direction of the $A^-$ in the $\omega$ rest frame. For a spin-0 $A^-$ the distribution will be cosine-squared. Again full polarization is possible if the $A^-
$ is other than spin-0, but any distribution other than cosine-squared would demonstrate that the spin is not equal to zero.

For this analysis we use all three $D^o$ final states for the $D^{*+}$ final state. To find the distributions we fit the number of events in the $M_B$ candidate plot selected on different angle bins. The $\omega\pi$ mass is required to be between 1.1 and 1.9 GeV. This leaves 111$\pm$13 events.

In Fig. \[cosd\] we show the helicity angle distribution, $\cos\theta_{D^*}$ for the $D^{*}$ decay. The data have been corrected for acceptance. We also show the expectation for spin-0 from the Monte Carlo. The data have been fit for the fraction of longitudinal polarization. We find $${\Gamma_L \over \Gamma}=0.63\pm 0.09 ~~.$$

The $\cos\theta_{D^*}$ distribution is not consistent with full polarization, yielding a $\chi^2$ of 17.7 for 5 degrees of freedom. The helicity angle distribution for the $A^-\to\omega\pi^-$, $\cos\theta_{\omega}$, is shown on Fig. \[cosom\]. Furthermore the $\cos\theta_{\omega}$ distribution is quite inconsistent with a $\cos^2\theta_{\omega}$, yielding a $\chi^2$ of 109 for 5 degrees of freedom. 