import java.io.FileInputStream;
import java.util.HashMap;
import java.util.Scanner;
import java.util.TreeSet;

// Recycled Numbers
// https://code.google.com/codejam/contest/1460488/dashboard#s=p2

public class C {

	private static String process(Scanner in) {
		int A = in.nextInt();
		int B = in.nextInt();
		int res = 0;
		int len = Integer.toString(A).length();
		for(int n = A; n < B; n++) {
			String str = Integer.toString(n);
			TreeSet<Integer> set = new TreeSet<Integer>();
			for(int i = 1; i < len; i++) {
				int m = Integer.parseInt(str.substring(i, len) + str.substring(0, i));
				if ( m > n && m <= B && ! set.contains(m) ) {
					set.add(m);
					res++;
				}
			}
		}
		return Integer.toString(res);
	}

	public static void main(String[] args) throws Exception {
		Scanner in = new Scanner(System.in.available() > 0 ? System.in : 
			new FileInputStream(Thread.currentThread().getStackTrace()[1].getClassName() + ".practice.in"));
		int T = in.nextInt();
		for(int i = 1; i <= T; i++) 
			System.out.format("Case #%d: %s\n", i, process(in));
	}
}

import java.io.*;
import java.util.*;

public class Main {
    public static void main(String[] args) throws IOException {
        Scanner in = new Scanner(new FileReader("C-small-attempt0.in"));
        PrintWriter out = new PrintWriter(new FileWriter("RecycledNumbers-Small.out"));

        RecycledNumbers solver = new RecycledNumbers();
        int testCases = in.nextInt();
        for (int i = 1; i <= testCases; ++i) {
            solver.solve(i, in, out);
        }

        in.close();
        out.close();
    }
}

class RecycledNumbers {
    int numberOfRecycledPairs(int A, int B) {
        int res = 0;
        boolean[] seen = new boolean[B + 1];
        for (int i = A; i <= B; ++i) {
            if (seen[i]) continue;
            int pairs = 0;
            char[] S = String.valueOf(i).toCharArray();
            for (int j = 0; j < S.length; ++j) {
                if (S[j] == '0') continue;
                int m = 0;
                for (int k = j; k < S.length; ++k) m = m * 10 + S[k] - '0';
                for (int k = 0; k < j; ++k) m = m * 10 + S[k] - '0';
                if (A <= m && m <= B && !seen[m]) {
                    seen[m] = true;
                    ++pairs;
                }
            }
            res += pairs * (pairs - 1) / 2;
        }
        return res;
    }

    public void solve(int testNumber, Scanner in, PrintWriter out) {
        int A = in.nextInt();
        int B = in.nextInt();

        out.println("Case #" + testNumber + ": " + numberOfRecycledPairs(A, B));
    }
}
