{"action":"opened","issue":{"url":"https://api.github.com/repos/Pomax/BezierInfo-2/issues/35","repository_url":"https://api.github.com/repos/Pomax/BezierInfo-2","labels_url":"https://api.github.com/repos/Pomax/BezierInfo-2/issues/35/labels{/name}","comments_url":"https://api.github.com/repos/Pomax/BezierInfo-2/issues/35/comments","events_url":"https://api.github.com/repos/Pomax/BezierInfo-2/issues/35/events","html_url":"https://github.com/Pomax/BezierInfo-2/issues/35","id":170309455,"number":35,"title":"Easy solution for Arc length for quadratics ","user":{"login":"behdad","id":142891,"avatar_url":"https://avatars.githubusercontent.com/u/142891?v=3","gravatar_id":"","url":"https://api.github.com/users/behdad","html_url":"https://github.com/behdad","followers_url":"https://api.github.com/users/behdad/followers","following_url":"https://api.github.com/users/behdad/following{/other_user}","gists_url":"https://api.github.com/users/behdad/gists{/gist_id}","starred_url":"https://api.github.com/users/behdad/starred{/owner}{/repo}","subscriptions_url":"https://api.github.com/users/behdad/subscriptions","organizations_url":"https://api.github.com/users/behdad/orgs","repos_url":"https://api.github.com/users/behdad/repos","events_url":"https://api.github.com/users/behdad/events{/privacy}","received_events_url":"https://api.github.com/users/behdad/received_events","type":"User","site_admin":false},"labels":[],"state":"open","locked":false,"assignee":null,"assignees":[],"milestone":null,"comments":0,"created_at":"2016-08-10T01:40:00Z","updated_at":"2016-08-10T01:40:00Z","closed_at":null,"body":"If you do some realigning, it simplifies to \\int \\sqrt(1+t^2) dt, which is much more palatable:\r\nhttp://www.wolframalpha.com/input/?i=antiderivative+for+sqrt(1%2BB*t*t)\r\n\r\nOr as I originally arrived at it, \\int sec(atan(t)) dt.\r\n\r\nI've implemented this in Python; it was 4 or 5 times faster than recursion.  Then again, Python has horrible object-creation overhead for curve recursion.\r\n\r\nAnyway, the code is here:\r\nhttp://www.wolframalpha.com/input/?i=antiderivative+for+sqrt(1%2BB*t*t)"}}
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