import java.util.*;
import java.io.*;

public class recycled_numbers {
	public static void main(String[]a) throws Exception{
		
		Scanner f = new Scanner(new File(a[0]));
		int result=0;
		int A,B;
		String n,m;
		HashSet<String> s=new HashSet<String>();
		
		int T=f.nextInt();	//T total case count
		for (int t=1; t<=T;t++){//for each case t
			
			s.clear();
			result=0;				//reset
			A=f.nextInt();B=f.nextInt();	//get values for next case
			
			if (A==B)result=0;//remove case not meeting problem limits 
			else{
				for(int i=A;i<=B;i++){//for each int in range
					n=Integer.toString(i);
					m=new String(n);
					//System.out.println(n);
					for (int j=1;j<n.length();j++){//move each digit to the front & test
						m = m.substring(m.length()-1)+m.substring(0,m.length()-1);
						if(m.matches("^0+[\\d]+")!=true &&
								Integer.parseInt(m)<=B &&
								Integer.parseInt(n)<Integer.parseInt(m)){
							s.add(new String(n+","+m));
							//result++;
							//System.out.println(" matched: "+m);
						}
						
					}
				}
				result = s.size();
			}

			//display output
			System.out.println("Case #" + t + ": " + result);
		}
	}
}
package qC;

import java.io.File;
import java.io.FileNotFoundException;
import java.util.Scanner;

import qB.B.Pair;

//Letfs say a pair of distinct positive integers (n, m) is recycled 
//if you can obtain m by moving some digits from the back of n to the 
//front without changing their order. For example, (12345, 34512) is a 
//recycled pair since you can obtain 34512 by moving 345 from the end 
//of 12345 to the front. Note that n and m must have the same number 
//of digits (excluding leading zeros) in order to be a recycled pair.

//Given integers A and B with the same number of digits, how many distinct
//recycled pairs (n, m) are there with A ? n < m ? B?

public class C2 {

	static int solve(int number, int b) {
		int numDigi = number;
		int orgNumber = number;
		int c = 1;
		int p = 1;
		int counter = 0;

		do {
			numDigi = numDigi / 10;
			p = p * 10;
			c++;
		} while (numDigi != 0);
		int k = c - 1;
		p = p / 10;

		for ( int i = 1; i <= k; i++) {
			number = number % p * 10 + number / p;
			if (number > orgNumber && number <= b) {
				// System.out.println( "no: " + number + ", " + check);
				counter++;
			}
		}
		return counter;
	}

	public static void main(String[] args) throws FileNotFoundException {
		if (args.length == 0) {
			throw new IllegalArgumentException("no file given");
		}
		String filename = args[0];
		Scanner scanner = new Scanner(new File(filename));
		int numOfLines = scanner.nextInt();
		scanner.nextLine();

		for (int lineIdx = 0; lineIdx < numOfLines; lineIdx++) {
			final int start = scanner.nextInt();
			final int end = scanner.nextInt();
			int ans = 0;
			for (int l = start; l <= end; l++) {
				ans += solve(l, end);
			}
			System.out.printf("Case #%d: %d\n", lineIdx + 1, ans);
		}
	}
}
