_{2}$ from $\{x_{r},b_{j},f_{2}\}$ to $\{x_{r},b_{j},f_{1}\}$ (represented by the domains $D_{13}$ and $D_{13}+\mathcal{P}$) and they both have an odd number of holomorphic representatives. Thus, we have $\# \widehat{\mathcal{M}}(\phi _{1})=\# \widehat{\mathcal{M}}(\phi _{2})=1$. The group $H_{1}({Y_{m,n}};{\mathbb {Z}})/\operatorname{Tors}={\mathbb {Z}}$ is generated by the simple closed curve $\mu _{3}$ on the Heegaard diagram (see Figure \[fig:heeg\]), so $a(\gamma ,\phi _{1})=0$ and $a(\gamma ,\phi _{2})=1$. It follows that $$A_{[\gamma ]}([\{x_{r},b_{j},f_{2}\},i])=[\{x_{r},b_{j},f_{1}\},i]$$ and the action on $\{x_{r},b_{j},f_{1}\}$ is trivial. So $d_{b}({Y_{m,n}},\mathfrak{s})$ is given as the absolute grading of the generator $\{x_{r},b_{j},f_{1}\}$ and $d_{t}({Y_{m,n}},\mathfrak{s})$ is the absolute grading of the generator $\{x_{r},b_{j},f_{2}\}$. For the definitions of the bottom and top correction terms, see [@LRS Definition 3.3].

[Absolute gradings]{} \[absolute\]

The absolute grading of the generators of $\widehat{HF}({Y_{m,n}})$ can be calculated using the cobordism $W$ from ${Y_{m,n}}$ to the simpler 3–manifold $-L(m,1)\# S^{1}\times S^{2}$ whose absolute grading is known. To construct the cobordism, we use a pointed Heegaard triple $(\Sigma ,\vec{\alpha },\vec{\beta },\vec{\gamma },z)$. Here the first two sets of the curves $\vec{\alpha },\vec{\beta }$ stay the same as before, so $Y_{\alpha ,\beta }={Y_{m,n}}$. The curves $\gamma _{1}$ and $\gamma _{3}$ are parallel copies of the curves $\beta _{1}$ and $\beta _{3}$ respectively, and the curve $\gamma _{2}$ is homologous 