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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def human_bytes(n):
 """ Return the number of bytes n in more human readable form. """

    if n < 1024:
        return '%d B' % n
    k = n/1024
    if k < 1024:
        return '%d KB' % round(k)
    m = k/1024
    if m < 1024:
        return '%.1f MB' % m
    g = m/1024
    return '%.2f GB' % g