and magnetic multipole moments, representing the response of the wire to an external illumination. Under normal incidence, the Mie S-matrix, connecting the incident ($\mathbf{E}_i$) and the asymptotic, scattered field ($\mathbf{E}_s$) writes[@bohren_absorption_1998] $$\label{eq:scattering_Smatrix}
 \begin{bmatrix}
  E_{s, \text{TM}} \\
  E_{s, \text{TE}}
 \end{bmatrix}
  = 
e^{\mathrm{i} 3\pi/4} \, \sqrt{\dfrac{2}{\pi k R}} \, e^{\mathrm{i} k R}
 \begin{bmatrix}
  T_1 & 0    \\
  0   & T_2
 \end{bmatrix}
 \begin{bmatrix}
  E_{i, \text{TM}} \\
  E_{i, \text{TE}}
 \end{bmatrix}$$ with the wavenumber $k=2\pi/\lambda$, the distance $R$ to the cylinder axis and $$\label{eq:Smatrix_T1_T2}
 \begin{aligned}
  T_1 & = b_0 + 2 \sum\limits_{n=1}^{\infty} b_n \cos(n \varphi) \\
  T_2 & = a_0 + 2 \sum\limits_{n=1}^{\infty} a_n \cos(n \varphi). 
 \end{aligned}$$ $\varphi$ is the scattering angle with respect to the incident wave vector and $\varphi = 0$ corresponds to the forward scattering direction.

As can be seen from Eq. , under normal incidence the transverse magnetic (TM) and transverse electric (TE) polarized components of the scattered fields are proportional to the S-matrix components $T_1$, respectively $T_2$. Therefore, according to Eqs.  scattering from a TE polarized normally incident plane wave ($\mathbf{E} \perp$ NW axis) is only due to the “electric” multipole contributions $a_i$. On the other hand, a TM polarized illumination ($\mathbf{E} \parallel$ NW axis) induces scattering exclusively via the 