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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def column_to_intermediary(col, type_formatter=format_type):
 """Transform an SQLAlchemy Column object to it's intermediary representation. """

    return Column(
        name=col.name,
        type=type_formatter(col.type),
        is_key=col.primary_key,
    )