import java.io.File;
import java.io.FileNotFoundException;
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.HashMap;
import java.util.Map;
import java.util.Scanner;
import java.util.Set;

public class CopyOfCopyOfMain {

	static int ndigits(int n) {
		return (int) (Math.log10(n) + 1);
	}

	static int rot(int n, int dig) {
		return (int) ((n % 10) * Math.pow(10, dig - 1)) + (int) (n / 10);
	}

	public static void main(String[] args) throws FileNotFoundException {
		String file = "C-large";
		Scanner in = new Scanner(new File(file + ".in"));
		PrintWriter out = new PrintWriter(new File(file + ".out"));

		int T = in.nextInt();
		for (int t = 1; t <= T; t++) {
			int A = in.nextInt();
			int B = in.nextInt();

			int c = 0;
			int[] list = new int[ndigits(B)];
			numbers: for (int i = A; i <= B; i++) {
				int digs = ndigits(i);
				int rot = i;
				int pairs = 0;

				Arrays.fill(list, -1);
				list[0] = i;

				digits: for (int j = 1; j <= digs + 1; j++) {

					rot = rot(rot, digs);
					if(rot < i)
						continue;

					if (A <= rot && rot <= B) {
						for (int k = 0; k < j; k++) {
							if (list[k] == rot) {
								continue digits;
							}
						}
						pairs++;
						list[j] = rot;
					}
				}

				//c += pairs * (pairs + 1) / 2;
				c += pairs ;
				// c+=digs;
			}
			out.println("Case #" + t + ": " + c);
		}

		in.close();
		out.close();
	}
}


import java.io.File;
import java.io.IOException;
import java.io.PrintWriter;
import java.util.HashSet;
import java.util.Scanner;

public class Recycled {
    public static void main(String[] args) throws IOException {
        int[] powersOf10 = {1, 10, 100, 1000, 10000, 100000, 1000000};
        String inFileName = "C-large.in";
        Scanner in = new Scanner(new File(inFileName));
        String outFileName = inFileName.substring(0, inFileName.lastIndexOf('.')) + ".out";
        PrintWriter out = new PrintWriter(outFileName);
        int numSets = in.nextInt();
        in.nextLine();
        for(int probSet = 1; probSet <= numSets; probSet++) {
            out.print("Case #" + probSet + ": ");
            int a = in.nextInt();
            int b = in.nextInt();
            HashSet<Pair> set = new HashSet<Pair>();
            int numOne = a;
            while(numOne <= b) {
                //figure out length of a, could use logs but don't want to worry
                //about double division, rounding, ceiling, etc.
                int temp = numOne;
                int len = 1;
                while((temp /= 10) > 0) len++;
                int numTwo = numOne;
                //cycle through all possible pairs with a
                for(int i = 0; i < len - 1; i++) {
                    int dig = numTwo % 10;
                    if(dig == 0) continue; //moving a 0 from the back to the front
                                            //would change the length of the number
                    numTwo /= 10;
                    numTwo += dig * powersOf10[len - 1];
                    if(numTwo < a || numTwo > b || numOne == numTwo) continue;
                    Pair pair = new Pair(numOne, numTwo);
                    set.add(pair);
                }
                numOne++;
            }
            out.println(set.size());
        }
        in.close();
        out.close();
    }
    
    private static class Pair {
        int one, two;
        public Pair(int o, int t) {
            one = o;
            two = t;
        }

        @Override
        public int hashCode() {
            return one + two; //a bad hash, but I need something commutative
        }
        
        public boolean equals(Object obj) {
            Pair other = (Pair) obj;
            return (other.one == one && other.two == two) || 
                    (other.one == two && other.two == one);
        }
        
        public String toString() {
            return "{" + one + ", " + two + "}";
        }
    }
}
