
import java.util.Scanner;
import java.util.Set;
import java.util.TreeSet;
import java.io.File;
import java.io.IOException;
import java.io.FileWriter;
import java.io.BufferedWriter;

public class Recycle
{
	public static void main(String[] args)
	{
/*		Set<Integer> perms = getPermutations(123456);
		
		for(Integer i: perms)
			System.out.println(i);*/
	
		try
		{
			Scanner s = new Scanner(new File("recycle.in"));
			BufferedWriter w = new BufferedWriter(new FileWriter(new File("recycle.out")));
			int numCases = s.nextInt();
			s.nextLine();
			
			for(int n = 1;n <= numCases; n++)
			{
				int A = s.nextInt();
				int B = s.nextInt();
				int count = 0;
				for(int k = A; k <= B; k++)
				{
					count += getNumPairs(k, B);
				}
				
				w.write("Case #" + n + ": " + count + "\n");
			}
			
			w.flush();
			w.close();
		}
		catch (IOException e)
		{
			e.printStackTrace();
		}
	}
	
	public static int getNumPairs(int n, int B)
	{
		Set<Integer> possibles = getPermutations(n);
		int count = 0;
		for(Integer i : possibles)
			if(i > n && i <= B)
				count++;
		return count;
	}
	
	public static Set<Integer> getPermutations(int n)
	{
		Set<Integer> perms = new TreeSet<Integer>();
		char[] digits = String.valueOf(n).toCharArray();
		
		for(int firstPos = 1; firstPos < digits.length; firstPos++)
		{
			String toBuild = "";
			for(int k = 0; k < digits.length; k++)
				toBuild += digits[(firstPos + k) % digits.length];
			perms.add(Integer.parseInt(toBuild));
		}
		return perms;
	}
	

}
public class RecycledNumbers
{
   public static void main(String[] args)
   {
      java.util.Scanner console = new java.util.Scanner(System.in);

      int T = 0;
      int A = 0, B = 0;

      int numRecycledNumbers = 0;


      T = console.nextInt();
      console.nextLine();

      for (int i = 0; i < T; i++)
      {
         A = console.nextInt();
         B = console.nextInt();
         console.nextLine();

         // do stuff
         numRecycledNumbers = findRecycledNumbers(A, B);

         System.out.println("Case #" + (i + 1) + ": " + numRecycledNumbers);
      }      


      return;
   }


   private static int findRecycledNumbers(int A, int B)
   {
      int n = B;
      int magnitude= 0;
      int pairs = 0;
      boolean alreadySubtractedOne = false;

      String str_m = String.valueOf(A);
      String str_n = String.valueOf(B);

      String firstHalf = "";
      String secondHalf = "";

      // m = x.y * 10^magnitude
      // magnitude 1 less then number of digits
      magnitude = str_n.length() - 1; 


      // halfPower is used to retrieve the first half of m.
      int halfPower = 1;
      for (int i = 0; i < (magnitude + 1) / 2; i++)
         halfPower *= 10;


      for (int m = A; m <= B; m++)
      {
         str_m = String.valueOf(m);

         
         for (int j = magnitude ; j > 0; j--)
         {
            // Substring goes from start to end - 1, hence need to add 1
            // as 'magnitude' already has 1 subtracted from it.
            str_n = str_m.substring(j, magnitude + 1) + str_m.substring(0, j);


            n = Integer.parseInt(str_n);

            if ((n > m) && (n <= B))
            {
               // If m is of even length and first half matches second half
               // two duplicate entries can be generated, so subtract 1 from count
               // ie. xyz|xyZ => Zxyz|xy or z|xyZxy
               if (!alreadySubtractedOne &&
                  (((m % halfPower) * halfPower) == (m - (m % halfPower))))
               {
                  alreadySubtractedOne = true;
                  pairs--;
               }
               
               pairs++;
            }
         }
         
      }

      return pairs;
   }

}
