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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def get_any_node(self, addr):
 """ Get any VFG node corresponding to the basic block at @addr. Note that depending on the context sensitivity level, there might be multiple nodes corresponding to different contexts. This function will return the first one it encounters, which might not be what you want. """

        for n in self.graph.nodes():
            if n.addr == addr:
                return n