE file formats is it does not recognize the corresponding index files without being explicitly opened and won't optimize queries... but again that is based on very old dBASE file formats.
Here's one showing a sample SQL Command for execution


Chapter VI. Flour And Sugar Sacks

Description

Chapter VI. Flour And Sugar Sacks

Flour sacks may be bleached by boiling in soapy water or by using commercial bleaching fluids. When dyed or decorated with crayon they make attractive and useful articles, especially for the home. Pillows may be stuffed with feathers, cotton, cat tail down, kapok or excelsior. Pot holders may be padded with pieces from old blankets, turkish towels or outing flannel. Bean bags may be filled with beans, corn or seeds of any kind.

Use ordinary dye for cotton material. Dissolve some of the dye in a little cold water, boil and add to it enough warm water to make desired color strength. Use cloth in natural or light colors. Always try a scrap of the material before dipping into dye so as to be sure of the color that will result. Colors are always more brilliant when wet.

Fold the cloth any way desired and wind string firmly around places where design is to occur. Tie with one knot as the water holds string in place.

Pillow made from a flour sack, showing steps in the process of tie-dyeing.

The cloth should then be wet in water, wrung out and dipped in the dye. The places that are covered with string remain the original color. More strings may be wound on to protect the new color and the material dipped in another color. The first dipping should be in the lightest dye and proceed in succeeding dips to darker colors. Be sure to dip a scrap of material in each bath to know how the next will come out.

The process of tying and dyeing may be repeated several times to give the desired number of colors. Small spots may be tied over toothpicks, matches, seeds, pebbles, buttons or other objects or the material may be gathered with needle and thread instead of tying. Desired patterns may be marked in chalk before tying. If colors closely related are used on one piece the colors will be clearer and brighter, for example: yellow, green and blue or yellow, orange and red. Opposite colors will make muddy colors when finished.

When all dyeing is done the strings are removed and the piece is waved in the air to dry. Hanging in one place may cause undesired streaks. If the piece is boiled at each dipping it can be washed when soiled by use. Pieces from old silk garments may

Tie-dyed wall hanging be dyed in the same manner. Suitable for middle and upper grades.

Embroidered Pillows, Pot Holder, Bean Bags And Aprons

With white chalk make a design on wrapping paper, using only lines. When design is finished copy to cloth which may be dyed if desired. Using chain stitch, embroider with ordinary string which may also be dyed. The material may be marked off in checks with a lead pencil and a cross stitch design worked with string. Scraps of checked gingham may be used for cross stitch work. Pieces from old duck or denim pants make excellent bean bags. Suitable for middle and upper grades.

Make a design on wrapping paper using white chalk. Try crayon on this to get the desired color scheme. Use all-over pattern or other design rather than a realistic picture. Copy the design to flour sack with pencil. Color in parts with crayon rubbing well into the cloth. When finished place the cloth between two pieces of paper and press with a hot iron. If carefully washed when soiled, these articles will retain the color for a long time. Suitable for all grades.

A book jacket made of crayon decorated flour sacking. How to make a doll from flour sacks.

A bean bag chain stitched with string and a cross stitched pot holder. A pillow decorated with crayon. All made from flour sacks.

Dolls

Cut a pattern from newspaper for the head, body, arms and legs. Lay each pattern on flour sack and cut the desired number of pieces. Sew up each part and stuff separately with rags or cotton. Embroider features on face with thread or color with crayon before stuffing. Sew parts to the body. Sew on hair of yarn raveled from an old sweater.

Sew pieces of black or colored cloth on for shoes. Dress the doll using dyed flour sacks or cloth scraps. Lower grade children can make a simpler doll, all in one piece as shown on page 36 make seam inside however, rather than blanket stitching on outside as shown. Suitable for middle and upper grades.


Beyond antibiotic selection: concordance with the IDSA guidelines for uncomplicated urinary tract infections.
The purpose of this report was to evaluate concordance with the most recent guidelines for the treatment of uncomplicated UTI based on antibiotic selection, dosage, frequency, and duration. A historical review of patients' medical records at a university-based internal medicine clinic was conducted. When aggregated across antibiotic type, frequency, and duration, overall concordance was 33.96 %. Prescribing concordance for uncomplicated UTI in the local region is suboptimal.


Lawyer drops charges agains Head, the broadcaster’s south-east Asia reporter, but another Briton still faces prosecution

This article is more than 3 years old

This article is more than 3 years old

A Thai lawyer has dropped his criminal defamation suit against a BBC correspondent who investigated foreigners being scammed of their retirement homes in the country, the broadcaster has said.

Jonathan Head, the BBC’s south-east Asia correspondent, faced up to five years in jail after his report exposed how two foreign retirees had Phuket properties stolen from them by a network of criminals and corrupt officials.

Rights groups have said the case highlights how Thailand’s broad defamation and computer crime laws scupper investigative journalism and make it difficult to uncover wrongdoing in a country where corruption is endemic.

The lawyer who brought the suit – Pratuan Thanarak – decided to drop the charges against Head on the first day of the trial on Wednesday.

“The plaintiff has withdrawn his case against BBC journalist Jonathan Head, but as the trial of his co-defendant is continuing we cannot comment further at present,” the BBC said in a short statement.

Foreigners cannot own land in Thailand but they often get around it by putting assets in the name of Thais, or by setting up majority Thai-owned shell companies.

The 2015 BBC report detailed how a network of Phuket criminals, aided by corrupt officials, stole properties from foreigners by forging land title transfers.

One of the victims who featured in the report, British national Ian Rance, is a joint defendant in the prosecution. He still faces a single defamation charge and up to two years in jail if convicted.

Rance said he lost $1.2m worth of properties after his then wife and a gang of money-lenders forged property paperwork.

According to the report, Pratuan admitted on tape to certifying Rance’s signature without him being present, a move which helped the wife transfer his properties out of his name.

She was later convicted and jailed for the scam, but Rance has been hit by a slew of legal cases since going public, a common outcome faced by whistleblowers in Thailand which markets itself as an ideal retirement destination for wealthy foreigners.

The criminal complaint filed by Pratuan, which AFP has seen, alleges Rance “defamed” him by talking to the BBC sometime in September 2015 but there are no details of what was said or how it was defamatory.

AFP understands the BBC will continue to fund Rance’s defamation defence.

Pratuan and Rance both declined to comment when contacted by AFP on Thursday, citing ongoing proceedings.

Unlike most countries where defamation is a civil crime, in Thailand it is a criminal offence.

Private citizens can also launch their own prosecutions and they are not forced to pay costs if they lose.

Similar cases have been brought in recent years.

Local news site Phuketwan closed down in 2015 after running out of money in its successful bid to defeat a suit brought by Thailand’s navy.

Andrew Drummond, a British crime reporter, left the country the same year because of multiple cases brought by those he exposed, as did British labour rights activist Andy Hall in 2016.


Cirque du Freak: The Vampire's Assistant

Cirque du Freak: The Vampire's Assistant is a 2009 American dark fantasy film adaptation of the Vampire Blood trilogy of the book series The Saga of Darren Shan by author Darren Shan. The film received mixed reviews and was a commercial failure.

