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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def skip_branch(self, level):
 """ Abandon the branch at the provided level and skip to the next. When we call out to skip to the next branch of the search space, we push sublevel pieces to the maximum positions of the board. So that the next time the permutation iterator is called, it can produce the vector state of the next adjacent branch. See #3. """

        for i in range(level + 1, self.depth):
            self.indexes[i] = self.range_size - 1