package qual;

import java.util.Scanner;

public class RecycledNumbers {

	public static void main(String[] args) {
		new RecycledNumbers().run();

	}

	private void run() {
		Scanner sc = new Scanner(System.in);
		int T = sc.nextInt();
		for (int t = 0; t < T; t++) {
			int A = sc.nextInt();
			int B = sc.nextInt();
			int result = solve(A, B);
			System.out.printf("Case #%d: %d\n", t + 1, result);
		}
	}

	public int solve(int A, int B) {
		int result = 0;
		for (int i = A; i <= B; i++) {
			int dig = (int) Math.log10(A/*same as B*/) + 1;
			int aa = i;
			for (int d = 0; d < dig - 1; d++) {
				aa = (aa % 10) * (int)Math.pow(10, dig - 1) + (aa / 10);
				if (i == aa) {
					break;
				}
				if (i < aa && aa <= B) {
//					System.out.printf("(%d, %d) ", i, aa);
					result++;
				}
			}
		}
		return result;
	}

}


import java.io.File;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.HashSet;
import java.util.Scanner;

public class Recycled {
    public static void main(String[] args) throws IOException {
        int[] powersOf10 = {1, 10, 100, 1000, 10000, 100000, 1000000};
        String inFileName = "C-small-attempt1.in";
        Scanner in = new Scanner(new File(inFileName));
        String outFileName = inFileName.substring(0, inFileName.lastIndexOf('.')) + ".out";
        PrintWriter out = new PrintWriter(outFileName);
        int numSets = in.nextInt();
        in.nextLine();
        for(int probSet = 1; probSet <= numSets; probSet++) {
            out.print("Case #" + probSet + ": ");
            int a = in.nextInt();
            int b = in.nextInt();
            HashSet<Pair> set = new HashSet<Pair>();
            int numOne = a;
            while(numOne <= b) {
                //figure out length of a, could use logs but don't want to worry
                //about double division, rounding, ceiling, etc.
                int temp = numOne;
                int len = 1;
                while((temp /= 10) > 0) len++;
                int numTwo = numOne;
                //cycle through all possible pairs with a
                for(int i = 0; i < len - 1; i++) {
                    int dig = numTwo % 10;
                    if(dig == 0) continue; //moving a 0 from the back to the front
                                            //would change the length of the number
                    numTwo /= 10;
                    numTwo += dig * powersOf10[len - 1];
                    if(numTwo < a || numTwo > b || numOne == numTwo) continue;
                    Pair pair = new Pair(numOne, numTwo);
                    set.add(pair);
                }
                numOne++;
            }
            out.println(set.size());
        }
        in.close();
        out.close();
    }
    
    private static class Pair {
        int one, two;
        public Pair(int o, int t) {
            one = o;
            two = t;
        }

        @Override
        public int hashCode() {
            return one + two; //a bad hash, but I need something commutative
        }
        
        public boolean equals(Object obj) {
            Pair other = (Pair) obj;
            return (other.one == one && other.two == two) || 
                    (other.one == two && other.two == one);
        }
        
        public String toString() {
            return "{" + one + ", " + two + "}";
        }
    }
}
