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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def _is_bounded_iterator_based(self):
 """ Iterator based check. With respect to a certain variable/value A, - there must be at least one exit condition being A//Iterator//HasNext == 0 - there must be at least one local that ticks the iterator next: A//Iterator//Next """


        # Condition 0
        check_0 = lambda cond: (isinstance(cond, Condition) and
                                cond.op == Condition.Equal and
                                cond.val1 == 0 and
                                isinstance(cond.val0, AnnotatedVariable) and
                                cond.val0.type == VariableTypes.HasNext
                                )

        check_0_results = [ (check_0(stmt[0]), stmt[0]) for stmt in self.loop_exit_stmts ]
        check_0_conds = [ cond for r, cond in check_0_results if r ]  # remove all False ones

        if not check_0_conds:
            return None

        the_iterator = check_0_conds[0].val0.variable

        # Condition 1
        check_1 = lambda local: (isinstance(local, AnnotatedVariable) and
                                 local.type == VariableTypes.Next and
                                 local.variable == the_iterator
                                 )

        if not any([ check_1(local) for local in self.locals.values() ]):
            return None

        return True