This task is to find the number of 'For' loops present in the given cpp program.

Example Input: 
int count;

void fun(int i, int j)
{
	int k;
	for(k=i; k<=sqrt(j); k++) {
		if(j%k == 0) {
			count++;
			fun(k,j/k);
		}
	}
}
int main()
{
     int N,turn,c;
      scanf("%d",&turn);
      for(c=1;c<=turn;c++)
      {
	int n,i;
	scanf("%d",&n);
	for(i=2; i<=sqrt(n); i++) {
		if(n%i == 0) {
			count++;
			fun(i,n/i);
		}
	}
	printf("%d\n",count+1);
	count=0;
}

}

Example Output: 3

Example Input: int sum = 0;
void f(int a,int s)
{
	int i;
	if(a == 1)
		sum++;
	else
	{

		for(i = s; i <= a; i++)
		{
			if(a % i == 0)
				f((a / i),i);
		}
	}
	return;
}


int main()
{
	int n, num, j;
	cin >> n;
	for (j = 1; j <= n; j++)
	{
		cin >> num;
		f(num,2);
		printf("%d\n",sum);
		sum = 0;
	
	}
	return 0;
}

Example Output: 2

Example Input: int times=1;
int used[1000]={0};
void fuck(int n)
{

	int i=0;
	for (i=2;i<=sqrt(n);i++)
	{
		if (used[i]==0&&n%i==0)
		{
			int j=0;
			for (j=0;j<=i-1;j++)
				used[j]=1;
			times++;
			fuck(n/i);
			for (j=0;j<=i-1;j++)
				used[j]=0;
		}
	}
}
int main()
{
	int n=0;
	int num=0;
	cin>>n;
	int i=0;
	for (i=0;i<n;i++)
	{
	cin>>num;
	fuck(num);
	cout<<times<<endl;
	times=1;
	int k=0;
	for (k=0;k<=999;k++)
	used[k]=0;
	}
	return 0;
}
Example Output:
5

