$\lambda_5=\lambda_6=\lambda_7=0$, we find $$\begin{aligned}
{\cal D} \lambda_1 &=&
6 \lambda_1^2 + 2 \lambda_3^2 + \lambda_4^2 + 2 \lambda_3 \lambda_4
- \tfrac{1}{2} \left( 9 g^2 + 3 {g^\prime}^2 \right) \lambda_1
+ \tfrac{1}{8} \left( 9 g^4 + 6 g^2 {g^\prime}^2 + 3{g^\prime}^4 \right),
\nonumber\\
{\cal D} \lambda_3 &=&
2 \lambda_3^2 + \lambda_4^2 + 2 \lambda_1 (3 \lambda_3 + \lambda_4)
- \tfrac{1}{2} \left( 9 g^2 + 3 {g^\prime}^2 \right) \lambda_3
+ \tfrac{1}{8} \left( 9 g^4 - 6 g^2 {g^\prime}^2 + 3{g^\prime}^4 \right),
\nonumber\\
{\cal D} \lambda_4 &=&
2 \lambda_4^2 + 2 \lambda_1 \lambda_4 + 4 \lambda_3 \lambda_4
- \tfrac{1}{2} \left( 9 g^2 + 3 {g^\prime}^2 \right) \lambda_4
+ \tfrac{3}{2} g^2 {g^\prime}^2, \label{D134}\end{aligned}$$ where ${\cal D} = 16 \pi^2 \mu (d/d\mu)$, and ${\cal D} \lambda_5 = {\cal D} \lambda_6 = {\cal D} \lambda_7 = 0$. Hence, given the constraints $\lambda_1=\lambda_2$ and $\lambda_5=\lambda_6=\lambda_7=0$, $$\begin{aligned}
{\cal D} (\lambda_4 + \lambda_3 - \lambda_1 ) &=&
\tfrac{1}{2}
(\lambda_4 + \lambda_3 - \lambda_1 )(12 \lambda_1 + 4 \lambda_4 - 9 g^2 - 3 {g^\prime}^2)
\label{D_O3}
\\*[2mm]
{\cal D} (\lambda_4 + \lambda_3 + \lambda_1 ) &=&
2 \left(3 \lambda _1^2+\left(3 \lambda _3+2 \lambda _4\right) \lambda _1+2 \lambda _3^2+2
   \lambda _4^2+3 \lambda _3 \lambda _4\right)
\nonumber\\
&&
- \tfrac{1}{2} \left( 9 