q: There are 5 sweets - Jammun, kaju, Peda, Ladu, Jilebi which can be consumed in 5 consecutive days. Monday to Friday. A person eats one sweet a day, based on the following constraints.
(i) Ladu not eaten on monday
(ii) If Jamun is eaten on Monday, Ladu should be eaten on friday.
(iii) Peda is eaten the day following the day of eating Jilebi
(iv) If Ladu eaten on tuesday, kaju should be eaten on monday
based on above, peda can be eaten on any day except
Options:
(A) monday
(B) tuesday
(C) tuWesday
(D) wednesday
(E) friday
a: OK... From the (iii) clue, peda must be eaten after jilebi. so Peda should not be eaten on monday.
The answer is (A).

q: Two persons A and B can complete a piece of work in 30 days and 45 days respectively. If they work together, what part of the work will be completed in 3 days?
Options:
(A) 1/9
(B) 1/7
(C) 1/6
(D) 1/2
(E) 1/1
a: OK... A's one day's work = 1/30
B's one day's work = 1/45
(A + B)'s one day's work = 1/30 + 1/45 = 1/18
The part of the work completed in 3 days = 3 (1/18) = 1/6.
The answer is (C).

q: 9 basketball players are trying out to be on a newly formed basketball team. Of these players, 5 will be chosen for the team. If 6 of the players are guards and 3 of the players are forwards, how many different teams of 3 guards and 2 forwards can be chosen?
Options:
(A) 23
(B) 30
(C) 42
(D) 60
(E) 126
a:
OK... Out of 6 gaurds we have to select 3 -> selection means we use C -> so 6C3
Out of 3 forwards we have to select 2 -> selection means we use C -> so 3C2
Total ways = 6C3 x 3C2 = 60
The answer is (D).