R_m} = 0\; ,$$ which using Eq. (\[d-Growth-Rate-Henry\]) leads to the following result $$\label{R_m-Henry-1}
R_m = R_c + \left( R_c^2 + R_c R_\sigma \right)^{1/2}\; .$$ Taking into account the strong inequality $R_\sigma \gg R_c$, we can simplify the obtained expression for $R_m$: $$\label{R_m-Henry}
R_m \simeq \left( R_c R_\sigma \right)^{1/2}\; .$$

The second stage of the process will be when the bubble growth occurs within the interval of sizes $$\label{2-nd}
R_m \leq R \leq R_\sigma\; .$$ During all this stage, as $R_m \simeq (R_c R_\sigma)^{1/2} \gg R_c$, it is already valid that $R \gg R_c$, thus the driving force $n_0 - n_R$ remains practically constant. As a result, bubble growth decelerates, although, as it was noted above, the counteraction of Laplace pressure to the growth gradually is attenuated. The Laplace contribution $2 \sigma/R$ to the pressure inside the bubble decreases during the second stage by $(R_\sigma/R_c)^{1/2}$ times and at the completion of this stage becomes comparable with the external pressure $\Pi$ contribution (from Eq. (\[R\_s\]) we have strict equality $2 \sigma/R_\sigma = 3 \Pi/2$). It is this physical condition that defines the completion of the second stage.

On the subsequent, third stage, which corresponds to the interval of sizes $$\label{3-rd}
R 