potential for the hidden sector $V_h$ now turns out to be, $$\label{pothidden}
V_{h0} = \frac{1}{M_p^2} e^{\frac{-\alpha}{2 \tilde t_0} - 
4 \alpha_1 {{\tilde t}^2}_0}\frac{m^6}{4 \tilde s_0 \tilde t_0} \frac{((\ln{\tilde{s}_0})^2 
+ k \ln{\tilde{s}_0} + k_1 \tilde{s}_0)^2}{\left(3-\frac{\alpha}{\tilde t_0} 
-8 \alpha_1 {{\tilde t}^2}_0\right)} \left(\frac{3}{2 \tilde t_0}
-{\frac{\alpha}{\tilde 4 t_0^2} + 4 \alpha_1 \tilde t_0}\right)^2.$$ From the preceding equation it can be estimated that with $k_1 \sim
10^{-17}$ and $m \sim 10^{14} ~\rm GeV$ the vacuum energy becomes $\sim 10^{12} ~\rm GeV^4$, provided the minimum of the potential corresponds to $\tilde s_0=1$. Such a minimum can indeed be found for suitable values of the parameters which is depicted in Fig(\[3dminimum\]).

![3D plot of $V_{h}$ vs moduli $\tilde s$ $\&$ $\tilde t$ in units of $10^{12}~\rm GeV^4$ for parameter values $A = - 1.60, W_0 = 1.7, a = 0.1, k= 0.1, \alpha = 0.72, \alpha_1 = 1.5$. Here $A$ and $W_0$ represent values in the unit of $\Lambda_N^3$.[]{data-label="3dminimum"}](minimum.eps)

While $\alpha$ and $\alpha_1$ are chosen so as to have the AdS minimum, the constant parameter $k$ is set at $O(1)$ values to satisfy the condition (\[const3\]). All the soft susy breaking parameters are now estimated assuming $k_1 \sim
10^{-17}$ and $m \sim 10^{14} ~\rm GeV$ along 