particle-number distribution is $$\label{ParticleNumber:2}
n(\omega) = 2 (1-\text{cos}\,\theta_{\omega})\frac{e^{2\pi \omega/a}}{(e^{2\pi \omega/a}-1)^2},$$ depending on the transmission coefficient of the uniformly accelerated mirror. Note that $n(\omega) = 0$ only when $\theta_{\omega} = 0$; in other words when the mirror is completely transparent to the field mode with frequency $\omega$. We also note that the distribution of the output Unruh particles is not thermal.

Radiation from an eternally accelerated mirror {#radiation}
==============================================

![(color online). A uniformly accelerated mirror on the right Rindler wedge. An inertial detector is placed at an appropriate position to detect left-moving particles coming from the uniformly accelerated mirror. []{data-label="Fig:Mirror"}](f3.png){width="8.0cm"}

As an application of the quantum circuit model, we calculate the radiation flux from an eternally accelerated mirror. As shown in Fig. \[Fig:Mirror\], an inertial detector is placed at an appropriate position to detect the left-moving particles radiated by the accelerated mirror. In the previous section, we have shown that the accelerated mirror radiates Unruh particles. However, the inertial detector responds only to Minkowski particles. In order to calculate the response of the inertial detector we need to find the transformation between Unruh modes and Minkowski modes. This can be done by comparing Eqs. (\[MinkowskiMode\]) and (\[UnruhMode\]), and then using the 