charm sector is complicated particularly in the baryon sector. Yet, using the local hidden gauge approach [@hidden1; @hidden2; @hidden4; @Yama; @hideko] the task is notably simplified and clarified simultaneously. In the hidden gauge approach the meson-baryon interaction in $\textrm{SU(3)}$ is obtained exchanging vector mesons as in Fig. \[diagXic\].

![\[diagXic\] Vector exchange in the meson-baryon interaction.](diagXic.eps){width="80.00000%"}

The ingredients needed are the vector(V)-pseudoscalar(P)-pseudoscalar(P) Lagrangian $$\begin{aligned}
\label{vppLag}
\mathcal{L}_{VPP} = -i g\, \langle \,\, [\,\Phi,\,\partial_{\mu} \Phi\,]\, V^{\mu}\, \rangle \, ,\end{aligned}$$ with $$\label{vfields}
V_\mu=\left(
\begin{array}{ccc}
\frac{1}{\sqrt{2}}\rho^0+\frac{1}{\sqrt{2}}\omega & \rho^+ & K^{*+}\\
\rho^- &-\frac{1}{\sqrt{2}}\rho^0+\frac{1}{\sqrt{2}}\omega & K^{*0}\\
K^{*-} & \bar{K}^{*0} &\phi\\
\end{array}
\right)_\mu\ ,$$ and the vector(V)-baryon(B)-baryon(B) Lagrangian $$\begin{aligned}
\label{vbbLag}
\mathcal{L}_{VBB} = g\, \Big( \langle \bar{B} \gamma_{\mu} [V^{\mu},B] \,\rangle +
\langle \bar{B} \gamma_{\mu} B \rangle \langle V^{\mu} \rangle \Big) \, ,\end{aligned}$$ with $g=m_V/2f_\pi$ and $m_V$ the mass of the vector mesons (we take an average of about 800 MeV).

It is easy to prove that the picture of the vector meson exchange with these Lagrangians gives rise to the same interaction as Eq.  taking $q^2/m^2_V\to 0$ in the propagator of the exchanged vector, which is quite good at low energies. One can even keep this term in the propagator, as done in Ref. [@xiaooz], since in the meson-meson 