import java.util.*;
import java.io.*;

public class recycled_numbers {
	public static void main(String[]a) throws Exception{
		
		Scanner f = new Scanner(new File(a[0]));
		int result=0;
		int A,B;
		String n,m;
		HashSet<String> s=new HashSet<String>();
		
		int T=f.nextInt();	//T total case count
		for (int t=1; t<=T;t++){//for each case t
			
			s.clear();
			result=0;				//reset
			A=f.nextInt();B=f.nextInt();	//get values for next case
			
			if (A==B)result=0;//remove case not meeting problem limits 
			else{
				for(int i=A;i<=B;i++){//for each int in range
					n=Integer.toString(i);
					m=new String(n);
					//System.out.println(n);
					for (int j=1;j<n.length();j++){//move each digit to the front & test
						m = m.substring(m.length()-1)+m.substring(0,m.length()-1);
						if(m.matches("^0+[\\d]+")!=true &&
								Integer.parseInt(m)<=B &&
								Integer.parseInt(n)<Integer.parseInt(m)){
							s.add(new String(n+","+m));
							//result++;
							//System.out.println(" matched: "+m);
						}
						
					}
				}
				result = s.size();
			}

			//display output
			System.out.println("Case #" + t + ": " + result);
		}
	}
}
import java.util.Scanner;

/*
 * Google Code Jam 2012
 * Program by Tommy Ludwig
 * Problem: Recycled Numbers (large dataset)
 * Date: 2012-04-14
 * Time: 18:30 (PM) EST
 */


public class recycle_big {
	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
		int T = in.nextInt();
		
		for (int i = 1; i <= T; i++) {
			int A, B, n, m, y = 0;
			A = in.nextInt();
			B = in.nextInt();
			
			for (m = B; m > A; m--) {
				boolean skip = true;
				int lastN = 0;
				String strM = String.valueOf(m);
				
				for (int x = 1; x < strM.length(); x++) {
					if (Integer.valueOf(strM.substring(x, x+1)) != 0 && Integer.valueOf(strM.substring(x, x+1)) <= Integer.valueOf(strM.substring(0, 1))) {
						skip = false;
						break;
					}
				}
				if (skip) continue;
				
				//mutate m to make a valid n
				for (int l = 1; l < strM.length(); l++) {
					String sub = strM.substring(l);
					
					String strN = sub + strM.substring(0, l);
					n = Integer.valueOf(strN);
					
					//check that n is within bounds
					//check for duplicate pairs
					//check for leading zeros in strN
					if (n >= A && n < m && n != lastN && strN.equalsIgnoreCase(String.valueOf(n))) {
						y++;
						lastN = n;
					}
				}
			}
			System.out.printf("Case #%d: %d\n", i, y);
		}
	}
}