Reasoning: (60/100) * 50 – (40/100) * 30
30 - 12 = 18ch 60% of 50 is greater than 40% of 30?
Ans: (A)
Question: How much 60% of 50 is greater than 40% of 30?
Options:
(A) 18
(B) 99
(C) 77
(D) 66
(E) 12

Rationale: Given Exp. = (a3 + b3) = (a + b) = (222 + 555) = 777(a2 - ab + b2)
The answer: (E)
Question: Solve:-
222 x 222 x 222 + 555 x 555 x 555 = ?(222 x 222 - 222 x 555 + 555 x 555)
Options:
(A) 888
(B) 333
(C) 555
(D) 988
(E) 777

Reasoning: Average of 20 numbers = 0
Sum of 20 numbers = (0 * 20) = 0
It is quite possible that 19 of these numbers may be positive and if their sum is a, then 20th number is (-a).
Ans: (D)
Question: The average of 20 numbers is zero. Of them, at the most, how many may be greater than zero?
Options:
(A) 17
(B) 16
(C) 17
(D) 19
(E) 62

Rationale: A frame 2 inches wide is placed around a rectangular picture with dimensions 8 inches by 12 inches. What is the area of the frame, in square inches?
(12*16)-(8*12) = 96
The answer: (B)
Question: A frame 2 inches wide is placed around a rectangular picture with dimensions 8 inches by 12 inches. What is the area of the frame, in square inches?
Options:
(A) 44
(B) 96
(C) 128
(D) 144
(E) 168

Reasoning: Speed = 45 * 5/18 = 25/2 m/sec
Total distance covered = 360 + 140 = 500 m
Required time = 500 * 2/25 = 40 sec
Ans: (A)
Question: A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
Options:
(A) 40 sec
(B) 22 sec
(C) 27 sec
(D) 17 sec
(E) 37 sec

Reasoning: Total revenues = x
Spent on marketing = x/4
Remaining amount = x-x/4 = 3x/4
1/7 of the remainder on maintenance of its facilities = 3x/4*1/7 = 3x/28
Amount left = 3x/4-3x/28 = 9x/14
Ans: (D)

Question: Company Z spent 1/4 of its revenues last year on marketing and 1/7 of the remainder on maintenance of its facilities. What fraction of last year’s original revenues did company Z have left after its marketing and maintenance expenditures?
Options:
(A) 5/14
(B) 1/2
(C) 17/28
(D) 9/14
(E) 9/11