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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def _dist_kw_arg(self, k):
 """ Returns a dictionary of keyword arguments for the k'th distribution. :param int k: Index of the distribution in question. :rtype: ``dict`` """

        if self._dist_kw_args is not None:
            return {
                key:self._dist_kw_args[key][k,:]
                for key in self._dist_kw_args.keys()
            }
        else:
            return {}