/*
 * Problem C. Recycled Numbers
 * 
 * Do you ever become frustrated with television because you keep seeing the
 * same things, recycled over and over again? Well I personally don't care about
 * television, but I do sometimes feel that way about numbers.
 * 
 * Let's say a pair of distinct positive integers (n, m) is recycled if you can
 * obtain m by moving some digits from the back of n to the front without
 * changing their order. For example, (12345, 34512) is a recycled pair since
 * you can obtain 34512 by moving 345 from the end of 12345 to the front. Note
 * that n and m must have the same number of digits in order to be a recycled
 * pair. Neither n nor m can have leading zeros.
 * 
 * Given integers A and B with the same number of digits and no leading zeros,
 * how many distinct recycled pairs (n, m) are there with A â¤ n < m â¤ B?
 * 
 * Input
 * 
 * The first line of the input gives the number of test cases, T. T test cases
 * follow. Each test case consists of a single line containing the integers A
 * and B.
 * 
 * Output
 * 
 * For each test case, output one line containing "Case #x: y", where x is the
 * case number (starting from 1), and y is the number of recycled pairs (n, m)
 * with A â¤ n < m â¤ B.
 * 
 * Limits
 * 
 * 1 â¤ T â¤ 50.
 * 
 * A and B have the same number of digits.

Small dataset

1 â¤ A â¤ B â¤ 1000.

Large dataset

1 â¤ A â¤ B â¤ 2000000.

Sample


Input 
 	
Output 
 
4
1 9
10 40
100 500
1111 2222
Case #1: 0
Case #2: 3
Case #3: 156
Case #4: 287
 */

package google.codejam.y2012.qualifications;

import google.codejam.commons.Utils;

import java.io.IOException;
import java.util.StringTokenizer;

/**
 * @author Marco Lackovic <marco.lackovic@gmail.com>
 * @version 1.0, Apr 14, 2012
 */
public class RecycledNumbers {

	private static final String INPUT_FILE_NAME = "C-large.in";
	private static final String OUTPUT_FILE_NAME = "C-large.out";

	public static void main(String[] args) throws IOException {
		String[] input = Utils.readFromFile(INPUT_FILE_NAME);
		String[] output = new String[input.length];
		int x = 0;
		for (String line : input) {
			StringTokenizer st = new StringTokenizer(line);
			int a = Integer.valueOf(st.nextToken());
			int b = Integer.valueOf(st.nextToken());
			System.out.println("Computing case #" + (x + 1));
			output[x++] = "Case #" + x + ": " + recycledNumbers(a, b);
		}
		Utils.writeToFile(output, OUTPUT_FILE_NAME);
	}

	private static int recycledNumbers(int a, int b) {
		int count = 0;
		for (int n = a; n < b; n++) {
			count += getNumGreaterRotations(n, b);
		}
		return count;
	}

	private static int getNumGreaterRotations(int n, int b) {
		int count = 0;
		char[] chars = Integer.toString(n).toCharArray();
		for (int i = 0; i < chars.length; i++) {
			chars = rotateRight(chars);
			if (chars[0] != '0') {
				int m = Integer.valueOf(new String(chars));
				if (n == m) {
					break;
				} else if (n < m && m <= b) {
					count++;
				}
			}
		}
		return count;
	}

	private static char[] rotateRight(char[] chars) {
		char last = chars[chars.length - 1];
		for (int i = chars.length - 2; i >= 0; i--) {
			chars[i + 1] = chars[i];
		}
		chars[0] = last;
		return chars;
	}

}

import java.io.*;
import java.util.StringTokenizer;

public class Ricky
{
    public static void main(String []args)
    {
        try{
            FileInputStream fstream = new FileInputStream("input.in");
              DataInputStream in = new DataInputStream(fstream);
              BufferedReader br = new BufferedReader(new InputStreamReader(in));
              String strLine;
              int n=0;
              FileWriter fstream1 = new FileWriter("out.in");
              BufferedWriter out = new BufferedWriter(fstream1);
              int i;
            while ((strLine = br.readLine()) != null)   
            {
                n=n+1;
                if (n==1) i = Integer.parseInt(strLine);
                else {
                    System.out.println (parse(strLine,n-1));
                    out.write(parse(strLine,n-1)+"\n");
                }
             
            
            }
            out.close();
  in.close();
    }catch (Exception e){//Catch exception if any
  System.err.println("Error: " + e.getMessage());
  }
    }

    private static String parse(String string1,int oo) 
    {
        String str="";
        int count =0;
        long aa = 0;
        long bb = 0; 
        
  	  StringTokenizer stringTokenizer = new  StringTokenizer(string1);
  	  	while(stringTokenizer.hasMoreTokens())
		  {
		  aa = Integer.parseInt(stringTokenizer.nextToken());
		  bb = Integer.parseInt(stringTokenizer.nextToken());
		  }
        
  	  for (long i = aa ;  i < bb;  i = i+1) 
  	  {    
  		  if(i<10)
  		  {
  			  count = 0;
  		  }
  		  else if(i>=10 && i<100)
  		  {
  			int m = (int) (i/10);
  			int n = (int) (i%10);	
  			int nm = 10*n + m;
  			if(i<nm && nm<= bb)
  			{ count++;}
  			
