don’t depend on external momenta. Also for the gluon self energy the $A_0$ loop cancels with the ghost loop, so we don’t have to compute diagrams **SE1e** and **SE1f**.

\[fig:SEFlat\] ![Self energy diagrams contributing to Z1 and Z2. Dashed (dotted) lines stand for the scalar ($A_0$) field, wiggly line for gluon and solid for the fermion. The dashed arrowed line stands for the ghost.](SE1.png "fig:"){width="50.00000%"}\
![Self energy diagrams contributing to Z1 and Z2. Dashed (dotted) lines stand for the scalar ($A_0$) field, wiggly line for gluon and solid for the fermion. The dashed arrowed line stands for the ghost.](SE2.png "fig:"){width="50.00000%"}\
![Self energy diagrams contributing to Z1 and Z2. Dashed (dotted) lines stand for the scalar ($A_0$) field, wiggly line for gluon and solid for the fermion. The dashed arrowed line stands for the ghost.](SE3.png "fig:"){width="50.00000%"}\

Diagrams $\mathbf{SE1a}$ and $\mathbf{SE1b}$ were evaluated in [@Aharony:2006rf]. The expressions for the other diagrams are (omitting $\lambda$ and group indices throughout.),

#### : $-\frac{1}{2}\langle A_i(\omega,p)A_j(-\omega,-p)\rangle^{1PI}$.

$$\begin{aligned}
\mathbf{SE1c} &= N_s\int\frac{d\nu d^{3+d}k}{(2\pi)^{4+d}}\frac{k^ip^j-2k^ik^j}{(\nu^2+k^2)((\omega-\nu)^2+(p-k)^2)}~~,\label{eq:SE1cFlat}\\
\mathbf{SE1d} &= 2N_f\int\frac{d\nu d^{3+d}k}{(2\pi)^{4+d}}\frac{[\nu(\omega-\nu)+k\cdot (p-k)]\delta^{ij}+2k^i(k-p)^j}{(\nu^2+k^2)((\omega-\nu)^2+(p-k)^2)}~~.\label{eq:SE1dFlat}\end{aligned}$$

#### : $-\frac{1}{2}\langle \phi_a(\omega,p)\phi_b(-\omega,-p)\rangle^{1PI}$.

$$\begin{aligned}
\mathbf{SE2a} &= -\delta^{ab}\int\frac{d\nu d^{3+d}k}{(2\pi)^{4+d}}\frac{(2p-k)\cdot\Delta\cdot (2p-k)}{(\omega-\nu)^2+(p-k)^2}~~,\label{eq:SE2aFlat}\\
\mathbf{SE2b} &= -\delta^{ab}\int\frac{d\nu d^{3+d}k}{(2\pi)^{4+d}}\frac{(2\omega-\nu)^2}{k^2((\omega-\nu)^2+(p-k)^2)}~~,\label{eq:SE2bFlat}\\
\mathbf{SE2c} &= \mathrm{tr}(\rho^{a\dag}\rho^b+\rho^{b\dag}\rho^a)\int\frac{d\nu d^{3+d}k}{(2\pi)^{4+d}}\frac{\nu(\omega-\nu)+k\cdot (p-k)}{(\nu^2+k^2)((\omega-\nu)^2+(p-k)^2)}~~.\label{eq:SE2cFlat}\end{aligned}$$

#### : $\langle \psi_I(\omega,p)\psi^{\dag J}(\omega,p)\rangle^{1PI}$.

$$\begin{aligned}
\mathbf{SE3a} &= 2\delta_I^J\int\frac{d\nu d^{3+d}k}{(2\pi)^{4+d}}\frac{2[(p-k)\cdot\Delta]_i\sigma^i-\Delta^{jj}[\omega-\nu+(p-k)_i\sigma^i]}{(\omega-\nu)^2+(p-k)^2}~~,\label{eq:SE3aFlat}\\
\mathbf{SE3b} 