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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def format_array_flat(array, max_width):
 """Return a formatted string for as many items in the flattened version of array that will fit within max_width characters. """

    # every item will take up at least two characters, but we always want to
    # print at least first and last items
    max_possibly_relevant = min(max(array.size, 1),
                                max(int(np.ceil(max_width / 2.)), 2))
    relevant_front_items = format_items(
        first_n_items(array, (max_possibly_relevant + 1) // 2))
    relevant_back_items = format_items(
        last_n_items(array, max_possibly_relevant // 2))
    # interleave relevant front and back items:
    #     [a, b, c] and [y, z] -> [a, z, b, y, c]
    relevant_items = sum(zip_longest(relevant_front_items,
                                     reversed(relevant_back_items)),
                         ())[:max_possibly_relevant]

    cum_len = np.cumsum([len(s) + 1 for s in relevant_items]) - 1
    if (array.size > 2) and ((max_possibly_relevant < array.size) or
                             (cum_len > max_width).any()):
        padding = ' ... '
        count = min(array.size,
                    max(np.argmax(cum_len + len(padding) - 1 > max_width), 2))
    else:
        count = array.size
        padding = '' if (count <= 1) else ' '

    num_front = (count + 1) // 2
    num_back = count - num_front
    # note that num_back is 0 <--> array.size is 0 or 1
    #                         <--> relevant_back_items is []
    pprint_str = (' '.join(relevant_front_items[:num_front]) +
                  padding +
                  ' '.join(relevant_back_items[-num_back:]))
    return pprint_str