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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def get_dep_names_of_package( package, keep_version_pins=False, recursive=False, verbose=False, include_build_requirements=False ):
 """ Gets the dependencies from the package in the given folder, then attempts to deduce the actual package name resulting from each dependency line, stripping away everything else. """


    # First, obtain the dependencies:
    dependencies = get_package_dependencies(
        package, recursive=recursive, verbose=verbose,
        include_build_requirements=include_build_requirements,
    )
    if verbose:
        print("get_dep_names_of_package_folder: " +
              "processing dependency list to names: " +
              str(dependencies))

    # Transform dependencies to their stripped down names:
    # (they can still have version pins/restrictions, conditionals, ...)
    dependency_names = set()
    for dep in dependencies:
        # If we are supposed to keep exact version pins, extract first:
        pin_to_append = ""
        if keep_version_pins and "(==" in dep and dep.endswith(")"):
            # This is a dependency of the format: 'pkg (==1.0)'
            pin_to_append = "==" + dep.rpartition("==")[2][:-1]
        elif keep_version_pins and "==" in dep and not dep.endswith(")"):
            # This is a dependency of the format: 'pkg==1.0'
            pin_to_append = "==" + dep.rpartition("==")[2]
        # Now get true (and e.g. case-corrected) dependency name:
        dep_name = get_package_name(dep) + pin_to_append
        dependency_names.add(dep_name)
    return dependency_names