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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def dump_service(self, sc):
 """Read all data blocks of a given service. :meth:`dump_service` reads all data blocks from the service with service code *sc* and returns a list of strings suitable for printing. The number of strings returned does not necessarily reflect the number of data blocks because a range of data blocks with equal content is reduced to fewer lines of output. """

        def lprint(fmt, data, index):
            ispchr = lambda x: x >= 32 and x <= 126  # noqa: E731

            def print_bytes(octets):
                return ' '.join(['%02x' % x for x in octets])

            def print_chars(octets):
                return ''.join([chr(x) if ispchr(x) else '.' for x in octets])

            return fmt.format(index, print_bytes(data), print_chars(data))

        data_line_fmt = "{0:04X}: {1} |{2}|"
        same_line_fmt = "{0:<4s}  {1} |{2}|"

        lines = list()
        last_data = None
        same_data = 0

        for i in itertools.count():  # pragma: no branch
            assert i < 0x10000
            try:
                this_data = self.read_without_encryption([sc], [BlockCode(i)])
            except Type3TagCommandError:
                i = i - 1
                break

            if this_data == last_data:
                same_data += 1
            else:
                if same_data > 1:
                    lines.append(lprint(same_line_fmt, last_data, "*"))
                lines.append(lprint(data_line_fmt, this_data, i))
                last_data = this_data
                same_data = 0

        if same_data > 1:
            lines.append(lprint(same_line_fmt, last_data, "*"))
        if same_data > 0:
            lines.append(lprint(data_line_fmt, this_data, i))

        return lines