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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def no_intersections(nodes1, degree1, nodes2, degree2):
 r"""Determine if one surface is in the other. Helper for :func:`combine_intersections` that handles the case of no points of intersection. In this case, either the surfaces are disjoint or one is fully contained in the other. To check containment, it's enough to check if one of the corners is contained in the other surface. Args: nodes1 (numpy.ndarray):
 The nodes defining the first surface in the intersection (assumed in :math:\mathbf{R}^2`). degree1 (int):
 The degree of the surface given by ``nodes1``. nodes2 (numpy.ndarray):
 The nodes defining the second surface in the intersection (assumed in :math:\mathbf{R}^2`). degree2 (int):
 The degree of the surface given by ``nodes2``. Returns: Tuple[Optional[list], Optional[bool]]: Pair (2-tuple) of * Edges info list; will be empty or :data:`None` * "Contained" boolean. If not :data:`None`, indicates that one of the surfaces is contained in the other. """

    # NOTE: This is a circular import.
    from bezier import _surface_intersection

    located = _surface_intersection.locate_point(
        nodes2, degree2, nodes1[0, 0], nodes1[1, 0]
    )
    if located is not None:
        return None, True

    located = _surface_intersection.locate_point(
        nodes1, degree1, nodes2[0, 0], nodes2[1, 0]
    )
    if located is not None:
        return None, False

    return [], None