package Main;

import com.sun.deploy.util.ArrayUtil;
import org.apache.commons.lang3.ArrayUtils;

import java.io.*;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.HashMap;
import java.util.HashSet;

/**
 * Created with IntelliJ IDEA.
 * User: arran
 * Date: 14/04/12
 * Time: 3:12 PM
 * To change this template use File | Settings | File Templates.
 */
public class Round {
    public StringBuilder parse(BufferedReader in) throws IOException {
        StringBuilder out = new StringBuilder();
        String lineCount = in.readLine();

        for (int i = 1; i <= Integer.parseInt(lineCount); i++)
        {
            out.append("Case #"+i+": ");
            System.err.println("Case #"+i+": ");
            String line = in.readLine();
            String[] splits = line.split(" ");
            int p1 = Integer.valueOf(splits[0]);
            int p2 = Integer.valueOf(splits[1]);
            int r = pairRecyclable(p1, p2);
            out.append(r);

//            if (i < Integer.parseInt(lineCount))
                out.append("\n");
        }
        return out;
    }

    public static int pairRecyclable(int i1, int i2) {
        HashSet<String> hash = new HashSet<String>();
        for (int i = i1; i < i2; i++)
        {
            String istr = String.valueOf(i);
            if (istr.length() < 2) continue;
            for (int p = 0; p < istr.length() ; p++)
            {
                String nistr = istr.substring(p,istr.length()).concat(istr.substring(0,p));
                if (Integer.valueOf(nistr) < i1) continue;
                if (Integer.valueOf(nistr) > i2) continue;
                if (nistr.equals(istr)) continue;
                String cnistr = (Integer.valueOf(nistr) > Integer.valueOf(istr)) ?  istr + "," + nistr : nistr + "," + istr;
                hash.add(cnistr);
            }
        }
        return hash.size();
    }

    public static void main(String[] args) {
        InputStreamReader converter = null;
        try {
            int attempt = 0;
            String quest = "C";
//            String size = "small-attempt";
            String size = "large";
            converter = new InputStreamReader(new FileInputStream("src/resource/"+quest+"-"+size+".in"));
            BufferedReader in = new BufferedReader(converter);
            Round r = new Round();
            String str = r.parse(in).toString();
            System.out.print(str);
            FileOutputStream fos = new FileOutputStream(quest+"-"+size+".out");
            OutputStreamWriter osw = new OutputStreamWriter(fos);
            BufferedWriter bw = new BufferedWriter(osw);
            bw.write(str);
            bw.flush();
            bw.close();
        } catch (IOException e) {
            e.printStackTrace();
        }

    }
}

package qualification.c;

import java.io.File;
import java.io.FileNotFoundException;
import java.util.HashSet;
import java.util.Scanner;
import java.util.Set;

/**
 * 
 * Problem
Do you ever become frustrated with television because you keep seeing the same things, recycled over and over again? Well I personally don't care about television, but I do sometimes feel that way about numbers.
Let's say a pair of distinct positive integers (n, m) is recycled if you can obtain m by moving some digits from the back of n to the front without changing their order. For example, (12345, 34512) is a recycled pair since you can obtain 34512 by moving 345 from the end of 12345 to the front. Note that n and m must have the same number of digits in order to be a recycled pair. Neither n nor m can have leading zeros.
Given integers A and B with the same number of digits and no leading zeros, how many distinct recycled pairs (n, m) are there with A â¤ n < m â¤ B?

Input
The first line of the input gives the number of test cases, T. T test cases follow. Each test case consists of a single line containing the integers A and B.

Output
For each test case, output one line containing "Case #x: y", where x is the case number (starting from 1), and y is the number of recycled pairs (n, m) with A â¤ n < m â¤ B.

Limits
1 â¤ T â¤ 50.
A and B have the same number of digits.

Small dataset
1 â¤ A â¤ B â¤ 1000.

Large dataset
1 â¤ A â¤ B â¤ 2000000.

Sample
Input 
4
1 9
10 40
100 500
1111 2222
Output 
Case #1: 0
Case #2: 3
Case #3: 156
Case #4: 287
Are we sure about the output to Case #4?
Yes, we're sure about the output to Case #4.

 * 2012.04.14. 16:22 - 16:38
 * @author Chei
 */
public class RecycledNumbers {
	Scanner scanner;
	public static void main(String[] args) throws FileNotFoundException {
		new RecycledNumbers().solve();
	}
	
	void solve() throws FileNotFoundException {
		scanner = new Scanner(new File("resources/C-large.in"));
		//scanner = new Scanner(new File("resources/C-small-attempt0.in"));
		//scanner = new Scanner(new File("resources/C-example.in"));
		int numberOfTestCases = scanner.nextInt();
		for (int testCaseIndex = 1; testCaseIndex <= numberOfTestCases; testCaseIndex++) {
			int result = solveTestCase();
			System.out.format("Case #%d: %d%n", testCaseIndex, result);
		}
	}

	int solveTestCase() {
		int a = scanner.nextInt();
		int b = scanner.nextInt();
		Set<String> recycledNumbers = new HashSet<String>();
		int result = 0;
		for (int num = a; num <= b; num++) {
			String numString = String.valueOf(num);
			recycledNumbers.clear();
			for (int i = 0; i < numString.length(); i++) {
				String newString = numString.substring(i) + numString.substring(0, i);
				if (newString.charAt(0) != '0') {
					int newNum = Integer.parseInt(newString);
					if (newNum >= a && newNum <= b) {
						recycledNumbers.add(newString);
					}
				}
			}
			result += recycledNumbers.size() - 1;
		}
		// all pairs were counted twice
		return result / 2;
	}
}
