also considered.

First, we take up the case of a simple (non-attractive) wall, corresponding to $b>0$ in Eqs. (\[BKPZ\]) and (\[mnminus\]). Figure (1) shows how the steady order parameter $\n$ changes with the system size $L$. Within the active phase, it saturates to a constant value, while in the absorbing one it bends down and decays exponentially. Our best estimate for the critical point is $a_c=1.57433(2)$ and from the slope of the curve we get $\beta_n/\nu_\bot \approx 0.33(2)$ [@note2]. This value of $a_c$ corresponds to the point where a free interface (far from the wall) has zero average velocity. The time evolution of $\n$ at the critical point for different system sizes (Figure (2)) behaves like $\langle n(t) \rangle \sim t^{-\theta_n}$, with $\theta_n =0.215(15)$ or, equivalently, $\langle h(t) \rangle \sim t^{\theta_h}$, with $\theta_h =0.355(15)$. As for the exponents $\beta$, which govern the saturation of the order parameter within the active phase, they have been computed using the largest available system sizes ($L=1600$ and $3200$). The best fit to $ \langle X \rangle \sim |a-a_c|^{\pm \beta_X}$ yields $\beta_n \approx 0.32 (3)$ (for $\langle n \rangle$) the and $\beta_h =0.52(2)$ (for $\langle h\rangle$), respectively. The error margin is typically larger here than 