Reasoning: Minimum age = Average - 1 Standard deviation = 35 - 30 = 5
Maximum age = average + 1 Standard deviation = 35+ 30 = 35
Maximum number of different ages of the applicants = 35- 5 + 1 = 31
Ans: (C)
Question: The average age of applicants for a new job is 35, with a standard deviation of 30. The hiring manager is only willing to accept applicants whose age is within one standard deviation of the average age. Assuming that all applicants' ages are integers and that the endpoints of the range are included, what is the maximum number of different ages of the applicants?
Options:
(A) 8
(B) 16
(C) 31
(D) 18
(E) 34

Rationale: Speed downstream = d/t = 65/(2 1/2) = 26 kmph
Speed upstream = d/t = 45/(2 1/2) = 18 kmph
The speed of the stream = (26 - 18)/2 = 4 kmph
The answer: (B)
Question: A man rows his boat 65 km downstream and 45 km upstream, taking 2 1/2 hours each time. Find the speed of the stream?
Options:
(A) 5 kmph
(B) 4 kmph
(C) 9 kmph
(D) 8 kmph
(E) 1 kmph

Reasoning: Speed downstream = 60 + 20 = 80 kmph
Speed upstream = 60 - 20 = 40 kmph
Ans: (C)
Question: The speed of a boat in still water is 60kmph and the speed of the current is 20kmph. Find the speed downstream and upstream?
Options:
(A) 80,70 kmph
(B) 87,40 kmph
(C) 80,40 kmph
(D) 70,40 kmph
(E) 80,44 kmph

Rationale: Speed = 99 * 5/18 = 55/2 m/sec
Total distance covered = 300 + 195 = 495 m
Required time = 495 * 2/55 = 18 sec
The answer: (B)
Question: A train 300 m long is running at a speed of 99 km/hr. In what time will it pass a bridge 195 m long?
Options:
(A) 17
(B) 18
(C) 19
(D) 20
(E) 21

Reasoning: 221 + 43 = 264/17 = 9 (Remainder)
Ans: (C)
Question: A no.when divided by 220 gives a remainder 43, what remainder will be obtainedby dividingthe same no.17?
Options:
(A) 5
(B) 6
(C) 9
(D) 11
(E) 15

Reasoning: Speed = 60 * 5/18 = 50/3 m/sec
Length of the train = speed * time = 50/3 * 9 = 150 m
Ans: (B)

Question: A train running at the speed of 60 km/hr crosses a pole in 9 sec. What is the length of the train?
Options:
(A) 118
(B) 150
(C) 277
(D) 258
(E) 191