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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def min_count(self, n=1):
 """ Returns a vocabulary after eliminating the words that appear < `n`. Args: n (integer):
 specifies the minimum word frequency allowed. """

    word_count = {w:c for w,c in iteritems(self.word_count) if c >= n}
    return CountedVocabulary(word_count=word_count)