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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def deleteByOrigIndex(self, index):
 """Removes a single entry from the list given the index reference. The index, in this instance, is a reference to the *original* list indexing as seen when the list was first inserted into PLOD. An example: [ {age: 19, income: 29000, name: 'Bill' , wigs: None }, {age: 18, income: 93000, name: 'Jim' , wigs: 68}, {age: 20, income: 15000, name: 'Joe' , wigs: [1, 2, 3]}, {age: 18, income: None , name: 'Larry', wigs: [3, 2, 9]} ] [ {age: 19, income: 29000, name: 'Bill' , wigs: None }, {age: 20, income: 15000, name: 'Joe' , wigs: [1, 2, 3]}, {age: 18, income: None , name: 'Larry', wigs: [3, 2, 9]} ] As you can see in the example, the list was sorted by 'name', which placed 'Bill' as the first entry. Yet, when the deleteByOrigIndex was passed a zero (for the first entry), it removed 'Jim' instead since it was the original first entry. :param index: An integer representing the place of entry in the original list of dictionaries. :return: self """

        result = []
        result_tracker = []
        for counter, row in enumerate(self.table):
            if self.index_track[counter] != index:
                result.append(row)
                result_tracker.append(self.index_track[counter])
        self.table = result
        self.index_track = result_tracker
        return self