$M_{h_i}(i=1-3)$ is the mass of the charged Higgs boson eigenstates and $m_{e_{\alpha}}$ is the charged lepton mass with $\alpha = 1,2~\text{and}~3$ representing the electron, muon and tau respectively. The neutrino mass matrix would thus be a $6\times6$ matrix in the $(\nu_{L_i},\nu_{R_j})$ $(i,j=1-3)$ basis given as: $$M_\nu = \begin{bmatrix}
M^L_\nu&M^D_\nu\\(M^D_\nu)^T&M^R_\nu
\end{bmatrix},$$ where $M_{\nu}^L$ and $M^R_{\nu}$ are generated at one-loop while $M^D_\nu$ is the neutrino Dirac mass term. With the seesaw approximation, the light neutrino mass matrix appears as a combination of Type-I and Type-II seesaw: $$M_{\nu}=M^L_{\nu}-{M^D_{\nu}}^T {M^R_{\nu}}^{-1} {M^D_{\nu}}.
\label{t2t1}$$

The redefined coupling $\wt Y_l$, which we have chosen to be diagonal, is entirely determined from the charged lepton masses as can be seen from Eq. \[eq:fmass\]. Similarly $Y^q$ (chosen to be diagonal) and $\wt Y^q$ can be determined from the up and down sector quark masses and CKM mixings. For the neutrino sector we first chose $Y_l$ to be zero to get the light neutrino masses and mixings from $M^L_\nu$ alone. This approach does not work as there are too few free parameters to fit the experimental neutrino data ($\lambda^{\prime}_L$ is anti-symmetric). We then considered the case with non-zero $Y_l$ while $\l'_L$ was chosen to be zero. The light neutrino masses 