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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def log1p( data: Union[AnnData, np.ndarray, spmatrix], copy: bool = False, chunked: bool = False, chunk_size: Optional[int] = None, ) -> Optional[AnnData]: """Logarithmize the data matrix. Computes :math:`X = \\log(X + 1)`, where :math:`log` denotes the natural logarithm. Parameters data The (annotated) data matrix of shape ``n_obs`` × ``n_vars``. Rows correspond to cells and columns to genes. copy If an :class:`~anndata.AnnData` is passed, determines whether a copy is returned. chunked Process the data matrix in chunks, which will save memory. Applies only to :class:`~anndata.AnnData`. chunk_size ``n_obs`` of the chunks to process the data in. Returns ------- Returns or updates ``data``, depending on ``copy``. """

    if copy:
        if not isinstance(data, AnnData):
            data = data.astype(np.floating)
        else:
            data = data.copy()
    elif not isinstance(data, AnnData) and np.issubdtype(data.dtype, np.integer):
        raise TypeError("Cannot perform inplace log1p on integer array")

    def _log1p(X):
        if issparse(X):
            np.log1p(X.data, out=X.data)
        else:
            np.log1p(X, out=X)
        return X

    if isinstance(data, AnnData):
        if not np.issubdtype(data.X.dtype, np.floating):
            data.X = data.X.astype(np.float32)
        if chunked:
            for chunk, start, end in data.chunked_X(chunk_size):
                 data.X[start:end] = _log1p(chunk)
        else:
            _log1p(data.X)
    else:
        _log1p(data)

    return data if copy else None