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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def _escapify(label):
 """Escape the characters in label which need it. @returns: the escaped string @rtype: string"""

    text = ''
    for c in label:
        if c in _escaped:
            text += '\\' + c
        elif ord(c) > 0x20 and ord(c) < 0x7F:
            text += c
        else:
            text += '\\%03d' % ord(c)
    return text