Plot
16-year-old Darren Shan and his best friend Steve Leonard visit the Cirque du Freak freak show. During the performance, Steve recognizes one of the troupe's members, Larten Crepsley, as a vampire, prompting him to try to find Crepsley after the show. Simultaneously, Darren, fascinated by Crepsley's spider, Madam Octa, impulsively steals her. Before he can leave, he is forced to hide as Crepsley returns to his room. Steve arrives, begging to be made into a vampire, but Crepsley refuses after tasting Steve's blood, which he says "tastes of evil". When Crepsley realizes that Madam Octa has been stolen, Darren flees from the theater with Crepsley hot on his trail. He gets away only when the mysterious Mr. Tiny arrives in his limousine, accompanied by the mad Vampeneze Murlough. The latter is unimpressed with Darren, dismissing him as a "bag of blood", but Tiny is greatly impressed, and promises to "be in touch" after dropping Darren off at home.

The next day, while at school Steve discovers Darren heard the conversation between Steve and Crepsley, forcing Darren to admit he overheard what Steve said to Crepsley. Steve makes Darren let him have a closer look at Madam Octa but the bell rings making Steve drop the cage allowing the spider to escape. After a brief struggle in the crowded hallway Madam Octa bites Steve and escapes, leaving Steve to slowly succumb to her deadly venom in the hospital. Becoming desperate, Darren returns to the theater and begs Crepsley for help. Initially annoyed and contemptuous, Crepsley agrees only if Darren becomes a half-vampire and Crepsley's personal assistant. Darren agrees, only to flee as soon as Crepsley administers an antidote to Steve. After nearly attacking his sister out of bloodlust soon after, however, Darren reluctantly agrees to leave with Crepsley, who arranges it so everyone believes Darren has killed himself.

After being buried, Darren is dug up by Crepsley, only for the both of them to be ambushed by Murlough. Crepsley fights him off and the two return to Cirque du Freak where Darren meets the snake boy, Evra Von, and Rebecca, the monkey girl. Meanwhile, Steve, contemplating suicide after losing his best friend, is stopped by Tiny who offers him a chance to become a Vampaneze, telling him that Darren has already achieved his dream of being a vampire, and wasn't the loyal friend Steve believed. Steve is turned into a half-Vampeneze, and after learning that Darren has been refusing to feed, Tiny has his family kidnapped, leaving a flyer for the Cirque du Freak at Darren's former home.

Darren arrives at the theater, where Murlough and Steve are waiting for him. They fight, but Darren is weak from not feeding. Crepsley arrives to fight Murlough. Rebecca frees herself, while Tiny watches from the balcony. Rebecca offers Darren some of her blood. He eventually agrees and fights with Steve using his new powers. Crepsley stabs Murlough and with his dying words Murlough declares that the truce between the two clans is broken. Steve and Darren continue to fight, but Tiny stops them and turns Murlough into a Little Person. Darren asks Steve to stay, but Steve refuses, saying "I have my destiny and you have yours." Steve then leaves with Tiny.

Darren's family are hypnotized to have forgotten what happened to them. Left by themselves, Rebecca and Darren then share a long heartfelt kiss before being interrupted by Crepsley. Crepsley gives Darren his own coffin, and Darren accepts his new life as a member of the Cirque du Freak.

Cast
Main article: (List of characters from The Saga of Darren Shan)

 Chris Massoglia as Darren Shan
 John C. Reilly as Larten Crepsley
 Josh Hutcherson as Steve "Leopard" Leonard
 Ray Stevenson as Murlough
 Salma Hayek as Madame Truska
 Patrick Fugit as Evra Von
 Jessica Carlson as Rebecca (Monkey Girl)
 Michael Cerveris as Desmond Tiny (Mr. Destiny)
 Willem Dafoe as Gavner Purl
 Ken Watanabe as Hibernius Tall
 Jane Krakowski as Corma Limbs
 Kristen Schaal as Gertha Teeth
 Orlando Jones as Alexander Ribs
 Frankie Faison as Rhamus Twobellies
 Morgan Saylor as Annie Shan
 Don McManus as Dermot Shan
 Colleen Camp as Angela Shan
 Patrick Breen as Mr Kersey
 Jonathan Nosan as Hans Hands
 Tom Woodruff, Jr. as The Wolfman
 Blake Nelson Boyd as Mr. Afraid of the Ground Man

Production
Cirque du Freak: The Vampire's Assistant was shot between February 19-June 1, 2008 in New Orleans, and the villages of Folsom, Louisiana and Baton Rouge, Louisiana. Some of the characters required a great deal of prosthetics and makeup led by Steve Koch, Brian Sipe, and Mark Garbarino. Prosthetics did not quite add the height needed on certain shots for the character of Mr. Tall, played by Academy Award-nominated Ken Watanabe. Although Watanabe is six feet tall, a body double was cast for certain shots. Trevon Flores, a local basketball player who stands 6'10" tall and weighs 210 pounds, was used for certain shots to show the abnormal height of Mr. Tall. Additionally, Watanabe utilized dialogue coaches Kathleen S. Dunn and Francie Brown in pre-production and production to further enhance his performance as the circus barker. The filmmakers took advantage of computer-generated imagery to portray other fantasy elements.

John Marshall High School in Los Angeles was used to film some parts of the movie.Sophie B. Wright Charter School in New Orleans was also used to shoot scenes from the film.

The film began principal photography on February 8, 2008 in New Orleans and ended on June 3, 2008. The film was distributed by Universal Studios. A portion of The Vampire's Assistant was filmed on a set constructed within New Orleans City Park, approximately 1,000 feet off of the side of the road, along Harrison Avenue. In one of the manga additions of the saga, the director says that the character of Gavner Purl was a hint of the sequel he wanted to make.

Music
The score to The Vampire's Assistant was composed by Stephen Trask, marking his third feature film with director Paul Weitz. He recorded his score with an 86-piece ensemble of the Hollywood Studio Symphony at the Newman Scoring Stage at 20th Century Fox. The movie also features the songs "Something Is Not Right with Me" by Cold War Kids, "Chelsea Dagger" by The Fratellis, and "Red Right Hand" by Nick Cave. The trailer features the songs Asleep From Day by The Chemical Brothers, Bliss by Syntax, and Superhero by Immediate Music.

Release
The film was originally set for release on January 15, 2010, but was moved ahead to October 23, 2009.

Critical reception
Review aggregation website Rotten Tomatoes assigns the film a rating of 38% based on 139 critics with an average rating of 4.87/10. The site's critical consensus reads "This overstuffed, scattershot vampire flick suffers from poor characterization and an unwieldy mix of scares and chuckles." On Metacritic, the film has a score of 43 out of 100, based on 25 reviews, indicating "mixed or average reviews".

Box office
The film opened in 2,754 theaters in the United States and made over $14 million, reaching #7 in the charts. In other countries, it made more than $25 million, giving it a worldwide box office total of more than $39 million. On DVD, sales in the United States made more than $5.5 million. Worldwide its chart placings included getting to #1 in Ukraine, #2 in Hungary, #2 in Russia, #2 in the United Arab Emirates, #3 in Mexico, #3 in Portugal, #4 in Egypt, #4 in Venezuela, #5 in Belgium, #5 in Peru, #5 in Singapore, #5 in the United Kingdom, #6 in Lebanon, #6 in the Philippines, #7 in Bulgaria, #7 in Japan, #8 in Chile, #8 in Colombia, #8 in the Netherlands, #9 in Austria, #9 in Romania, #11 in Germany, #11 in Malaysia, #11 in New Zealand.

