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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def filter_paths(d, paths, list_of_dicts=False, deepcopy=True):
 """ filter dict by certain paths containing key sets Parameters d : dict paths : list[str] or list[tuple] list_of_dicts: bool treat list of dicts as additional branches deepcopy: bool deepcopy values Examples -------- {'a': {'c': {'d': 2}}} {} {'a': [{'c': 3}, {'c': 2}]} """

    list_of_dicts = '__list__' if list_of_dicts else None

    all_keys = [x for y in paths if isinstance(y, tuple) for x in y]
    all_keys += [x for x in paths if not isinstance(x, tuple)]
    # faster to filter first I think
    new_d = filter_keys(d, all_keys, list_of_dicts=list_of_dicts)
    new_d = flatten(d, list_of_dicts=list_of_dicts)
    for key in list(new_d.keys()):
        if not any([
                set(key).issuperset(path if isinstance(path, tuple) else[path])
                for path in paths]):
            new_d.pop(key)
    return unflatten(new_d, list_of_dicts=list_of_dicts, deepcopy=deepcopy)