package CodeJam.c2012.clasificacion;

import java.io.BufferedReader;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;

/**
 * Problem
 *
 * You're watching a show where Googlers (employees of Google) dance, and then
 * each dancer is given a triplet of scores by three judges. Each triplet of
 * scores consists of three integer scores from 0 to 10 inclusive. The judges
 * have very similar standards, so it's surprising if a triplet of scores
 * contains two scores that are 2 apart. No triplet of scores contains scores
 * that are more than 2 apart.
 *
 * For example: (8, 8, 8) and (7, 8, 7) are not surprising. (6, 7, 8) and (6, 8,
 * 8) are surprising. (7, 6, 9) will never happen.
 *
 * The total points for a Googler is the sum of the three scores in that
 * Googler's triplet of scores. The best result for a Googler is the maximum of
 * the three scores in that Googler's triplet of scores. Given the total points
 * for each Googler, as well as the number of surprising triplets of scores,
 * what is the maximum number of Googlers that could have had a best result of
 * at least p?
 *
 * For example, suppose there were 6 Googlers, and they had the following total
 * points: 29, 20, 8, 18, 18, 21. You remember that there were 2 surprising
 * triplets of scores, and you want to know how many Googlers could have gotten
 * a best result of 8 or better.
 *
 * With those total points, and knowing that two of the triplets were
 * surprising, the triplets of scores could have been:
 *
 * 10 9 10 6 6 8 (*) 2 3 3 6 6 6 6 6 6 6 7 8 (*)
 *
 * The cases marked with a (*) are the surprising cases. This gives us 3
 * Googlers who got at least one score of 8 or better. There's no series of
 * triplets of scores that would give us a higher number than 3, so the answer
 * is 3.
 *
 * Input
 *
 * The first line of the input gives the number of test cases, T. T test cases
 * follow. Each test case consists of a single line containing integers
 * separated by single spaces. The first integer will be N, the number of
 * Googlers, and the second integer will be S, the number of surprising triplets
 * of scores. The third integer will be p, as described above. Next will be N
 * integers ti: the total points of the Googlers.
 *
 * Output
 *
 * For each test case, output one line containing "Case #x: y", where x is the
 * case number (starting from 1) and y is the maximum number of Googlers who
 * could have had a best result of greater than or equal to p.
 *
 * Limits
 *
 * 1 â¤ T â¤ 100. 0 â¤ S â¤ N. 0 â¤ p â¤ 10. 0 â¤ ti â¤ 30. At least S of the ti values
 * will be between 2 and 28, inclusive.
 *
 * Small dataset
 *
 * 1 â¤ N â¤ 3.
 *
 * Large dataset
 *
 * 1 â¤ N â¤ 100.
 *
 * Sample
 *
 * Input Output 4 Case #1: 3 3 1 5 15 13 11 Case #2: 2 3 0 8 23 22 21 Case #3: 1
 * 2 1 1 8 0 Case #4: 3 6 2 8 29 20 8 18 18 21
 *
 * @author Leandro Baena Torres
 */
public class B {

    public static void main(String[] args) throws FileNotFoundException, IOException {
        BufferedReader br = new BufferedReader(new FileReader("B.in"));
        String linea;
        int numCasos, N, S, p, t[], y, minSurprise, minNoSurprise;

        linea = br.readLine();
        numCasos = Integer.parseInt(linea);
        for (int i = 0; i < numCasos; i++) {
            linea = br.readLine();
            String[] aux = linea.split(" ");
            N = Integer.parseInt(aux[0]);
            S = Integer.parseInt(aux[1]);
            p = Integer.parseInt(aux[2]);
            t = new int[N];
            y = 0;
            minSurprise = p + ((p - 2) >= 0 ? (p - 2) : 0) + ((p - 2) >= 0 ? (p - 2) : 0);
            minNoSurprise = p + ((p - 1) >= 0 ? (p - 1) : 0) + ((p - 1) >= 0 ? (p - 1) : 0);
            for (int j = 0; j < N; j++) {
                t[j] = Integer.parseInt(aux[3 + j]);
                if (t[j] >= minNoSurprise) {
                    y++;
                } else {
                    if (t[j] >= minSurprise) {
                        if (S > 0) {
                            y++;
                            S--;
                        }
                    }
                }
            }

