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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def is_higher_permission(level1, level2):
 """ Return True if the level1 is higher than level2 """

    return (is_publish_permission(level1) and
            not is_publish_permission(level2) or
            (is_edit_permission(level1) and
             not is_publish_permission(level2) and
             not is_edit_permission(level2)) or
            (is_showon_permission(level1) and
             is_view_permission(level2)))