<SYSTEM_TASK:>
Solve the following problem using Python, implementing the functions described below, one line at a time
<END_TASK>
<USER_TASK:>
Description:
 def history(self, hash):
 """ Retrieve the ownership tree of all editions of a piece given the hash. Args: hash (str):
 Hash of the file to check. Can be created with the :class:`File` class Returns: dict: Ownsership tree of all editions of a piece. .. note:: For now we only support searching the blockchain by the piece hash. """

        txs = self._t.get(hash, max_transactions=10000)['transactions']
        tree = defaultdict(list)
        number_editions = 0

        for tx in txs:
            _tx = self._t.get(tx['txid'])
            txid = _tx['txid']
            verb_str = BlockchainSpider.check_script(_tx['vouts'])
            verb = Spoolverb.from_verb(verb_str)
            from_address, to_address, piece_address = BlockchainSpider._get_addresses(_tx)
            timestamp_utc = _tx['time']
            action = verb.action

            edition_number = 0
            if action != 'EDITIONS':
                edition_number = verb.edition_number
            else:
                number_editions = verb.num_editions

            tree[edition_number].append({'txid': txid,
                                         'verb': verb_str,
                                         'from_address': from_address,
                                         'to_address': to_address,
                                         'piece_address': piece_address,
                                         'timestamp_utc': timestamp_utc,
                                         'action': action,
                                         'number_editions': number_editions,
                                         'edition_number': edition_number})

        # lets update the records with the number of editions of the piece since we do not know
        # this information before the EDITIONS transaction
        for edition, chain in tree.items():
            [d.update({'number_editions': number_editions}) for d in chain]
        return dict(tree)