\tilde{T}^*)$ is appended to the tree level Kähler potential. It turns out that the correction term has a crucial role to play in determining the AdS nature of the potential. The corrected Kähler potential has the form,

$$\label{kahler2}
\hat K=M_p^2\left[-3 \log (\tilde{T} +\tilde{T}^*)-\log (\tilde{S} + 
\tilde{S}^*)+h(\tilde{T} + \tilde{T}^*)\right],$$

Where $\tilde S=\frac{S}{M_p}$ and $\tilde{T}=\frac{T}{M_p}$. For these choices, the scalar potential (\[pot2\]) can be written as,

$$\label{scalarpot}
V_h=\frac{1}{M_p^2}\frac{e^{ h}}{16 \tilde s \tilde t^3}\left[4  \tilde s^2 \left
[f'(\tilde s)-\frac{\hat W}{2 \tilde s} \right]^2+  \frac{1}
{(\frac{3}{4 \tilde t^2}+h'')} \left[a A e^{-a \tilde t} +\hat W 
 \left(\frac{3}{{2 \tilde t}}-h'\right)\right]^2-3 \hat W^2 \right].$$

Here, $V_h$ stands for the scalar potential in the hidden sector only, $\tilde t$ and $\tilde s$ are the real components of the complex moduli $\tilde T$ and $\tilde S$ respectively. Following [@KKLT] we assume $W_T = W_0 + A e^{-a \tilde{t}}$, with the condition for susy preserving minimum (\[condition\]),

$$W_T = \frac{A a e^{- a \tilde{t}_0}}{-\frac{3}{2 \tilde{t_0}} + h'(\tilde{t_0})}, 
\label{constraint1}$$

Here $t_0$ and $s_0$ are the VEVs of the real superfield $t$ and $s$ respectively. Remembering that the SUSY breaking at the observable sector at the scale $\Lambda$ ( $\sim$ Tev ) results into positive vacuume energy $\sim$ $\Lambda^4$, whereas the observed 