Home media
The film debuted on DVD and Blu-ray Disc in Canada, the United Kingdom and United States at the end of February 2010. In Canada, at the end of its first week on sale and rent, it was #1 on the Rogers DVD bestselling chart and #2 on the Blockbuster Canada bestselling chart, and #6 on the rental charts of both. In the United States it was #2 on the Rentrak bestseller chart, and #6 on the Blockbuster, Home Media and IMDb rental charts. In the United Kingdom it reached #5 on the MyMovies bestsellers chart, and #6 on the Yahoo chart.

Cancelled sequels
In a Reddit AMA in March 2015, Darren Shan stated that three sequels to Cirque du Freak: The Vampire's Assistant had been in active development by Universal prior to the film's underperformance, as well as expressing interest in a potential future reboot of the series.

See also
 Vampire films

References

External links

Category:2009 films
Category:American films
Category:English-language films
Category:American fantasy adventure films
Category:2000s children's fantasy films
Category:Dark fantasy films
Category:Circus films
Category:Films about sideshow performers
Category:Films based on fantasy novels
Category:Films based on Irish novels
Category:Films directed by Paul Weitz
Category:Films produced by Lauren Shuler Donner
Category:Films with screenplays by Brian Helgeland
Category:Films shot in New Orleans
Category:Relativity Media films
Category:Universal Pictures films
Category:Films with screenplays by Paul Weitz
Category:Vampires in film
Category:Films scored by Stephen Trask
Category:2000s fantasy adventure films

