most general form not containing a dependence on the Klein operator $K$: $$S_{\alpha}=L^{\beta}\left((P\gamma)_{\beta\alpha}+\varepsilon
m\epsilon_{\beta\alpha}\right),
\label{da}$$ where, again, $P_{\mu}=-i\partial_{\mu}$ and $\varepsilon=\pm1$. Therefore, one can consider the spinor set of linear differential equations $$S_{\alpha}\Psi=0.
\label{baseq}$$ Here we suppose that the field $\Psi=\Psi^{n}(x)$ is an infinite-component function given on the Fock space of the $\nu$-deformed bosonic oscillator, i.e. eq. (\[baseq\]) is a symbolic presentation of the set of two infinite-component equations $S_{\alpha}^{nn'}\Psi^{n'}=0$ with $S_\alpha^{nn'}=<n|S_{\alpha}|n'>$.

Operator (\[da\]) satisfies the relation $$S^{\alpha}S_{\alpha}=L^{\alpha}L_{\alpha}(P^{2}+m^{2}).$$ Since $L^{\alpha}L_{\alpha}=-i(1+\nu K)\neq 0$ due to restriction (\[restr\]), we conclude that the Klein-Gordon equation (\[kle\]) is the consequence of eqs. (\[baseq\]). Moreover, we have the relation $$L^{\alpha}S_{\alpha}=-4i\left(PJ-\varepsilon m\hat{\alpha}\right),$$ where $\hat{\alpha}$ is given by eq. (\[hatal\]). Decomposing the field $\Psi$ as $\Psi=\Psi_{+}+\Psi_{-}$, $$\Psi_{\pm}=\Pi_{\pm}\Psi,
\label{psipm}$$ and, so, $\Psi_{+}=\Psi^{2k}$, $\Psi_{-}=\Psi^{2k+1}$, $k=0,1,\ldots$, we conclude that as a consequence of basic eqs. (\[baseq\]), the fields $\Psi_{\pm}$ satisfy, respectively, the equations $$(PJ-\varepsilon\alpha_{+}m)\Psi_{+}=0,
\label{maje}$$ $$\left(PJ-\varepsilon
\left(\alpha_{-}-\frac{1}{2}(1+\nu)\right)m\right)\Psi_{-}=0,
\label{majo}$$ where $\alpha_+$ and $\alpha_-$ are given by eq. (\[aeo\]). Note, that eq. (\[maje\]) is exactly the (2+1)-dimensional analogue of the Majorana equation. Taking into account eq. (\[kle\]), and passing over to the rest frame ${\bf P}={\bf
0}$ in the momentum representation, we find with the help of eq. (\[jmu\]) that eq. (\[maje\]) has 