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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def intersection(self, other):
 """AND together version ranges. Calculates the intersection of this range with one or more other ranges. Args: other: VersionRange object (or list of) to AND with. Returns: New VersionRange object representing the intersection, or None if no ranges intersect. """

        if not hasattr(other, "__iter__"):
            other = [other]

        bounds = self.bounds
        for range in other:
            bounds = self._intersection(bounds, range.bounds)
            if not bounds:
                return None

        range = VersionRange(None)
        range.bounds = bounds
        return range