rapidity variable $\zeta$ varies between $-\eta_{max}$ and $\eta_{max}$. In a similar fashion, we can calculate the energy of the m-th meson by using the following formula :

=(-)m\_[T]{}\^[3]{}yrdrdddm\_[T]{}.

Here, $E_{m}$, $g_m$, and $\lambda_m$ represent the energy, degeneracy factor and fugacity of the m-th meson. Now, eq. (4) can be reduced in the following form : $$\langle E_{T} \rangle=\langle \sum_i E_i \sin \theta_i \rangle.$$ The average of $\sin\theta$ can be calculated as follows : $$\begin{aligned}
\langle \sin\theta \rangle=\frac{1}{4\pi}\int\; \sin\theta d\Omega \nonumber
&=&\frac{1}{4\pi}\int\; \sin^2\theta\; d\theta d\phi,\end{aligned}$$ where $d\Omega$ ($=\sin\theta d\theta d\phi$) is the solid angle. Now, integrating above equation we get : $$\begin{aligned}
\langle\sin\theta\rangle=\frac{1}{4\pi}\int_0^\pi\; \sin^2\theta\; d\theta \int_0^{2\pi} d\phi \nonumber
&=&\frac{\pi}{4}.\end{aligned}$$ Now, we can write the expression of the transverse energy of hadrons as follows [@Cleymans:2007uk] : $$\langle E_{T} \rangle=\frac{\pi}{4}\Big[\langle E \rangle - m_{N}\langle N_{B} - N_{\bar{B}} \rangle\Big].$$ $\langle E \rangle$ is the total energy of hadrons. $N_{B} - N_{\bar{B}}$ is the net-baryon which can be calculated by using eq. (1). After obtaining the transverse energy, we calculate the Bjorken energy density by using the following formula: $$\epsilon_{Bj}=\frac{dE_{T}}{dy}\frac{1}{\tau\;\pi\;R^{2}},$$ where $\tau$ is the formation time and $\pi\;R^{2}$ is the transverse overlap area of the colliding nuclei. There are various ways to quantify the overlap 