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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def feed(self, data):
 """ Feed the input stream. :param data: Input string (unicode). """

        assert isinstance(data, six.text_type)

        if _DEBUG_RENDERER_INPUT:
            self.LOG.write(repr(data).encode('utf-8') + b'\n')
            self.LOG.flush()

        # Handle bracketed paste. (We bypass the parser that matches all other
        # key presses and keep reading input until we see the end mark.)
        # This is much faster then parsing character by character.
        if self._in_bracketed_paste:
            self._paste_buffer += data
            end_mark = '\x1b[201~'

            if end_mark in self._paste_buffer:
                end_index = self._paste_buffer.index(end_mark)

                # Feed content to key bindings.
                paste_content = self._paste_buffer[:end_index]
                self.feed_key_callback(KeyPress(Keys.BracketedPaste, paste_content))

                # Quit bracketed paste mode and handle remaining input.
                self._in_bracketed_paste = False
                remaining = self._paste_buffer[end_index + len(end_mark):]
                self._paste_buffer = ''

                self.feed(remaining)

        # Handle normal input character by character.
        else:
            for i, c in enumerate(data):
                if self._in_bracketed_paste:
                    # Quit loop and process from this position when the parser
                    # entered bracketed paste.
                    self.feed(data[i:])
                    break
                else:
                    # Replace \r by \n. (Some clients send \r instead of \n
                    # when enter is pressed. E.g. telnet and some other
                    # terminals.)

                    # XXX: We should remove this in a future version. It *is*
                    #      now possible to recognise the difference.
                    #      (We remove ICRNL/INLCR/IGNCR below.)
                    #      However, this breaks IPython and maybe other applications,
                    #      because they bind ControlJ (\n) for handling the Enter key.

                    #      When this is removed, replace Enter=ControlJ by
                    #      Enter=ControlM in keys.py.
                    if c == '\r':
                        c = '\n'
                    self._input_parser.send(c)