$$\begin{aligned}
q_n=(1-(1-c_0)^{2^n})PR + (1-c_0)^{2^n}L_7\end{aligned}$$ From that, we have that $q_n\rightarrow PR$ as $n\rightarrow\infty.$

All correlations in some $2$D quantum voids can be distilled to a PR-box
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Consider a generic $2$D quantum void described by the distribution $$p=c_0 PR+ (1-c_0)\left( c_{i}L_{i} +c_{j}L_{j} \right) .$$ where we can order the coefficients as $c_i \geq c_j$. By searching over the $3152$ wirings such that $B^0_0=PR$ we found that there is always at most one value of $i$ (for all $i$) such that $B^0_{i}=B_0^{i}=PR$. Furthermore, there always exist a wiring such that $B^0_{j}$ and $B_0^j$ are mapped to a distribution of the form , that is, the condition becomes a sufficient condition for distillation. Thus, choosing a wiring such that $\tilde{c}_2=c_i$ we always will distill the nonlocality of the distribution, unless $\tilde{c_0}=c_j$ and $c_i=c_j$ (that is, we are at the isotropic line defined by the non-signalling facet). If $c_i=c_j$ we have to guarantee that $\tilde{c_0}=0$, what only happen at a subset of $2$D quantum voids given by the sets consisting of the following pairs of local points: $(L_1L_2)$, $(L_1L_3)$, $(L_1L_5)$, $(L_2L_4)$, $(L_2L_6)$, $(L_3L_4)$, $(L_3L_8)$, $(L_4L_7)$, $(L_5L_6)$, $(L_5L_7)$, $(L_6L_8)$ and $(L_7L_8)$. All the other $2$D quantum voids are distillable but not at the isotropic 