There are different 10 circles. What is the number of the greatest possible points with which the circles intersect?
Options:
(A) 90
(B) 100
(C) 110
(D) 180
(E) 200
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Maximum points of intersection between n different circles = n*(n - 1) = 10*9 = 90 So the answer is: (A).
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If the average (arithmetic mean) of the four numbers K, 2K + 3, 3K – 5 and 5K + 1 is 118, what is the value of K?
Options:
(A)  11
(B)  15 3/4
(C)  22
(D)  118
(E)  25 3/10
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K + 2K +3 + 3K - 5 + 5K +1 = 11K -1
(11K -1)/4 = 118
11K = 118 * 4 +1 = 472 +1 = 473
K = 473 / 11 = 43. So the answer is: (D).
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Three 6 faced dice are thrown together. The probability that exactly two dice show the same number on them is
Options:
(A) 5/54
(B) 5/12
(C) 5/17
(D) 5/18
(E) 5/14
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Using question number 11 and 12, we get the probability as
1 - (1/36 + 5/9) = 5/12 So the answer is: (B).
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