{\cal{M}}_0(t,r)
\over \partial t} + {2M \over r(r-2M)} {\cal{M}}_1(t,r)   \nonumber \\
 \widetilde{H}_1(t,r) & = &   H_1(t,r)  +{r-2M \over r}{\partial
 {\cal{M}}_0(t,r) \over \partial r} - {r \over r-2M} {\partial
 {\cal{M}}_1(t,r) \over \partial t}   \nonumber \\
 \widetilde{H}_2(t,r) & = &    H_2(t,r) +{2M \over r(r-2M)}
{\cal{M}}_1(t,r) -2  {\partial {\cal{M}}_1(t,r) \over \partial
r}\nonumber \\
 \widetilde{h}_0(t,r) & = &   h_0(t,r) +{r-2M \over r} {\cal{M}}_0(t,r)
 -r^2 {\partial {\cal{M}}_2(t,r) \over \partial t} \nonumber \\
 \widetilde{h}_1(t,r) & = &   h_1(t,r)  -{r \over r-2M}{\cal{M}}_1(t,r)
 -r^2  {\partial {\cal{M}}_2(t,r) \over \partial r}\nonumber \\
 \widetilde{K}(t,r) & = &   K(t,r) -{2 \over r} {\cal{M}}_1(t,r) +2
 {\cal{M}}_2(t,r)\end{aligned}$$ where the functions ${\cal{M}}_i$ are arbitrary.

One can use this gauge freedom to go to a restricted gauge in which $h_0 = h_1 = K =0$. This gauge is not completely fixed. One still can perform gauge transformations of the form, $${\cal{M}}_0 = {r^3 \over r -2M} {\partial {\cal{M}}_2  \over \partial
t}
\;\;\;,\;\;\;
{\cal{M}}_1 = r {\cal{M}}_2  \;\;\;,\;\;\;
{\cal{M}}_2 = {f(t) \over r-2M}
\label{eqxi1}$$ where $f(t)$ is arbitrary.

An interesting result, is that in this gauge it is straightforward to find the [*general*]{} solution of the linearized Einstein equations for $\ell=1$ even parity perturbations. The result is, $$\begin{aligned}
H_1 & = &  - {r \over (r-2M)^2} {d 