import java.util.*;
import java.io.*;

public class recycled_numbers {
	public static void main(String[]a) throws Exception{
		
		Scanner f = new Scanner(new File(a[0]));
		int result=0;
		int A,B;
		String n,m;
		HashSet<String> s=new HashSet<String>();
		
		int T=f.nextInt();	//T total case count
		for (int t=1; t<=T;t++){//for each case t
			
			s.clear();
			result=0;				//reset
			A=f.nextInt();B=f.nextInt();	//get values for next case
			
			if (A==B)result=0;//remove case not meeting problem limits 
			else{
				for(int i=A;i<=B;i++){//for each int in range
					n=Integer.toString(i);
					m=new String(n);
					//System.out.println(n);
					for (int j=1;j<n.length();j++){//move each digit to the front & test
						m = m.substring(m.length()-1)+m.substring(0,m.length()-1);
						if(m.matches("^0+[\\d]+")!=true &&
								Integer.parseInt(m)<=B &&
								Integer.parseInt(n)<Integer.parseInt(m)){
							s.add(new String(n+","+m));
							//result++;
							//System.out.println(" matched: "+m);
						}
						
					}
				}
				result = s.size();
			}

			//display output
			System.out.println("Case #" + t + ": " + result);
		}
	}
}
import java.util.*;

public class QualC12 {

	public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
		int T = in.nextInt();	
		for (int i = 1; i <= T; i++) {
			int A = in.nextInt();
			int B = in.nextInt();
			int npairs = 0;
			for (int j = A; j <= B; j++) {
				String s = String.valueOf(j);
				String ns = s + s;
				boolean containsRepeat = false;
				for (int k = 1; k < s.length(); k++) {
					String rot = ns.substring(k, k + s.length());
					int rnum = Integer.valueOf(rot);
					if (rnum > j && rnum <= B && String.valueOf(rnum).length() == s.length()) {
						if (containsRepeat(s)) containsRepeat = true;
						++npairs;
					}
				}
				if (containsRepeat) --npairs;
			}
			System.out.println("Case #" + i + ": " + npairs);
		}
	}

	private static boolean containsRepeat(String s) {
		if (s.length() % 2 != 0) return false;
		if (s.substring(0, s.length()/2).equals(s.substring(s.length()/2, s.length()))) {
			return true;
		}
		else return false;
	}

}