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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def _find_balanced(self, text, start, open_c, close_c):
 """Returns the index where the open_c and close_c characters balance out - the same number of open_c and close_c are encountered - or the end of string if it's reached before the balance point is found. """

        i = start
        l = len(text)
        count = 1
        while count > 0 and i < l:
            if text[i] == open_c:
                count += 1
            elif text[i] == close_c:
                count -= 1
            i += 1
        return i