ja:ダレン・シャン (小説)#映画版


 = 20*d - 25*d - 16, d = 2*j for j.
2
Solve -f + 4*j = -17, -2*j + 22 = 2*f - 23 + 51 for f.
1
Solve 47132 = -2*f + 2*v + 47118, -f - 17 = 4*v for f.
-9
Solve 22 = -4*w - 15*y + 17*y, -5*y + 60 = 76*w - 87*w for w.
-5
Solve -522 = 44*p - 3*z, 0 = -2*p - 1192*z + 1188*z - 32 for p.
-12
Solve 4*x + 5*x - 36 = 0, 4*v + 3*x - 155 = -41 + 74 for v.
44
Solve -t = 16*b - 11*b - 100, 0 = -4*t - 5*b + 520 - 180 for t.
80
Solve -2*y = -3*u + 105, 0 = 3*u + 17874*y - 17871*y - 120 for u.
37
Solve 4*j + 12 = 4*r, -2*j + 7*j - 8*j + 37 = 20*r for j.
-1
Solve -2553*l + 2555*l + 218 = -5*d, -4*d = -4*l + 152 for l.
-4
Solve 5*d - o + 2999 = 3052, 0 = -4*d - 4*o + 28 for d.
10
Solve 2*t = -2*u - 2*u - 44, 164 = 3*u - 4*t + 32 for u.
4
Solve -13*p - 196 + 108 = -5*z - 141, 3*z - z + 4*p = -12 for z.
-8
Solve -2*l - 2 = 5*w - 14, 214 = -318*l + 2*w + 2122 for l.
6
Solve -5*m = v + 16, 2*m - 122 = 15*m - 36*v + 74 for m.
-4
Solve 105*u - 107*u = -4*i - 61 + 49, 0 = -5*i - 3*u - 15 for i.
-3
Solve 0 = b + 56*u - 122, 2*b - 411*u - 26 = -414*u for b.
10
Solve 0 = -11*c + 13*c + 2, 94*c + 40*c + 129 = -f for f.
5
Solve -7*i + 2*k - 66 = 0, -314802*i + 314804*i = -3*k - 26 for i.
-10
Solve 17*b = 17, -4541*v + 4*b = -4536*v - 1 for v.
1
Solve 64 = -4*k + 4*m, -5986*m + 66 = -5980*m for k.
-5
Solve 4*p + 480 = 25*z + 460, -3*p - 15 = 8*z for p.
-5
Solve -148*j - 15 = -151*j - 4*t, 7*j = 2*t + 1 for j.
1
Solve 3*y - 9 = -d, -5*y - 97*d + 98*d - 15 = -3*y - 1 for y.
-1
Solve -13*a + 9*a - 4*r = 18*a + 188, -5*a - 4*r = -199 + 251 for a.
-8
Solve 2*y + 6 + 1 = 2*v + 3*v + 3, -36744*y + 36740*y + 12 = 0 for v.
2
Solve b - 2 = 1, -1865*r + 1858*r + 108 = 29*b for r.
3
Solve 6949*d - 6945*d = 12*p + 112, d + 17 = -2*p for p.
-9
Solve 13*l = a + 298, -111*l = -4*a - 110*l - 19 for a.
1
Solve -4*m = -2*l - 2, -10*l + 28588 = -5*m + 28628 for l.
-5
Solve -b + 4*n = -135 + 83, 3*b + 12*n - 26 = 14*n for b.
0
Solve -26 = -5*j - 19*x - 170, 23 + 5 - 6 = -18*j + 2*x - 74 for j.
-6
Solve -6*x + 491*m - 494*m - 33 = -2*x + 1, 13*m = 4*x - 62 for x.
-4
Solve -35 = -2*y - f, 106*f + 113*f - 333*f = -111*f - 9 for y.
16
Solve -2*l + 4*g + 32 = 0, 24*l - 15 = 28*l + 5*g + 38 for l.
-2
Solve 2*l + 380 - 432 = -20*g, -4*l + 22 = -g for l.
6
Solve 19*m = 4*b + 6*m - 66, 3*m + 6 = 4*b - 0 for b.
-3
Solve 0 = -58*q - r + 29 - 310, 0 = -3*q - 23*r + 20*r + 12 for q.
-5
Solve 15502*b - 15490*b = -p - 79, 0 = 4*p - 4*b - 48 for p.
5
Solve k + 16*u = 22*u + 113 - 240, -4*k + 5*u = 109 for k.
-1
Solve -q - 29 - 1 = 5*u, -2*u - 1432 + 1422 = 0 for q.
-5
Solve 158 = -3758*a + 3760*a + 2*k, 44*k - 3380 = 4*a for a.
2
Solve 95528*s + y = 95524*s + 28 - 90, 5*s + 79 = -2*y for s.
-15
Solve -5*h + 0 = i - 10, 3*i - 1001 = -13*h - 979 for i.
-10
Solve 3*g - 2*v + 5*v = -2112562 + 2112451, g + 0*g + 3*v = -111 for g.
0
Solve 1539*n = 5*j - 3*j + 1533*n - 78, 2*n = 3*j - 82 for j.
24
Solve 133*b - 5*r + 522 = 0, -5*b + 485*r - 12 = -0*b + 490*r + 18 for b.
-4
Solve 5*j = -70, -13077 = -5*b + 4891*j - 3958*j for b.
3
Solve 3 = 4*k - 17*a, 19*k - 23*k - 2*a - 23 = -9*k for k.
5
Solve -13*x - 4*a + 13 = 0, 24*x + 8*x + 17*x - 5*a = 46*x + 80 for x.
5
Solve -2*k + 26 = -5*x, -4*x - 20*x + 23*x = 4*k - 30 for k.
8
Solve -4*w - 7*d = 147, 9*w + 63 = 15*w - 929*d + 926*d for w.
0
Solve 119 = 2*m + 3*j, -32*m - 20*j - 19*j + 42*j + 17 = 0 for m.
4
Solve -4*a + 1305299 = -5*l + 1305306, 13*l - 2*a + 7 = 0 for l.
-1
Solve 11*m - 4*m - 2*z + 4 = 2*m, 2*z + 36 = -21*m + 4*z for m.
-2
Solve 119*a - d + 71 = 56*a, 365 = -4*a + 3*d + 337 for a.
-1
Solve -24 = -u + 2*c, -5*u + 137 = -4*c + c + 38 for u.
18
Solve 4*j - 48 = -2*l, 111*j - 30 = 114*j - 19*l + 15*l for j.
6
Solve -2*k - 14 = -4*c, 46*k = 85*k + 4*c + 109 for k.
-3
Solve -h - 12 = 26*c - 25*c + 3, -c - 48 = -3*h - 73 for h.
-10
Solve -2*p = -3*x + 50 + 58 - 103, 2*x + 3*p + 1 = 0 for x.
1
Solve 6 = -3*x - w - 14, 43*x + 91 = -w - 209 for x.
-7
Solve 4*p - 30012*q = -30017*q + 29, 5*p - 64 + 237 = 17*q for p.
-4
Solve -p + 17 = 3*t - 2*p, 2*p + 90349 = 5*t + 90317 for t.
2
Solve -1659507*b + 43 = -1659512*b - 3*r, -27 = b - 4*r for b.
-11
Solve -3*d - 7*k + 2*k = -525, 0*k - 913 = -181*d + 182*d - 9*k for d.
5
Solve -3*j + 58 = 5*t - 6*j, 59*t - 55*t - 4*j = 48 for t.
11
Solve 0 = 5*h - 26*g + 119, 35*h + 3*g = 33*h + 6 for h.
-3
Solve -11*q + 133 = 32660*g - 32661*g, -2*g = 2*q - 22 for g.
-1
Solve 13*p + 0*p - 42 = 5*j, -6 = j - 5*p + 3*p for j.
2
Solve -5*f = -2*a + 9537673 - 9537718, 3*a + f + 8 = 0 for a.
-5
Solve -3*b = 2*n - 0*b - 50, -425*b + 421*b - 75 = -3*n for n.
25
Solve -3*q - 22 = q - 9*q + g, 14*q - 13*g = 3*q + 16 for q.
5
Solve 2073*z + 19 = 2072*z - x, -z + 2*x = -5*x - 109 for z.
-3
Solve 4*v + 5*d - 137 = 0, -5*v + 2496*d = 2500*d - 169 for v.
33
Solve 2*f + 3 = 3*j + 13, 3*j - 3*f + 6717 - 6702 = 0 for j.
0
Solve -t - 7*y = 4*t + 48, 1335 = 2*t + 4*y + 1365 for t.
3
Solve 4*o = -7*d + 313 - 311, 6*d + 4*o = 4 for d.
-2
Solve 21 = -u, 508814*a - 508816*a - 6*u = 124 for a.
1
Solve 14*x - 86 = -6*u + 2*u, 7*u = -31*x + u + 4*u + 163 for x.
5
Solve 5*c + 9*h - 157 = -5*h - 135 + 403, 2*c - 4*h = -118 for c.
1
Solve -8*j + 16 = 0, 3*j + 896 = -5*n + 922 for n.
4
Solve 13949*g - 13956*g + 4*y + 62 = 0, -3*g - 2 = 4*y for g.
6
Solve z + 0*p = -7*p + 59 + 36, -2*z + p - 5 = 0 for z.
4
Solve -a - 9*h - 30 = 8*h - 15*h, -2*h - 22 = -a for a.
-4
Solve s = 4*u + 15, 14*u = -71*u + 5*s - 335 for u.
-4
Solve 41*m + 64 = 10*m + 19*m - n + 92, 0 = -21*m - 3*n + 39 for m.
3
Solve -5*h + 474 = -4*s + 374, 10*h + 17 = -4*s + 51 + 106 for h.
16
Solve -m = -4*o - 345 - 82, 3*m + 13*o + 555 = -0*o + 8*o for m.
-5
Solve -3*z - 104 + 134 = -2*r + 4*r, -3*z = 4*r - 66 - 6 for r.
21
Solve 2*v - 5*v - 9*w - 36 = 0, 2*w = 2*v + 16 for v.
-9
Solve -p + 13 = 2*x, x + 19*p - 52*p - 2 = -22*p - 10*p for x.
5
Solve -4*w + 19*m - 59 = 16*m, 0 = -6*w + 4*m - 88 for w.
-14
Solve -5*n + 5*o = -35, 1123989*n - 20 = 1123984*n + 2*o for n.
2
Solve -14*m = 29*m + 4*l - 141, 3*m - 45 = -12*l for m.
3
Solve -t + 5*k = 4*t - 20, -t + 12*t + k + 10 = 6*t for t.
-1
Solve 3*k + 3*l + 6 = -0, 9*l = -k - 12*l + l - 17*l - 182 for k.
3
Solve 15*h - 3533 + 3509 = 5*f + 12*h, 2*h = 4*f + 18 for f.
-3
Solve 3*g + 5140*q - 5154*q = -104, 2*g - 252 = -71*q for g.
-16
Solve 3*j = -4*b - 532 + 493, -73 = 4*b + 5*j for b.
3
Solve 7936*u - 3*r = 7934*u - 34, -14*u + 5*r = 110 for u.
-5
Solve 473*j + 35 = 7*n + 488*j, 0 = -3*n - 3*j + 15 for n.
5
Solve -5*a - 5*x = -20, 4*x + 85813 = a + 85804 for a.
5
Solve -3*p - 19 = 5*h - 38, -40 = -10*p - 3*h + 28 + 50 for p.
13
Solve 5*y + 14*w = 3*y + 100, -6*y - 22 = 69*w - 73*w for y.
1
Solve -154*i + 80*i + 85*i = 3*v + 63, 2*i = -5*v - 166 for i.
-3
Solve 1155*p + 1148*p - 3446*p - 4 = 2*t - 1146*p, 4*p - 16 = 8*t for t.
-2
Solve 19382*v + 126 = 4*f + 19379*v, 70 = 2*f - 5*v for f.
30
Solve -32*a + 3*x = -64, a - 8*a - 5*x - 27 = -4*a - 33 for a.
2
Solve -45 = -5*c - 6*w, 2874*c + 32*w = 2875*c + 157 for c.
3
Solve 0 = 291*h - a - 1244 + 430 - 655, -h - 2*a - 2*a - 51 = -0*h for h.
5
Solve -2*y + 3 = k, -80*k + 46 - 10 = -4*y - 40 for y.
1
Solve -8*q + 5*k = 3*q - 69, -27428*k = 2*q - 27432*k - 28 for q.
4
Solve 11*k + a = 2*a - 70, 3*k + 5*a - 14 = 2*k - 0*a for k.
-6
Solve -2*k = -2*y + 32, 43*y = -3*k + 37*y - 30 for k.
-14
Solve -c = 4*n + 10, -c + 33360*n + 2 = 33352*n for c.
-6
Solve -f + 71 = 4*o, -83482*f = 5*o - 83480*f - 88 for o.
18
Solve -4*c + 222 = -5*d, 4*c - 34 = d + 3 + 17 for d.
-42
Solve -5*g + 3*i - 17 = 0, -254*g + 10 = -252*g + 3*i for g.
-1
Solve -2*g + 1526046 = -4*j + 1526074, -5*g = 80 for j.
-1
Solve 0 = 4*s + 4*r + 4, -5*s + 21 + 18 = 6*s + r for s.
4
Solve -3*u - 37*x = -19*x - 22*x - 51, 43*u - 2*x = 67 for u.
1
Solve -2*f = 3*s + 2022 - 2004, 0 = -5*f - s - 6 for f.
0
Solve -2*p + 4*p - 5*h + 4*h = -2, 12 = -3387*p + 3415*p - 4*h for p.
1
Solve -4*o + 14 + 22 = b, -10*b - 7*o = b - 56 - 7 for b.
0
Solve -48*w + 77*w = 2*x + 2*w + 318, 4*x + 17*w - 216 = 0 for x.
3
Solve -1433*k + 1442*k = 4*j - 27, 3*j - 7*k + 3*k - 12 = 0 for j.
0
Solve 1091104*n - 20 = 1091099*n, -4*n + 12 = 4*t + 4 for t.
-2
Solve 8 = -3*r - 2*b, -3*b - 164 = -170 for r.
-4
Solve 7 = -m - 3*x, -285950*m + 285981*m + x = 151 for m.
5
Solve 0 = -76


