import java.io.*;
import java.math.BigInteger;
import java.util.*;

import org.jfree.data.function.PowerFunction2D;

public class r2a
{

	Map numMap = new HashMap();
    int output = 0;

    /**
     * @param args
     */
    public static void main(String[] args)
    {
        r2a mk = new r2a();
        try {
            FileInputStream fstream = new FileInputStream("d:/cjinput.txt");
            DataInputStream in = new DataInputStream(fstream);
            BufferedReader br = new BufferedReader(new InputStreamReader(in));
            String str;
            int i = 0;
            while ((str = br.readLine()) != null) {
            	int begin=0,end = 0;
                i++;
                if (i == 1)
                    continue;
                mk.numMap = new HashMap();
                StringTokenizer strTok = new StringTokenizer(str, " ");
                while (strTok.hasMoreTokens()) {
                	begin =  Integer.parseInt(((String) strTok.nextToken()));
                    end = Integer.parseInt(((String) strTok.nextToken()));
                }

                mk.evaluate(i, begin, end);

            }
            in.close();
        }
        catch (Exception e) {
            System.err.println(e);
        }

    }

    private void evaluate(int rowNum, int begin, int end)
    {
    	output=0;
    	for (int i = begin; i<= end; i++) {
    		if(numMap.containsKey(Integer.valueOf(i)))
    			continue;
    		List l = getPairElems(i);
    		if (l.size() > 0) {
    			Iterator itr = l.iterator();
    			int ctr = 0;
    			ArrayList tempList = new ArrayList();
    			while (itr.hasNext()) {
    				int next = ((Integer)itr.next()).intValue();
    				if (next <= end && next > i) {
    					numMap.put(Integer.valueOf(next), i);
    					tempList.add(next);
    					ctr++;
    				}
    			}
    			ctr = getCounter(ctr+1,2);
/*    			if (tempList.size() > 0 || ctr > 0)
    				System.out.println("DD: " + i + ": " + tempList +" ; ctr = " + ctr);*/
    			output = output + ctr;
    		}
    		
    	}

        String outputStr = "Case #" + (rowNum -1) + ": " + output;
        
        System.out.println(outputStr);
    }

	private int getCounter(int n, int r) {
		int ret = 1;
		int nfactorial =1;
		for (int i = 2; i<=n; i++) {
			nfactorial = i*nfactorial;
		}
		int nrfact =1;
		for (int i = 2; i<=n-r; i++) {
			nrfact = i*nrfact;
		}
		
		return nfactorial/(2*nrfact);
	}

	private ArrayList getPairElems(int num) {
		ArrayList retList = new ArrayList();
		int temp = num;
		if (num/10 == 0)
			return retList;
		
		String str = String.valueOf(num);
		
		int arr[] = new int[str.length()];
		int x = str.length();
		while (temp/10 > 0) {
			arr[x-1] = temp%10;
			temp=temp/10;
			x--;
		}
		arr[0]=temp;
		
		int size = arr.length;
		for (int pos = size -1; pos >0; pos--) {
			if(arr[pos] == 0)
				continue;
			int pairNum = 0;
			int multiplier =1;
			for (int c=0; c < size-1; c++) {
				multiplier = multiplier*10;
			}
			pairNum = pairNum + (arr[pos]*multiplier);
			for(int ctr = pos+1, i=1; i < size; i++,ctr++) {
				if (ctr == size)
					ctr=0;
				if (multiplier!=1)
					multiplier=multiplier/10;
				pairNum = pairNum + (arr[ctr]*multiplier);
			}
			if (pairNum != num)
				retList.add(Integer.valueOf(pairNum));			
		}
		
		return retList;
	}
}

/**
 * 
 */
package codejam2012.qualification;

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.File;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
import java.util.HashSet;
import java.util.Set;

/**
 * @author Jaffar Ramay
 *
 *
Problem

Do you ever become frustrated with television because you keep seeing the same things, recycled over and over again? Well I personally don't care about television, but I do sometimes feel that way about numbers.

Let's say a pair of distinct positive integers (n, m) is recycled if you can obtain m by moving some digits from the back of n to the front without changing their order. For example, (12345, 34512) is a recycled pair since you can obtain 34512 by moving 345 from the end of 12345 to the front. Note that n and m must have the same number of digits in order to be a recycled pair. Neither n nor m can have leading zeros.

Given integers A and B with the same number of digits and no leading zeros, how many distinct recycled pairs (n, m) are there with A â¤ n < m â¤ B?

Input

The first line of the input gives the number of test cases, T. T test cases follow. Each test case consists of a single line containing the integers A and B.

Output

For each test case, output one line containing "Case #x: y", where x is the case number (starting from 1), and y is the number of recycled pairs (n, m) with A â¤ n < m â¤ B.

Limits

1 â¤ T â¤ 50.
A and B have the same number of digits.

Small dataset

1 â¤ A â¤ B â¤ 1000.

Large dataset

1 â¤ A â¤ B â¤ 2000000.

Sample


Input 
 	 
4
1 9
10 40
100 500
1111 2222

Output 

Case #1: 0
Case #2: 3
Case #3: 156
Case #4: 287

Are we sure about the output to Case #4?

Yes, we're sure about the output to Case #4.
 */
public class RecycledNumbers {

	public static void solve() throws IOException {
		BufferedReader reader = new BufferedReader(new FileReader(new File("/Users/jaffar_ramay/Workspaces/eclipseWorkspace/Revision/src/codejam2012/qualification/RecycledNumbers.in")));
		BufferedWriter writer = new BufferedWriter(new FileWriter(new File("/Users/jaffar_ramay/Workspaces/eclipseWorkspace/Revision/src/codejam2012/qualification/RecycledNumbers.out")));
		String line = null;
		while((line=reader.readLine())!=null){
			int testCases = Integer.parseInt(line);
			for (int i = 1; i <= testCases; i++) {
				String[] testCase = reader.readLine().split(" ");
			     int numberA = Integer.parseInt(testCase[0]);
			     int numberB = Integer.parseInt(testCase[1]);
			     int result = getRecycledCount(numberA, numberB);
			     writer.write("Case #"+i+": "+result);
			     if(i<testCases)
			    	 writer.newLine();
			}
		}
		reader.close();
		writer.close();
	}
	public static int getRecycledCount(int numberA, int numberB) {
		int result=0;
		Set<String> set = new HashSet<String>();
		for (int i = numberA; i <= numberB; i++) {
			
			String number = i+"";
			
			for (int j = 0; j < number.length(); j++) {
				
				int firstNumber = Integer.parseInt(number);
				int index = (number.length()-(j+1));
				if(index>0 && index<number.length()){
					int secondNumber =  (Integer.parseInt(number.substring(index,number.length())+number.substring(0,index)));
					
					if(numberA<=firstNumber && firstNumber<secondNumber && secondNumber<=numberB && (firstNumber+"").length() == (secondNumber+"").length()){
						set.add(firstNumber+""+secondNumber);
					}	
				}
				
			}
			
		}
		return set.size();
	}
	
	public static void main(String[] args) throws IOException {
		solve();
	}
}
