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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def intersection(self, other):
 """ Return the intersection of this RDD and another one. The output will not contain any duplicate elements, even if the input RDDs did. .. note:: This method performs a shuffle internally. [1, 2, 3] """

        return self.map(lambda v: (v, None)) \
            .cogroup(other.map(lambda v: (v, None))) \
            .filter(lambda k_vs: all(k_vs[1])) \
            .keys()