calculation. This leads to the following trial central charge $$\label{ctr1N4}
\begin{split}
c_{r}^{\text{tr}} &= -3 \,\eta_{\Sigma} \,d_{G} \left[ t_{\frak{b}}^{(\lambda)}(q_{\rm tr}^{(\lambda)})^2 +t_{\frak{b}}^{(\chi_1)}(q_{\rm tr}^{(\chi_1)})^2+t_{\frak{b}}^{(\chi_2)} (q_{\rm tr}^{(\chi_2)})^2 + t_{\frak{b}}^{(\chi_3)}(q_{\rm tr}^{(\chi_3)})^2 \right] \\[6 pt]
 &= \frac{3}{8} \,\eta_{\Sigma} \,d_{G}\,(3-\epsilon^2+4\mathfrak{b}\epsilon)\;.
\end{split}$$ This expression for $c_{r}^{\text{tr}}$ is the same as for the simple reason that the fermions $\chi_1$ have vanishing charges under $T_F$ and $T_R $. Then $t_{\frak{b}}^{(\chi_1)}=0$ and thus reduces to . One can now extremize $c_{r}^{\text{tr}}$ as a function of $\epsilon$ to find that the right-moving central charge is given by and the resulting $(0,2)$ SCFTs are the same as in Section \[subsec:LSFT\].

However, there is also a new feature of these RG flows not present in Section \[subsec:LSFT\]. For a fixed value of the flavor flux $\mathfrak{b}$, the trajectory of the RG flow from $\mathcal{N}=4$ SYM may not be unique given that now one has two scales with which to deform, namely, the mass $m$ and the volume of the Riemann surface. Thus, for a given value of $\frak b$, there should be a one parameter family of RG flow trajectories which connect $\mathcal{N}=4$ SYM with the corresponding two-dimensional $(0,2)$ SCFT. In contrast, the RG flow trajectory from the LS fixed point to the same 