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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def _get_augmented_label_matrix(self, L, higher_order=False):
 """Returns an augmented version of L where each column is an indicator for whether a certain source or clique of sources voted in a certain pattern. Args: """

        # Create a helper data structure which maps cliques (as tuples of member
        # sources) --> {start_index, end_index, maximal_cliques}, where
        # the last value is a set of indices in this data structure
        self.c_data = {}
        for i in range(self.m):
            self.c_data[i] = {
                "start_index": i * self.k,
                "end_index": (i + 1) * self.k,
                "max_cliques": set(
                    [
                        j
                        for j in self.c_tree.nodes()
                        if i in self.c_tree.node[j]["members"]
                    ]
                ),
            }

        L_ind = self._create_L_ind(L)

        # Get the higher-order clique statistics based on the clique tree
        # First, iterate over the maximal cliques (nodes of c_tree) and
        # separator sets (edges of c_tree)
        if higher_order:
            L_aug = np.copy(L_ind)
            for item in chain(self.c_tree.nodes(), self.c_tree.edges()):
                if isinstance(item, int):
                    C = self.c_tree.node[item]
                    C_type = "node"
                elif isinstance(item, tuple):
                    C = self.c_tree[item[0]][item[1]]
                    C_type = "edge"
                else:
                    raise ValueError(item)
                members = list(C["members"])
                nc = len(members)

                # If a unary maximal clique, just store its existing index
                if nc == 1:
                    C["start_index"] = members[0] * self.k
                    C["end_index"] = (members[0] + 1) * self.k

                # Else add one column for each possible value
                else:
                    L_C = np.ones((self.n, self.k ** nc))
                    for i, vals in enumerate(product(range(self.k), repeat=nc)):
                        for j, v in enumerate(vals):
                            L_C[:, i] *= L_ind[:, members[j] * self.k + v]

                    # Add to L_aug and store the indices
                    if L_aug is not None:
                        C["start_index"] = L_aug.shape[1]
                        C["end_index"] = L_aug.shape[1] + L_C.shape[1]
                        L_aug = np.hstack([L_aug, L_C])
                    else:
                        C["start_index"] = 0
                        C["end_index"] = L_C.shape[1]
                        L_aug = L_C

                    # Add to self.c_data as well
                    id = tuple(members) if len(members) > 1 else members[0]
                    self.c_data[id] = {
                        "start_index": C["start_index"],
                        "end_index": C["end_index"],
                        "max_cliques": set([item]) if C_type == "node" else set(item),
                    }
            return L_aug
        else:
            return L_ind