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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def is_tag_matched(self, tag, **attribute_filter):
 r""" Return true if the attributes matches in attribute filter. An attribute filter is a dictionary containing: {attribute_name: value}. This function will return True if and only if all attributes have the same value. This function allows to set the dictionary via kwargs, thus you can filter like this: example:: a.is_tag_matched(tag, name="foobar", other="barfoo") This function uses a fallback for attribute searching. It will by default use the namespace variant but fall back to the non-namespace variant. Thus specifiying :code:`{"name": "foobar"}` will match on :code:`<bla name="foobar" \>` as well as on :code:`<bla android:name="foobar" \>`. :param lxml.etree.Element tag: specify the tag element :param attribute_filter: specify the attribute filter as dictionary """

        if len(attribute_filter) <= 0:
            return True
        for attr, value in attribute_filter.items():
            _value = self.get_value_from_tag(tag, attr)
            if _value != value:
                return False
        return True