/*
 * Problem C. Recycled Numbers
 * 
 * Do you ever become frustrated with television because you keep seeing the
 * same things, recycled over and over again? Well I personally don't care about
 * television, but I do sometimes feel that way about numbers.
 * 
 * Let's say a pair of distinct positive integers (n, m) is recycled if you can
 * obtain m by moving some digits from the back of n to the front without
 * changing their order. For example, (12345, 34512) is a recycled pair since
 * you can obtain 34512 by moving 345 from the end of 12345 to the front. Note
 * that n and m must have the same number of digits in order to be a recycled
 * pair. Neither n nor m can have leading zeros.
 * 
 * Given integers A and B with the same number of digits and no leading zeros,
 * how many distinct recycled pairs (n, m) are there with A â¤ n < m â¤ B?
 * 
 * Input
 * 
 * The first line of the input gives the number of test cases, T. T test cases
 * follow. Each test case consists of a single line containing the integers A
 * and B.
 * 
 * Output
 * 
 * For each test case, output one line containing "Case #x: y", where x is the
 * case number (starting from 1), and y is the number of recycled pairs (n, m)
 * with A â¤ n < m â¤ B.
 * 
 * Limits
 * 
 * 1 â¤ T â¤ 50.
 * 
 * A and B have the same number of digits.

Small dataset

1 â¤ A â¤ B â¤ 1000.

Large dataset

1 â¤ A â¤ B â¤ 2000000.

Sample


Input 
 	
Output 
 
4
1 9
10 40
100 500
1111 2222
Case #1: 0
Case #2: 3
Case #3: 156
Case #4: 287
 */

package google.codejam.y2012.qualifications;

import google.codejam.commons.Utils;

import java.io.IOException;
import java.util.StringTokenizer;

/**
 * @author Marco Lackovic <marco.lackovic@gmail.com>
 * @version 1.0, Apr 14, 2012
 */
public class RecycledNumbers {

	private static final String INPUT_FILE_NAME = "C-large.in";
	private static final String OUTPUT_FILE_NAME = "C-large.out";

	public static void main(String[] args) throws IOException {
		String[] input = Utils.readFromFile(INPUT_FILE_NAME);
		String[] output = new String[input.length];
		int x = 0;
		for (String line : input) {
			StringTokenizer st = new StringTokenizer(line);
			int a = Integer.valueOf(st.nextToken());
			int b = Integer.valueOf(st.nextToken());
			System.out.println("Computing case #" + (x + 1));
			output[x++] = "Case #" + x + ": " + recycledNumbers(a, b);
		}
		Utils.writeToFile(output, OUTPUT_FILE_NAME);
	}

	private static int recycledNumbers(int a, int b) {
		int count = 0;
		for (int n = a; n < b; n++) {
			count += getNumGreaterRotations(n, b);
		}
		return count;
	}

	private static int getNumGreaterRotations(int n, int b) {
		int count = 0;
		char[] chars = Integer.toString(n).toCharArray();
		for (int i = 0; i < chars.length; i++) {
			chars = rotateRight(chars);
			if (chars[0] != '0') {
				int m = Integer.valueOf(new String(chars));
				if (n == m) {
					break;
				} else if (n < m && m <= b) {
					count++;
				}
			}
		}
		return count;
	}

	private static char[] rotateRight(char[] chars) {
		char last = chars[chars.length - 1];
		for (int i = chars.length - 2; i >= 0; i--) {
			chars[i + 1] = chars[i];
		}
		chars[0] = last;
		return chars;
	}

}

import java.util.*;
import java.io.*;

public class CodeJam {
    public static void main(String[] args) {
        try {
            //recycleLarge(1000000, 2000000);
            // read
            FileInputStream instream = new FileInputStream("A-small.in");
            DataInputStream in = new DataInputStream(instream);
            BufferedReader br = new BufferedReader(new InputStreamReader(in));

            // write
            FileOutputStream outstream = new FileOutputStream("A-small.out");
            DataOutputStream out = new DataOutputStream(outstream);
            BufferedWriter bw = new BufferedWriter(new OutputStreamWriter(out));

            // reading file information
            int testcases = Integer.parseInt(br.readLine());
            for (int i = 0; i < testcases; i++) {
                // -------------------------------------------------------------------------------------------------------------
                String line = br.readLine();
                String[] items = line.split(" ");
                int A = Integer.parseInt(items[0]);
                int B = Integer.parseInt(items[1]);
                // -------------------------------------------------------------------------------------------------------------
                bw.write("Case #" + (i + 1) + ": " + recycleLarge(A, B) + "\r\n");
            }

            // close input file
            in.close();
            // close output file
            bw.flush();
            out.close();
        } catch (Exception e) {
            System.err.println("Error: " + e.getMessage());
        }
    }

    private static int eval(int i) {
        if (i < 0)
            return 0;
        else
            return i;
    }

    private static void printArray(Object[] array) {
        for (Object ch : array)
            System.out.print(ch);
    }

    private static boolean isRecycled(String str, String m) {
        for (int i = 1; i < str.length(); i++) {
            String digits = str.substring(i) + str.substring(0, i);
            if (digits.equals(m)) return true;
        }
        return false;
    }

    private static String convertTo(int n) {
        String str = "";
        while (n != 0) {
            str = (n % 10) + str;
            n = n / 10;
        }
        return str;
    }

    private static long recycle(int A, int B) {
        long count = 0;
        for (int n = A; n < B; n++) {
            for (int m = n + 1; m <= B; m++) {
                String nstr = convertTo(n);
                String mstr = convertTo(m);
                if (isRecycled(nstr, mstr))
                    count++;
            }
        }
        return count;
    }

    private static long evaluate(int n, int A, int B) {
        String nstr = convertTo(n);
        int c = 0;
        for (int i = 1; i < nstr.length(); i++) {
            String digits = nstr.substring(i) + nstr.substring(0, i);
            int variation = Integer.parseInt(digits);
            if(digits.charAt(0) == '0') continue;
            if (digits.equals(nstr)) continue;
            if (variation <= B && variation >= A){
                visit[variation] = true;
                c++;
            }

        }
        return sum(c);
    }

    private static long sum(int n){
        return n * (n+1) / 2;
    }

    private static long recycleLarge(int A, int B) {
        long sum = 0;
        visit = new boolean[B+1];
        for(int i=0; i<B; i++) visit[i] = false;
        for (int n = A; n <= B; n++) {
            if (visit[n] == false)
                sum += evaluate(n, A, B);
        }
        return sum;
    }

    private static boolean[] visit = null;


}

