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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def get_display_label(choices, status):
 """Get a display label for resource status. This method is used in places where a resource's status or admin state labels need to assigned before they are sent to the view template. """


    for (value, label) in choices:
        if value == (status or '').lower():
            display_label = label
            break
    else:
        display_label = status

    return display_label