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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def ssh_accept(cfg, code, key_file, yes, **kwargs):
 """ Send your SSH public-key In response to a 'wormhole ssh invite' this will send public-key you specify (if there's only one in ~/.ssh/* that will be sent). """


    for name, value in kwargs.items():
        setattr(cfg, name, value)
    from . import cmd_ssh
    kind, keyid, pubkey = cmd_ssh.find_public_key(key_file)
    print("Sending public key type='{}' keyid='{}'".format(kind, keyid))
    if yes is not True:
        click.confirm(
            "Really send public key '{}' ?".format(keyid), abort=True)
    cfg.public_key = (kind, keyid, pubkey)
    cfg.code = code

    return go(cmd_ssh.accept, cfg)