Born double-Pomeron-exchange amplitude for process [(\[eq:adder\])]{} now contains the kinematical factor $(\vec p_{3\perp}\times \vec p_{4\perp})\cdot \vec n_0$ and this, in turn, implies that the Fourier transform contains the factor $(\vec b_1 \times \vec b_2)\cdot \vec n_0$. Thus the corresponding amplitude $T_{PP}^{h(0^-)}(s_1,s_2,\vec b_1,\vec b_2)$ tends to zero as $\vec b_1$ or $\vec b_2\to0$. As a result, the suppression arising from rescattering is less effective, and the factor $S^2$ is larger than for $h(0^+)$ production. Also the $\phi$ distribution is distorted due to absorption.

The effect of the absorptive corrections on the angular correlations $\phi$ between the outgoing protons was discussed in detail in Ref. [@a17] for $h(0^+)$ production[^8]. There it was shown that the absorptive corrections are largest in the back-to-back configuration where $\vec p_{3\perp}$ is directed against $\vec p_{4\perp}$, since in this case both $t_1 \simeq -(\vec k_\perp + \vec p_{3\perp})^2$ and $t_2\simeq -(\vec
k_\perp - \vec p_{4\perp})^2$ can be minimized simultaneously by the same momentum $\vec k_\perp$ transferred in the elastic rescattering, see Fig. \[fig:3\](b). Thus for $\phi = 180^\circ$ the momentum is transferred mainly through the rescattering amplitude. The suppression factor $S^2$ was plotted versus $\phi$ for different choices of $p_{3\perp}$ and $p_{4\perp}$ in Ref. [@a17]. It was 