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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def load_exports(self, args=None):
 """Load all export modules in the 'exports' folder."""

        if args is None:
            return False
        header = "glances_"
        # Build the export module available list
        args_var = vars(locals()['args'])
        for item in os.listdir(exports_path):
            export_name = os.path.basename(item)[len(header):-3].lower()
            if (item.startswith(header) and
                    item.endswith(".py") and
                    item != (header + "export.py") and
                    item != (header + "history.py")):
                self._exports_all[export_name] = os.path.basename(item)[:-3]
                # Set the disable_<name> to False by default
                setattr(self.args,
                        'export_' + export_name,
                        getattr(self.args, 'export_' + export_name, False))

        # Aim is to check if the export module should be loaded
        for export_name in self._exports_all:
            if getattr(self.args, 'export_' + export_name, False):
                # Import the export module
                export_module = __import__(self._exports_all[export_name])
                # Add the export to the dictionary
                # The key is the module name
                # for example, the file glances_xxx.py
                # generate self._exports_list["xxx"] = ...
                self._exports[export_name] = export_module.Export(args=args,
                                                                  config=self.config)
                self._exports_all[export_name] = self._exports[export_name]

        # Log plugins list
        logger.debug("Active exports modules list: {}".format(self.getExportsList()))
        return True