{"action":"opened","issue":{"url":"https://api.github.com/repos/vighneshbirodkar/dating_game/issues/4","repository_url":"https://api.github.com/repos/vighneshbirodkar/dating_game","labels_url":"https://api.github.com/repos/vighneshbirodkar/dating_game/issues/4/labels{/name}","comments_url":"https://api.github.com/repos/vighneshbirodkar/dating_game/issues/4/comments","events_url":"https://api.github.com/repos/vighneshbirodkar/dating_game/issues/4/events","html_url":"https://github.com/vighneshbirodkar/dating_game/issues/4","id":188997787,"number":4,"title":"Recommendation: on game end, print round in which player achieves highest score","user":{"login":"Kevin-Jin","id":1700612,"avatar_url":"https://avatars.githubusercontent.com/u/1700612?v=3","gravatar_id":"","url":"https://api.github.com/users/Kevin-Jin","html_url":"https://github.com/Kevin-Jin","followers_url":"https://api.github.com/users/Kevin-Jin/followers","following_url":"https://api.github.com/users/Kevin-Jin/following{/other_user}","gists_url":"https://api.github.com/users/Kevin-Jin/gists{/gist_id}","starred_url":"https://api.github.com/users/Kevin-Jin/starred{/owner}{/repo}","subscriptions_url":"https://api.github.com/users/Kevin-Jin/subscriptions","organizations_url":"https://api.github.com/users/Kevin-Jin/orgs","repos_url":"https://api.github.com/users/Kevin-Jin/repos","events_url":"https://api.github.com/users/Kevin-Jin/events{/privacy}","received_events_url":"https://api.github.com/users/Kevin-Jin/received_events","type":"User","site_admin":false},"labels":[],"state":"open","locked":false,"assignee":null,"assignees":[],"milestone":null,"comments":0,"created_at":"2016-11-13T21:53:53Z","updated_at":"2016-11-13T21:53:53Z","closed_at":null,"body":"According to the specs: \"The value of M is the lexicographic value (score, number of candidates) A player X beats player Y if X obtains a greater score or obtains the same score but with fewer candidates than Y does for X's P. \"\r\n\r\nCurrently it is only obvious at which round the matchmaker gets a score of 1. In order to make it easier to break ties, the architect should also make it obvious which round the matchmaker gets his best score (if not at the very last turn) in case neither opponent achieves a perfect score but they both achieve the same best score."}}
{"actor":{"display_login":"Kevin-Jin"}}