state of Nature, $$\frac{r( 1-p) ( 1-q) }{r( 1-p) (1-q) +( 1-r) pq} \geq \frac{1}{2},$$ if and only if $$r \geq \bar{p}\equiv\frac{pq}{1-p-q+2pq}.$$

The FIS can be obtained from honest sequential majority voting for all ability triples if and only if the highest ability juror votes second.

If the highest ability juror R votes first (R = $J_1$), then $J_2$ and then $J_3$ will copy his vote in a cascade. This will fail to choose the FIS if $r<\bar{p}$ and $J_2$ and $J_3$ both have the opposite signal to R, since in this case the FIS is $s_{2}=s_{3}$, while the verdict is $s_{1}$. If R votes last (R = $J_3$) and $r>\bar{p}$, then R’s signal $s_{r}$ is the FIS. However, the first two jurors $J_1$ and $J_2$ will vote their signals, creating a majority verdict for their signals, which might not be $s_{r}$. Hence a jury where R votes first or last does not always give the FIS.

On the other hand, suppose that R votes second (R = $J_2$). Then $J_1$ and $J_3$ are P and Q, in some order. So $J_1$ and $J_2$ = R vote their signals. If they are the same, that is the verdict and the 