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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def parse_version(version):
 """ Return a comparable tuple from a version string. We try to force tuple to semver with version like 1.2.0 Replace pkg_resources.parse_version which now display a warning when use for comparing version with tuple :returns: Version string as comparable tuple """


    release_type_found = False
    version_infos = re.split('(\.|[a-z]+)', version)
    version = []
    for info in version_infos:
        if info == '.' or len(info) == 0:
            continue
        try:
            info = int(info)
            # We pad with zero to compare only on string
            # This avoid issue when comparing version with different length
            version.append("%06d" % (info,))
        except ValueError:
            # Force to a version with three number
            if len(version) == 1:
                version.append("00000")
            if len(version) == 2:
                version.append("000000")
            # We want rc to be at lower level than dev version
            if info == 'rc':
                info = 'c'
            version.append(info)
            release_type_found = True
    if release_type_found is False:
        # Force to a version with three number
        if len(version) == 1:
            version.append("00000")
        if len(version) == 2:
            version.append("000000")
        version.append("final")
    return tuple(version)