Xác định rằng tọa độ của đường thẳng là phương trình bậc hai. Thiết lập công thức cho phương trình bậc hai. Thay mọi giá trị vào công thức bậc hai. Tối giản phương trình. Tính số mũ. Giải công thức cộng. Giải công thức trừ. Tìm cặp giá trị cho giao điểm x của hàm số với trục hoành.

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A quadratic equation is an equation that takes the form ax2+bx+c=0{\displaystyle ax^{2}+bx+c=0}. A quadratic equation has two solutions, which means a line written in this form is a parabola and will have two x-intercepts. For example, the equation x2+3x−10=0{\displaystyle x^{2}+3x-10=0} is a quadratic equation, so this line will have two x-intercepts. The formula is x=−b±b2−4ac2a{\displaystyle x={\frac {-b\pm {\sqrt {b^{2}-4ac}}}{2a}}}, where a{\displaystyle a} equals the coefficient of the second-degree term (x2{\displaystyle x^{2}}), b{\displaystyle b} equals the coefficient of the first-degree term (x{\displaystyle x}), and c{\displaystyle c} equals the constant. Make sure you substitute the correct values for each variable from the equation of the line. For example, if the equation of your line is x2+3x−10=0{\displaystyle x^{2}+3x-10=0}, your quadratic formula will look like this: x=−3±32−4(1)(−10)2(1){\displaystyle x={\frac {-3\pm {\sqrt {3^{2}-4(1)(-10)}}}{2(1)}}}. To do this, first complete all of the multiplication. Make sure you pay close attention to all positive and negative signs. For example:x=−3±32−4(−10)2(1){\displaystyle x={\frac {-3\pm {\sqrt {3^{2}-4(-10)}}}{2(1)}}}x=−3±32+402{\displaystyle x={\frac {-3\pm {\sqrt {3^{2}+40}}}{2}}} Square the b{\displaystyle b} term. Then, add this number to the other number under the square root sign. For example:x=−3±32+402{\displaystyle x={\frac {-3\pm {\sqrt {3^{2}+40}}}{2}}}x=−3±9+402{\displaystyle x={\frac {-3\pm {\sqrt {9+40}}}{2}}}x=−3±492{\displaystyle x={\frac {-3\pm {\sqrt {49}}}{2}}} Since the quadratic formula has a ±{\displaystyle \pm }, you will solve once by adding, and once by subtracting. Solving by adding will give you your first x{\displaystyle x} value. For example:x=−3+492{\displaystyle x={\frac {-3+{\sqrt {49}}}{2}}}x=−3+72{\displaystyle x={\frac {-3+7}{2}}}x=42{\displaystyle x={\frac {4}{2}}}x=2{\displaystyle x=2} This will give you the second value for x{\displaystyle x}. First calculate the square root, then find the difference in...