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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def results( self ):
 """Return a list of all the results currently available. This excludes pending results. Results are returned as a single flat list, so any repetition structure is lost. :returns: a list of results"""

        rs = []
        for k in self._results.keys():
            # filter out pending job ids, which can be anything except dicts
            ars = [ res for res in self._results[k] if isinstance(res, dict) ]
            rs.extend(ars)
        return rs