-   if $\Delta(X,K_X+\Lambda)=1$, then

    -   either $X_1$ and $X_2$ are both normal. Each $|(K_X+\Lambda)|_{X_i}|$ is composed with a pencil. $X_1\cap X_2$ is a fiber on each $X_i$. $|K_X+\Lambda|$ is composed with a pencil as well.

    -   or $X_1$ and $X_2$ are both non-normal. The base points of $|(K_X+\Lambda)|_{X_i}|$ coincide into the unique base point of $|K_X+\Lambda|$. $X_1\cap X_2$ is a line passing through the base point of $|(K_X+\Lambda)|_{X_i}|$ on each $X_i$.

\(i) follows from Lemma \[2comps\] and Lemma \[globalsection\].

For (ii), applying Lemma \[2comps\] we see that either $X_i$ is non-normal or $(K_X+\Lambda)|_{X_i}$ is composed with a pencil. It is easy to see that either $X_1$, $X_2$ are both non-normal or $(K_X+\Lambda)|_{X_1}$, $(K_X+\Lambda)|_{X_2}$ are both composed with a pencil of elliptic curve, since the geometric genus of $X_1\cap X_2$ on $X_1$ or $X_2$ should coincide.

If $(K_X+\Lambda)|_{X_1}$, $(K_X+\Lambda)|_{X_2}$ are both composed with a pencil of elliptic curve, then by Lemma \[2comps\] each $(K_X+\Lambda)|_{X_i}$ is composed with a pencil and $X_1\cap X_2$ is a fiber on each $X_i$. Therefore $|K_X+\Lambda|$ is composed with a pencil as well. If $X_1$ and $X_2$ are both non-normal, then by Lemma \[restdim\], $X_1\cap X_2$ is a line passing through the base point of $|(K_X+\Lambda)|_{X_i}|$ on 