You will be given a definition of a task first, then an example. Follow the example to solve a new instance of the task.
This task is to find the number of 'For' loops present in the given cpp program.

main()
{
      float a[4];
      float k;
      float c;
      int i;
      for(i=0;i<4;i++)
      {
                      scanf("%f",&a[i]);
      }
      scanf("%f",&c);
      c=2*3.1415926*c/360;
      k=(a[0]+a[1]+a[2]+a[3])/2;
      double s,sq;
      sq=(k-a[0])*(k-a[1])*(k-a[2])*(k-a[3]) - a[0]*a[1]*a[2]*a[3]*(double)cos(c/2)*(double)cos(c/2);
    
      if(sq<0)
      printf("Invalid input");
      else
      {
          s=sqrt(sq);
          printf("%.4f",s);
      }
    
}

Solution: 1
Why? The number of 'for' loops in the code is given by the number of 'for' string present in the code. Since we can find the exact number of for loops, this is a good example.

New input: int s=0;
void devide(int,int);
int main()
{
    int n,m;
    cin>>n;
    while(n--)
    {
       cin>>m;
       s=0;
       devide(2,m);
       cout<<s+1<<endl;
       
    }
    return 0;
}

void devide(int a,int b)
{
    int i;
    for(i=a;i<=sqrt(b);i++)
    {
       if(b%i==0)
       {
         s++;
         devide(i,b/i);
         
       }
       
       
    }
    
}                     
     
           

Solution:
1