import java.io.*;
import java.util.*;

public class C {

    void solve() throws IOException {
        in("C-large.in"); out("C-large.out");

        long tm = System.currentTimeMillis();
        boolean[] mask = new boolean[2000000];
        int[] r = new int[10];
        int t = readInt();
        for (int cs = 1; cs <= t; ++cs) {
            int a = readInt();
            int b = readInt();
            int ans = 0;
            for (int m = a + 1; m <= b; ++m) {
                char[] d = String.valueOf(m).toCharArray();
                int c = 0;
                for (int i = 1; i < d.length; ++i) {
                    if (d[i] != '0' && d[i] <= d[0]) {
                        int n = 0;
                        for (int j = 0; j < d.length; ++j) {
                            int jj = i + j;
                            if (jj >= d.length) jj -= d.length;
                            n = n * 10 + (d[jj] - '0');
                        }
                        if (n >= a && n < m && !mask[n]) {
                            ++ans;
                            mask[n] = true;
                            r[c++] = n;
                        }
                    }
                }
                for (int i = 0; i < c; ++i) {
                    mask[r[i]] = false;
                }
            }
            println("Case #" + cs + ": " + ans);
            //System.out.println(cs);
        }
        System.out.println("time: " + (System.currentTimeMillis() - tm));
        exit();
    }

    void in(String name) throws IOException {
        if (name.equals("__std")) {
            in = new BufferedReader(new InputStreamReader(System.in));
        } else {
            in = new BufferedReader(new FileReader(name));
        }
    }

    void out(String name) throws IOException {
        if (name.equals("__std")) {
            out = new PrintWriter(System.out);
        } else {
            out = new PrintWriter(name);
        }
    }

    void exit() {
        out.close();
        System.exit(0);
    }

    int readInt() throws IOException {
        return Integer.parseInt(readToken());
    }

    long readLong() throws IOException {
        return Long.parseLong(readToken());
    }

    double readDouble() throws IOException {
        return Double.parseDouble(readToken());
    }

    String readLine() throws IOException {
        st = null;
        return in.readLine();
    }

    String readToken() throws IOException {
        while (st == null || !st.hasMoreTokens()) {
            st = new StringTokenizer(in.readLine());
        }
        return st.nextToken();
    }

    boolean eof() throws IOException {
        return !in.ready();
    }

    void print(String format, Object ... args) {
        out.println(new Formatter(Locale.US).format(format, args));
    }

    void println(String format, Object ... args) {
        out.println(new Formatter(Locale.US).format(format, args));
    }

    void print(Object value) {
        out.print(value);
    }

    void println(Object value) {
        out.println(value);
    }

    void println() {
        out.println();
    }

    StringTokenizer st;

    BufferedReader in;
    PrintWriter out;

    public static void main(String[] args) throws IOException {
        new C().solve();
    }
}

package qualification;

import java.util.HashMap;
import java.util.Scanner;

public class RecycledNumbers {

	//recycled numbers between A and B
	//OK, the key is being able to reduce each number to a single comparable value instead of comparing every possible match.
	//Let's say: We will take the permutation that has the smallest value.
	//creating them may be slow as long as looking them up is fast.

	//[not needed] Cache values to improve performance
	// perf test - worst possible case was solved in seconds.
	//we've only given 50 cases at most.
	//[DONE] what if more than two match? does that make 3 distinct recycled pairs?
	public static void main(final String[] args) {
		new RecycledNumbers().start();
	}

	private  void start() {
		final Scanner s = new Scanner(System.in);
		final int numTests = s.nextInt();
		for (int i = 0; i < numTests; i++) {
			//			deb("Case " + (i + 1) + "---------");
			final int startNum = s.nextInt();
			final int endNum = s.nextInt();
			final HashMap<String, Integer> values = new HashMap<String, Integer>();
			int distinctPairsCount = 0;
			for (int val = startNum; val <= endNum; val++) {
				final String newValue = findSmallestPermutation(""+val);
				if (values.containsKey(newValue)) {
					final int count = values.get(newValue);
					distinctPairsCount += count;
					values.put(newValue, count + 1);
					//					deb("found a match of " + count + ", total matches: " + distinctPairsCount);
				} else {
					values.put(newValue, 1);
				}
			}
			System.out.println("Case #" + (i+1) + ": " + distinctPairsCount);
		}
	}

	//We can't compare every permutation to every permutation
	//so we find the smallest and only use that.
	//this function looks slow, but it isn't called that often so should be OK.
	private String findSmallestPermutation(final String value) {
		int bestValue = Integer.MAX_VALUE;
		String bestString = null;
		final String valueTwice = value + value; //We will extract the substrings from this.
		for (int i = 0; i < value.length(); i++) {
			final String permutation = valueTwice.substring(i, value.length() + i);
			final int permutationValue = Integer.parseInt(permutation);
			if (permutationValue < bestValue) {
				bestValue = permutationValue;
				bestString = permutation;
			}
		}
		//		deb("source: " + value +", adding " + bestString);
		return bestString;
	}

	//	private void deb(final Object o) {
	//		System.out.println(o.toString());
	//	}

}
