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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def update_values(self):
 """ This method is for updating in the finite horizon case. It shifts the current value function .. math:: V_t(x) = x' P_t x + d_t and the optimal policy :math:`F_t` one step *back* in time, replacing the pair :math:`P_t` and :math:`d_t` with :math:`P_{t-1}` and :math:`d_{t-1}`, and :math:`F_t` with :math:`F_{t-1}` """

        # === Simplify notation === #
        Q, R, A, B, N, C = self.Q, self.R, self.A, self.B, self.N, self.C
        P, d = self.P, self.d
        # == Some useful matrices == #
        S1 = Q + self.beta * dot(B.T, dot(P, B))
        S2 = self.beta * dot(B.T, dot(P, A)) + N
        S3 = self.beta * dot(A.T, dot(P, A))
        # == Compute F as (Q + B'PB)^{-1} (beta B'PA + N) == #
        self.F = solve(S1, S2)
        # === Shift P back in time one step == #
        new_P = R - dot(S2.T, self.F) + S3
        # == Recalling that trace(AB) = trace(BA) == #
        new_d = self.beta * (d + np.trace(dot(P, dot(C, C.T))))
        # == Set new state == #
        self.P, self.d = new_P, new_d