/*
 * Problem C. Recycled Numbers
 * 
 * Do you ever become frustrated with television because you keep seeing the
 * same things, recycled over and over again? Well I personally don't care about
 * television, but I do sometimes feel that way about numbers.
 * 
 * Let's say a pair of distinct positive integers (n, m) is recycled if you can
 * obtain m by moving some digits from the back of n to the front without
 * changing their order. For example, (12345, 34512) is a recycled pair since
 * you can obtain 34512 by moving 345 from the end of 12345 to the front. Note
 * that n and m must have the same number of digits in order to be a recycled
 * pair. Neither n nor m can have leading zeros.
 * 
 * Given integers A and B with the same number of digits and no leading zeros,
 * how many distinct recycled pairs (n, m) are there with A â¤ n < m â¤ B?
 * 
 * Input
 * 
 * The first line of the input gives the number of test cases, T. T test cases
 * follow. Each test case consists of a single line containing the integers A
 * and B.
 * 
 * Output
 * 
 * For each test case, output one line containing "Case #x: y", where x is the
 * case number (starting from 1), and y is the number of recycled pairs (n, m)
 * with A â¤ n < m â¤ B.
 * 
 * Limits
 * 
 * 1 â¤ T â¤ 50.
 * 
 * A and B have the same number of digits.

Small dataset

1 â¤ A â¤ B â¤ 1000.

Large dataset

1 â¤ A â¤ B â¤ 2000000.

Sample


Input 
 	
Output 
 
4
1 9
10 40
100 500
1111 2222
Case #1: 0
Case #2: 3
Case #3: 156
Case #4: 287
 */

package google.codejam.y2012.qualifications;

import google.codejam.commons.Utils;

import java.io.IOException;
import java.util.StringTokenizer;

/**
 * @author Marco Lackovic <marco.lackovic@gmail.com>
 * @version 1.0, Apr 14, 2012
 */
public class RecycledNumbers {

	private static final String INPUT_FILE_NAME = "C-large.in";
	private static final String OUTPUT_FILE_NAME = "C-large.out";

	public static void main(String[] args) throws IOException {
		String[] input = Utils.readFromFile(INPUT_FILE_NAME);
		String[] output = new String[input.length];
		int x = 0;
		for (String line : input) {
			StringTokenizer st = new StringTokenizer(line);
			int a = Integer.valueOf(st.nextToken());
			int b = Integer.valueOf(st.nextToken());
			System.out.println("Computing case #" + (x + 1));
			output[x++] = "Case #" + x + ": " + recycledNumbers(a, b);
		}
		Utils.writeToFile(output, OUTPUT_FILE_NAME);
	}

	private static int recycledNumbers(int a, int b) {
		int count = 0;
		for (int n = a; n < b; n++) {
			count += getNumGreaterRotations(n, b);
		}
		return count;
	}

	private static int getNumGreaterRotations(int n, int b) {
		int count = 0;
		char[] chars = Integer.toString(n).toCharArray();
		for (int i = 0; i < chars.length; i++) {
			chars = rotateRight(chars);
			if (chars[0] != '0') {
				int m = Integer.valueOf(new String(chars));
				if (n == m) {
					break;
				} else if (n < m && m <= b) {
					count++;
				}
			}
		}
		return count;
	}

	private static char[] rotateRight(char[] chars) {
		char last = chars[chars.length - 1];
		for (int i = chars.length - 2; i >= 0; i--) {
			chars[i + 1] = chars[i];
		}
		chars[0] = last;
		return chars;
	}

}

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;


public class RecycledNumbers {

	private static int noOfDigits(int n){
		if (n < 10) return 1;
		return 1 + noOfDigits(n/10);
	}

	private static int raisedTo(int n, int m){
		if (n==0) return 0;
		else if (m==0) return 1;
		else if (m==1) return n;
		return n*raisedTo(n, m-1);
	}

	private static int rotateBy(int n, int s, int nod){
		if (s == 0) return n;
		int N = noOfDigits(n);
		int pow = raisedTo(10, nod-1);
		int MSB = (N==nod)? n/pow: 0;
		return rotateBy((n%pow)*10+MSB, s-1, nod);
	}

	private static int[] giveDistinctNos(int n, int min, int max){
		int s = 0, r = n, j=0;
		int N = noOfDigits(r);
		int A[] = new int[N];
		for (int i=0; i<N; i++){
			for (j=0; j<s; j++){
				if (A[j] == r)
					break;
			}
			if (j == s){
				A[s++] = r;
			}
			r = rotateBy(r, 1, N);
			while (r<min || r>max || N != noOfDigits(r))
				r = rotateBy(r, 1, N);
		}
		return A;
	}

	private static int nC2(int n){
		return n*(n-1)/2;
	}

	public static void main(String[] args) throws NumberFormatException, IOException {
		//		for (int i=0; i< 2000000; i++);

		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
		int T = new Integer(in.readLine()).intValue();
		int A = 0, B = 0, ans = 0;
		String str[];
		int X[];
		for (int i=0; i<T; i++){
			ans = 0;
			str = in.readLine().split(" ");
			A = new Integer(str[0]).intValue();
			B = new Integer(str[1]).intValue();
			X = new int[B-A+1];
			for (int j=A; j<B+1; j++){
				if (X[j-A] != 1){
					int N[] = giveDistinctNos(j, A, B);
					int n=0;
					for (int k=0; k<N.length; k++){
						if (N[k] == 0)
							break;
						X[N[k]-A] = 1;
						n++;
					}
					ans += nC2(n);
				}
			}
			System.out.print("Case #"+(i+1)+": "+ans);
			System.out.println();
		}
	}

}
