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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def intersects(self, other):
 		""" 		Returns True if there exists a segmentlist in self that 		intersects the corresponding segmentlist in other; returns 		False otherwise. 		See also: 		.intersects_all(), .all_intersects(), .all_intersects_all() 		"""

		return any(key in self and self[key].intersects(value) for key, value in other.iteritems())