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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def _h_function(self,h):
 """ private method for the spherical variogram "h" function Parameters h : (float or numpy.ndarray) distance(s) Returns ------- h_function : float or numpy.ndarray the value of the "h" function implied by the SphVario """


        hh = h / self.a
        h = self.contribution * (1.0 - (hh * (1.5 - (0.5 * hh * hh))))
        h[hh > 1.0] = 0.0
        return h