Show institution names along with the number of proteins for each institution.
SELECT T1.institution ,  count(*) FROM institution AS T1 JOIN protein AS T2 ON T1.institution_id  =  T2.institution_id GROUP BY T1.institution_id
institution names refers to T1.institution; number of proteins for each institution refers to COUNT(*); joining condition is T1.institution_id = T2.institution_id; grouping is done by institution_id to calculate the number of proteins per institution;