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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def b58encode(v):
 """ encode v, which is a string of bytes, to base58."""


    long_value = 0
    for c in v:
        long_value = long_value * 256 + c

    result = ""
    while long_value >= __b58base:
        div, mod = divmod(long_value, __b58base)
        result = __b58chars[mod] + result
        long_value = div
    result = __b58chars[long_value] + result

    # Bitcoin does a little leading-zero-compression:
    # leading 0-bytes in the input become leading-1s
    nPad = 0
    for c in v:
        if c == 0:
            nPad += 1
        else:
            break

    return (__b58chars[0] * nPad) + result