import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.StringTokenizer;

class RecycledNumbers{
	
	
	
	int getcount(int small,int large){
		int count = 0;
		for(int currnum = small; currnum < large; currnum++){
			int permut = currnum;
			int no_of_digits = 0;
			while(permut > 0){
				permut = permut/10;
				no_of_digits++;
			}
			int lastDigit = currnum % 10;
			permut = currnum / 10;
			permut = permut + lastDigit * (int)Math.pow(10, no_of_digits-1);
			while(permut != currnum){
				
				if(permut >= currnum && permut <= large){
					
					count++;
				}
				lastDigit = permut % 10;
				permut = permut / 10;
				permut = permut + lastDigit * (int)Math.pow(10, no_of_digits-1);
				
			}
			
		}
		
		return count;
	}
	
	public static void main(String args[]){
		RecycledNumbers d = new RecycledNumbers();
		
		int no_of_cases = 0;
		String input = "";
		
		BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
		try{
			no_of_cases = Integer.parseInt(br.readLine());
		}
		catch(Exception e){
			System.out.println("First line is not a number");
		}
		
		for(int i=1; i <= no_of_cases;i++){
			try{
				input = br.readLine();
			}
			catch(Exception e){
				System.out.println("Number of test cases different from the number mentioned in first line");
			}
			
			System.out.print("Case #" +i+": ");
			
			StringTokenizer t =  new StringTokenizer(input);
			int small=0,large=0;
			if(t.hasMoreTokens()){
				small = Integer.parseInt(t.nextToken());
			}
			if(t.hasMoreTokens()){
				large = Integer.parseInt(t.nextToken());
			}
			System.out.println(d.getcount(small,large));
			
		}
		
		
		

	}
	
	
}
import java.util.HashSet;
import java.util.Scanner;


class ProblemCSmall {
	// Not happy that my previous approaches didn't work and that I have to do it this way, but whatever works...
	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
		
		int T = in.nextInt(), I = 0;
		while (T --> 0) {
			int A = in.nextInt(), B = in.nextInt();
			int lenA = (int) Math.log10(A), lenB = (int) Math.log10(B);
			int prevStart = A;
			HashSet<String> pairs = new HashSet<String>();
			for (int i = lenA; i <= lenB; ++i) {
				int currPow10 = (int) Math.pow(10, i);
				int start = (int) Math.max(prevStart, currPow10), end = (int) Math.min(B, 10*currPow10-1);
				for (int j = start; j <= end; ++j) {
					int k = j;
					for (int l = 0; l < i; ++l) {
						k = (k % currPow10) * 10 + (k / currPow10);
						if (k >= start && k <= end && k != j) {
							pairs.add(String.format("%07d%07d", Math.min(j, k), Math.max(j, k)));
						}
					}
				}
				prevStart = end + 1;
			}
			System.out.printf("Case #%d: %d\n", ++I, pairs.size());
		}
	}

}
