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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def _draw_label(self, obj, count):
 """Helper method to draw on the current label. Not intended for external use. """

        # Start a drawing for the whole label.
        label = Drawing(float(self._lw), float(self._lh))
        label.add(self._clip_label)

        # And one for the available area (i.e., after padding).
        available = Drawing(float(self._dw), float(self._dh))
        available.add(self._clip_drawing)

        # Call the drawing function.
        self.drawing_callable(available, float(self._dw), float(self._dh), obj)

        # Render the contents on the label.
        available.shift(float(self._lp), float(self._bp))
        label.add(available)

        # Draw the border if requested.
        if self.border:
            label.add(self._border)

        # Add however many copies we need to.
        for i in range(count):
            # Find the next available label.
            self._next_unused_label()

            # Have we been told to skip this page?
            if self.pages_to_draw and self.page_count not in self.pages_to_draw:
                continue

            # Add the label to the page. ReportLab stores the added drawing by
            # reference so we have to copy it N times.
            thislabel = copy(label)
            thislabel.shift(*self._calculate_edges())
            self._current_page.add(thislabel)