This task is to find the number of 'For' loops present in the given cpp program.

Q: int fenjie(int out[16],int a,int n,int m,int sheng,int b[2])
//n??out?????????m?????????????2?????????,sheng???????
{
	int i;
	for(i=m;i<=a/2;i++)
	{
		if(sheng%i==0)
		{
			out[n]=i;
			int qiu=1,k;
			for(k=0;k<=n;k++)qiu=out[k]*qiu;
			//cout<<i<<" "<<qiu<<" "<<n<<endl;
			if(qiu==a){b[0]++;break;}
			if(qiu>a)break;
			else fenjie(out,a,n+1,i,sheng/i,b);


		}
		

	}
	return 0;
}
int main()
{
	int hang=0;
	cin>>hang;
	while(hang>0)
	{
		int a;
		int b[2]={0};
		cin>>a;
		int out[16]={0};
		fenjie(out,a,0,2,a,b);
		cout<<b[0]+1<<endl;
		hang--;
	}
	return 0;
}


A: 2
****
Q: int f(int a,int min){
	if(a<min)
		return 0;
	int sum=1;
	for(int i=min;i<a;i++){
		if(a%i==0)
			sum+=f(a/i,i);
	}
	return sum;
}
int main(){
	int n;
	int a[100];
	scanf("%d",&n);
	for(int i=0;i<n;i++){
		scanf("%d",&a[i]);
		a[i]=f(a[i],2);
	}
	for(int i=0;i<n;i++){
		printf("%d\n",a[i]);
	}
	return 0;
}


A: 3
****
Q: 
const int mov[4][2] = {{-1, 0}, {0, -1}, {1, 0}, {0, 1}};

int m, n, counter;

void dfs(int m, int i) {
	//cout << m << ' ' << n << endl;
	if (m == 1) {
		++counter;
		return;
	}
	for (;i <= m; ++i) {
		if (m % i == 0) {
			dfs(m/i, i); 
		}
	}
}

int main() {
	int t, m, n;
	cin >> t;
	while (t--) {
		counter = 0;
		cin >> m;
		dfs(m, 2);
		cout << counter << endl;
	}
}

A:
1
****
