that the ABS is no longer pinned to zero energy. All plots are obtained numerically by diagonalizing Eq.  for $L=300$, $L_s=2001$, $d=51$, $\mu_{sc}/t_{sc}=0.1$, $\Delta_0/t_{sc}=0.001$, $t_w/t_{sc}=5$, $t/t_{sc}=0.25$, and $\Delta_Z^c/\Delta_0=7$. []{data-label="fig2"}](evsZ.pdf){width="\linewidth"}

We consider a discretized model described by $$\label{Htb}
H=H_w+H_s+H_t.$$ The Hamiltonian of the nanowire, which we take to be a strictly 1D system with open boundaries, is given by $$\label{Hw}
\begin{aligned}
H_w&=\sum_{x=1}^{L+L_s-1}\biggl[b^\dagger_x(2t_w-\mu-\Delta_Z\sigma_1)b_x \\
    &\hspace{40pt} -\{b^\dagger_x(t_w-i\alpha\sigma_3/2)b_{x+1}+H.c.\}\biggr],
\end{aligned}$$ where $b_x=(b_{x,\uparrow},b_{x,\downarrow})^T$ is a spinor of operators $b^\dagger_{x,\sigma}$ ($b_{x,\sigma}$) that create (destroy) an electron of spin $\sigma$ at site $x$ within the nanowire, which has length $L+L_s$, and $t_w=1/2m$ is the hopping amplitude (we set the lattice spacing $a=1$). \[Note that $\alpha$ in Eq.  is the same as that in Eq.  due to the choice $a=1$.\] The superconductor is described by a BCS Hamiltonian with constant $s$-wave pairing potential, $$\begin{aligned}
H_{sc}&=\sum_{x=L+1}^{L+L_s-1}\sum_{y=1}^{d-1}\biggl[c_{x,y}^\dagger(4t_{sc}-\mu_{sc})c_{x,y}-\{t_{sc}c^\dagger_{x,y}c_{x+1,y} \\
    &+t_{sc}c^\dagger_{x,y}c_{x,y+1}+\Delta c^\dagger_{x,y,\downarrow}c^\dagger_{x,y,\uparrow}+H.c.\}\biggr],
\end{aligned}$$ where $c_{x,y}=(c_{x,y,\uparrow},c_{x,y,\downarrow})^T$ is a spinor of operators $c^\dagger_{x,y,\sigma}$ ($c_{x,y,\sigma}$) that create (destroy) an electron of spin $\sigma$ at site $(x,y)$ within the superconductor. Again, the superconductor is taken to have open boundaries ($d$ is the thickness), and the magnetic field is incorporated only through the suppression of the pairing potential such that $\Delta=\Delta_0\sqrt{1-(\Delta_Z/\Delta_Z^c)^2}$. We note that $\Delta$ here is the 