of the source of the Einstein equation is related to component $\mathcal{J}^{0}$ of the source of the combined Maxwell and Bianchi equations $\mathcal{E}^{a}$. If the electromagnetic fields have only one static point-like source at $r=0$, $\mathcal{E}^{t}\sim
\frac{1}{\sqrt{2}}q\delta^{(3)}(\vec{x})/ \sqrt{|g|}$, then using the fact that $\mathcal{Z}/X$ is real (see Eq. (\[eq:noNUT\]) and the previous discussion)

$$\mathcal{E}^{0t}= \pm 2\sqrt{2} \left.|\mathcal{Z}|\right|_{r=0}
\delta^{(3)}(\vec{x})/ \sqrt{|g|}\, ,$$

which shows that, if the attractor equations are satisfied, the source for the Einstein equations is just $\pm |\mathcal{Z}_{\rm fix}(q)|$. The sign is related to the positivity of $\langle\, \mathcal{R} \mid q \, \rangle$, which is, as was discussed before, associated to the positivity of the mass etc. This is the only value admissible by supersymmetry, since we can understand this source as a source of energy. However, if the scalars take non-admissible values we will find the wrong sign or a zero at $r=0$ and supersymmetry will be broken at the source: we will have to require that the attractor equations are solved by admissible values of the scalars.

The second piece of information we can obtain from the real part concerns the spacelike components of the electromagnetic sources. Combined with the spacelike components of the imaginary part, Eq. 