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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def filter_iqr(array, lower, upper):
 """ Return elements which falls within specified interquartile range. Arguments: array (list):
 Sequence of numbers. lower (float):
 Lower bound for IQR, in range 0 <= lower <= 1. upper (float):
 Upper bound for IQR, in range 0 <= upper <= 1. Returns: list: Copy of original list, with elements outside of IQR removed. """

    upper, lower = iqr(array, upper, lower)

    new = list(array)
    for x in new[:]:
        if x < lower or x > upper:
            new.remove(x)

    return new