import java.io.FileInputStream;
import java.util.HashMap;
import java.util.Scanner;
import java.util.TreeSet;

// Recycled Numbers
// https://code.google.com/codejam/contest/1460488/dashboard#s=p2

public class C {

	private static String process(Scanner in) {
		int A = in.nextInt();
		int B = in.nextInt();
		int res = 0;
		int len = Integer.toString(A).length();
		for(int n = A; n < B; n++) {
			String str = Integer.toString(n);
			TreeSet<Integer> set = new TreeSet<Integer>();
			for(int i = 1; i < len; i++) {
				int m = Integer.parseInt(str.substring(i, len) + str.substring(0, i));
				if ( m > n && m <= B && ! set.contains(m) ) {
					set.add(m);
					res++;
				}
			}
		}
		return Integer.toString(res);
	}

	public static void main(String[] args) throws Exception {
		Scanner in = new Scanner(System.in.available() > 0 ? System.in : 
			new FileInputStream(Thread.currentThread().getStackTrace()[1].getClassName() + ".practice.in"));
		int T = in.nextInt();
		for(int i = 1; i <= T; i++) 
			System.out.format("Case #%d: %s\n", i, process(in));
	}
}

public class RecycledNumbers
{
   public static void main(String[] args)
   {
      java.util.Scanner console = new java.util.Scanner(System.in);

      int T = 0;
      int A = 0, B = 0;

      int numRecycledNumbers = 0;


      T = console.nextInt();
      console.nextLine();

      for (int i = 0; i < T; i++)
      {
         A = console.nextInt();
         B = console.nextInt();
         console.nextLine();

         // do stuff
         numRecycledNumbers = findRecycledNumbers(A, B);

         System.out.println("Case #" + (i + 1) + ": " + numRecycledNumbers);
      }      


      return;
   }


   private static int findRecycledNumbers(int A, int B)
   {
      int n = B;
      int magnitude= 0;
      int pairs = 0;
      boolean alreadySubtractedOne = false;

      String str_m = String.valueOf(A);
      String str_n = String.valueOf(B);

      String firstHalf = "";
      String secondHalf = "";

      // m = x.y * 10^magnitude
      // magnitude 1 less then number of digits
      magnitude = str_n.length() - 1; 


      // halfPower is used to retrieve the first half of m.
      int halfPower = 1;
      for (int i = 0; i < (magnitude + 1) / 2; i++)
         halfPower *= 10;


      for (int m = A; m <= B; m++)
      {
         str_m = String.valueOf(m);

         
         for (int j = magnitude ; j > 0; j--)
         {
            // Substring goes from start to end - 1, hence need to add 1
            // as 'magnitude' already has 1 subtracted from it.
            str_n = str_m.substring(j, magnitude + 1) + str_m.substring(0, j);


            n = Integer.parseInt(str_n);

            if ((n > m) && (n <= B))
            {
               // If m is of even length and first half matches second half
               // two duplicate entries can be generated, so subtract 1 from count
               // ie. xyz|xyZ => Zxyz|xy or z|xyZxy
               if (!alreadySubtractedOne &&
                  (((m % halfPower) * halfPower) == (m - (m % halfPower))))
               {
                  alreadySubtractedOne = true;
                  pairs--;
               }
               
               pairs++;
            }
         }
         
      }

      return pairs;
   }

}
