instruction:
This task is to find the number of 'For' loops present in the given cpp program.
question:
/*
 * 1118-4.cpp
 *
 *  Created on: 2011-11-29
 *      Author: Administrator
 */
int divide(int n,int a){
	int s=0,t=0,i;
	if(n==1) return 1;
	for(i=a;i>1;i--)
		if(n%i==0){
			s+=divide(n/i,i);
			t++;
		}
	if(t==0) return 0;
	return s;
}
int main(){
	int n,k;
	cin>>k;
	while(k>0){
	cin>>n;
	cout<<divide(n,n)<<endl;
	k--;
	}
	
	return 0;
}

answer:
1


question:
struct node
{
	int s,n;
};
void cpy_clr(struct node a[],struct node b[])
{
	int i;
	for(i=0;i<=MAX&&(a[i].s!=0||b[i].s!=0);i++)
		if(b[i].s!=0)
		{a[i].s=b[i].s;a[i].n=b[i].n;b[i].s=0;b[i].n=0;}
		else
		{a[i].s=0;a[i].n=0;b[i].n=0;}
}
int chklst(struct node a[],int n)
{
	int i;
	int result=0;
	for(i=0;a[i].s!=0;i++)
	{	if(a[i].s!=n){result=0;break;}
		else result++;
	}
	return result;
}
void init(struct node a[])
{
	int i;
	for(i=0;i<MAX;i++) {a[i].s=0;a[i].n=0;}
}
void main()
{
	struct node a[MAX],b[MAX];	
	int i,j,k,l,_n,n,sum=0;
	scanf("%d",&n);
	while(n--)
	{
	scanf("%d",&_n);
	for(l=2;l<_n;l++) 
		if(_n%l==0)	
		{	init(a);init(b); 
			a[0].s=l;a[0].n=l;
			while(chklst(a,_n)==0&&a[0].s!=0)
			{
				i=0;k=-1;
				if(a[0].s==0) break;
				while(a[i].s!=0)
				{
					if(a[i].s==_n) sum++;
					else
					{
						for(j=a[i].n;j<=(_n/a[i].s);j++)
							if(_n%(a[i].s*j)==0)
							{b[++k].s=a[i].s*j;b[k].n=j;}
					}
					i++;
				}
				cpy_clr(a,b);
			}
			i=0;
			while(a[i].s!=0)
			{
				if(a[i].s==_n) sum++;
					i++;
			}
		} 
	printf("%d\n",++sum);
	sum=0;
	}
}

answer:
5


question:
int num;
void divide(int n,int n2)
{
	int i,m1;
	m1=(int)sqrt((double)n);
	for(i=n2;i<=m1;i++)
	{if(n%i==0)
	{num++;divide(n/i,i);}//?????????????????????????????
	}
}
int main()
{
	int n,i,m;
	cin>>n;
	for(i=0;i<n;i++)
	{
		num=1;
		cin>>m;
		
		divide(m,2);
		cout<<num<<endl;
	}
	return 0;
}
answer:

2