Comedian Matt Braunger returns this spring to Atlanta aka “Black Portland,” so dubbed at his noteworthy drop-in at the 1AM Secret Show during last year’s weekend run at the Laughing Skull. Braunger had crowds rolling at both venues with his unique and lively brand of storytelling. Since that trip, Braunger returned to his old Oregon stomping grounds to record his third special at the Bridgetown Comedy Festival, recorded another appearance on the late “@Midnight,” and tied the knot. Atliens have four nights to catch the culmination of a very eventful year for our favorite Big Dumb Animal.


Taking Care of Our Own: A Multispecialty Study of Resident and Program Director Perspectives on Contributors to Burnout and Potential Interventions.
Rates of resident physician burnout range from 60 to 76 % and are rising. Consequently, there is an urgent need for academic medical centers to develop system-wide initiatives to combat burnout in physicians. Academic psychiatrists who advocate for or treat residents should be familiar with the scope of the problem and the contributors to burnout and potential interventions to mitigate it. We aimed to measure burnout in residents across a range of specialties and to describe resident- and program director-identified contributors and interventions. Residents across all specialties at a tertiary academic hospital completed surveys to assess symptoms of burnout and depression using the Maslach Burnout Inventory and the Patient Health Questionnaire-9, respectively. Residents and program directors identified contributors to burnout and interventions that might mitigate its risk. Residents were asked to identify barriers to treatment. There were 307 residents (response rate of 61 %) who completed at least one question on the survey; however, all residents did not respond to all questions, resulting in varying denominators across survey questions. In total, 190 of 276 residents (69 %) met criteria for burnout and 45 of 263 (17 %) screened positive for depression. Program directors underestimated rates of burnout, with only one program director estimating a rate of 50 % or higher. Overall residents and program directors agreed that lack of work-life balance and feeling unappreciated were major contributors. Forty-two percent of residents reported that inability to take time off from work was a significant barrier to seeking help, and 25 % incorrectly believed that burnout is a reportable condition to the medical board. Resident distress is common and most likely due to work-life imbalance and feeling unappreciated. However, residents are reluctant to seek help. Interventions that address work-life balance and increase access to support are urgently needed in academic medical centers.


Q:

Why my listview style change when I loop the javascript twice?

I develop an android native application using phonegap and jquery mobile. I've made a function to create a listview style dynamically using looping for... When I run the function for the first time, it works, the listview style is working, and match with the content. but when I press back button and run the function again, the style change (the listview style is gone) but the content still there. is my function wrong? how to solve this problem?
the screenshoot for more explanation:

this is the result when I press the back button and run the function again

the codes for more detail:
function detail(kodenegara, koderesult)
        {
            $.ajax({
                type: "GET",
                contentType: "application/json; charset=utf-8",
                url: "http://10.80.3.73/webservice/Service1.svc/json/weeklyflash/"+kodenegara,
                dataType: "json",
                success:function(data){
                    var result = koderesult;

                    maks = -1;
                    for(i = 0; i < data[result].length; i++) {
                        if(data[result][i].bulan > maks)
                        maks = data[result][i].bulan;
                    }

                    var loop_tipe = countTypesForBulan(data[result], maks);
                    var innerHtml = "";

                    for (i = 0; i < loop_tipe; i++){
                        a=i+loop_tipe;
                        b=a+loop_tipe;
                        innerHtml +=
                        "
"+
                        "
"+data[result][i].type+"
"+
                        "
"+
                            "
"+
                                " 	"+
                                ""+data[result][i].bulan+"/2012	"+
                                ""+data[result][a].bulan+"/2012	"+
                                ""+data[result][b].bulan+"/2012	"+
                            "
"+
                            "
"+
                                "Cash	"+
                                ""+data[result][i].uang+"	"+
                                ""+data[result][a].uang+"	"+
                                ""+data[result][b].uang+"	"+
                            "
"+
                            "
"+
                                "Qty	"+
                                ""+data[result][i].total+"	"+
                                ""+data[result][a].total+"	"+
                                ""+data[result][b].total+"	"+
                            "
"+
                        "
"+
                        "
";
                    }
                    $('#tipe').html(innerHtml);
                    $.mobile.changePage("#detail", "slide", false, true);

                    //show the page
                },
                error: function () {
                    alert("ERROR");
                }
            });
        }

        function countTypesForBulan(resultArray, bulanVal) {
            var i,
                types,
                count = 0;
            for (i=0, types = {}; i < resultArray.length; i++)
                if (resultArray[i].bulan === bulanVal && !types[resultArray[i].type]) {
                types[resultArray[i].type] = true;
                count++;
            }
            return count;
        }

here is for simulation my project with jsfiddle

A:

I can't see anything wrong with your code in terms of why it gives you different styles. I would however ensure you have a consistent coding standard.
For example my coding standards usually include:

Always declare variables. Variable maks is never declared here (I'm going to assume it is never declared.) Change it to var maks = -1;
Always use { and }. This will ensure you don't screw up a block.
if(data[result][i].bulan > maks)
    maks = data[result][i].bulan;

would become:
if(data[result][i].bulan > maks)
{
    maks = data[result][i].bulan;
}

Its just proofing for us who make mistakes from time to time.
make local variables where possible
if (resultArray[i].bulan === bulanVal && !types[resultArray[i].type]) {
    types[resultArray[i].type] = true;
    count++;
}

could be:
 var current = resultArray[i];
 if (current.bulan === bulanVal && !types[current.type]) {
    types[current.type] = true;
    count++;
}

It means less look ups. Most of the time its easier to read.


