orbital transitions is strongly deformed nuclei. Can one conclude that $^{10}\mbox{Be}$ is not strongly deformed? The answer, by examining the tables of Raman et. al. [@ram] is no! There is a strong $E2$ connecting the $0_1^+$ and $2_1^+$ states in $^{10}\mbox{Be}$. From this the authors conclude that the deformation parameter $\beta$ is about $1.13$ -quite enormous. Of course $^8\mbox{Be}$ might have an even stronger $E2$ transition -there is no data on this in the Raman paper [@ram], probably because of the rapid decay of the $2_1^+$ state into two alpha particles.

The cumulative energy weighted strength for orbital transitions in $^8\mbox{Be}$ and $^{10}\mbox{Be}$
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In this section we present results and figures for the cumulative energy weighted sum of magnetic dipole strength.

We are motivated in so doing by various energy-weighted sum rules that have been developed e.g. by Zheng and Zamick [@zz], Heyde and de Coster [@ibm], Moya de Guerra and Zamick [@dz1], Nojarov [@no], Hamamoto and Nazarewicz [@hz] and Fayache and Zamick [@fay]. We will focus in particular on the orbital strength for which the operator is ($\vec{L_{\pi}}-\vec{L_{\nu}}$)/2. In a previous publication we presented results for the ($x,y$) interaction with $x$=$1$, $y$=$1$ for $^8\mbox{Be}$ [@fay]. In this work 