should be equal to 16 MeV and the total energy should have a minimum at $\rho_0$. The third parameter $\gamma$ is usually treated as a free parameter. Its value is given in term of the compressibility: $$\kappa~=~
9\rho^{2}\frac{\partial^{2}}{\partial\rho^{2}}\left(\frac{E}{A}\right)~~.$$ The different values of compressibility give rise to soft and hard equations of state. The soft equation of state is employed in the present study with the parameters $\alpha~=~-356$ MeV, $\beta~=~303$ MeV, and $\gamma$ = 7/6, corresponding to an isoscaler compressibility of $\kappa~=~200~$ MeV. In the third term $E^{pot}_{Sym}$ is the potential part of the symmetry energy, which is adjusted on the basis of calculations from the microscopic or phenomenological many-body theory, having the form $$E^{pot}_{Sym}~=~\frac{C_{s,p}}{2}\left(\frac{\rho}{\rho_0}\right)^{\gamma_i}
.$$ Here $C_{s,p}~=~35.19~$MeV, parameterized on the basis of the experimental value of the symmetry energy, is known as the symmetry potential energy coefficient. On the basis of the $\gamma_i$ value, symmetry energy is divided into two types with $\gamma_i~=~0.5$ and $\gamma_i~=~1.5$, corresponding to soft and stiff symmetry energies, respectively.

The total symmetry energy per nucleon employed in the simulation is the sum of the kinetic and potential terms and is given as $$E_{Sym}(\rho)~=~\frac{C_{s,k}}{2}\left(\frac{\rho}{\rho_0}\right)^{2/3}~+~E^{pot}_{Sym},$$ where $C_{s,k}~=~
\frac{\hbar^2}{3m}\left(\frac{3\pi^2\rho_0}{2}\right)^{2/3}~\approx~25$ MeV is known as the symmetry kinetic energy coefficient. The 