Jawaban: $\sqrt{\pi}$. Solusi: Urang bisa ngitung $I = \int_{-\infty}^\infty e^{-x^2} dx$ dina cara kieu: 1. Kahiji, kuadrat integral: $$I^2 = \left(\int_{-\infty}^\infty e{-x^2} dx \right)^2 = \int_{-\infty}^\infty \int_{-\infty}^\infty e^{-x^2} dx$2. Dipeunteun ka koordinat kutub. Inget yén $dx = rd$i2 = \theta dr: $i$2 = \0_in \0_{0^2} e^rr2} Since we get rd$i\in \\in\
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