To find the solitons of the $SU(2)$ $n=1$ model, we substitute  in  and observe that they are [*time-dependent*]{}. For $\alpha=0$,  reduces to the solution  given above. Moreover, after the redefinition $x_0\rightarrow x_0\pm {1\over
m\sqrt{1-\kappa^2}}\rm{log}(|\alpha| {1-\sqrt{1-\kappa^2}
\over\sqrt{1-\kappa^2}})$,  reduces in the limit $\alpha\rightarrow \pm \infty$ to the embedded SO(2) solitons found in the previous section. The charge and the mass of the solutions  are $$Q=\mp 4 \sqrt{1-\kappa^2} e^\sigma \ ,
\eqn\mthreed$$ and $$E= 2 m \sqrt{1-\kappa^2} e^\sigma\ ,
\eqn\mfourd$$ respectively, where $$e^\sigma=1+{\alpha \kappa^2\over \sqrt{1-\kappa^2} \sqrt{1+\alpha^2 
\kappa^2}}\bigg[- {\pi\over2}+{\rm
arc}\tan \big({\alpha \kappa^2\over \sqrt{1-\kappa^2} \sqrt{1+\alpha^2
\kappa^2}}\big)\bigg]\ .
\eqn\msixd$$ The constant $\alpha$ is not a modular parameter because the mass and the charge depend upon it. For example, the mass of the $\alpha=0$ solutions  is $$E=2 m \sqrt{1-\kappa^2}\ .
\eqn\msixdd$$ Note that the mass  of the solitons as a function of $\alpha$ has critical points at $\alpha\rightarrow\pm\infty$. It turns out that $E(+\infty)$ is the absolute minimum and is the value of the mass of the embedded static solution   for $n=1$, while $E(-\infty)$ is the absolute maximum and is the value of the mass of the embedded static solution   for $n=1$. This is in agreement with the corresponding limits of the solution  mentioned above. The moduli space 