coefficient $C^{\rm BE}(0)$ diverges as $x_0 \rightarrow 0$. This may be interpreted as a Bose-Einstein condensation, and shows that our theory breaks down in describing properly the transport of Bose-Einstein condensates.]{.nodecor}

\[remarks FD\] [In mesoscopic physics, one is usually interested in electronic transport at low temperature, $x_0
  = -\mu/(k_\B T) \rightarrow -\infty$. Observe that in this limit $C^{\rm FD}(1) \rightarrow 0$ and consequently $L_{ij}^{{\rm
FD}(1)} \rightarrow 0$. In order to have non-zero transport coefficients $L_{ij}^{{\rm
  FD}(1)}$ in this regime, one usually considers the first order term in the Taylor expansion, $\Gamma_{ij}(E) = \Gamma_{ij}(\mu) +
  \Gamma'_{ij}(\mu) (E-\mu) + O((E-\mu)^2)$, which leads to $L_{ij}^{{\rm
FD}(1)} \sim \Gamma'_{ij}(\mu)$.]{.nodecor}

[Observe that the transport coefficients $L_{ij}^{(k)}$ depend on the properties of the quantum dots through the scattering matrix $S$. Here we can see why the assumption A\[Assumption Gamma2\] is useful. Indeed, suppose that $t_{ii} = M_i$ for some $i$ (total reflection). Then $t_{ij} = 0$ for all $j \not = i$ and consequently $L^{(k)}_{ij} = 0$ for all $j$. In other words, in such a situation the $i$-th reservoir is disconnected from the rest of the system.]{.nodecor}

Looking at the relations –, one sees that the transport coefficients are related as follows: $$L_{ij}^{(0)} = \frac{e^2}{h} 