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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def aget(dct, key):
 r"""Allow to get values deep in a dict with iterable keys Accessing leaf values is quite straightforward: 1 2 If key is empty, it returns unchanged the ``dct`` value. {'x': 1} """

    key = iter(key)
    try:
        head = next(key)
    except StopIteration:
        return dct

    if isinstance(dct, list):
        try:
            idx = int(head)
        except ValueError:
            raise IndexNotIntegerError(
                "non-integer index %r provided on a list."
                % head)
        try:
            value = dct[idx]
        except IndexError:
            raise IndexOutOfRange(
                "index %d is out of range (%d elements in list)."
                % (idx, len(dct)))
    else:
        try:
            value = dct[head]
        except KeyError:
            ## Replace with a more informative KeyError
            raise MissingKeyError(
                "missing key %r in dict."
                % (head, ))
        except Exception:
            raise NonDictLikeTypeError(
                "can't query subvalue %r of a leaf%s."
                % (head,
                   (" (leaf value is %r)" % dct)
                   if len(repr(dct)) < 15 else ""))
    return aget(value, key)