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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def intcomma(value):
 """ Borrowed from django.contrib.humanize Converts an integer to a string containing commas every three digits. For example, 3000 becomes '3,000' and 45000 becomes '45,000'. """

    orig = str(value)
    new = re.sub("^(-?\d+)(\d{3})", '\g<1>,\g<2>', orig)
    if orig == new:
        return new
    else:
        return intcomma(new)