$0$           $0$           $0$           $R_{5}$       $0$           
              $F$             $0$           $0$           $0$           $0$           $0$           $R_{6}$       
                                                                                                                  
   Sum of the column entries  ${\ Z}_{1}$   ${\ Z}_{2}$   ${\ Z}_{3}$   ${\ Z}_{4}$   ${\ Z}_{5}$   ${\ Z}_{6}$   

  : []{data-label="A5"}

whose core is the matrix (\[A6\]) $$\mathbb{B}=\left( 
\begin{array}{cccccc}
R_{1} & P_{1} & P_{5} & Q_{4} & 0 & S_{1} \\ 
Q_{1} & R_{2} & P_{2} & P_{6} & 0 & 0 \\ 
Q_{5} & Q_{2} & R_{3} & P_{3} & 0 & 0 \\ 
P_{4} & Q_{6} & Q_{3} & R_{4} & 0 & 0 \\ 
V_{1} & 0 & 0 & 0 & R_{5} & 0 \\ 
0 & 0 & 0 & 0 & 0 & R_{6}\end{array}\right) ,  \label{A6}$$ whose entries contain the number of counted vehicles in an *ad hoc* interval of time, or by averaging from previous observations. The matrix (\[A1\]) is a submatrix of matrix (\[A6\]).

As the time goes on the distribution of vehicles, in matrix (\[A6\]), changes due to their circulation. The sum of the entries of row $i$, $W_{i}\left( 0\right)
=\sum_{j}B_{ij}$, gives the number of vehicles that are in site $i$ plus those that left it having as destination all the other sites, excluding site $F$, which is a depository of 