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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:

def display_rows(self,
                     rows,
                     labels,
                     indent):

        '''Prepares row content and displays.'''

        out = []

        if not rows:
            return out

        first_row_type = type(rows[0])
        # all rows must have the same datatype
        consistent = True
        for row in rows[1:]:
            if type(row) != first_row_type:
                consistent = False

        if not consistent:
            return out

        if isinstance(labels, dict):
            labels_temp = []
            for key in sorted(labels):
                labels_temp.append(labels[key])
            labels = labels_temp

        if first_row_type is dict:  # and all the others
            temp_rows = []
            if not labels:
                labels = [six.text_type(label).replace('_', ' ').title() for label in sorted(rows[0])]
            for row in rows:
                temp_row = []
                for key in sorted(row):
                    temp_row.append(six.text_type(row[key]))
                temp_rows.append(temp_row)
            rows = temp_rows
        elif isinstance(rows[0], six.string_types):
            rows = [[row] for row in rows]  # encapsulate each row in a single-element list

        labels_and_rows = [labels] + rows if labels else rows
        has_header = self.has_header and labels

        return self.prepare_rows(labels_and_rows, indent + 4, has_header)