been stated previously, the same result can be obtained by substituting anti-Hermitian fields $A_{\mu}$ in (), using (), and taking the limit $\Lambda^2\to\infty$.

As the next step, we compute the electric isovector form factor. In this case, the regularization is necessary and the second order terms in the FSD expansion have to be taken into account. Contribution to the first order come from the terms of $W_2$ containing both $A_4$ and $\Omega$. The second order includes terms from $W_1$ and $W_3$.

In the first order FSD term we insert unity: $\sum_m \psi^{\dagger}_m (x) \psi_m(x)$ and we get identical overall isospin-space factor of the form:

$$j^{em}_4 \sim \psi^{\dagger}_n \Omega \psi_m \
\psi^{\dagger}_m R \tau^3 R^{\dagger} \psi_n \ ,
\eqno(\EVCUR)$$

to which the Fierz identity () is applied. Then, we express $\Omega$ in terms of the rotational matrix $R$ using the identity:

$$\Omega \equiv - i R {\dot R}^{\dagger} \equiv
-i {\dot R}^{\dagger} R
\eqno(\OMR)$$

and ().

Finally, from the quantization rule for the collective coordinate $\Omega$ (), where the moment of inertia $I$ has been computed numerically in \[\], we arrive at the following expression for the electric isovector form factor:

$$\openup3\jot
\eqalign{
G_E^{T=1} (q^2) = &\int d^3 x\ e^{-i \vec 