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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def locate(self, point, _verify=True):
 r"""Find a point on the current surface. Solves for :math:`s` and :math:`t` in :math:`B(s, t) = p`. This method acts as a (partial) inverse to :meth:`evaluate_cartesian`. .. warning:: A unique solution is only guaranteed if the current surface is valid. This code assumes a valid surface, but doesn't check. .. image:: ../../images/surface_locate.png :align: center .. doctest:: surface-locate 0.5 0.25 .. testcleanup:: surface-locate import make_images make_images.surface_locate(surface, point) Args: point (numpy.ndarray):
 A (``D x 1``) point on the surface, where :math:`D` is the dimension of the surface. _verify (Optional[bool]):
 Indicates if extra caution should be used to verify assumptions about the inputs. Can be disabled to speed up execution time. Defaults to :data:`True`. Returns: Optional[Tuple[float, float]]: The :math:`s` and :math:`t` values corresponding to ``point`` or :data:`None` if the point is not on the surface. Raises: NotImplementedError: If the surface isn't in :math:`\mathbf{R}^2`. ValueError: If the dimension of the ``point`` doesn't match the dimension of the current surface. """

        if _verify:
            if self._dimension != 2:
                raise NotImplementedError("Only 2D surfaces supported.")

            if point.shape != (self._dimension, 1):
                point_dimensions = " x ".join(
                    str(dimension) for dimension in point.shape
                )
                msg = _LOCATE_ERROR_TEMPLATE.format(
                    self._dimension, self._dimension, point, point_dimensions
                )
                raise ValueError(msg)

        return _surface_intersection.locate_point(
            self._nodes, self._degree, point[0, 0], point[1, 0]
        )