import java.io.*;
import java.util.*;

class B
{
	public static void main(String[] args) 
	{
		try
		{
			BufferedReader br = new BufferedReader(new FileReader("B.in"));
			PrintWriter pw = new PrintWriter(new FileWriter("B.out"));
			int X = Integer.parseInt(br.readLine());

			for(int i=0; i<X; i++)
			{
				String[] S = br.readLine().split(" ");
				int A = Integer.parseInt(S[0]);
				int B = Integer.parseInt(S[1]);
				int R = 0;

				int x = 1;
				int n = 0;
				while(A/x > 0) {
					n++;
					x *= 10;
				}

				for(int j=A; j<B; j++) {
					Set<Integer> seen = new HashSet<Integer>();
					for(int k=1; k<n; k++) {
						int p1 = j % (int)Math.pow(10, k);
						int p2 = (int) Math.pow(10, n-k);
						int p3 = j / (int)Math.pow(10, k);
						int y = p1*p2 + p3;
						
						if(j < y && !seen.contains(y) && y <= B) {
							seen.add(y);
							R++;
						}
					}
				}

				pw.printf("Case #%d: %d\n", i+1, R);
				pw.flush();
			}
		}
		catch(Exception e)
		{ 
			e.printStackTrace();
		}
	}
}

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.HashSet;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

/**
 * Google code jam.
 * Qualification Round 2012.
 * Problem C. Recycled Numbers
 * 
 * Usage: &lt;app&gt; &lt;input &gt;output
 * 
 * @author sombrabr@gmail.com
 *
 */
public class QualC {

	public static void main(String[] args) throws NumberFormatException, IOException {
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
		
		int cases = new Integer(in.readLine());
		
		for(int i=0; i<cases; ++i) {
			String line = in.readLine();
			System.out.print("Case #" + (i+1) + ": ");
			run(line);
		}
	}

	private static void run(String line) {
		String[] parts = line.split(" ");
		
		int digits = parts[0].length();
		
		int A = Integer.parseInt(parts[0]);
		int B = Integer.parseInt(parts[1]);
		
		int count = 0;
		
		for(int n=A; n<=B; ++n) { // n is the number to recycle
			String strN = Integer.toString(n);
			
			if(strN.length()!=digits)
				continue;
			
			HashSet<Integer> numbers = new HashSet<Integer>();
			
			for(int i=1; i<digits; ++i) {
				Pattern p = Pattern.compile("(\\d*)(\\d{" + i + "})");
				Matcher m = p.matcher(strN);
				
				if(!m.matches()) {
					System.err.println("BUG: " + strN + " for " + i + " digits");
					return;
				}
				
				String strNewN = m.group(2) + m.group(1);
				if(strNewN.length() != digits) {
					System.err.println("BUG: " + strN + " for " + i + " digits with " + strNewN);
					return;
				}
				
				int newN = Integer.parseInt(strNewN);
				
				if(n < newN && newN <= B && ! numbers.contains(newN)) {
					count++;
					numbers.add(newN);
				}
			}
		}
		
		System.out.println(count);
	}
}
