which lead to very different results. The surface effects essentially depend on the orientation of the electric field with respect to the boundary [@Ma88; @Ma89]. In the case of an electric field parallel to the boundary, the pair production rate per unit time and unit volume in the region $z\geq
0$ is $w\left( z\right) =\sum_{n=1}^{\infty }w_{n}\left[ 1-\exp
\left( -eEz^{2}/n\pi \right) \right] $, where $w_{n}=\left(
e^{2}E^{2}/4\pi ^{3}\right) \exp \left( -n\pi E_{cr}/E\right) $ is the Schwinger production rate in constant field with infinite extension. As one can see for $z=0$ the boundary effects cancels the Schwinger volume term, and thus electron-positron pair creation cannot take place on a boundary parallel to the field [@Ma88; @Ma89]. Generally, there is a significant reduction of the Schwinger pair production rate near a surface which is parallel to the electric field. For an electric field of the order of $E=5\times E_{cr}$, the reduction in the production rate at a distance of $z=197.5$ fm from the parallel boundary is, for the case of the dominant term with $n=1$, $\left[ 1-\exp \left( -eEz^{2}/\pi \right) \right] =0.33$, while for $z=987.362$ fm the reduction rate is $0.999$. For the case of an electric field $E=50\times E_{cr}$, we have a reduction 