/*
 * To change this template, choose Tools | Templates
 * and open the template in the editor.
 */

package recycled;

import java.io.BufferedReader;
import java.io.DataInputStream;
import java.io.FileInputStream;
import java.io.FileWriter;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.TreeSet;

/**
 *
 * @author Alfred
 */
public class Main {

    /**
     * @param args the command line arguments
     */
    public static void main(String[] args) {
    try {
            FileInputStream fstream = new FileInputStream("C-small-attempt0.in");
            DataInputStream in = new DataInputStream(fstream);
            BufferedReader br = new BufferedReader(new InputStreamReader(in));
            FileWriter outFile = new FileWriter("out.txt");
            PrintWriter out = new PrintWriter(outFile);
            String line;
            line = br.readLine();
            int cases = Integer.parseInt(line);
            for (int i=1; i<=cases;i++){
                line = br.readLine();
                String[] values = line.split(" ");
                int A = Integer.parseInt(values[0]);
                int B = Integer.parseInt(values[1]);
                int total=0;
                for (int n=A; n<=B;n++){
                    TreeSet<String> solutions = new TreeSet<String>();
                    for (int k=1;k<values[1].length();k++){
                        String m = circshift(n,k);
                        int mVal = Integer.parseInt(m);
                        if(mVal<=B && mVal!=n  && mVal> n && !m.startsWith("0") && m.length()==Integer.toString(n).length() )
                        {
                            solutions.add(m);
                        }                   
                    }
                    total+=solutions.size();
                }
                out.println("Case #"+i+": "+total);
            }
            in.close();
            out.close();
        } catch (Exception e) {//Catch exception if any
            System.err.println("Error: " + e.getMessage());
        }

}

    private static String circshift(int n, int k) {
        String nString=Integer.toString(n);
        int len=nString.length();
        String m =  nString.substring(len-k)+nString.subSequence(0, len-k);
        //System.out.println(n+" "+m);
        return m;
    }

}

package qC;

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;

import qB.B.Pair;

//Letfs say a pair of distinct positive integers (n, m) is recycled 
//if you can obtain m by moving some digits from the back of n to the 
//front without changing their order. For example, (12345, 34512) is a 
//recycled pair since you can obtain 34512 by moving 345 from the end 
//of 12345 to the front. Note that n and m must have the same number 
//of digits (excluding leading zeros) in order to be a recycled pair.

//Given integers A and B with the same number of digits, how many distinct
//recycled pairs (n, m) are there with A ? n < m ? B?

public class C2 {

	static int solve(int number, int b) {
		int numDigi = number;
		int orgNumber = number;
		int c = 1;
		int p = 1;
		int counter = 0;

		do {
			numDigi = numDigi / 10;
			p = p * 10;
			c++;
		} while (numDigi != 0);
		int k = c - 1;
		p = p / 10;

		for ( int i = 1; i <= k; i++) {
			number = number % p * 10 + number / p;
			if (number > orgNumber && number <= b) {
				// System.out.println( "no: " + number + ", " + check);
				counter++;
			}
		}
		return counter;
	}

	public static void main(String[] args) throws FileNotFoundException {
		if (args.length == 0) {
			throw new IllegalArgumentException("no file given");
		}
		String filename = args[0];
		Scanner scanner = new Scanner(new File(filename));
		int numOfLines = scanner.nextInt();
		scanner.nextLine();

		for (int lineIdx = 0; lineIdx < numOfLines; lineIdx++) {
			final int start = scanner.nextInt();
			final int end = scanner.nextInt();
			int ans = 0;
			for (int l = start; l <= end; l++) {
				ans += solve(l, end);
			}
			System.out.printf("Case #%d: %d\n", lineIdx + 1, ans);
		}
	}
}
