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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def convertDay(self, day, prefix="", weekday=False):
 """Convert a datetime object representing a day into a human-ready string that can be read, spoken aloud, etc. Args: day (datetime.date):
 A datetime object to be converted into text. prefix (str):
 An optional argument that prefixes the converted string. For example, if prefix="in", you'd receive "in two days", rather than "two days", while the method would still return "tomorrow" (rather than "in tomorrow"). weekday (bool):
 An optional argument that returns "Monday, Oct. 1" if True, rather than "Oct. 1". Returns: A string representation of the input day, ignoring any time-related information. """

        def sameDay(d1, d2):
            d = d1.day == d2.day
            m = d1.month == d2.month
            y = d1.year == d2.year
            return d and m and y

        tom = self.now + datetime.timedelta(days=1)

        if sameDay(day, self.now):
            return "today"
        elif sameDay(day, tom):
            return "tomorrow"

        if weekday:
            dayString = day.strftime("%A, %B %d")
        else:
            dayString = day.strftime("%B %d")

        # Ex) Remove '0' from 'August 03'
        if not int(dayString[-2]):
            dayString = dayString[:-2] + dayString[-1]

        return prefix + " " + dayString