Q:

The code is required to make a random number then keepon spouting random numbers until it reaches that number, but its always the same

Here's the idea of the code: The code is required to make a random number then keepon spouting random numbers until it reaches that number, but its always the same.
heres the code:
#include <stdio.h>
#include <math.h>

int rdt () {
long long int randomonium;
randomonium=rand();
return randomonium;
}
int main (){
int rd;
int no;

while(1){
rd=rand();
printf("%d\n", rd);
if (rd== rdt()){
    break;

}
}
return 0;

}

A:

You can put a srand(time(NULL)); just before the while to change the random seed used by rand().
Don't forget to include time.h in the code.


Put the spring on before you place the cam release on. This allows the shoes to spread further apart making it easier to get the spring on. Then place the cam release over the tube and compress the shoes together with your hands so the cam drops in place.

Thanks Eric... I did part of that and ended up putting the spring on first, then using a wide jaw pliers and my fingers, I aligned the holes of the brake pads and pushed them onto their post. It was awkward and required a few tries, but it worked. Then I put on the cam as you suggested.
... Orv D

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Calculate prob of sequence pwoj when four letters picked without replacement from {w: 1, o: 1, p: 1, j: 1, g: 1}.
1/120
Calculate prob of sequence frf when three letters picked without replacement from {f: 7, r: 1}.
1/8
What is prob of sequence ippn when four letters picked without replacement from tttipptpinpinttni?
3/1190
What is prob of sequence tjn when three letters picked without replacement from tjtjwoonojjj?
1/132
Four letters picked without replacement from ssssssssss. What is prob of sequence ssss?
1
Calculate prob of sequence ai when two letters picked without replacement from {y: 1, q: 6, i: 2, c: 2, a: 4}.
4/105
What is prob of sequence aada when four letters picked without replacement from {d: 4, u: 2, a: 5}?
1/33
Two letters picked without replacement from mmmm. Give prob of sequence mm.
1
Three letters picked without replacement from ziciihilchhch. What is prob of sequence lzi?
1/429
Four letters picked without replacement from {g: 1, s: 5, m: 3, b: 1, d: 2, e: 1}. Give prob of sequence mmbg.
1/2860
Four letters picked without replacement from nzayzmhny. What is prob of sequence ymya?
1/1512
Four letters picked without replacement from vvvvevve. What is prob of sequence vvee?
1/28
Calculate prob of sequence fjd when three letters picked without replacement from jddjdfjdjdd.
4/165
What is prob of sequence aall when four letters picked without replacement from {a: 13, l: 5}?
13/306
Four letters picked without replacement from vxwwwwavwxxxaxa. What is prob of sequence xawa?
5/1092
What is prob of sequence dtd when three letters picked without replacement from gdggddrtta?
1/60
Three letters picked without replacement from qqqqqq. Give prob of sequence qqq.
1
What is prob of sequence heel when four letters picked without replacement from {l: 8, h: 2, e: 4}?
8/1001
What is prob of sequence hhh when three letters picked without replacement from {h: 7, y: 5}?
7/44
Three letters picked without replacement from rrrrr. What is prob of sequence rrr?
1
What is prob of sequence nt when two letters picked without replacement from {j: 1, a: 1, t: 1, n: 1, w: 1, f: 2}?
1/42
Three letters picked without replacement from {w: 2, p: 1, z: 6, t: 4, x: 1, a: 4}. What is prob of sequence awp?
1/612
What is prob of sequence dpdp when four letters picked without replacement from {d: 5, p: 3}?
1/14
Calculate prob of sequence bz when two letters picked without replacement from qbmpqmmbmzzzrzb.
2/35
Four letters picked without replacement from {t: 2, p: 1, d: 1, g: 3, c: 3, k: 3}. Give prob of sequence pckd.
3/5720
Calculate prob of sequence ooo when three letters picked without replacement from oooooosoooooooo.
4/5
Two letters picked without replacement from kcvbxkvbnkbc. What is prob of sequence kk?
1/22
Calculate prob of sequence jrr when three letters picked without replacement from jtthrnnthtjtrhtjj.
1/510
Two letters picked without replacement from ooionnlola. Give prob of sequence na.
1/45
Two letters picked without replacement from ugquguquququ. Give prob of sequence ug.
1/11
Two letters picked without replacement from {w: 2, z: 1, e: 3, i: 1, x: 7, v: 3}. What is prob of sequence ix?
7/272
What is prob of sequence jmm when three letters picked without replacement from {v: 2, g: 1, m: 7, j: 3, p: 5}?
7/272
Two letters picked without replacement from bcaaaljjjlj. Give prob of sequence ja.
6/55
Calculate prob of sequence be when two letters picked without replacement from {e: 5, b: 5}.
5/18
Four letters picked without replacement from {u: 3, p: 1, f: 1, h: 1, b: 1}. What is prob of sequence fhbp?
1/840
What is prob of sequence weee when four letters picked without replacement from {w: 4, e: 14}?
91/765
Calculate prob of sequence ggg when three letters picked without replacement from gggggggegegg.
6/11
Calculate prob of sequence amu when three letters picked without replacement from {w: 6, a: 2, m: 2, u: 1, i: 5}.
1/840
Three letters picked without replacement from {z: 4, c: 1, s: 3}. What is prob of sequence css?
1/56
Four letters picked without replacement from {k: 4, t: 1, y: 7, h: 4, v: 3}. What is prob of sequence yvkt?
7/7752
Two letters picked without replacement from ssyasiaaaaysasaa. Give prob of sequence is.
1/48
What is prob of sequence vc when two letters picked without replacement from cccvqcq?
2/21
Calculate prob of sequence lll when three letters picked without replacement from {l: 7}.
1
Two letters picked without replacement from uigoui. Give prob of sequence ui.
2/15
Two letters picked without replacement from iwkwlklswpklis. Give prob of sequence is.
2/91
Calculate prob of sequence rrr when three letters picked without replacement from {r: 4, v: 2}.
1/5
What is prob of sequence tt when two letters picked without replacement from tttthhh?
2/7
What is prob of sequence hx when two letters picked without replacement from khxkkshxsxxkxxxx?
1/15
What is prob of sequence dv when two letters picked without replacement from {m: 10, j: 5, v: 4, d: 1}?
1/95
Calculate prob of sequence zh when two letters picked without replacement from haptzaz.
1/21
What is prob of sequence ii when two letters picked without replacement from isssssssisssssisss?
1/51
Three letters picked without replacement from ktxmktkxmkdkktkuxu. What is prob of sequence muk?
7/1224
Four letters picked without replacement from jjqjjsojjjjsorjjjqqj. What is prob of sequence qjjr?
11/3230
Calculate prob of sequence jgj when three letters picked without replacement from {g: 1, l: 5, z: 8, j: 4}.
1/408
Calculate prob of sequence gfgf when four letters picked without replacement from {g: 2, f: 4, c: 1, y: 12}.
1/3876
What is prob of sequence qm when two letters picked without replacement from {a: 1, q: 1, m: 1, f: 2}?
1/20
Calculate prob of sequence qaa when three letters picked without replacement from {q: 9, a: 9}.
9/68
Three letters picked without replacement from {o: 3, t: 2}. Give prob of sequence tto.
1/10
Three letters picked without replacement from {m: 5, f: 6, v: 2}. Give prob of sequence fff.
10/143
What is prob of sequence ay when two letters picked without replacement from {n: 2, l: 3, y: 1, u: 1, a: 5}?
5/132
What is prob of sequence oyyo when four letters picked without replacement from {o: 2, y: 11}?
1/78
Three letters picked without replacement from {c: 9}. What is prob of sequence ccc?
1
Two letters picked without replacement from yyggmyydrmm. What is prob of sequence mr?
3/110
What is prob of sequence kxr when three letters picked without replacement from kjvxkjr?
1/105
Calculate prob of sequence xxkx when four letters picked without replacement from {x: 3, k: 15}.
1/816
Four letters picked without replacement from {x: 3, b: 3, y: 7, w: 2}. What is prob of sequence wyxy?
1/130
Two letters picked without replacement from {z: 1, e: 1, q: 1}. What is prob of sequence qz?
1/6
Three letters picked without replacement from lwulggbwgg. What is prob of sequence wuw?
1/360
Calculate prob of sequence ta when two letters picked without replacement from {t: 2, a: 3}.
3/10
Three letters picked without replacement from ncf. Give prob of sequence cnf.
1/6
Two letters picked without replacement from {i: 2, p: 1, d: 2, m: 1, n: 8}. What is prob of sequence mi?
1/91
Calculate prob of sequence nknk when four letters picked without replacement from {n: 10, k: 10}.
45/646
Three letters picked without replacement from {d: 9, g: 10}. What is prob of sequence dgd?
40/323
Calculate prob of sequence aoya when four letters picked without replacement from oyaafyayffffffaa.
1/728
Two letters picked without replacement from ibiiibiiibbiiibiii. Give prob of sequence ib.
65/306
Calculate prob of sequence mmz when three letters picked without replacement from mtmsmsszmzmzzmzsmz.
7/136
Three letters picked without replacement from {x: 2, r: 1, n: 3, i: 1}. Give prob of sequence nir.
1/70
What is prob of sequence jc when two letters picked without replacement from rccccrrhcjcmcrccd?
9/272
Two letters picked without replacement from xxxxxxxxxmxxyxxxxxx. Give prob of sequence xm.
17/342
Two letters picked without replacement from {u: 2, h: 2, d: 2}. What is prob of sequence dd?
1/15
What is prob of sequence cs when two letters picked without replacement from {s: 3, c: 4}?
2/7
Four letters picked


