import java.io.*;
import java.util.*;

class B
{
	public static void main(String[] args) 
	{
		try
		{
			BufferedReader br = new BufferedReader(new FileReader("B.in"));
			PrintWriter pw = new PrintWriter(new FileWriter("B.out"));
			int X = Integer.parseInt(br.readLine());

			for(int i=0; i<X; i++)
			{
				String[] S = br.readLine().split(" ");
				int A = Integer.parseInt(S[0]);
				int B = Integer.parseInt(S[1]);
				int R = 0;

				int x = 1;
				int n = 0;
				while(A/x > 0) {
					n++;
					x *= 10;
				}

				for(int j=A; j<B; j++) {
					Set<Integer> seen = new HashSet<Integer>();
					for(int k=1; k<n; k++) {
						int p1 = j % (int)Math.pow(10, k);
						int p2 = (int) Math.pow(10, n-k);
						int p3 = j / (int)Math.pow(10, k);
						int y = p1*p2 + p3;
						
						if(j < y && !seen.contains(y) && y <= B) {
							seen.add(y);
							R++;
						}
					}
				}

				pw.printf("Case #%d: %d\n", i+1, R);
				pw.flush();
			}
		}
		catch(Exception e)
		{ 
			e.printStackTrace();
		}
	}
}

import java.io.BufferedReader;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
import java.util.StringTokenizer;


public class RecycledNumbers {
	public static void main(String[] args) throws IOException {
		RecycledNumbers r = new RecycledNumbers();
		r.run("C-large.in", "C-large.out");
	}
	
	public void run(String input, String output) throws IOException {
		BufferedReader br = new BufferedReader(new FileReader(input));
		FileWriter fw = new FileWriter(output);
		long C = 0;
		int N = new Integer(br.readLine());
		for (int cases = 1; cases <= N; cases++) {
			StringTokenizer st = new StringTokenizer(br.readLine());
			long A = new Long(st.nextToken());
			long B = new Long(st.nextToken());
			C = count(A, B);
			fw.write("Case #" + cases + ": " + C + "\n");
		}
		fw.flush();
		fw.close();
	}
	
	public long count(long A, long B) {
		int recycledPairs = 0;
		for (long K = A; K <= B; K++) {
			int n = digits(K);
			int pairs = 0;
			long[] a = new long[n - 1];
			for (int i = 1; i < n; i++) {
				long divisor = (long) Math.pow(10, i);
				long R = (K % divisor) * (long) Math.pow(10, n - i) + (K / divisor);
				if (R > K && R <=B) {
					boolean repeat = false;
					for (int j = 0; j < pairs; j++) {
						if (R == a[j]) {
							repeat = true;
							break;
						}
					}
					if (!repeat) {
						a[pairs] = R;
						pairs++;
						recycledPairs++;
					}
				}
			}
		}
		return recycledPairs;
	}
	
	public int digits(long k) {
		int length = 0;
		for (int i = 0; i < 8; i++) {
			k /= 10;
			length++;
			if (k == 0)
				break;
		}
		return length;
	}
}
