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package year_2012.qualification;

import java.io.BufferedReader;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.HashSet;
import java.util.Set;

/**
 *
 * @author paul
 * @date 14 Apr 2012
 */
public class QuestionC {

    private static Set<Integer> getCycle(int x) {

        String s = Integer.toString(x);
        Set<Integer> set = new HashSet<Integer>();
        set.add(x);
        for (int c = 1; c < s.length(); c++) {
            String t = s.substring(c).concat(s.substring(0, c));
            set.add(Integer.parseInt(t));
        }
        return set;
        
    }

    private static Set<Integer> mask(Set<Integer> set, int a, int b) {
        Set<Integer> result = new HashSet<Integer>();

        for (int x : set) {
            if (x >= a && x <= b) {
                result.add(x);
            }
        }
        
        return result;

    }


    public static void main(String[] args) throws FileNotFoundException, IOException {

        String question = "C";

//        String name = "large";
        String name = "small-attempt0";
//        String name = "test";

        String filename = String.format("%s-%s", question, name);

        BufferedReader input = new BufferedReader(
                new FileReader(String.format("/home/paul/Documents/code-jam/2012/qualification/%s.in",
                filename)));

        String firstLine = input.readLine();

        PrintWriter pw = new PrintWriter(new File(
                String.format("/home/paul/Documents/code-jam/2012/qualification/%s.out", filename)));


        int T = Integer.parseInt(firstLine);

        // Loop through test cases.
        for (int i = 0; i < T; i++) {

//             Read data.
            String[] tokens = input.readLine().split(" ");

//            int N = Integer.parseInt(input.readLine());

            int A = Integer.parseInt(tokens[0]);
            int B = Integer.parseInt(tokens[1]);

//            System.out.format("%d, %d\n", A, B);

            boolean[] used = new boolean[B+1];
            int total = 0;
            for (int n = A; n <= B; n++) {
                if (!used[n]) {
                    Set<Integer> set = mask(getCycle(n), A, B);
                    int k = set.size();
                    total += (k * (k-1))/2;
                    for (int m : set) {
                        used[m] = true;
                    }
                }
            }

            pw.format("Case #%d: %d\n", i + 1, total);
        }

        pw.close();

    }

}

package qualification.c;

import java.io.File;
import java.io.FileNotFoundException;
import java.util.HashSet;
import java.util.Scanner;
import java.util.Set;

/**
 * 
 * Problem
Do you ever become frustrated with television because you keep seeing the same things, recycled over and over again? Well I personally don't care about television, but I do sometimes feel that way about numbers.
Let's say a pair of distinct positive integers (n, m) is recycled if you can obtain m by moving some digits from the back of n to the front without changing their order. For example, (12345, 34512) is a recycled pair since you can obtain 34512 by moving 345 from the end of 12345 to the front. Note that n and m must have the same number of digits in order to be a recycled pair. Neither n nor m can have leading zeros.
Given integers A and B with the same number of digits and no leading zeros, how many distinct recycled pairs (n, m) are there with A â¤ n < m â¤ B?

Input
The first line of the input gives the number of test cases, T. T test cases follow. Each test case consists of a single line containing the integers A and B.

Output
For each test case, output one line containing "Case #x: y", where x is the case number (starting from 1), and y is the number of recycled pairs (n, m) with A â¤ n < m â¤ B.

Limits
1 â¤ T â¤ 50.
A and B have the same number of digits.

Small dataset
1 â¤ A â¤ B â¤ 1000.

Large dataset
1 â¤ A â¤ B â¤ 2000000.

Sample
Input 
4
1 9
10 40
100 500
1111 2222
Output 
Case #1: 0
Case #2: 3
Case #3: 156
Case #4: 287
Are we sure about the output to Case #4?
Yes, we're sure about the output to Case #4.

 * 2012.04.14. 16:22 - 16:38
 * @author Chei
 */
public class RecycledNumbers {
	Scanner scanner;
	public static void main(String[] args) throws FileNotFoundException {
		new RecycledNumbers().solve();
	}
	
	void solve() throws FileNotFoundException {
		//scanner = new Scanner(new File("resources/C-large.in"));
		scanner = new Scanner(new File("resources/C-small-attempt0.in"));
		//scanner = new Scanner(new File("resources/C-example.in"));
		int numberOfTestCases = scanner.nextInt();
		for (int testCaseIndex = 1; testCaseIndex <= numberOfTestCases; testCaseIndex++) {
			int result = solveTestCase();
			System.out.format("Case #%d: %d%n", testCaseIndex, result);
		}
	}

	int solveTestCase() {
		int a = scanner.nextInt();
		int b = scanner.nextInt();
		Set<String> recycledNumbers = new HashSet<String>();
		int result = 0;
		for (int num = a; num <= b; num++) {
			String numString = String.valueOf(num);
			recycledNumbers.clear();
			for (int i = 0; i < numString.length(); i++) {
				String newString = numString.substring(i) + numString.substring(0, i);
				if (newString.charAt(0) != '0') {
					int newNum = Integer.parseInt(newString);
					if (newNum >= a && newNum <= b) {
						recycledNumbers.add(newString);
					}
				}
			}
			result += recycledNumbers.size() - 1;
		}
		// all pairs were counted twice
		return result / 2;
	}
}