  		  }
  		else if(i>=100 && i<1000)
		  {
  			int mn = (int) (i/10);
  			int z = (int) (i%10);	
  			int zmn = 100*z + mn;
  			if(i<zmn && zmn<= bb)
  			{ count++;}  	
  			
  			
  			int m = (int) (i/100);
  			int nz = (int) (i%100);	
  			int nzm = 10*nz + m;
  			if(i<nzm && nzm<= bb)
  			{ count++;}  			
  			
  			
  			
		  }
  		else if(i>=1000 && i<10000)
		  {
  			int mnz = (int) (i/10);
  			int t = (int) (i%10);	
  			int tmnz = 1000*t + mnz;
  			if(i<tmnz && tmnz<= bb )
  			{ count++;}  	
		int mn = (int) (i/100);
  			int zt = (int) (i%100);	
  			int ztmn = 100*zt + mn;
  			if(i<ztmn && ztmn<= bb)
  			{ count++;}  			
  			int m = (int) (i/1000);
  			int nzt = (int) (i%1000);	
  			int nztm = 10*nzt + m;
  			if(i<nztm && nztm<= bb && (mn!=zt))
  			{ count++;}  			
  		  }
  		else if(i>=10000 && i<100000)
		  {
  			int mnzt = (int) (i/10);
  			int w = (int) (i%10);	
  			int wmnzt = 10000*w + mnzt;
  			if(i<wmnzt && wmnzt<= bb )
  			{ count++;}  	
		int mnz = (int) (i/100);
  			int tw = (int) (i%100);	
  			int twmnz = 1000*tw + mnz;
  			if(i<twmnz && twmnz<= bb)
  			{ count++;}  			
 	
  			
  			
  			int mn = (int) (i/1000);
  			int ztw = (int) (i%1000);	
  			int ztwmn = 100*ztw + mn;
  			if(i<ztwmn && ztwmn<= bb )
  			{ count++;}  			
 
  			
  			int m = (int) (i/10000);
  			int nztw = (int) (i%10000);	
  			int nztwm = 10*nztw + m;
  			if(i<nztwm && nztwm<= bb )
  			{ count++;}  			
 			
  			
  			
		  }
  		else if(i>=100000 && i<1000000)
		  {
  			int mnzt = (int) (i/10);
  			int w = (int) (i%10);	
  			int wmnzt = 100000*w + mnzt;
  			if(i<wmnzt && wmnzt<= bb )
  			{ count++;}  	
 
  			
  			int mnz = (int) (i/100);
  			int tw = (int) (i%100);	
  			int twmnz = 10000*tw + mnz;
  			if(i<twmnz && twmnz<= bb)
  			{ count++;}  			
  	  	
  			
  			
  			int mn = (int) (i/1000);
  			int ztw = (int) (i%1000);	
  			int ztwmn = 1000*ztw + mn;
  			if(i<ztwmn && ztwmn<= bb )
  			{ count++;}  			
  	
  			
  			int m = (int) (i/10000);
  			int nztw = (int) (i%10000);	
  			int nztwm = 100*nztw + m;
  			if(i<nztwm && nztwm<= bb &&(mn!=ztw))
  			{ count++;}  			
  		
  			
  			int ml = (int) (i/100000);
  			int nztwx = (int) (i%100000);	
  			int nztwxm = 10*nztwx + ml;
  			if(i<nztwxm && nztwxm<= bb &&(mn!=ztw) )
  			{ count++;}  			
  					
  			
  			
		  }
  		else if(i>=1000000 && i<10000000)
		  {
 			int mnzt = (int) (i/10);
  			int w = (int) (i%10);	
  			int wmnzt = 1000000*w + mnzt;
  			if(i<wmnzt && wmnzt<= bb )
  			{ count++;}  	
 
  			
  			int mnz = (int) (i/100);
  			int tw = (int) (i%100);	
  			int twmnz = 100000*tw + mnz;
  			if(i<twmnz && twmnz<= bb)
  			{ count++;}  			
	
  			
  			
  			int mn = (int) (i/1000);
  			int ztw = (int) (i%1000);	
  			int ztwmn = 10000*ztw + mn;
  			if(i<ztwmn && ztwmn<= bb )
  			{ count++;}  			

  			
  			int m = (int) (i/10000);
  			int nztw = (int) (i%10000);	
  			int nztwm = 1000*nztw + m;
  			if(i<nztwm && nztwm <= bb )
  			{ count++;}  			
  			
  			
  			int ml = (int) (i/100000);
  			int nztwx = (int) (i%100000);	
  			int nztwxm = 100*nztwx + ml;
  			if(i<nztwxm && nztwxm <= bb )
  			{ count++;}  			
  			
  			
  			
  			int a = (int) (i/1000000);
  			int bcdefg = (int) (i%1000000);	
  			int bcdefga = 10*bcdefg + a;
  			if(i<bcdefga && bcdefga<= bb  )
  			{ count++;}  			
  			
  			
		  }
  		else if(i>=10000000 && i<100000000)
		  {}
  		  else
  		  {}
  	  }
        return "Case #"+oo+": "+count;
     }
    
 
    
}