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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def get_model_name(model):
 """ Get model name for the field. Django 1.5 uses module_name, does not support model_name Django 1.6 uses module_name and model_name DJango 1.7 uses model_name, module_name raises RemovedInDjango18Warning """

    opts = model._meta
    if django.VERSION[:2] < (1, 7):
        model_name = opts.module_name
    else:
        model_name = opts.model_name

    return model_name