            System.out.println("Case #" + (i + 1) + ": " + y);
        }
    }
}

package com.example;

import java.io.IOException;
import java.util.List;

public class ProblemB {
    
    enum Result {
	INSUFFICIENT,
	SUFFICIENT,
	SUFFICIENT_WHEN_SURPRISING
    }

    public static void main(String[] a) throws IOException {

	List<String> lines = FileUtil.getLines("/B-small-attempt0.in");
	
	int cases = Integer.valueOf(lines.get(0));
	
	for(int c=0; c<cases; c++) {
	    String[] tokens = lines.get(c+1).split(" ");
	    
	    int n = Integer.valueOf(tokens[0]); // N = number of Googlers
	    int s = Integer.valueOf(tokens[1]); // S = number of surprising triplets
	    int p = Integer.valueOf(tokens[2]); // P = __at least__ a score of P
	    
	    int sumSufficient = 0;
	    int sumSufficientSurprising = 0;
	    
	    for(int i=0; i<n; i++) {
		int points = Integer.valueOf(tokens[3+i]);
		
		switch(test(points, p)) {
		case SUFFICIENT:
		    sumSufficient++;
		    break;
		    
		case SUFFICIENT_WHEN_SURPRISING:
		    sumSufficientSurprising++;
		    break;
		}
		
//		uSystem.out.println("points "+ points +" ? "+ p +" => "+ result);
	    }
	    
	    System.out.println("Case #"+ (c+1) +": "+ (sumSufficient + Math.min(s, sumSufficientSurprising)));
	    
//	    System.out.println();
//	    System.out.println("N="+ n +", S="+ s +", P="+ p);
//	    System.out.println();
	}
    }

    private static Result test(int n, int p) {
	int fac = n / 3;
	int rem = n % 3;
	
	if(rem == 0) {
	    
//	    int triplet0[] = { fac, fac, fac };
//	    print(n, triplet0);
	    
	    if(fac >= p) {
		return Result.SUFFICIENT;
	    }
	    
	    if(fac > 0 && fac < 10) {
		
		if(fac+1 >= p) {
		    return Result.SUFFICIENT_WHEN_SURPRISING;
		}
		
//		int triplet1[] = { fac+1, fac, fac-1 }; // surprising 
//		print(n, triplet1);
	    }
	    
	    
	} else if(rem == 1) {
	    
//	    int triplet0[] = { fac+1, fac, fac };
//	    print(n, triplet0);
	    
	    if(fac+1 >= p) {
		return Result.SUFFICIENT;
	    }
	    
//	    if(fac > 0 && fac < 10) {
//		int triplet1[] = { fac+1, fac+1, fac-1 };
//		print(n, triplet1);
//	    }
	    
	} else if(rem == 2) {
	    
//	    int triplet0[] = { fac+1, fac+1, fac };
//	    print(n, triplet0);
	    
	    if(fac+1 >= p) {
		return Result.SUFFICIENT;
	    }
	    
	    if(fac < 9) {
//		int triplet1[] = { fac+2, fac, fac }; // surprising
//		print(n, triplet1);

		if(fac+2 >= p) {
		    return Result.SUFFICIENT_WHEN_SURPRISING;
		}
	    }
	    
	} else {
	    throw new RuntimeException("error");
	}
	
	return Result.INSUFFICIENT;
//	System.out.println();
//	System.out.println(n +" => "+ div3 +" ("+ rem +")");
    }
    
//    private static void print(int n, int[] triplet) {
//	System.out.println("n="+ n +" ("+ (n/3) +","+ (n%3) +") => ["+ triplet[0] +","+ triplet[1] +","+ triplet[2] +"]" + (triplet[0]-triplet[2] > 1 ? " *" : ""));
//    }
    
}
