Does one is forced to conclude that 2X=X\sqrt {2} if series a+b+c+d+…=X?
If [math]\sqrt{a} \gt \sqrt{b} \gt \sqrt{c} \gt \sqrt{d} ,[/math] where [math] a,b,c,d[/math]  are consecutive natural numbers, then which of the following is correct- [math] \scriptsize (1) \sqrt{a} -\sqrt{b} >\sqrt{c} -\sqrt{d}, \; (2) \sqrt{c} -\sqrt{d} >\sqrt{a} -\sqrt{b} , \; (3) \sqrt{a} -\sqrt{c} >\sqrt{c} -\sqrt{d} ,\; (4) \sqrt{c} -\sqrt{d} =\sqrt{a} -\sqrt{b}  \text{ [explain] }?[/math]