L_i T L_j + \lambda_1 H_1 T H_1 +
\lambda_2 H_2 \oline{T} H_2  \nonumber \\
%
 & & + M_T T \oline{T} + \mu H_1 H_2 ,
%
\label{Wnu} \end{aligned}$$ where the $SU(2)$ indices on the doublets and triplet have been suppressed. Strictly speaking, the coupling $\lambda_1$ is not necessary to generate the required neutrino masses, but given the Standard Model charge assignments of the fields $T$ and $\oline{T}$ there is no [*a priori*]{} reason to exclude this coupling. The mass scale $M$ in (\[mnu\]) is to be identified with $M_T$ in this case, and the matrix $\lambda_{T}$ is symmetric in its generation indices. From the Lagrangian determined by (\[Wnu\]), it is clear that should the auxiliary fields of the chiral supermultiplets for the triplets vanish in the vacuum $\lang F^T \rang = \lang F^{\oline{T}} \rang = 0$, and we assume no vevs for the left-handed sneutrino fields, then there is a simple solution for the vevs of the neutral components of the triplet fields $$%
\lang T \rang = -\frac{\lambda_2 \lang H_2 \rang ^2}{M_T} \; ;
\quad \lang \oline{T} \rang = -\frac{\lambda_1 \lang H_1 \rang
^2}{M_T} ,
%
\label{Tvevs}$$ implying $m_{\nu} = \lambda_T \lang T \rang$.

Recent models of 