1.03                       1.889   3.03       4.44       0.96
  89    (2)$_{c}$-11   0         1          4.0000           1.07                       1.555   2.00       1.90       0.98
  90    (1)$_{c}$-12   0         0                                                      1.120   0.97       0.42       1.094
  92    (6)$_{c}$-7    0         15         2.0976           1.04                       2.700   6.26       19.70      0.94
  93    (8)$_{c}$-5    0         28         1.9272           1.13                       2.414   4.99       12.43      0.964
  94    (5)$_{c}$-8    0         10         2.2913           1.06                       2.377   5.01       12.51      0.967
  95    (9)$_{h}$-4    0         45         1.5811                                      2.205   4.06       8.30       0.967
  96    (4)$_{c}$-9    0         6          2.5820           1.07                       2.181   3.89       7.38       0.998
  97    (7)$_{h}$-6    1         28         1.6956           0.96                       1.942   3.04       4.80       0.967
  98    (3)$_{c}$-10   0         3          3.0822           1.08                       1.926   2.91       4.19       1.012
  99    (5)$_{h}$-8    1         15         1.8708           0.86                       1.519   1.74       1.86       0.904
  100   (2)$_{c}$-11   0         1          4.2426           1.14                       1.611   1.90       1.98       0.981
  100   (4)$_{h}$-9    1         10         2.0000           0.83                                                     
  101   (3)$_{h}$-10   1         6          2.1794           0.77                       1.936   2.82       6.54       0.813
  ----- -------------- --------- ---------- ---------------- -------------------------- ------- ---------- ---------- -----------

4, EIGENENERGIES

After performing the diagonalization, eigenenergies and eigenstates are obtained. Let $E((L)_{i})$ be the energy of the $(L)_{i}$ state. It is noted that , for a first-state, if the Coulomb repulsion among the electrons are removed, all the electrons would fall in the LLL with the energy $(L+N)\hbar \omega _{o}$ .  For this reason, let us define $%
\varepsilon (L)\equiv E((L)_{1})-(L+N)\hbar 