However, we can see that, even if the cut-off has the same order of magnitude as $\mu$, the non-perturbative potential alone will not have a significant effect. It is suppressed by the small expectation values of $\Phi_0$, given by the perturbative potential. If $\<\Phi\>
\gg \mu$ the non-perturbative potential can dominate, but this is far from the case here.

We also note that, while there are non-perturbative contributions to the one-loop effective potential, these effects are generically small. They will only need close consideration when $\<\Phi\> \gg \mu$ and even in this case, the non-perturbative contributions to the tree-level will be more important, except at singular points where the perturbative expansion breaks down.

Finally, the complete calculation with a fully realistic number of flavours is numerically intractable, and we are only able to compute everything for the case where $N_f=3$ and $N_c=2$. While this case does not correspond to a dualized theory, it does capture the important low energy phenomena: the rank condition still holds and SUSY is still broken spontaneously. However, the non-perturbative contributions are qualitatively different. Firstly the coefficient is automatically 1, irrespective of the size of the cut-off, and the determinant piece is larger by roughly $h^2 