import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.HashSet;

public class Recycled {
    public static void main(String[] args) {
        try {
            BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
            int t = Integer.parseInt(br.readLine());
            for (int i = 0; i < t; i++) {
                String[] str = br.readLine().split(" ");
                int a = Integer.parseInt(str[0]);
                int b = Integer.parseInt(str[1]);
                System.out.println("Case #" + (i + 1) + ": " + find(a, b));
            }
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

    private static int find(int a, int b) {
        HashSet<Long> used = new HashSet<Long>();
        int digits = String.valueOf(a).length();
        if (digits == 1) return 0;
        for (int i = a; i <= b; i++) {
            int s = 10;
            int m = (int) Math.pow(10, digits-1);
            for (int j = 0; j < digits-1; j++) {
                int r = i % s;
                if (r < s/10) continue;
                int q = i / s;
                int rn = r * m + q;
                s *= 10; m /= 10;
                if (i != rn && rn >= a && rn <= b) {
                    long pp;
                    if (rn < i) pp = (long)rn << 30 | i;
                    else pp = (long)i << 30 | rn;
                    if (!used.contains(pp)) {
                        used.add(pp);
                    }
                }
            }
        }
        return used.size();
    }
}

public class RecycledNumbers
{
   public static void main(String[] args)
   {
      java.util.Scanner console = new java.util.Scanner(System.in);

      int T = 0;
      int A = 0, B = 0;

      int numRecycledNumbers = 0;


      T = console.nextInt();
      console.nextLine();

      for (int i = 0; i < T; i++)
      {
         A = console.nextInt();
         B = console.nextInt();
         console.nextLine();

         // do stuff
         numRecycledNumbers = findRecycledNumbers(A, B);

         System.out.println("Case #" + (i + 1) + ": " + numRecycledNumbers);
      }      


      return;
   }


   private static int findRecycledNumbers(int A, int B)
   {
      int n = B;
      int magnitude= 0;
      int pairs = 0;
      boolean alreadySubtractedOne = false;

      String str_m = String.valueOf(A);
      String str_n = String.valueOf(B);

      String firstHalf = "";
      String secondHalf = "";

      // m = x.y * 10^magnitude
      // magnitude 1 less then number of digits
      magnitude = str_n.length() - 1; 


      // halfPower is used to retrieve the first half of m.
      int halfPower = 1;
      for (int i = 0; i < (magnitude + 1) / 2; i++)
         halfPower *= 10;


      for (int m = A; m <= B; m++)
      {
         str_m = String.valueOf(m);

         
         for (int j = magnitude ; j > 0; j--)
         {
            // Substring goes from start to end - 1, hence need to add 1
            // as 'magnitude' already has 1 subtracted from it.
            str_n = str_m.substring(j, magnitude + 1) + str_m.substring(0, j);


            n = Integer.parseInt(str_n);

            if ((n > m) && (n <= B))
            {
               // If m is of even length and first half matches second half
               // two duplicate entries can be generated, so subtract 1 from count
               // ie. xyz|xyZ => Zxyz|xy or z|xyZxy
               if (!alreadySubtractedOne &&
                  (((m % halfPower) * halfPower) == (m - (m % halfPower))))
               {
                  alreadySubtractedOne = true;
                  pairs--;
               }
               
               pairs++;
            }
         }
         
      }

      return pairs;
   }

}
