package CodeJam.c2012.clasificacion;

import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;

/**
 * Problem
 *
 * You're watching a show where Googlers (employees of Google) dance, and then
 * each dancer is given a triplet of scores by three judges. Each triplet of
 * scores consists of three integer scores from 0 to 10 inclusive. The judges
 * have very similar standards, so it's surprising if a triplet of scores
 * contains two scores that are 2 apart. No triplet of scores contains scores
 * that are more than 2 apart.
 *
 * For example: (8, 8, 8) and (7, 8, 7) are not surprising. (6, 7, 8) and (6, 8,
 * 8) are surprising. (7, 6, 9) will never happen.
 *
 * The total points for a Googler is the sum of the three scores in that
 * Googler's triplet of scores. The best result for a Googler is the maximum of
 * the three scores in that Googler's triplet of scores. Given the total points
 * for each Googler, as well as the number of surprising triplets of scores,
 * what is the maximum number of Googlers that could have had a best result of
 * at least p?
 *
 * For example, suppose there were 6 Googlers, and they had the following total
 * points: 29, 20, 8, 18, 18, 21. You remember that there were 2 surprising
 * triplets of scores, and you want to know how many Googlers could have gotten
 * a best result of 8 or better.
 *
 * With those total points, and knowing that two of the triplets were
 * surprising, the triplets of scores could have been:
 *
 * 10 9 10 6 6 8 (*) 2 3 3 6 6 6 6 6 6 6 7 8 (*)
 *
 * The cases marked with a (*) are the surprising cases. This gives us 3
 * Googlers who got at least one score of 8 or better. There's no series of
 * triplets of scores that would give us a higher number than 3, so the answer
 * is 3.
 *
 * Input
 *
 * The first line of the input gives the number of test cases, T. T test cases
 * follow. Each test case consists of a single line containing integers
 * separated by single spaces. The first integer will be N, the number of
 * Googlers, and the second integer will be S, the number of surprising triplets
 * of scores. The third integer will be p, as described above. Next will be N
 * integers ti: the total points of the Googlers.
 *
 * Output
 *
 * For each test case, output one line containing "Case #x: y", where x is the
 * case number (starting from 1) and y is the maximum number of Googlers who
 * could have had a best result of greater than or equal to p.
 *
 * Limits
 *
 * 1 â¤ T â¤ 100. 0 â¤ S â¤ N. 0 â¤ p â¤ 10. 0 â¤ ti â¤ 30. At least S of the ti values
 * will be between 2 and 28, inclusive.
 *
 * Small dataset
 *
 * 1 â¤ N â¤ 3.
 *
 * Large dataset
 *
 * 1 â¤ N â¤ 100.
 *
 * Sample
 *
 * Input Output 4 Case #1: 3 3 1 5 15 13 11 Case #2: 2 3 0 8 23 22 21 Case #3: 1
 * 2 1 1 8 0 Case #4: 3 6 2 8 29 20 8 18 18 21
 *
 * @author Leandro Baena Torres
 */
public class B {

    public static void main(String[] args) throws FileNotFoundException, IOException {
        BufferedReader br = new BufferedReader(new FileReader("B.in"));
        String linea;
        int numCasos, N, S, p, t[], y, minSurprise, minNoSurprise;

        linea = br.readLine();
        numCasos = Integer.parseInt(linea);
        for (int i = 0; i < numCasos; i++) {
            linea = br.readLine();
            String[] aux = linea.split(" ");
            N = Integer.parseInt(aux[0]);
            S = Integer.parseInt(aux[1]);
            p = Integer.parseInt(aux[2]);
            t = new int[N];
            y = 0;
            minSurprise = p + ((p - 2) >= 0 ? (p - 2) : 0) + ((p - 2) >= 0 ? (p - 2) : 0);
            minNoSurprise = p + ((p - 1) >= 0 ? (p - 1) : 0) + ((p - 1) >= 0 ? (p - 1) : 0);
            for (int j = 0; j < N; j++) {
                t[j] = Integer.parseInt(aux[3 + j]);
                if (t[j] >= minNoSurprise) {
                    y++;
                } else {
                    if (t[j] >= minSurprise) {
                        if (S > 0) {
                            y++;
                            S--;
                        }
                    }
                }
            }

            System.out.println("Case #" + (i + 1) + ": " + y);
        }
    }
}

package b;

import java.io.BufferedReader;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.OutputStream;
import java.io.PrintWriter;
import java.text.AttributedCharacterIterator;
import java.util.Arrays;
import java.util.StringTokenizer;

public class Main {
	public static void main(String[] args) {
		InputStream inputStream;
		try {
			inputStream = new FileInputStream("input.txt");
		} catch (IOException e) {
			throw new RuntimeException(e);
		}
		OutputStream outputStream;
		try {
			outputStream = new FileOutputStream("output.txt");
		} catch (IOException e) {
			throw new RuntimeException(e);
		}
		InputReader in = new InputReader(inputStream);
		PrintWriter out = new PrintWriter(outputStream);
		Dancing solver = new Dancing();
		int testCases = in.nextInt();
		for (int i = 1; i <= testCases; i++)
			solver.solve(i, in, out);

		out.close();
	}
}

class InputReader {
	private BufferedReader reader;
	private StringTokenizer tokenizer;

	public InputReader(InputStream stream) {
		reader = new BufferedReader(new InputStreamReader(stream));
		tokenizer = null;
	}

	public String next() {
		while (tokenizer == null || !tokenizer.hasMoreTokens()) {
			try {
				tokenizer = new StringTokenizer(reader.readLine());
			} catch (IOException e) {
				throw new RuntimeException(e);
			}
		}
		return tokenizer.nextToken();
	}

	public boolean haveNextInCurrentLine() {
		return (tokenizer != null && tokenizer.hasMoreTokens());
	}

	public int nextInt() {
		return Integer.parseInt(next());
	}
}

class Dancing {

	static final int IMPOSSIBLE = 0, POSSIBLE = 1, ACHIEVED = 2;

	public void solve(int testCase, InputReader in, PrintWriter out) {
		int n = in.nextInt();
		int s = in.nextInt();
		int p = in.nextInt();
		int[] t = new int[n];
		for (int i = 0; i < n; i++) {
			t[i] = in.nextInt();
		}

		System.out.println("Case #" + testCase + ": " + n + " " + s + " " + p
				+ " " + Arrays.toString(t));

		int result = n;
		if (p > 0) {
			int possible = 0;
			int achieved = 0;

			for (int i = 0; i < n; i++) {
				System.out
						.println("n: " + (i + 1) + " = " + getResult(t[i], p));
				switch (getResult(t[i], p)) {
				case ACHIEVED:
					achieved++;
					break;
				case POSSIBLE:
					possible++;
					break;
				}
			}

			result = achieved + Math.min(possible, s);
		}

		out.println("Case #" + testCase + ": " + result);
		System.out.println("Case #" + testCase + ": " + result);
	}

	private int getResult(int sum, int p) {
		if (sum < p)
			return IMPOSSIBLE;

		int third = sum / 3;
		if (third >= p)
			return ACHIEVED;

		if (sum % 3 == 0) {
			if ((sum - 2) / 3 + 2 >= p)
				return POSSIBLE;
		} else {
			if (third + 1 >= p)
				return ACHIEVED;
			else if ((sum - 2) / 3 + 2 >= p)
				return POSSIBLE;
		}

		return IMPOSSIBLE;
	}
}