Q:

Can you explain this syntax: ros::Rate loop_rate(10);

I am trying to understand this line of code
 ros::Rate loop_rate(10);

It seems to be creating some kind of object, however this looks like a function call and I don't see where the object is named. What is this line of code doing? I understand what loop_rate is in ros, but I am new to c++ and don't understand the syntax.
#include "ros/ros.h"
#include "std_msgs/String.h"
#include <sstream>

int main(int argc, char **argv)
{
  ros::init(argc, argv, "talker");

  ros::NodeHandle n;

  ros::Publisher chatter_pub = n.advertise<std_msgs::String>("chatter", 1000);

  ros::Rate loop_rate(10);

  int count = 0;
  while (ros::ok())
  {
    std_msgs::String msg;

    std::stringstream ss;
    ss << "hello world " << count;
    msg.data = ss.str();

    ROS_INFO("%s", msg.data.c_str());

    chatter_pub.publish(msg);

    ros::spinOnce();

    loop_rate.sleep();
    ++count;
  }

  return 0;
}

A:

It's nothing sinister.
In fact, it's a pretty straightforward variable declaration.
The type is ros::Rate, the name is loop_rate, and the sole constructor argument is 10.
It does look a bit like a function call, but it isn't one. (It also looks a bit like a function declaration, which can cause problems if you're not careful!)
It's like:
std::string str("Hi!");

or:
Rectangle rect(10, 5);

or even:
int x(42);

In the case of built-ins, many of us tend to use old-style copy-initialisation instead:
int x = 42;

… though this is not so feasible for most class types.
Do you perhaps need to review declaration syntax in your C++ book?

