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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def pores(self, labels='all', mode='or', asmask=False):
 r""" Returns pore indicies where given labels exist, according to the logic specified by the ``mode`` argument. Parameters labels : string or list of strings The label(s) whose pores locations are requested. This argument also accepts '*' for wildcard searches. mode : string Specifies how the query should be performed. The options are: **'or', 'union', 'any'** : (default) Pores with *one or more* of the given labels are returned. **'and', 'intersection', 'all'** : Pores with *all* of the given labels are returned. **'xor', 'exclusive_or'** : Pores with *only one* of the given labels are returned. **'nor', 'none', 'not'** : Pores with *none* of the given labels are returned. **'nand'** : Pores with *not all* of the given labels are returned. **'xnor'** : Pores with *more than one* of the given labels are returned. asmask : boolean If ``True`` then a boolean array of length Np is returned with ``True`` values indicating the pores that satisfy the query. Returns ------- A Numpy array containing pore indices filtered by the logic specified in ``mode``. See Also -------- throats Notes ----- Technically, *nand* and *xnor* should also return pores with *none* of the labels but these are not included. This makes the returned list more useful. To perform more complex or compound queries, you can opt to receive the result a a boolean mask (``asmask=True``), then manipulate the arrays manually. Examples -------- array([0, 1, 2, 3, 4]) array([ 4, 9, 14, 19, 24]) """

        ind = self._get_indices(element='pore', labels=labels, mode=mode)
        if asmask:
            ind = self.tomask(pores=ind)
        return ind