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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def _get_metadata_path_for_display(self, name):
 """ Return the path to the given metadata file, if available. """

        try:
            # We need to access _get_metadata_path() on the provider object
            # directly rather than through this class's __getattr__()
            # since _get_metadata_path() is marked private.
            path = self._provider._get_metadata_path(name)

        # Handle exceptions e.g. in case the distribution's metadata
        # provider doesn't support _get_metadata_path().
        except Exception:
            return '[could not detect]'

        return path