Article in English: Let's say you're working with the equation: x3 - 4x2 - 7x + 10 = 0. The constant "d" is going to be the number that doesn't have any variables, such as "x," next to it. Factors are the numbers you can multiply together to get another number. In your case, the factors of 10, or "d," are: 1, 2, 5, and 10. We want to determine which factor makes the polynomial equal zero when we substitute the factor for each "x" in the equation.  Start by using your first factor, 1. Substitute "1" for each "x" in the equation:  (1)3 - 4(1)2 - 7(1) + 10 = 0 This gives you: 1 - 4 - 7 + 10 = 0. Because 0 = 0 is a true statement, you know that x = 1 is a solution. If x = 1, you can rearrange the statement to look a bit different without changing what it means. "x = 1" is the same thing as "x - 1 = 0" or "(x - 1)". You've just subtracted a "1" from each side of the equation. "(x - 1)" is our root. See if you can factor it out of the rest of the equation. Take it one polynomial at a time.  Can you factor (x - 1) out of the x3? No you can't. But you can borrow a -x2 from the second variable; then factor it: x2(x - 1) = x3 - x2. Can you factor (x - 1) out of what remains from your second variable? No, again you can't. You need to borrow another little bit from the third variable. You need to borrow a 3x from -7x. This gives you -3x(x - 1) = -3x2 + 3x. Since you took a 3x from -7x, our third variable is now -10x and our constant is 10. Can you factor this? You can! -10(x - 1) = -10x + 10. What you did was rearrange the variables so that you could factor out a (x - 1) out of the entire equation. Your rearranged equation looks like this: x3 - x2 - 3x2 + 3x - 10x + 10 = 0, but it's still the same thing as x3 - 4x2 - 7x + 10 = 0. Look at the numbers that you factored out using the (x - 1) in Step 5:  x2(x - 1) - 3x(x - 1) - 10(x - 1) = 0. You can rearrange this to be a lot easier to factor one more time: (x - 1)(x2 - 3x - 10) = 0. You're only trying to factor (x2 - 3x - 10) here. This factors down into (x + 2)(x - 5). You can check whether...

Summary in Vietnamese:
Sắp xếp lại đa thức về dạng aX3+bX2+cX+d. Tìm tất cả các nhân tử của "d". Tìm một nhân tử có thể khiến đa thức bằng 0. Đảo vị trí. Tách nghiệm ra khỏi phần còn lại của phương trình. Tiếp tục thế nghiệm của hạng tử tự do. Đáp án của phương trình chính là nghiệm đã được tách ra.