import java.util.Scanner;

class Main {
	public static void main(String[] args) {
		Scanner sc = new Scanner(System.in);
		int t=sc.nextInt();
		int casos=1, a, b, n, m, cont;
		while(t!=0){
			a=sc.nextInt();
			b=sc.nextInt();
			if(a>b){
				int aux=a;
				a=b;
				b=aux;
			}
			System.out.printf("Case #%d: ",casos++);
			if(a==b){
				System.out.printf("%d\n",0);
			}else{
				cont=0;
				for(n=a;n<b;n++){					
					for(m=n+1;m<=b;m++){					
						if(isRecycled(n,m)) cont++;
					}
				}
				System.out.printf("%d\n",cont);
			}
			t--;
		}		
	}
	public static boolean isRecycled(int n1, int n2){
		String s1, s2, aux;
		s1 =  String.valueOf( n1 );
		s2 =  String.valueOf( n2 );		
		boolean r = false;		
		for(int i=0;i<s1.length();i++){
			aux="";
			aux=s1.substring(i,s1.length())+s1.substring(0,i);
//			System.out.println(aux);
			if(aux.equals(s2)){
				r=true;
				break;
			}
		}		
		return r;
	}
}

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.HashSet;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

/**
 * Google code jam.
 * Qualification Round 2012.
 * Problem C. Recycled Numbers
 * 
 * Usage: &lt;app&gt; &lt;input &gt;output
 * 
 * @author sombrabr@gmail.com
 *
 */
public class QualC {

	public static void main(String[] args) throws NumberFormatException, IOException {
		BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
		
		int cases = new Integer(in.readLine());
		
		for(int i=0; i<cases; ++i) {
			String line = in.readLine();
			System.out.print("Case #" + (i+1) + ": ");
			run(line);
		}
	}

	private static void run(String line) {
		String[] parts = line.split(" ");
		
		int digits = parts[0].length();
		
		int A = Integer.parseInt(parts[0]);
		int B = Integer.parseInt(parts[1]);
		
		int count = 0;
		
		for(int n=A; n<=B; ++n) { // n is the number to recycle
			String strN = Integer.toString(n);
			
			if(strN.length()!=digits)
				continue;
			
			HashSet<Integer> numbers = new HashSet<Integer>();
			
			for(int i=1; i<digits; ++i) {
				Pattern p = Pattern.compile("(\\d*)(\\d{" + i + "})");
				Matcher m = p.matcher(strN);
				
				if(!m.matches()) {
					System.err.println("BUG: " + strN + " for " + i + " digits");
					return;
				}
				
				String strNewN = m.group(2) + m.group(1);
				if(strNewN.length() != digits) {
					System.err.println("BUG: " + strN + " for " + i + " digits with " + strNewN);
					return;
				}
				
				int newN = Integer.parseInt(strNewN);
				
				if(n < newN && newN <= B && ! numbers.contains(newN)) {
					count++;
					numbers.add(newN);
				}
			}
		}
		
		System.out.println(count);
	}
}
