def median(self, nums):
        n = len(nums)
        return self.find_kth(nums, 0, n, (n-1)/2)
ARGUMENTS:
dataset/ETHPy150Open algorhythms/LintCode/Median.py/Solution.median--crossover with--dataset/ETHPy150Open tyiannak/pyAudioAnalysis/audioSegmentation.py/speakerDiarization