$mm$
        $\eta=d^{2}\,\rho'$           $ $$10^{-2}$         $Kg/m$

  : \[ParametersValues\]Values of the parameters of the relaxed model used in the numerical simulations (left) and corresponding values of the Lamé parameters and of the Young modulus and Poisson ratio (right).

   Parameter   Value    Unit
  ----------- -------- -------
   $\lambda$   $82.5$   $MPa$
     $\mu$     $66.7$   $MPa$
      $E$      $170$    $MPa$
     $\nu$     $0.28$    $-$

  : \[ParametersValues\]Values of the parameters of the relaxed model used in the numerical simulations (left) and corresponding values of the Lamé parameters and of the Young modulus and Poisson ratio (right).

We start by showing in Tab.\[ParametersValues\] (left) the values of the parameters of the relaxed model used in the performed numerical simulations. In order to make the obtained results more exploitable, we also recall that in [@NeffRelaxed] the following homogenized formulas were obtained which relate the parameters of the relaxed model to the macroscopic Lamé parameters $\lambda$ and $\mu$ which are usually measured by means of standard mechanical tests $$\mu_{e}=\frac{\mu_{h}\,\mu}{\mu_{h}-\mu},\qquad2\mu_{e}+3\lambda_{e}=\frac{(2\mu_{h}+3\lambda_{h})\left(2\mu+3\lambda\right)}{(2\mu_{h}+3\lambda_{h})-\left(2\mu+3\lambda\right)}.\label{Homogenized}$$ These relationships imply that the following inequalities are satisfied $$\mu_{h}>\mu,\qquad3\lambda_{h}+2\mu_{h}>3\lambda+2\mu.$$ It is clear that, once the values of the parameters of the relaxed models are known, the standard Lamé parameters can be calculated by means of formulas (\[Homogenized\]), which is what was done in Tab.\[ParametersValues\] 