package it.simone.google.code.jam2012;

import java.util.HashSet;
import java.util.Set;

public class RecycledNumber implements GoogleCodeExercise {

	int a = 0;
	int b = 0;
	Set<Couple> distinctCouple = null;
	long maxTime = 0;

	private class Couple {
		int x = 0;
		int y = 0;

		public Couple(int x, int y) {
			this.x = x;
			this.y = y;
		}

		@Override
		public int hashCode() {
			final int prime = 31;
			int result = 1;
			result = prime * result + getOuterType().hashCode();
			result = prime * result + x;
			result = prime * result + y;
			return result;
		}

		@Override
		public boolean equals(Object obj) {
			if (this == obj)
				return true;
			if (obj == null)
				return false;
			if (getClass() != obj.getClass())
				return false;
			Couple other = (Couple) obj;
			if (!getOuterType().equals(other.getOuterType()))
				return false;
			if (x == other.x && y == other.y)
				return true;
			if (x == other.y && y == other.x)
				return true;
			return false;
		}

		private RecycledNumber getOuterType() {
			return RecycledNumber.this;
		}

	}

	@Override
	public String execute(String line) {
		int result = 0;

		String[] data = line.split(" ");
		a = Integer.parseInt(data[0]);
		b = Integer.parseInt(data[1]);
		initialize();

		int n = a;
		//
		while (n <= b) {
			result += analize(n);
			n++;
//			if (n % 1000 == 0)
//				System.out.println(n);
		}

		System.out.println(result);
		return "" + result;
	}

	@Override
	public void initialize() {
		distinctCouple = new HashSet<Couple>();
	}

	private int analize(int number) {
		String numString = "" + number;
		initialize();
		for (int i = 1; i < numString.length(); i++) {
			int m = shift(numString, i);
			if (a <= number && number < m && m <= b) {
				Couple couple=new Couple(number,m);
				if (!distinctCouple.contains(couple))
					distinctCouple.add(couple);
			}
		}
		return distinctCouple.size();
	}

	private int shift(String numString, int posx) {

		String result = null;
		result = "" + numString.substring(posx) + numString.substring(0, posx);

		return Integer.parseInt(result.toString());
	}

}

/**
 * 
 */
package codejam2012.qualification;

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.File;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
import java.util.HashSet;
import java.util.Set;

/**
 * @author Jaffar Ramay
 *
 *
Problem

Do you ever become frustrated with television because you keep seeing the same things, recycled over and over again? Well I personally don't care about television, but I do sometimes feel that way about numbers.

Let's say a pair of distinct positive integers (n, m) is recycled if you can obtain m by moving some digits from the back of n to the front without changing their order. For example, (12345, 34512) is a recycled pair since you can obtain 34512 by moving 345 from the end of 12345 to the front. Note that n and m must have the same number of digits in order to be a recycled pair. Neither n nor m can have leading zeros.

Given integers A and B with the same number of digits and no leading zeros, how many distinct recycled pairs (n, m) are there with A â¤ n < m â¤ B?

Input

The first line of the input gives the number of test cases, T. T test cases follow. Each test case consists of a single line containing the integers A and B.

Output

For each test case, output one line containing "Case #x: y", where x is the case number (starting from 1), and y is the number of recycled pairs (n, m) with A â¤ n < m â¤ B.

Limits

1 â¤ T â¤ 50.
A and B have the same number of digits.

Small dataset

1 â¤ A â¤ B â¤ 1000.

Large dataset

1 â¤ A â¤ B â¤ 2000000.

Sample


Input 
 	 
4
1 9
10 40
100 500
1111 2222

Output 

Case #1: 0
Case #2: 3
Case #3: 156
Case #4: 287

Are we sure about the output to Case #4?

Yes, we're sure about the output to Case #4.
 */
public class RecycledNumbers {

	public static void solve() throws IOException {
		BufferedReader reader = new BufferedReader(new FileReader(new File("/Users/jaffar_ramay/Workspaces/eclipseWorkspace/Revision/src/codejam2012/qualification/RecycledNumbers.in")));
		BufferedWriter writer = new BufferedWriter(new FileWriter(new File("/Users/jaffar_ramay/Workspaces/eclipseWorkspace/Revision/src/codejam2012/qualification/RecycledNumbers.out")));
		String line = null;
		while((line=reader.readLine())!=null){
			int testCases = Integer.parseInt(line);
			for (int i = 1; i <= testCases; i++) {
				String[] testCase = reader.readLine().split(" ");
			     int numberA = Integer.parseInt(testCase[0]);
			     int numberB = Integer.parseInt(testCase[1]);
			     int result = getRecycledCount(numberA, numberB);
			     writer.write("Case #"+i+": "+result);
			     if(i<testCases)
			    	 writer.newLine();
			}
		}
		reader.close();
		writer.close();
	}
	public static int getRecycledCount(int numberA, int numberB) {
		int result=0;
		Set<String> set = new HashSet<String>();
		for (int i = numberA; i <= numberB; i++) {
			
			String number = i+"";
			
			for (int j = 0; j < number.length(); j++) {
				
				int firstNumber = Integer.parseInt(number);
				int index = (number.length()-(j+1));
				if(index>0 && index<number.length()){
					int secondNumber =  (Integer.parseInt(number.substring(index,number.length())+number.substring(0,index)));
					
					if(numberA<=firstNumber && firstNumber<secondNumber && secondNumber<=numberB && (firstNumber+"").length() == (secondNumber+"").length()){
						set.add(firstNumber+""+secondNumber);
					}	
				}
				
			}
			
		}
		return set.size();
	}
	
	public static void main(String[] args) throws IOException {
		solve();
	}
}
