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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def compare(dicts):
 """Compare by iteration"""


    common_members = {}
    common_keys = reduce(lambda x, y: x & y, map(dict.keys, dicts))
    for k in common_keys:
        common_members[k] = list(
            reduce(lambda x, y: x & y, [set(d[k]) for d in dicts]))

    return common_members