/*
 * Problem C. Recycled Numbers
 * 
 * Do you ever become frustrated with television because you keep seeing the
 * same things, recycled over and over again? Well I personally don't care about
 * television, but I do sometimes feel that way about numbers.
 * 
 * Let's say a pair of distinct positive integers (n, m) is recycled if you can
 * obtain m by moving some digits from the back of n to the front without
 * changing their order. For example, (12345, 34512) is a recycled pair since
 * you can obtain 34512 by moving 345 from the end of 12345 to the front. Note
 * that n and m must have the same number of digits in order to be a recycled
 * pair. Neither n nor m can have leading zeros.
 * 
 * Given integers A and B with the same number of digits and no leading zeros,
 * how many distinct recycled pairs (n, m) are there with A â¤ n < m â¤ B?
 * 
 * Input
 * 
 * The first line of the input gives the number of test cases, T. T test cases
 * follow. Each test case consists of a single line containing the integers A
 * and B.
 * 
 * Output
 * 
 * For each test case, output one line containing "Case #x: y", where x is the
 * case number (starting from 1), and y is the number of recycled pairs (n, m)
 * with A â¤ n < m â¤ B.
 * 
 * Limits
 * 
 * 1 â¤ T â¤ 50.
 * 
 * A and B have the same number of digits.

Small dataset

1 â¤ A â¤ B â¤ 1000.

Large dataset

1 â¤ A â¤ B â¤ 2000000.

Sample


Input 
 	
Output 
 
4
1 9
10 40
100 500
1111 2222
Case #1: 0
Case #2: 3
Case #3: 156
Case #4: 287
 */

package google.codejam.y2012.qualifications;

import google.codejam.commons.Utils;

import java.io.IOException;
import java.util.StringTokenizer;

/**
 * @author Marco Lackovic <marco.lackovic@gmail.com>
 * @version 1.0, Apr 14, 2012
 */
public class RecycledNumbers {

	private static final String INPUT_FILE_NAME = "C-large.in";
	private static final String OUTPUT_FILE_NAME = "C-large.out";

	public static void main(String[] args) throws IOException {
		String[] input = Utils.readFromFile(INPUT_FILE_NAME);
		String[] output = new String[input.length];
		int x = 0;
		for (String line : input) {
			StringTokenizer st = new StringTokenizer(line);
			int a = Integer.valueOf(st.nextToken());
			int b = Integer.valueOf(st.nextToken());
			System.out.println("Computing case #" + (x + 1));
			output[x++] = "Case #" + x + ": " + recycledNumbers(a, b);
		}
		Utils.writeToFile(output, OUTPUT_FILE_NAME);
	}

	private static int recycledNumbers(int a, int b) {
		int count = 0;
		for (int n = a; n < b; n++) {
			count += getNumGreaterRotations(n, b);
		}
		return count;
	}

	private static int getNumGreaterRotations(int n, int b) {
		int count = 0;
		char[] chars = Integer.toString(n).toCharArray();
		for (int i = 0; i < chars.length; i++) {
			chars = rotateRight(chars);
			if (chars[0] != '0') {
				int m = Integer.valueOf(new String(chars));
				if (n == m) {
					break;
				} else if (n < m && m <= b) {
					count++;
				}
			}
		}
		return count;
	}

	private static char[] rotateRight(char[] chars) {
		char last = chars[chars.length - 1];
		for (int i = chars.length - 2; i >= 0; i--) {
			chars[i + 1] = chars[i];
		}
		chars[0] = last;
		return chars;
	}

}

import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.FileOutputStream;
import java.io.PrintStream;
import java.util.HashSet;
import java.util.Scanner;

import javax.management.RuntimeErrorException;

public class C {

	public static void main(String[] args) throws FileNotFoundException {
		Scanner sc = new Scanner(new FileInputStream("C-large.in"));
		System.setOut(new PrintStream(new FileOutputStream("c.out")));
		C c = new C();
		long start = System.currentTimeMillis();
		int t = sc.nextInt();
		for (int i = 0; i < t; i++)
			System.out.println("Case #" + (i + 1) + ": "
					+ c.solve(sc.nextInt(), sc.nextInt()));
		long end = System.currentTimeMillis();
//		System.out.println((end - start) / 1000.0);
		// System.out.println("Case #" + (i + 1) + ": " +
		// c.bruteSolve(sc.nextInt(), sc.nextInt()));
	}

	private int compare(String a, String b, int shift) {
		int l = a.length();
		int ai = 0;
		int bi = shift;
		for (int i = 0; i < l; i++) {
			int c = a.charAt(ai) - b.charAt(bi);
			if (c != 0)
				return c;
			ai++;
			bi++;
			if (bi == l)
				bi = 0;
		}
		return 0;
	}

	private String shift(String a, int shift) {
		return a.substring(shift) + a.substring(0, shift);
	}

	private long solve(int a, int b) {
		long count = 0;
		String aStr = a + "";
		String bStr = b + "";
		if (aStr.length() != bStr.length())
			throw new RuntimeException("Need the same length");
		HashSet<String> ready = new HashSet<String>();
		int l = aStr.length();
		for (int i = a; i <= b; i++) {
			ready.clear();
			for (int j = 1; j < l; j++) {
				String iStr = i + "";
				String iShifted = shift(iStr, j);
//				debug("Par: " + iStr + " and " + iShifted);
				if (iShifted.equals(iStr))
					continue; // Get the same
//				debug("1");
				if (iShifted.charAt(0) == '0')
					continue; // has leading zero
//				debug("2");
				if (iShifted.compareTo(aStr) <= 0)
					continue;// smaller than lower bound
//				debug("4");
				if (iShifted.compareTo(iStr) <= 0)
					continue; // smaller than first
//				debug("3");
				if (iShifted.compareTo(bStr) > 0)
					continue;// smaller than great bound
//				debug("5");
				if (ready.contains(iShifted))
					continue;
//				debug("6");
				ready.add(iShifted);
				count++;
			}
		}
		return count;
	}

	private long bruteSolve(int a, int b) {
		long count = 0;
		String aStr = a + "";
		String bStr = b + "";
		if (aStr.length() != bStr.length())
			throw new RuntimeException("Need the same length");

		HashSet<String> ready = new HashSet<String>();
		int l = aStr.length();
		for (int i = a; i <= b; i++)
			for (int j = i + 1; j <= b; j++) {
				ready.clear();
				for (int k = 1; k < l; k++) {
					if (shift(i + "", k).equals(j + "")
							&& !ready.contains(j + "")) {
						ready.add(j + "");
						System.out.println("Pair: " + i + " and " + j);
						count++;
					}
				}
			}
		return count;
	}

}
