within the macro-sphere of radius $r= 50$ km, the following order of magnitude: $${\cal P}\approx {r_0^3\over r^3}\approx \left({5.3\times 10^{-11} \,{\rm m}\over 5\times 10^4 \,{\rm m}}\right)^3\approx 10^{-45}.
\label{eq2}$$ This is undoubtedly a very small number, with 45 zeros after the decimal point! And of course, we can easily do the same calculation for larger macro-spheres, i.e., waiting more time than just a second. For example, if we wait $10$ s, the radius of the macro-sphere will increase by a further factor of 10 (from $50$ km to $500$ km), and consequently the estimated value of the probability ${\cal P}$ will decrease from $10^{-45}$ to $10^{-48}$, i.e., by a factor of a thousand, and so on.

Now that we have obtained an estimate of the probability of quantum self-teleportation of a hydrogen atom from an initial micro-sphere to a given final micro-sphere, we must consider the case of an entire macroscopic body, like that of a human being of planet Earth, which we can assume to have a mass of $100$ kg. Here of course we have to face the already mentioned problem that a macroscopic body has the property of spatiality, and therefore cannot be conveniently described by a wave function 