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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:

def si_parse(value):
    '''
    Parse a value expressed using SI prefix units to a floating point number.

    Parameters
    ----------
    value : str or unicode
        Value expressed using SI prefix units (as returned by :func:`si_format`
        function).


    .. versionchanged:: 1.0
        Use unicode string for SI unit to support micro (i.e., µ) character.

        .. seealso::

            `Issue #4`_.

    .. _`Issue #4`: https://github.com/cfobel/si-prefix/issues/4
    '''
    CRE_10E_NUMBER = re.compile(r'^\s*(?P<integer>[\+\-]?\d+)?'
                                r'(?P<fraction>.\d+)?\s*([eE]\s*'
                                r'(?P<expof10>[\+\-]?\d+))?$')
    CRE_SI_NUMBER = re.compile(r'^\s*(?P<number>(?P<integer>[\+\-]?\d+)?'
                               r'(?P<fraction>.\d+)?)\s*'
                               u'(?P<si_unit>[%s])?\s*$' % SI_PREFIX_UNITS)
    match = CRE_10E_NUMBER.match(value)
    if match:
        # Can be parse using `float`.
        assert(match.group('integer') is not None or
               match.group('fraction') is not None)
        return float(value)
    match = CRE_SI_NUMBER.match(value)
    assert(match.group('integer') is not None or
           match.group('fraction') is not None)
    d = match.groupdict()
    si_unit = d['si_unit'] if d['si_unit'] else ' '
    prefix_levels = (len(SI_PREFIX_UNITS) - 1) // 2
    scale = 10 ** (3 * (SI_PREFIX_UNITS.index(si_unit) - prefix_levels))
    return float(d['number']) * scale