import java.util.Scanner;
import java.io.*;
import java.lang.Math;


public class C{
	public static int recycle(String str){
		String[] numbers = str.split(" ");
		int min = Integer.parseInt(numbers[0]);
		int max = Integer.parseInt(numbers[1]);
		int ret = 0;

		for(int i = min; i < max; i++){
			String num = i + "";
			int len = num.length();
			int k = i;
			for(int j = 1; j < len; j++){
				k = (k/10) + (int)java.lang.Math.pow(10.0,(double)(len-1))*(k%10);
				if (k > i && k <= max)
					ret++;
				else if(k == i)
					break;
			}
		}

		return ret;
	}

	public static void main(String[] args){
		Scanner sc = null;
		String next;
		int out;
		try{
			sc = new Scanner(new File("C-large.in"));
			int cases = Integer.parseInt(sc.nextLine());
			int current = 0;
			

			FileWriter fs = new FileWriter("output.txt");
			BufferedWriter buff = new BufferedWriter(fs);
			while(current < cases){
				next = sc.nextLine();
				current++;
				out = recycle(next);
				buff.write("Case #" + current + ": " + out + "\n");
			}
			buff.close();
		}
		catch(Exception ex){}
	}
}
public class RecycledNumbers
{
   public static void main(String[] args)
   {
      java.util.Scanner console = new java.util.Scanner(System.in);

      int T = 0;
      int A = 0, B = 0;

      int numRecycledNumbers = 0;


      T = console.nextInt();
      console.nextLine();

      for (int i = 0; i < T; i++)
      {
         A = console.nextInt();
         B = console.nextInt();
         console.nextLine();

         // do stuff
         numRecycledNumbers = findRecycledNumbers(A, B);

         System.out.println("Case #" + (i + 1) + ": " + numRecycledNumbers);
      }      


      return;
   }


   private static int findRecycledNumbers(int A, int B)
   {
      int n = B;
      int magnitude= 0;
      int pairs = 0;
      boolean alreadySubtractedOne = false;

      String str_m = String.valueOf(A);
      String str_n = String.valueOf(B);

      String firstHalf = "";
      String secondHalf = "";

      // m = x.y * 10^magnitude
      // magnitude 1 less then number of digits
      magnitude = str_n.length() - 1; 


      // halfPower is used to retrieve the first half of m.
      int halfPower = 1;
      for (int i = 0; i < (magnitude + 1) / 2; i++)
         halfPower *= 10;


      for (int m = A; m <= B; m++)
      {
         str_m = String.valueOf(m);

         
         for (int j = magnitude ; j > 0; j--)
         {
            // Substring goes from start to end - 1, hence need to add 1
            // as 'magnitude' already has 1 subtracted from it.
            str_n = str_m.substring(j, magnitude + 1) + str_m.substring(0, j);


            n = Integer.parseInt(str_n);

            if ((n > m) && (n <= B))
            {
               // If m is of even length and first half matches second half
               // two duplicate entries can be generated, so subtract 1 from count
               // ie. xyz|xyZ => Zxyz|xy or z|xyZxy
               if (!alreadySubtractedOne &&
                  (((m % halfPower) * halfPower) == (m - (m % halfPower))))
               {
                  alreadySubtractedOne = true;
                  pairs--;
               }
               
               pairs++;
            }
         }
         
      }

      return pairs;
   }

}
