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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:

def any(self, predicate=None):
        '''Determine if the source sequence contains any elements which satisfy
        the predicate.

        Only enough of the sequence to satisfy the predicate once is consumed.

        Note: This method uses immediate execution.

        Args:
            predicate: An optional single argument function used to test each
                element. If omitted, or None, this method returns True if there
                is at least one element in the source.

        Returns:
            True if the sequence contains at least one element which satisfies
            the predicate, otherwise False.

        Raises:
            ValueError: If the Queryable is closed()
        '''
        if self.closed():
            raise ValueError("Attempt to call any() on a closed Queryable.")

        if predicate is None:
            predicate = lambda x: True

        if not is_callable(predicate):
            raise TypeError("any() parameter predicate={predicate} is not callable".format(predicate=repr(predicate)))

        for item in self.select(predicate):
            if item:
                return True
        return False