package fixjava;

public class StringUtils {

	/** Repeat the given string the requested number of times. */
	public static String repeat(String str, int numTimes) {
		StringBuilder buf = new StringBuilder(Math.max(0, str.length() * numTimes));
		for (int i = 0; i < numTimes; i++)
			buf.append(str);
		return buf.toString();
	}

	/**
	 * Pad the left hand side of a field with the given character. Always adds at least one pad character. If the length of str is
	 * greater than numPlaces-1, then the output string will be longer than numPlaces.
	 */
	public static String padLeft(String str, char padChar, int numPlaces) {
		int bufSize = Math.max(numPlaces, str.length() + 1);
		StringBuilder buf = new StringBuilder(Math.max(numPlaces, str.length() + 1));
		buf.append(padChar);
		for (int i = 1, mi = bufSize - str.length(); i < mi; i++)
			buf.append(padChar);
		buf.append(str);
		return buf.toString();
	}

	/**
	 * Pad the right hand side of a field with the given character. Always adds at least one pad character. If the length of str is
	 * greater than numPlaces-1, then the output string will be longer than numPlaces.
	 */
	public static String padRight(String str, char padChar, int numPlaces) {
		int bufSize = Math.max(numPlaces, str.length() + 1);
		StringBuilder buf = new StringBuilder(Math.max(numPlaces, str.length() + 1));
		buf.append(str);
		buf.append(padChar);
		while (buf.length() < bufSize)
			buf.append(padChar);
		return buf.toString();
	}

	/** Intern all strings in an array, skipping null elements. */
	public static String[] intern(String[] arr) {
		for (int i = 0; i < arr.length; i++)
			arr[i] = arr[i].intern();
		return arr;
	}

	/** Intern a string, ignoring null */
	public static String intern(String str) {
		return str == null ? null : str.intern();
	}

}

/**
 * 
 */
package codejam2012.qualification;

import java.io.BufferedReader;
import java.io.BufferedWriter;
import java.io.File;
import java.io.FileReader;
import java.io.FileWriter;
import java.io.IOException;
import java.util.HashSet;
import java.util.Set;

/**
 * @author Jaffar Ramay
 *
 *
Problem

Do you ever become frustrated with television because you keep seeing the same things, recycled over and over again? Well I personally don't care about television, but I do sometimes feel that way about numbers.

Let's say a pair of distinct positive integers (n, m) is recycled if you can obtain m by moving some digits from the back of n to the front without changing their order. For example, (12345, 34512) is a recycled pair since you can obtain 34512 by moving 345 from the end of 12345 to the front. Note that n and m must have the same number of digits in order to be a recycled pair. Neither n nor m can have leading zeros.

Given integers A and B with the same number of digits and no leading zeros, how many distinct recycled pairs (n, m) are there with A â¤ n < m â¤ B?

Input

The first line of the input gives the number of test cases, T. T test cases follow. Each test case consists of a single line containing the integers A and B.

Output

For each test case, output one line containing "Case #x: y", where x is the case number (starting from 1), and y is the number of recycled pairs (n, m) with A â¤ n < m â¤ B.

Limits

1 â¤ T â¤ 50.
A and B have the same number of digits.

Small dataset

1 â¤ A â¤ B â¤ 1000.

Large dataset

1 â¤ A â¤ B â¤ 2000000.

Sample


Input 
 	 
4
1 9
10 40
100 500
1111 2222

Output 

Case #1: 0
Case #2: 3
Case #3: 156
Case #4: 287

Are we sure about the output to Case #4?

Yes, we're sure about the output to Case #4.
 */
public class RecycledNumbers {

	public static void solve() throws IOException {
		BufferedReader reader = new BufferedReader(new FileReader(new File("/Users/jaffar_ramay/Workspaces/eclipseWorkspace/Revision/src/codejam2012/qualification/RecycledNumbers.in")));
		BufferedWriter writer = new BufferedWriter(new FileWriter(new File("/Users/jaffar_ramay/Workspaces/eclipseWorkspace/Revision/src/codejam2012/qualification/RecycledNumbers.out")));
		String line = null;
		while((line=reader.readLine())!=null){
			int testCases = Integer.parseInt(line);
			for (int i = 1; i <= testCases; i++) {
				String[] testCase = reader.readLine().split(" ");
			     int numberA = Integer.parseInt(testCase[0]);
			     int numberB = Integer.parseInt(testCase[1]);
			     int result = getRecycledCount(numberA, numberB);
			     writer.write("Case #"+i+": "+result);
			     if(i<testCases)
			    	 writer.newLine();
			}
		}
		reader.close();
		writer.close();
	}
	public static int getRecycledCount(int numberA, int numberB) {
		int result=0;
		Set<String> set = new HashSet<String>();
		for (int i = numberA; i <= numberB; i++) {
			
			String number = i+"";
			
			for (int j = 0; j < number.length(); j++) {
				
				int firstNumber = Integer.parseInt(number);
				int index = (number.length()-(j+1));
				if(index>0 && index<number.length()){
					int secondNumber =  (Integer.parseInt(number.substring(index,number.length())+number.substring(0,index)));
					
					if(numberA<=firstNumber && firstNumber<secondNumber && secondNumber<=numberB && (firstNumber+"").length() == (secondNumber+"").length()){
						set.add(firstNumber+""+secondNumber);
					}	
				}
				
			}
			
		}
		return set.size();
	}
	
	public static void main(String[] args) throws IOException {
		solve();
	}
}
