Simple velocity vector problem; IS MY SOLUTION MANUAL WRONG OR AM I?! 1. The problem statement, all variables and given/known data A particle starts from the origin with velocity 5i at t=0, and moves in the xy plane with a varying acceleration given by a= 6 Sqrt(t) j, where t is in s. a.) Determine the vector velocity of the particle as a function of time. 2. Relevant equations Vi=5i; a = 6 sqrt(t)j Vf=Vi+at Vf = Vfx +Vfy = (Vix+axt)i+(Viy+ayt)j =(5+0)i + (0+6sqrt(t)*t)j =5i +6t^3/2 j The solution manual states the answer as Vf=5i +4t^3/2 j Whos right here?