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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def available_updates(self, obj):
 """Print out all versions ahead of the current one."""

        from package_monitor import pypi
        package = pypi.Package(obj.package_name)
        versions = package.all_versions()
        return html_list([v for v in versions if v > obj.current_version])