\text{if} \quad Y^\epsilon_t=+1 \quad \text{and} \quad mod(t,T)> T/2
\end{array}
\right.\end{aligned}$$ and similarly the averaged Out-of-Phase Markov Chain is defined by $$\begin{aligned}
\left\langle \overline{Y}^\epsilon_t \right\rangle=E\left(\overline{Y}^\epsilon_t\right)\end{aligned}$$ Define two new functions by $$\begin{aligned}
\phi^-(t)=
\left\{
\begin{array}{c}
1 \quad \text{if} \quad mod(t,T)\leq T/2\\
0 \quad \text{if} \quad mod(t,T)> T/2
\end{array}
\right.
\quad \text{and} \quad 
\phi^+(t)=
\left\{
\begin{array}{c}
0 \quad \text{if} \quad mod(t,T)\leq T/2\\
1 \quad \text{if} \quad mod(t,T)> T/2
\end{array}
\right.\end{aligned}$$ The following trajectories are Fourier transformed $$\begin{aligned}
\tilde{x}(\omega)&=\mathcal{F}\left(
\langle x_t  \rangle
\right)
=
\langle \mathcal{F} \left(x_t\right) \rangle
\\[0.5em]
\tilde{Y}(\omega)&=\mathcal{F}\left(
\left\langle Y^\epsilon_t \right\rangle
\right)
=
\langle \mathcal{F} \left(x_t\right) \rangle\end{aligned}$$ The linear response is defined as the intensity of the Fourier Transform at the driving frequency $\Omega$. $$\begin{aligned}
X_{lin}=\left|\tilde{x}\left(\frac{\Omega}{2\pi}\right)\right|
\quad \text{and} \quad 
Y_{lin}=\left|\tilde{Y}\left(\frac{\Omega}{2\pi}\right)\right|\end{aligned}$$ Note that the forcing is periodic and monochromatic. Now we can define the six measures. For the diffusion case only $M_1$ and $M_2$ are defined $$\begin{aligned}
M_1=\frac{1}{F}X_{lin}
\quad \text{and} \quad 
M_2=\frac{1}{\epsilon F}X_{lin}\end{aligned}$$ where $F$ is the magnitude of the forcing. For the Markov Chain $M_1$, $M_2$, $M_3$, $M_4$, $M_5$ and $M_6$ are all defined as $$\begin{aligned}
M_1&=\frac{1}{F}Y_{lin}\\
M_2&=\frac{1}{\epsilon F}Y_{lin}\\
M_3&=\int_0^T \left\langle Y^\epsilon_t \right\rangle^2 dt\\
M_4&=\int_0^T \left\langle \overline{Y}^\epsilon_t \right\rangle dt\\
M_5&=\int_0^T
\phi^-(t)\ln\left(\frac{\phi^-(t)}{\overline{\nu}_-(t)}\right)+
\phi^+(t)\ln\left(\frac{\phi^+(t)}{\overline{\nu}_+(t)}\right)
dt\\
M_6&=\int^T_0
-\overline{\nu}_-(t)\ln\overline{\nu}_-(t)
-\overline{\nu}_+(t)\ln\overline{\nu}_+(t)\,
dt\end{aligned}$$ Note that in definition of 