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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def convert_numpy_str_to_uint32(data):
 """ Converts a numpy.unicode\_ to its numpy.uint32 representation. Convert a ``numpy.unicode_`` or an array of them (they are UTF-32 strings) into the equivalent array of ``numpy.uint32`` that is byte for byte identical. Strings are expanded along rows (across columns) so a 2x3x4 array of 10 element strings will get turned into a 2x30x4 array of uint32's. Parameters data : numpy.unicode\_ or numpy.ndarray of numpy.unicode\_ The string or array of them to convert. Returns ------- array : numpy.ndarray of numpy.uint32 The result of the conversion. See Also -------- convert_numpy_str_to_uint16 convert_to_numpy_str """

    if data.nbytes == 0:
        # An empty string should be an empty uint32.
        return np.uint32([])
    else:
        # We need to calculate the new shape from the current shape,
        # which will have to be expanded along the rows to fit all the
        # characters (the dtype.itemsize gets the number of bytes in
        # each string, which is just 4 times the number of
        # characters. Then it is a mstter of getting a view of the
        # string (in flattened form so that it is contiguous) as uint32
        # and then reshaping it.
        shape = list(np.atleast_1d(data).shape)
        shape[-1] *= data.dtype.itemsize//4
        return data.flatten().view(np.uint32).reshape(tuple(shape))