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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def parse_wyckoff_csv(wyckoff_file):
 """Parse Wyckoff.csv There are 530 data sets. For one example: 9:C 1 2 1::::::: ::4:c:1:(x,y,z):
(-x,y,-z):
: ::2:b:2:(0,y,1/2):
:: ::2:a:2:(0,y,0):
:: """


    rowdata = []
    points = []
    hP_nums = [433, 436, 444, 450, 452, 458, 460]
    for i, line in enumerate(wyckoff_file):
        if line.strip() == 'end of data':
            break
        rowdata.append(line.strip().split(':'))

        # 2:P -1  ::::::: <-- store line number if first element is number
        if rowdata[-1][0].isdigit():
            points.append(i)
    points.append(i)

    wyckoff = []
    for i in range(len(points) - 1):  # 0 to 529
        symbol = rowdata[points[i]][1]  # e.g. "C 1 2 1"
        if i + 1 in hP_nums:
            symbol = symbol.replace('R', 'H', 1)
        wyckoff.append({'symbol': symbol.strip()})

    # When the number of positions is larger than 4,
    # the positions are written in the next line.
    # So those positions are connected.
    for i in range(len(points) - 1):
        count = 0
        wyckoff[i]['wyckoff'] = []
        for j in range(points[i] + 1, points[i + 1]):
            # Hook if the third element is a number (multiplicity), e.g.,
            #
            # 232:P 2/b 2/m 2/b:::::::  <- ignored
            # ::8:r:1:(x,y,z):(-x,y,-z):(x,-y+1/2,-z):(-x,-y+1/2,z)
            # :::::(-x,-y,-z):(x,-y,z):(-x,y+1/2,z):(x,y+1/2,-z)  <- ignored
            # ::4:q:..m:(x,0,z):(-x,0,-z):(x,1/2,-z):(-x,1/2,z)
            # ::4:p:..2:(0,y,1/2):(0,-y+1/2,1/2):(0,-y,1/2):(0,y+1/2,1/2)
            # ::4:o:..2:(1/2,y,0):(1/2,-y+1/2,0):(1/2,-y,0):(1/2,y+1/2,0)
            # ...
            if rowdata[j][2].isdigit():
                pos = []
                w = {'letter': rowdata[j][3].strip(),
                     'multiplicity': int(rowdata[j][2]),
                     'site_symmetry': rowdata[j][4].strip(),
                     'positions': pos}
                wyckoff[i]['wyckoff'].append(w)

                for k in range(4):
                    if rowdata[j][k + 5]:  # check if '(x,y,z)' or ''
                        count += 1
                        pos.append(rowdata[j][k + 5])
            else:
                for k in range(4):
                    if rowdata[j][k + 5]:
                        count += 1
                        pos.append(rowdata[j][k + 5])

        # assertion
        for w in wyckoff[i]['wyckoff']:
            n_pos = len(w['positions'])
            n_pos *= len(lattice_symbols[wyckoff[i]['symbol'][0]])
            assert n_pos == w['multiplicity']

    return wyckoff