+ z^+ \left(  \phi_Q \right) + z^0\right] $, over both angles $\phi_Q$ and $\phi_{N_{\Omega}}$: $$\begin{aligned}
P_{ce} \left(N_{\Omega}\right) &\equiv&  Z_{ce}^{-1} \times
\int \limits_{-\pi}^{\pi} \frac{d\phi_{N_{\Omega}}}{2\pi} \int
\limits_{-\pi}^{\pi} \frac{d\phi_{Q}}{2\pi} ~ e^{-iN_{\Omega}
  \phi_{N_{\Omega}} } ~ e^{-i Q \phi_{ Q} } ~\mathcal{Z} \left(
  \phi_{N_{\Omega}}, \phi_Q \right) \\ 
 &=& I_Q^{-1}\left(2z \right) \times 
\frac{\left(z^-_{\Omega}\right)^{N_{\Omega}}}{N_{\Omega}!} ~ \sum 
\limits_{a=0}^{\infty} ~ \frac{\left(z^-_{\bar \Omega}\right)^{a}}{a!} ~
\frac{z^{Q+N_{\Omega}+a}}{\left(Q+N_{\Omega}+a\right)!}~,\end{aligned}$$ where in CE $z^-_{\Omega} =  z^-_{\Omega} \left(\phi_{N_{\Omega}}=\phi_Q=0
\right)$, $z^-_{\bar \Omega} =  z^-_{\bar \Omega} \left(\phi_Q=0 \right)$, and $z= z^+\left(\phi_Q=0\right)=z^0$. For the respective first two moments one finds from Eq.(\[Moments\]): $$\begin{aligned}
\langle N_{\Omega} \rangle = z^-_{\Omega } ~ \frac{I_{Q+1} \left(2z
  \right)}{I_Q   \left(2z \right)}~,  \qquad \textrm{and} \qquad 
\langle N^2_{\Omega} \rangle =   \left( z^-_{\Omega }\right)^2 ~\frac{I_{Q+2} 
  \left(2z \right)}{I_Q \left(2z \right)} +  z^-_{\Omega }~ \frac{I_{Q+1} 
  \left(2z\right)}{I_Q   \left(2z \right)}~. \end{aligned}$$ Thus, we obtain the well known canonical suppression of yields [@CEyield; @CEfits; @CEtransport; @RateEqYield] and fluctuations [@CEfluc1; @RateEqFluc]. The result, however, is completely independent of the position of the segment $\Omega$. And therefore the scaled variance, Eq.(\[ScaledVar\]), takes the form: $$\begin{aligned}
\omega^{ce}_{\Omega} =  1 +  z^-_{\Omega} ~\left[ \frac{I_{Q+2}
  \left(2z\right)}{I_{Q+1}   \left(2z \right)}  -\frac{I_{Q+1}
  \left(2z\right)}{I_Q   \left(2z \right)}  \right]~, \qquad \textrm{and}
\qquad \omega^{ce}_{4\pi} =  1 +  z ~ \left[ \frac{I_{Q+2}
  \left(2z\right)}{I_{Q+1}   \left(2z \right)}  -\frac{I_{Q+1}
  \left(2z\right)}{I_Q   \left(2z \right)}  \right]~,\end{aligned}$$ where $\omega_{\Omega}$ is the width of 