/*
 * To change this template, choose Tools | Templates
 * and open the template in the editor.
 */

import java.io.File;
import java.io.FileInputStream;
import java.util.Scanner;

/**
 *
 * @author imgps
 */
public class C {
    public static void main(String args[]) throws Exception{
        int A,B;
        int ctr = 0;
        int testCases;
        
        Scanner sc = new Scanner(new FileInputStream("C-small-attempt0.in "));
        testCases = sc.nextInt();
        int input[][] = new int[testCases][2];
        for(int i=0;i<testCases;i++)
        {
          //  System.out.print("Enter input A B: ");
            input[i][0] = sc.nextInt();
            input[i][1] = sc.nextInt();
            
        }
  

for(int k=0;k<testCases;k++){
      ctr = 0;
      A = input[k][0];
      B = input[k][1];
        for(int i = A;i<=B;i++){
            int num = i;
            int nMul = 1;
            int mul = 1; 
            int tnum = num/10;
            while(tnum > 0){
                mul = mul *10;
                tnum= tnum/10;
            }
            tnum = num;
            int n = 0;
            while(tnum > 0 && mul >= 10){
                nMul = nMul * 10;
                n = (num % nMul) * mul + (num / nMul);
                mul = mul / 10;
                tnum = tnum / 10;
                for(int m=num;m<=B;m++){
                    
                    if(n == m && m > num){
                        ctr++;
                    }
                }
                
                
                
         
            }
        }
        System.out.println("Case #"+(k+1)+": "+ctr);
        
    }
    }
}

/*
Problem

Do you ever become frustrated with television because you keep seeing the same things, recycled over and over again? Well I personally don't care about television, but I do sometimes feel that way about numbers.

Let's say a pair of distinct positive integers (n, m) is recycled if you can obtain m by moving some digits from the back of n to the front without changing their order. For example, (12345, 34512) is a recycled pair since you can obtain 34512 by moving 345 from the end of 12345 to the front. Note that n and m must have the same number of digits in order to be a recycled pair. Neither n nor m can have leading zeros.

Given integers A and B with the same number of digits and no leading zeros, how many distinct recycled pairs (n, m) are there with A = n < m = B?

Input

The first line of the input gives the number of test cases, T. T test cases follow. Each test case consists of a single line containing the integers A and B.

Output

For each test case, output one line containing "Case #x: y", where x is the case number (starting from 1), and y is the number of recycled pairs (n, m) with A = n < m = B.

Limits

1 = T = 50.
A and B have the same number of digits.

Small dataset

1 = A = B = 1000.

Large dataset

1 = A = B = 2000000.

Sample


Input 
 	
Output 
 
4
1 9
10 40
100 500
1111 2222
Case #1: 0
Case #2: 3
Case #3: 156
Case #4: 287

*/

import java.io.*;
import java.util.*;
import java.util.logging.Level;
import java.util.logging.Logger;
public class RecycledNumbers

{
     BufferedReader read;
     BufferedWriter write;
    public static void main(String args[])
    {
        try {
            new RecycledNumbers().init("C-small-attempt0");
        } catch (Exception ex) {
            //Logger.getLogger(RecycledNumbers.class.getName()).log(Level.SEVERE, null, ex);
			System.out.println("Error" + ex);
			
        }
    }
     void init(String name) throws Exception
    {
        read=new BufferedReader(new FileReader(new File(name+".in")));
        write=new BufferedWriter(new FileWriter(new File(name+".out")));
        
		String x="";
        
            try {
                   x = read.readLine();
                   int nos = Integer.parseInt(x.trim());
                   for(int z=0;z<nos;z++)
                      {
					      
                                  x = read.readLine();
								  String ss[]=x.split(" ");
								 // int[] anb = new int[ss.length];
								   int a =  Integer.parseInt(ss[0].trim());
								   int b =  Integer.parseInt(ss[1].trim());;
								   //System.out.println(a+"  "+b );
								   //a=10;b=40;
									  int count=0;
								   for(int i=a;i<=b;i++)
								    {
									  String sub="",s1="";
									  String s= "" + i;
									  //System.out.println("....   "+s);
									  int len = s.length();
									  ArrayList<Integer> ar=new ArrayList<Integer>();
									  for(int j=0;j<len;j++)
										{
									      String c = ""+(s.charAt(len-1));
										  // System.out.print("....   "+c);
										  sub = s.substring(0,len-1);
										   //System.out.print("....   "+sub);
										//  s1 = c + sub;
										  s = c + sub;
										 //System.out.print("....   "+s);
										  if(s.charAt(0)!='0')
										   {
										     int num = Integer.parseInt(s);
											 if(!ar.contains(num)&&num>i && num<=b)
											 {
											 ar.add(num);
											 //System.out.println("   i....   "+i+"...num....   "+num);
											 count++;}
										   }
									    }
									}

								write.write("Case #"+(z+1)+":"+" "+count+"\n");
							System.out.println("Case #"+(z+1)+":"+" "+count+"\n");
					 }                
				write.flush();
                   write.close();
                   read.close();
                  // System.out.println(a+"    "+b);
                
              }
             catch (Exception ex) {
			 System.out.println("Error" + ex);
                           System.exit(0);
            }
      
}
}