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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def get_conflicting_tools(self, request_only=False):
 """Returns tools of the same name provided by more than one package. Args: request_only: If True, only return the key from resolved packages that were also present in the request. Returns: Dict of {tool-name: set([Variant])}. """

        from collections import defaultdict

        tool_sets = defaultdict(set)
        tools_dict = self.get_tools(request_only=request_only)
        for variant, tools in tools_dict.itervalues():
            for tool in tools:
                tool_sets[tool].add(variant)

        conflicts = dict((k, v) for k, v in tool_sets.iteritems() if len(v) > 1)
        return conflicts