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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def same_id(self, manifest, skip_version_check=False):
 """ Return a bool indicating if another manifest has the same identitiy. This is done by comparing language, name, processorArchitecture, publicKeyToken, type and version. """

        if skip_version_check:
            version_check = True
        else:
            version_check = self.version == manifest.version
        return (self.language == manifest.language and
                self.name == manifest.name and
                self.processorArchitecture == manifest.processorArchitecture and
                self.publicKeyToken == manifest.publicKeyToken and
                self.type == manifest.type and
                version_check)