package it.simone.google.code.jam2012;

import java.util.HashSet;
import java.util.Set;

public class RecycledNumber implements GoogleCodeExercise {

	int a = 0;
	int b = 0;
	Set<Couple> distinctCouple = null;
	long maxTime = 0;

	private class Couple {
		int x = 0;
		int y = 0;

		public Couple(int x, int y) {
			this.x = x;
			this.y = y;
		}

		@Override
		public int hashCode() {
			final int prime = 31;
			int result = 1;
			result = prime * result + getOuterType().hashCode();
			result = prime * result + x;
			result = prime * result + y;
			return result;
		}

		@Override
		public boolean equals(Object obj) {
			if (this == obj)
				return true;
			if (obj == null)
				return false;
			if (getClass() != obj.getClass())
				return false;
			Couple other = (Couple) obj;
			if (!getOuterType().equals(other.getOuterType()))
				return false;
			if (x == other.x && y == other.y)
				return true;
			if (x == other.y && y == other.x)
				return true;
			return false;
		}

		private RecycledNumber getOuterType() {
			return RecycledNumber.this;
		}

	}

	@Override
	public String execute(String line) {
		int result = 0;

		String[] data = line.split(" ");
		a = Integer.parseInt(data[0]);
		b = Integer.parseInt(data[1]);
		initialize();

		int n = a;
		//
		while (n <= b) {
			result += analize(n);
			n++;
//			if (n % 1000 == 0)
//				System.out.println(n);
		}

		System.out.println(result);
		return "" + result;
	}

	@Override
	public void initialize() {
		distinctCouple = new HashSet<Couple>();
	}

	private int analize(int number) {
		String numString = "" + number;
		initialize();
		for (int i = 1; i < numString.length(); i++) {
			int m = shift(numString, i);
			if (a <= number && number < m && m <= b) {
				Couple couple=new Couple(number,m);
				if (!distinctCouple.contains(couple))
					distinctCouple.add(couple);
			}
		}
		return distinctCouple.size();
	}

	private int shift(String numString, int posx) {

		String result = null;
		result = "" + numString.substring(posx) + numString.substring(0, posx);

		return Integer.parseInt(result.toString());
	}

}

package qC;

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;

import qB.B.Pair;

//Letfs say a pair of distinct positive integers (n, m) is recycled 
//if you can obtain m by moving some digits from the back of n to the 
//front without changing their order. For example, (12345, 34512) is a 
//recycled pair since you can obtain 34512 by moving 345 from the end 
//of 12345 to the front. Note that n and m must have the same number 
//of digits (excluding leading zeros) in order to be a recycled pair.

//Given integers A and B with the same number of digits, how many distinct
//recycled pairs (n, m) are there with A ? n < m ? B?

public class C2 {

	static int solve(int number, int b) {
		int numDigi = number;
		int orgNumber = number;
		int c = 1;
		int p = 1;
		int counter = 0;

		do {
			numDigi = numDigi / 10;
			p = p * 10;
			c++;
		} while (numDigi != 0);
		int k = c - 1;
		p = p / 10;

		for ( int i = 1; i <= k; i++) {
			number = number % p * 10 + number / p;
			if (number > orgNumber && number <= b) {
				// System.out.println( "no: " + number + ", " + check);
				counter++;
			}
		}
		return counter;
	}

	public static void main(String[] args) throws FileNotFoundException {
		if (args.length == 0) {
			throw new IllegalArgumentException("no file given");
		}
		String filename = args[0];
		Scanner scanner = new Scanner(new File(filename));
		int numOfLines = scanner.nextInt();
		scanner.nextLine();

		for (int lineIdx = 0; lineIdx < numOfLines; lineIdx++) {
			final int start = scanner.nextInt();
			final int end = scanner.nextInt();
			int ans = 0;
			for (int l = start; l <= end; l++) {
				ans += solve(l, end);
			}
			System.out.printf("Case #%d: %d\n", lineIdx + 1, ans);
		}
	}
}