[Clinical application of perforator propeller flaps with anastomosis of superficial veins].
To investigate the clinical effect of anastomosis of superficial veins for improving the drainage of perforator propeller flaps. From Sept. 2011 to Dec. 2012, 11 cases with soft tissue defects and chronic ulcer wound at extremities were treated with adjacent perforator propeller flaps, which were pedicled by the peroneal artery(5 cases), or the lateral supramalleolar artery(3 cases), or the ulnar artery (2 cases), or the posterior interrosseous artery (1 case). The wound size ranged from from 3.0 cm x 2. 5 cm to 11. 0 cm x 4. 0 cm, and the falps size ranged from 6 cm x 3 cm to 21 em x 5 cm. One superficial vein in all the flaps was anastomosed with superficial vein in the recipient area. The blood supply of the flaps were recorded after operation 1 - 3 months after operation, the fluency of anastomosed vein was detected by color Doppler ultrasound. Flap swelling evaluations were performed in early 3 months and later 3 - 6 months, and the results were classified into 4 grading degrees. 6 months later, Questionnaire of the flap aesthetic satisfactory was performed for seven patients during follow-up period. 9 flaps survived completely, two flaps had partial marginal skin necrosis in the distal end, which were both managed with surgical debridement, and both wounds healed in two months. 9 cases were followed up for more than 12 - 19 months. The early rsults of flap swelling evaluations were: I degree 0 case, II degree 8 cases, III degree 3 cases, IV degree 0 case, and the later results were: I degree 7 cases, II degree 4 cases, III degree 0 case, IV degree 0 case. The flaps had ideal appearance, good contour, and high aesthetic satisfactory (100%). The mean flap survival area rate of veins anastomosed was (98. 6 ± 9. 7) %. Perforator propeller flaps with anastomosis of superficial veins can improve the flap venous drainage, avoid transient venous venous congestion, so as to increase the flap survival. It is an effective way for improving the vein drainage.


Q:

MouseDown, PreviewMouseDown, etc... and COMMAND Binding in MVVM

I'm trying to understand this concept and it's eluding me.
What is the general concept behind this?  I know it's possible, but I'm not totally following how to do this based on my research/own test projects.
I want to avoid code behind at all costs in my View.  I want to decouple events such as "PreviewMouseDown" from the View and have them trigger a Command in the ViewModel.
Can anyone give me some basic guidance on how to accomplish this?
Summary:
View (PreviewMouseDown) -> Calls Command in ViewModel (MyPreviewMouseDownCommand)
Thank you

A:

At risk of being downvoted I don't think this is the worst thing in the world
public void PreviewMouseDown(Object sender, RoutedEventArgs e)
{
    var viewModel= (MyViewModel)DataContext;
    if (viewModel.MyCommand.CanExecute(null))
        viewModel.MyCommand.Execute(null);
}

A:

This is typically handled via some form of Attached Property or (Blend) Behavior.
For example, MVVM Light includes an EventToCommand Behavior which allows you to route any event to an ICommand in XAML, with no code behind added.

A:

It's all about Commanding and Binding. But I'll encourage you to better use a framework that provides you the plumbing. If you want View first strategy you can you go with MVVM Light as Reed suggested. But, if you want ViewModel first approach (which I personally found to be more simple to understand) then I'll suggest you to use Caliburn Micro.
Anyway, you'll end up using Event to Command or the Interactivity Library (from the Blend SDK) if you want to go code-behind clean.


The U.S. State Department has criticized Pakistan’s treatment of Ahmadiyya Muslims in its annual international religious freedom report.

During the report launch on Wednesday Deputy Secretary of State, Antony J. Blinken said “When a government denies religious liberty, it turns citizens who have done nothing wrong into criminals, igniting tension that breeds contempt, hopelessness, alienation.”

While speaking at the reports’ launch, U.S. Ambassador-at-Large for International Religious Freedom David Saperstein said:

In Pakistan, the government continued to enforce blasphemy laws, for which a punishment can be death sentence, for a range of charges including defiling the Prophet Muhammad. Christians as well as Muslims were arrested on charges of blasphemy in the last year. In 2016 after a Hindu convert to Islam was accused of blasphemy, two Hindu youths were shot and one died from his wounds in ensuing communal violence. We remain deeply concerned also over authorities targeting and harassment of Ahmadi Muslims for blasphemy, violations of anti-Ahmadi laws, and other crimes.

