{"action":"opened","issue":{"url":"https://api.github.com/repos/hadley/dplyr/issues/2028","repository_url":"https://api.github.com/repos/hadley/dplyr","labels_url":"https://api.github.com/repos/hadley/dplyr/issues/2028/labels{/name}","comments_url":"https://api.github.com/repos/hadley/dplyr/issues/2028/comments","events_url":"https://api.github.com/repos/hadley/dplyr/issues/2028/events","html_url":"https://github.com/hadley/dplyr/issues/2028","id":166643175,"number":2028,"title":"mutate converts data.table to (only) data.frame","user":{"login":"dxf1david","id":498246,"avatar_url":"https://avatars.githubusercontent.com/u/498246?v=3","gravatar_id":"","url":"https://api.github.com/users/dxf1david","html_url":"https://github.com/dxf1david","followers_url":"https://api.github.com/users/dxf1david/followers","following_url":"https://api.github.com/users/dxf1david/following{/other_user}","gists_url":"https://api.github.com/users/dxf1david/gists{/gist_id}","starred_url":"https://api.github.com/users/dxf1david/starred{/owner}{/repo}","subscriptions_url":"https://api.github.com/users/dxf1david/subscriptions","organizations_url":"https://api.github.com/users/dxf1david/orgs","repos_url":"https://api.github.com/users/dxf1david/repos","events_url":"https://api.github.com/users/dxf1david/events{/privacy}","received_events_url":"https://api.github.com/users/dxf1david/received_events","type":"User","site_admin":false},"labels":[],"state":"open","locked":false,"assignee":null,"assignees":[],"milestone":null,"comments":0,"created_at":"2016-07-20T17:58:12Z","updated_at":"2016-07-20T17:58:12Z","closed_at":null,"body":"Hi - I use data.tables and dplyr together.  In going from v 0.4.3 to 0.5.0, it appears that using mutate on a data.table converts it to a data.frame - it's no longer a data.table.  Is this an oversight or was this planned?  I realize that I could always use setDT(df), but this would require many changes in many programs. \r\n\r\nIs there any possibility that mutate with a data.table could output an object that is both a data.frame and a data.table as in dplyr v0.4.3?\r\n\r\nThanks, David Freedman"}}
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