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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def _glob_to_re(self, pattern):
 """Translate a shell-like glob pattern to a regular expression. Return a string containing the regex. Differs from 'fnmatch.translate()' in that '*' does not match "special characters" (which are platform-specific). """

        pattern_re = fnmatch.translate(pattern)

        # '?' and '*' in the glob pattern become '.' and '.*' in the RE, which
        # IMHO is wrong -- '?' and '*' aren't supposed to match slash in Unix,
        # and by extension they shouldn't match such "special characters" under
        # any OS.  So change all non-escaped dots in the RE to match any
        # character except the special characters (currently: just os.sep).
        sep = os.sep
        if os.sep == '\\':
            # we're using a regex to manipulate a regex, so we need
            # to escape the backslash twice
            sep = r'\\\\'
        escaped = r'\1[^%s]' % sep
        pattern_re = re.sub(r'((?<!\\)(\\\\)*)\.', escaped, pattern_re)
        return pattern_re