ionization rate depends on all three, viz. $n_{\rm{e}}\alpha_{\rm{eII}}\sim n_{\rm{e}} q^{-3}T^{-1/2}$. An initial suggestion is that the activation density is attained when these two are approximately equal, i.e., $$\begin{aligned}
n_{\rm{e},\rm{a}}q^{-3}T^{-1/2}\sim q^4\ ,\end{aligned}$$ indicating that the activation density should scale as $ n_{\rm{e},\rm{a}}\sim q^7T^{1/2}$, if the above qualitative discussion holds. The log activation density for all $q$ and $T$ might therefore be expected to obey the scaling relationship $$\begin{aligned}
x_{\rm{a}}(q,T) & = & x_{\rm{a}}(q_0,T_0) + log_{10}\left[\left(\frac{q}{q_0}\right)^7\left(\frac{T}{T_0}\right)^{1/2}\right]\ , \label{eqxa}\end{aligned}$$ where $x_{\rm{a}}(q_0,T_0)=0.608$, $q_0=3$, and $T_0=10^5$ K are the (log) activation density, the charge, and the temperature for the case treated by [@badnell]. We note that this expression, when applied to Li-like , gives an increase in the activation density by a factor of $(5/3)^7 = 35.7$, in agreement with the approximate factor of 40 found by @davidson. Furthermore, when scaled in temperature, the formula gives fairly good agreement with the suppression results of @davidson for at $T=1.5\times 10^4$ K (see Fig. \[fig1\]).

### Fit to the Collisional Radiative Data {#cr}

The preceding treatment reasonably extends the suppression factor at $10^5$ K to other high temperatures and to other Li-like ions. However, we need suppression factors applicable to all ionization stages of all elements up 