of two independent dipoles and the question is how the two dipoles share the recoil from the emission. We solve this by assuming that when a dipole emits a gluon, the initial gluons, which make up the parent dipole, may contribute with all their energy. This means that the next time a neighboring dipole emits a gluon, the avaliable energy is reduced because one of its gluons has lost energy from an earlier emission. How much energy does each parton in the dipole give to the emitted gluon? Obviously the answer should be such that if the new gluon comes very close to one of the partons, that parton should take most of the recoil, while the other one should be less affected. There are, however, different ways to share the amount of energy between the partons.

Consider the emission of gluon $n$ from the dipole $ij$. Let $r_{in}$ and $r_{nj}$ denote the distance between the new gluon and parton $i$ and parton $j$ respectively. Denote the recoil by $p_+''$, while $p_+'$ is the amount of energy left after the emission, which implies that $p_+=p_+''+p_+'$. We then make the ansatz that $$p_{+i}''=\frac{r_{jn}}{r_{jn}+r_{in}}p_{+n} \; \; \textrm{and}\; \;
p_{+j}''=\frac{r_{in}}{r_{jn}+r_{in}}p_{+n}$$

Thus we assume 