This task is to find the number of 'For' loops present in the given cpp program.

Ex Input:
int fact(int n,int m);//????fact
int main()//?????
{
	int n,a[35000],i,b[35000];
	cin>>n;
	for(i=0;i<n;i++)cin>>a[i];//???????????
	for(i=0;i<n;i++)b[i]=fact(a[i],2);//?????????????????fact(a[i],2)
	for(i=0;i<n;i++)cout<<b[i]<<endl;//????????
	return 0;
}//?????
int fact(int n,int m)//fact??
{
	int sum=1,i,temp=0;
	if(n<m)return 0;//?n<m,?????0
	else if(n==2)return 1;//?n???2??????1
	else
	{
			for(i=m;i<n;i++)//??????m?n
	{if(n%i==0)sum=sum+fact(n/i,i);}//?n??i????sum??fact(n/i,i)??,????
	return sum;
	}
}//fact??

Ex Output:
4


Ex Input:
/*
/???   10(1)
/??     ???
/??     2012?11?26?
/???   ????
*/
int main()
{
	int fenjie(int x, int y);
	int a, n, i;
	cin >> n;
	for(i = 1; i <= n; i++)
	{
		cin >> a;
cout << fenjie(a, 2) << endl;
	}
	return 0;
}
int fenjie(int x, int y)
{
	int b, i, count = 1; // ?????????
	if(x == 1)
		return 0;
	if(x == 2)
		return 1;
	b = sqrt((double) x);
	for(i = y; i <= b; i++)
	{
		if(x % i == 0)   // ?????????????????????count???
		{
			count += fenjie(x / i, i); // ????????????i??????????
		}
	}
	return count;
}

Ex Output:
2


Ex Input:
int main()
{
	int ys(int s,int p);
	int n,m,i,t;
	scanf("%d",&n);
    for(i=1;i<=n;i++)
	{
		scanf("%d",&m);
        t=ys(m,2);
		printf("%d\n",t);
	}
    return 0;
}
int ys(int s,int p)
{
	int j,a=1,b;
	for(j=p;j*j<=s;j++)
	{
        if(s%j==0)
		{
			b=s/j;
			a=a+ys(b,j);
		}
	}
	return(a);
}

Ex Output:

2


