shown that the diffractive dip (which arises from the maximum cancellation between the bare amplitude and rescattering contribution) moves to smaller $\phi$ as the values of $p_{i\perp}$ are increased.

Here we calculate $S^2$ as a function of $\phi$ for $h(0^-)$, as well as $h(0^+)$, exclusive diffractive production. We integrate over the $p_{i\perp}$ of the outgoing protons assuming an $\exp(-b(p_{3\perp}^2 +
p_{4\perp}^2))$ behaviour of the Pomeron-proton vertices $g_{13}$ and $g_{24}$, with $b=2~\GeV^{-2}$. We use the two-channel eikonal model of Ref. [@KMRsoft]. For the central vertex we take $(\vec p_{3\perp} \times \vec
p_{4\perp})\cdot \vec n_0$ for $h(0^-)$ production and a constant for $h(0^+)$ production. The results for the suppression factor $S^2$ are shown in Fig. \[fig:5\] for $h(0^\pm)$ production of mass 120 GeV at the LHC energy, $\sqrt s = 14$ TeV.

As the azimuthal angle between $\vec p_{3\perp}$ and $\vec p_{4\perp}$ increases, the first diffractive dip, followed by the second maximum, are evident in the $S^2$ curves obtained by integrating over all $p_{i\perp}$. The dotted curves show the effect of restricting the outgoing protons to the domain $p_{i\perp}<0.35~\GeV$. As expected, the diffractive dip is pushed to larger angles and is barely reached even for the back-to-back configuration, $\phi=180^\circ$. As we see 