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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def connect(self, name=None, remoteId=None, ha=None, verKeyRaw=None, publicKeyRaw=None):
 """ Connect to the node specified by name. """

        if not name:
            raise ValueError('Remote name should be specified')

        publicKey = None
        if name in self.remotes:
            remote = self.remotes[name]
        else:
            publicKey = z85.encode(
                publicKeyRaw) if publicKeyRaw else self.getPublicKey(name)
            verKey = z85.encode(
                verKeyRaw) if verKeyRaw else self.getVerKey(name)
            if not ha or not publicKey or (self.isRestricted and not verKey):
                raise ValueError('{} doesnt have enough info to connect. '
                                 'Need ha, public key and verkey. {} {} {}'.
                                 format(name, ha, verKey, publicKey))
            remote = self.addRemote(name, ha, verKey, publicKey)

        public, secret = self.selfEncKeys
        remote.connect(self.ctx, public, secret)

        logger.info("{}{} looking for {} at {}:{}"
                    .format(CONNECTION_PREFIX, self,
                            name or remote.name, *remote.ha),
                    extra={"cli": "PLAIN", "tags": ["node-looking"]})

        # This should be scheduled as an async task

        self.sendPingPong(remote, is_ping=True)

        # re-send previously stashed pings/pongs from unknown remotes
        logger.trace("{} stashed pongs: {}".format(self.name, str(self._stashed_pongs)))
        if publicKey in self._stashed_pongs:
            logger.trace("{} sending stashed pongs to {}".format(self.name, str(z85_to_friendly(publicKey))))
            self._stashed_pongs.discard(publicKey)
            self.sendPingPong(name, is_ping=False)

        return remote.uid