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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def calc_requiredremoterelease_v1(self):
 """Guess the required release necessary to not fall below the threshold value at a cross section far downstream with a certain level of certainty. Required control parameter: |RemoteDischargeSafety| Required derived parameters: |RemoteDischargeSmoothPar| |dam_derived.TOY| Required flux sequence: |RemoteDemand| |RemoteFailure| Calculated flux sequence: |RequiredRemoteRelease| Basic equation: :math:`RequiredRemoteRelease = RemoteDemand + RemoteDischargeSafety \\cdot smooth_{logistic1}(RemoteFailure, RemoteDischargeSmoothPar)` Used auxiliary method: |smooth_logistic1| Examples: As in the examples above, define a short simulation time period first: Prepare the dam model: Define a safety factor of 0.5 m³/s for the summer months and no safety factor at all for the winter months: Assume the actual demand at the cross section downsstream has actually been estimated to be 2 m³/s: Prepare a test function, that calculates the required discharge based on the parameter values defined above and for a "remote failure" values ranging between -4 and 4 m³/s: On May 31, the safety factor is 0 m³/s. Hence no discharge is added to the estimated remote demand of 2 m³/s: | ex. | remotefailure | requiredremoterelease | | 1 | -4.0 | 2.0 | | 2 | -3.0 | 2.0 | | 3 | -2.0 | 2.0 | | 4 | -1.0 | 2.0 | | 5 | 0.0 | 2.0 | | 6 | 1.0 | 2.0 | | 7 | 2.0 | 2.0 | | 8 | 3.0 | 2.0 | | 9 | 4.0 | 2.0 | On April 1, the safety factor is 1 m³/s. If the remote failure was exactly zero in the past, meaning the control of the dam was perfect, only 0.5 m³/s are added to the estimated remote demand of 2 m³/s. If the actual recharge did actually fall below the threshold value, up to 1 m³/s is added. If the the actual discharge exceeded the threshold value by 2 or 3 m³/s, virtually nothing is added: | ex. | remotefailure | requiredremoterelease | | 1 | -4.0 | 2.0 | | 2 | -3.0 | 2.000001 | | 3 | -2.0 | 2.000102 | | 4 | -1.0 | 2.01 | | 5 | 0.0 | 2.5 | | 6 | 1.0 | 2.99 | | 7 | 2.0 | 2.999898 | | 8 | 3.0 | 2.999999 | | 9 | 4.0 | 3.0 | """

    con = self.parameters.control.fastaccess
    der = self.parameters.derived.fastaccess
    flu = self.sequences.fluxes.fastaccess
    flu.requiredremoterelease = (
        flu.remotedemand+con.remotedischargesafety[der.toy[self.idx_sim]] *
        smoothutils.smooth_logistic1(
            flu.remotefailure,
            der.remotedischargesmoothpar[der.toy[self.idx_sim]]))