posted by Chemistry .
At 1650 °C the value of Kc for the equilibrium represented by the balanced equation is 2.38 x 10-1. Calculate the value of Kp at the same temperature. Express answer in scientific notation.
CO(g)+H2O(g) = CO2(g)+H2(g)
___ x 10 ____
As I remember,
Kp=Kc * (RT)n where n is equal to the sum of moles on products side minus total moles on reactants side.
I would make a quick guess it is 0.238. Why?
Kp = Kc(RT)^delta n
where dn = nproducts - nreactants.
I see 2 mols on the right and 2 mols on the left which means dn = 0, RT raised to the zero power is 1; bingo.