assume the cross-section of the jets is circular. The quantity of injection mass can be calculated by the following equation: $$\label{eq5}
    M_j=\int m_H n_H \frac{w^2(t)\pi}{4}v(t)dt,$$ where $m_H$ is the mass of the hydrogen atom, $n_H$ is the total hydrogen number density, $w(t)$ is the width of the cross-section of the jet, $v(t)$ is the speed of the cool plasma. Considering that the cool plasma come from the lower atmosphere, it is reasonable to assume that the density of the cool plasma driven by the jets is similar to that of the chromosphere. Thus, the total hydrogen number density $n_H$ is about 3.26 $\times$ $10^{10}$ $cm^{-3}$. The mass of the hydrogen atom $m_H$ is about 1.67 $\times$ $10^{-24}$ g. From the above diagnosis, the speed of the cool plasma ($v(t)$) was estimated as about 20-30 km/s. In order to derive the width cross-section of the jets ($w(t)$), we make a time-distance diagram along the blue dashed line in the panel (b) of Fig.\[fig4\]. To allow for uncertainty in the definition of the boundary between the jet and the filament, the blue dashed line was placed nearby the footpoints of the jets. This avoids the effect of the main filament as much 