/*
 * To change this template, choose Tools | Templates
 * and open the template in the editor.
 */
package gcj;

import java.io.File;
import java.io.FileWriter;
import java.util.ArrayList;
import java.util.Scanner;

/**
 *
 * @author daniele
 */
public class GCJ_C {
    
    public static void main(String[] args) throws Exception{
        
        
        
        Scanner in = new Scanner(new File(args[0]));
        FileWriter out = new FileWriter("/home/daniele/Scrivania/Output");
        

        int prove=in.nextInt();
        int min,max;
        int cifre;
        int cifreaus;
        String temp;
        int aus;
        int count=0;
        ArrayList<Integer> vals = new ArrayList<Integer>();
        int jcount=0;
        ArrayList<Integer> perm = new ArrayList<Integer>();
        
        out.write("");
        out.flush();
        
        for(int i=1;i<=prove;i++){
            
            out.append("Case #" +i+": ");out.flush();
            
            min=in.nextInt();
            max=in.nextInt();
            
            for(int j=min;j<=max;j++){
               if(!vals.contains(j)){
                    temp=""+j;
                    cifre=temp.length();
                    aus=j;
                    perm.add(j);
                    for(int k=1;k<cifre;k++){
                        aus=rotateOnce(aus);
                        temp=""+aus;
                        cifreaus=temp.length();//elusione zeri iniziali
                        if(aus>=min && aus<=max && aus!=j && cifreaus==cifre && nobody(vals,perm)){ 
                            perm.add(aus);
                            jcount ++;
                            
                        }
                        
                    }
                    while(jcount>0){count+=jcount; jcount--;}
                    vals.addAll(perm);
                    perm= new ArrayList<Integer>();
                    
                }
            }
            out.append(count+"\n");out.flush();
            count=0;
            vals= new ArrayList<Integer>();
        }
        
        
        
    }
        static public int rotateOnce(int n){
            String s=""+n;
            if(s.length()>1){
                s=s.charAt(s.length()-1) + s.substring(0,s.length()-1);
                n=Integer.parseInt(s);
            }
            return n;
        }    
        
        static public boolean nobody(ArrayList<Integer> v,ArrayList<Integer> a){;
            for(int i=0;i<a.size();i++)
                if(v.contains(a.get(i))) return false;
            return true;
        } 
    
}


package qC;

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;

import qB.B.Pair;

//Letfs say a pair of distinct positive integers (n, m) is recycled 
//if you can obtain m by moving some digits from the back of n to the 
//front without changing their order. For example, (12345, 34512) is a 
//recycled pair since you can obtain 34512 by moving 345 from the end 
//of 12345 to the front. Note that n and m must have the same number 
//of digits (excluding leading zeros) in order to be a recycled pair.

//Given integers A and B with the same number of digits, how many distinct
//recycled pairs (n, m) are there with A ? n < m ? B?

public class C2 {

	static int solve(int number, int b) {
		int numDigi = number;
		int orgNumber = number;
		int c = 1;
		int p = 1;
		int counter = 0;

		do {
			numDigi = numDigi / 10;
			p = p * 10;
			c++;
		} while (numDigi != 0);
		int k = c - 1;
		p = p / 10;

		for ( int i = 1; i <= k; i++) {
			number = number % p * 10 + number / p;
			if (number > orgNumber && number <= b) {
				// System.out.println( "no: " + number + ", " + check);
				counter++;
			}
		}
		return counter;
	}

	public static void main(String[] args) throws FileNotFoundException {
		if (args.length == 0) {
			throw new IllegalArgumentException("no file given");
		}
		String filename = args[0];
		Scanner scanner = new Scanner(new File(filename));
		int numOfLines = scanner.nextInt();
		scanner.nextLine();

		for (int lineIdx = 0; lineIdx < numOfLines; lineIdx++) {
			final int start = scanner.nextInt();
			final int end = scanner.nextInt();
			int ans = 0;
			for (int l = start; l <= end; l++) {
				ans += solve(l, end);
			}
			System.out.printf("Case #%d: %d\n", lineIdx + 1, ans);
		}
	}
}
