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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def _ComputeHash( key, seed = 0x0 ):
 """Computes the hash of the value passed using MurmurHash3 algorithm with the seed value. """

        def fmix( h ):
            h ^= h >> 16
            h  = ( h * 0x85ebca6b ) & 0xFFFFFFFF
            h ^= h >> 13
            h  = ( h * 0xc2b2ae35 ) & 0xFFFFFFFF
            h ^= h >> 16
            return h

        length = len( key )
        nblocks = int( length / 4 )

        h1 = seed

        c1 = 0xcc9e2d51
        c2 = 0x1b873593

        # body
        for block_start in xrange( 0, nblocks * 4, 4 ):
            k1 = key[ block_start + 3 ] << 24 | \
                 key[ block_start + 2 ] << 16 | \
                 key[ block_start + 1 ] <<  8 | \
                 key[ block_start + 0 ]
             
            k1 = c1 * k1 & 0xFFFFFFFF
            k1 = ( k1 << 15 | k1 >> 17 ) & 0xFFFFFFFF # inlined ROTL32
            k1 = ( c2 * k1 ) & 0xFFFFFFFF
        
            h1 ^= k1
            h1  = ( h1 << 13 | h1 >> 19 ) & 0xFFFFFFFF # inlined _ROTL32 
            h1  = ( h1 * 5 + 0xe6546b64 ) & 0xFFFFFFFF

        # tail
        tail_index = nblocks * 4
        k1 = 0
        tail_size = length & 3

        if tail_size >= 3:
            k1 ^= key[ tail_index + 2 ] << 16
        if tail_size >= 2:
            k1 ^= key[ tail_index + 1 ] << 8
        if tail_size >= 1:
            k1 ^= key[ tail_index + 0 ]
    
        if tail_size != 0:
            k1  = ( k1 * c1 ) & 0xFFFFFFFF
            k1  = ( k1 << 15 | k1 >> 17 ) & 0xFFFFFFFF # _ROTL32
            k1  = ( k1 * c2 ) & 0xFFFFFFFF
            h1 ^= k1

        return fmix( h1 ^ length )