The report said that in Pakistan, 40 people remain on death row for blasphemy, many of them religious minorities.

The report also mentioned that U.S. Ambassador, consuls general, and Embassy officers met with Pakistani government officials to discuss reform of the blasphemy law, curriculum reform in the public and madrassah education systems, the treatment of the Ahmadi Muslim, Christian, Hindu, Sikh, and other minority communities.


Supreme Court Rules Against Software Patents

SAN FRANCISCO -- A Supreme Court decision today may affect the technology industry for years to come. The justices' unanimous vote in Alice Corporation Pty. Ltd. v. CLS Bank International renders software patents ineligible as abstract ideas. Such ideas, the court said, have always been patent ineligible.

The Australian company Alice International had obtained patent protection for software that creates a settlement between two parties and generates instructions to the institutions involved to carry out their agreement. The justices ruled that the software was generic and did not make technical advancements or improve how the computer functioned.

"The patents at issue in this case disclose a computer-implemented scheme for mitigating 'settlement risk'… by using a third-party intermediary," Justice Clarence Thomas wrote in the court's opinion. "We hold that the claims at issue are drawn to the abstract idea of intermediated settlement, and that merely requiring generic computer implementation fails to transform that abstract idea into a patent-eligible invention."

Open-source advocates such as the Electronic Frontier Foundation (EFF) called the ruling a step in the right direction to curb patent trolls and improve consumer experience.

"We think that it will cut down on a lot of the worst patents that are out there, the most ridiculous and overbroad software patents… A lot of patent trolls' patents are now more questionable then they were," EFF staff attorney Daniel Nazer told us. "I think maybe there will be more of a focus on trying to create products people want and putting them in the market place rather than fighting each other with patents."

Though patents have been hotly debated as both detrimental instruments and catalysts for innovation, industry analysts said the ruling doesn't change much or provide a rubric for patentability. Those seeking patents will have to figure out what constitutes generic software and what is actual invention.

"Those applying for or defending software patents will argue that their inventions are not 'generic' computer implementations of abstract ideas," Florian Mueller, an analyst following patent disputes, wrote in a blog post on the Supreme Court ruling. "Those challenging such patents will try to define 'generic computer implementation' as broadly as possible and argue that every software patent they attack involves previously known computing technology and an abstract idea."

Patent attorney Jeffery Frazier told us that whether the ruling will deter patent trolls is up for debate. "People that draft applications are going to think around these lines and include language that sounds like there's an improvement made."

Nazer expects "wide and narrow interpretations" of the ruling, as well as the invalidation of many software patents. Still, the ruling "doesn't purport to be a decision invalidating software patents." Trolls will likely continue to operate, but they will try harder to avoid court rulings.

Language around the ruling may be cause for concern among hardware engineers. The term "computer-implemented" refers to the mode of invention, rather than the invention itself. Frazier said system elements such as a data storage unit and communications controller were called out in the case as generic, but they were only named at a high level.

"It concerns me a little bit. I'm sure it was the right thing to do here," he said. "Don't see it eroding patents on the system side or creating problems for hardware manufacturers. My concern is more trying to figure out where the line is. How far down from the high level that these claims were reciting do these hardware elements become tangible?"

The ruling was issued nearly a year after the Patent Litigation and Innovation Act of 2013 was introduced in the House of Representatives. Julie Samuels, then a senior staff attorney for the EFF, wrote in a blog post in December that the bill "gives defendants tools to fight back, makes litigation cheaper and includes an important fee-shifting provision."

The bill cleared the House and garnered support from President Obama, but Sen. Patrick Leahy (D-VT) removed the bill from the Senate Judiciary Committee agenda last month.

"The full contours of this decision will take some time to work out. The Supreme Court has left a lot of work for the lower courts to do to interpret it," Nazer said. "It's going to be 2-3 years before we have a good understanding of what the decision will mean in practice. But this is promising. There's a lot of good language here."

>> Similarly if C was patented then we shouldn't have seen so much of growth in software development.

It is the chicken and egg question. The true fact is that the software lawyers are smarter than their hardware equivalents. When you buy Windows and want to build an application on it, you pay Microsoft license on the product. But Intel powers the OS for Windows and they simply pay-out for the hardware. Intel could have also asked for royalty for OS running on their hardware. Oracle gets money from banks running banking applications powered by Oracle. Yet, IBM and co that supply the server do not (only puchase revenue).

>> , I totally agree with you. Software is as important as hardware for optimal systems performance.Some times the performance is limited by the software and not hardware.

That is why they have valuations in multiples better than IC startups becuase they make all the difference. Hard to see any IC firm at startup phase with $250M valuation. Yet, we see these web startups in the north of billions of dollars.

Seems to finally rule out Amazon's "One Click" which is long overdue, along with dozens of other SW implementations of existing HW. Take Apple's slide switch to turn off a phone, slide switches have been in use longer than I've been alive and yet they want to patent that LOL!

Per comments, it's important to clarify that the Supreme Court did make a decision *on one case* and not all software patents; though the decision has implications on future patent requests.

Several commenters also have taken issue with abstract ideas being patentable, and I think there may have been confusion over the lede in this article. Software has not always been considered an abstract idea, but abstract ideas have long been considered patent ineligible:

"A principle, in the abstract, is a fundamental truth; an original cause; a motive; these cannot be patented, as no one can claim in either of them an exclusive right." Le Roy v. Tatham,55 U.S. (14 How.) 156, 175 (1852).


Radio-controlled-clock (RCC) devices that rely on time signal broadcasts have become widely used in recent years. A radio-controlled-clock (RCC) is a timekeeping device that provides the user with accurate timing information that is derived from a received signal, which is broadcast from a central location, to allow multiple users to be aligned or synchronized in time. Colloquially, these are often referred to as “atomic clocks” due to the nature of the source used to derive the timing at the broadcasting side. In the United States, the National Institute of Standards and Technology (NIST) provides such broadcast in the form of a low-frequency (60 kHz) digitally-modulated signal that is transmitted at high power from radio station WWVB in Fort Collins, Colo. The information encoded in this broadcast includes the official time of the United States.
Similar services operating at low frequencies exist in other regions worldwide, including Europe and Japan. Many consumer-market products exist, including watches, alarm clocks and wall clocks, that are capable of receiving one or more of these broadcasts and which can display the correct time to within approximately one or two seconds of accuracy. While the broadcast may be active continuously, a typical radio-controlled clock may be set to receive the broadcast only once a day. Such reception, if successful (depending on the condition of the wireless link and potential interference), is typically used to reset the timekeeping device, such that if it were set incorrectly or has drifted away from the correct time, it will be set in accordance to the time communicated through the broadcast signal.
Reception of the time signal, however, is being challenged by a growing number of sources of electromagnetic interference. In particular, the on-frequency interference from the MSF radio station in the United Kingdom has been identified as a particularly challenging jammer for receivers on the East Coast.
There is thus a need for an improved protocol for time signal broadcasts, such as that provided by WWVB in the United States and radio stations in other countries, that attempts to cost-effectively address the reception challenges. Such a new protocol should preserve existing amplitude modulation properties of the transmitted signal, in order to maintain backwards compatibility and not impact existing devices.