model was shown to give the second plateau at twice the energy of the first plateau [@zz] [@ibm]. That is to say the high energy rise was equal to the low energy rise. In the more detailed calculations performed here the high energy rise is less than the low energy rise.

We next turn to $^{10}\mbox{Be}$. Here there are two channels: $J=0^+$ $T=1$ $\rightarrow$ $J=1^+$ $T=1$ and $J=0^+$ $T=1$ $\rightarrow$ $J=1^+$ $T=2$. Let us discuss the latter channel first. The behaviour for $T=2$ in $^{10}\mbox{Be}$ is similar to that for $T=1$ in $^8\mbox{Be}$. As shown in Figs $3$ and $4$ for the ($x,y$) and $Q \cdot Q$ interactions respectively, there are two rises separated by a plateau and here the second rise is about twice the first rise for the ($x,y$) interaction. For the $Q \cdot Q$ interaction (with $\chi=0.3615$) the low energy rise is to $1.7$ $\mu_N^2MeV$ and the next rise is to $2.6$ $\mu_N^2MeV$ -only $1.5$ to one.

There is a big difference in the cumulative energy weighted distributions, shown in Figs 5 and 6, for the $J=0^+$ $T=1$ $\rightarrow$ $J=1^+$ $T=1$ channel. For the ($x,y$) interaction the first plateau (at about $2.5$ $\mu_N^2MeV$) is not very flat, 