where $\tilde{\omega} = \omega - \tilde{\lambda} v^4 V$.

Now we easily derive the tree level estimates: $$\begin{aligned}
M_H &=& \sqrt{2}|\mu| = 2\sqrt{4+(2\lambda-1)/\gamma}; \nonumber\\
M_W &=& \sqrt{2} \frac{v}{\sqrt{\beta}} =  \sqrt{\frac{\gamma(4\gamma+2\lambda-1)}{2\lambda\beta}}; \nonumber\\
M_W &=& {\rm cos}\theta_W M_Z\nonumber\\
M_H/M_W &=& \sqrt{8\lambda \beta/\gamma^2};\nonumber\\
\Lambda &=&\pi \sqrt{\frac{2\lambda\beta}{\gamma(4\gamma+2\lambda-1)}} \, [80\, {\rm
GeV}];\label{tree}\end{aligned}$$ The fine structure constant is given by $\alpha = \frac{{\rm tg}^2 \theta_W}{\pi
\beta(1+{\rm tg}^2 \theta_W)}$ and does not depend on $\lambda$ and $\gamma$. From (\[tree\]) we learn that at the tree level LCP on the phase diagram corresponds to fixed $\beta = \frac{{\rm tg}^2 \theta_W}{\pi \alpha(1+{\rm tg}^2 \theta_W)} \sim 10 $ and $\eta = M_H/M_W$, and is given by the equation $\lambda(\gamma) =
\frac{\eta^2}{8\beta} \gamma^2$.

The important case is $\lambda = \infty$, where the tree level estimates give $$\begin{aligned}
M_H &=& \infty; \nonumber\\
M_W &=& \sqrt{\frac{\gamma}{\beta}}; \nonumber\\
M_Z &=& \sqrt{\frac{\gamma}{\beta}}{\rm cos}^{-1}\theta_W; \nonumber\\
\Lambda &=& \pi \sqrt{\frac{\beta}{\gamma}} \, [80\, {\rm GeV}];\label{treei}\end{aligned}$$

In the $SU(2)$ gauge Higgs model for the small values of $\lambda << 0.1$ the tree level estimate for $M_H/M_W$ gives values that differ from the renormalized ratio by about 20%[@11]. The tree level estimate for the ultraviolet cutoff is about $1$ TeV at $\lambda =
\infty,\gamma = 1, \beta = 15$ that is 