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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def _repeat_bytes(byt, rep):
 """ Get a long number for a byte being repeated for many times. This is part of the effort of optimizing performance of angr's memory operations. :param int byt: the byte to repeat :param int rep: times to repeat the byte :return: a long integer representing the repeating bytes ;rtype: int """


        if rep == 1:
            return byt

        remainder = rep % 2
        quotient = rep // 2

        r_ = memset._repeat_bytes(byt, quotient)
        if remainder == 1:
            r = r_ << ((quotient + 1) * 8)
            r |= (r_ << 8) + byt
        else:
            r = r_ << (quotient * 8)
            r |= r_
        return r