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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def compare_name(given_name, family_name, question_name):
 """Compares a name in question to a specified name separated into given and family. The name in question ``question_name`` can be of varying format, including "Kyle E. Niemeyer", "Kyle Niemeyer", "K. E. Niemeyer", "KE Niemeyer", and "K Niemeyer". Other possibilities include names with hyphens such as "Chih-Jen Sung", "C. J. Sung", "C-J Sung". Examples: True True Args: given_name (`str`):
 Given (or first) name to be checked against. family_name (`str`):
 Family (or last) name to be checked against. question_name (`str`):
 The whole name in question. Returns: `bool`: The return value. True for successful comparison, False otherwise. """

    # lowercase everything
    given_name = given_name.lower()
    family_name = family_name.lower()
    question_name = question_name.lower()

    # rearrange names given as "last, first middle"
    if ',' in question_name:
        name_split = question_name.split(',')
        name_split.reverse()
        question_name = ' '.join(name_split).strip()

    # remove periods
    question_name = question_name.replace('.', '')
    given_name = given_name.replace('.', '')
    family_name = family_name.replace('.', '')

    # split names by , <space> - .
    given_name = list(filter(None, re.split(r"[, \-.]+", given_name)))
    num_family_names = len(list(filter(None, re.split("[, .]+", family_name))))

    # split name in question by , <space> - .
    name_split = list(filter(None, re.split(r"[, \-.]+", question_name)))
    first_name = [name_split[0]]
    if len(name_split) > 2:
        first_name += [n for n in name_split[1:-num_family_names]]

    if len(first_name) > 1 and len(given_name) == len(first_name):
        # both have same number of first and middle names/initials
        for i in range(1, len(first_name)):
            first_name[i] = first_name[i][0]
            given_name[i] = given_name[i][0]
    elif len(given_name) != len(first_name):
        min_names = min(len(given_name), len(first_name))
        first_name = first_name[:min_names]
        given_name = given_name[:min_names]

    # first initial
    if len(first_name[0]) == 1 or len(given_name[0]) == 1:
        given_name[0] = given_name[0][0]
        first_name[0] = first_name[0][0]

    # first and middle initials combined
    if len(first_name[0]) > 1 or len(given_name[0]) > 1:
        given_name[0] = given_name[0][0]
        first_name[0] = name_split[0][0]

    # Hyphenated last name may need to be reconnected
    if num_family_names == 1 and '-' in family_name:
        num_hyphen = family_name.count('-')
        family_name_compare = '-'.join(name_split[-(num_hyphen + 1):])
    else:
        family_name_compare = ' '.join(name_split[-num_family_names:])

    return given_name == first_name and family_name == family_name_compare