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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def get_n_resources_for_iteration(self, iteration, bracket_iteration):
 """Return the number of iterations to run for this barcket_i This is just util function around `get_n_resources` """

        bracket = self.get_bracket(iteration=iteration)
        n_resources = self.get_resources(bracket=bracket)
        return self.get_n_resources(n_resources=n_resources, bracket_iteration=bracket_iteration)