Open two tcp connection using TcpListener class on both side <p>I want to open tcp connection between two machine. I want to use the class TcpListener on the client side and on the server side and by this to have the option to make the two side 'talk' with the other by sending and receiving byte[]. </p> <p>That mean that each side is a server and a client. </p> <p>I using the code from msdn to do it. But on this code the server start and wait till the client will connect to him. </p> <p>If i doing so on the both sides i will fail. Is there any other way ? </p> <p>The code:</p> <pre><code>public static void Main() { TcpListener server=null; try { // Set the TcpListener on port 13000. Int32 port = 13000; IPAddress localAddr = IPAddress.Parse("127.0.0.1"); // TcpListener server = new TcpListener(port); server = new TcpListener(localAddr, port); // Start listening for client requests. server.Start(); // Buffer for reading data Byte[] bytes = new Byte[256]; String data = null; // Enter the listening loop. while(true) { Console.Write("Waiting for a connection... "); // Perform a blocking call to accept requests. // You could also user server.AcceptSocket() here. TcpClient client = server.AcceptTcpClient(); Console.WriteLine("Connected!"); data = null; // Get a stream object for reading and writing NetworkStream stream = client.GetStream(); int i; // Loop to receive all the data sent by the client. while((i = stream.Read(bytes, 0, bytes.Length))!=0) { // Translate data bytes to a ASCII string. data = System.Text.Encoding.ASCII.GetString(bytes, 0, i); Console.WriteLine("Received: {0}", data); // Process the data sent by the client. data = data.ToUpper(); byte[] msg = System.Text.Encoding.ASCII.GetBytes(data); // Send back a response. stream.Write(msg, 0, msg.Length); Console.WriteLine("Sent: {0}", data); } // Shutdown and end connection client.Close(); } } catch(SocketException e) { Console.WriteLine("SocketException: {0}", e); } finally { // Stop listening for new clients. server.Stop(); } Console.WriteLine("\nHit enter to continue..."); Console.Read(); } </code></pre>