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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def easeInOutBack(n, s=1.70158):
 """A "back-in" tween function that overshoots both the start and destination. Args: n (float):
 The time progress, starting at 0.0 and ending at 1.0. Returns: (float) The line progress, starting at 0.0 and ending at 1.0. Suitable for passing to getPointOnLine(). """

    _checkRange(n)
    n = n * 2
    if n < 1:
        s *= 1.525
        return 0.5 * (n * n * ((s + 1) * n - s))
    else:
        n -= 2
        s *= 1.525
        return 0.5 * (n * n * ((s + 1) * n + s) + 2)