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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:

def scc(graph):
    ''' Computes the strongly connected components of a graph '''
    order = []
    vis = {vertex: False for vertex in graph}

    graph_transposed = {vertex: [] for vertex in graph}

    for (v, neighbours) in graph.iteritems():
        for u in neighbours:
            add_edge(graph_transposed, u, v)

    for v in graph:
        if not vis[v]:
            dfs_transposed(v, graph_transposed, order, vis)

    vis = {vertex: False for vertex in graph}
    vertex_scc = {}

    current_comp = 0
    for v in reversed(order):
        if not vis[v]:
            # Each dfs will visit exactly one component
            dfs(v, current_comp, vertex_scc, graph, vis)
            current_comp += 1

    return vertex_scc