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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def num_neighbors(self, pores, mode='or', flatten=False):
 r""" Returns the number of neigbhoring pores for each given input pore Parameters pores : array_like Pores whose neighbors are to be counted flatten : boolean (optional) If ``False`` (default) the number of pores neighboring each input pore as an array the same length as ``pores``. If ``True`` the sum total number of is counted. mode : string The logic to apply to the returned count of pores. **'or'** : (default) All neighbors of the input pores. This is also known as the 'union' in set theory or 'any' in boolean logic. Both keywords are accepted and treated as 'or'. **'xor'** : Only neighbors of one and only one input pore. This is useful for counting the pores that are not shared by any of the input pores. This is known as 'exclusive_or' in set theory, and is an accepted input. **'xnor'** : Neighbors that are shared by two or more input pores. This is equivalent to counting all neighbors with 'or', minus those found with 'xor', and is useful for finding neighbors that the inputs have in common. **'and'** : Only neighbors shared by all input pores. This is also known as 'intersection' in set theory and (somtimes) as 'all' in boolean logic. Both keywords are accepted and treated as 'and'. Returns ------- If ``flatten`` is False, a 1D array with number of neighbors in each element, otherwise a scalar value of the number of neighbors. Notes ----- This method literally just counts the number of elements in the array returned by ``find_neighbor_pores`` using the same logic. Explore those methods if uncertain about the meaning of the ``mode`` argument here. See Also -------- find_neighbor_pores find_neighbor_throats Examples -------- [3 4] 6 1 """

        pores = self._parse_indices(pores)
        # Count number of neighbors
        num = self.find_neighbor_pores(pores, flatten=flatten,
                                       mode=mode, include_input=True)
        if flatten:
            num = sp.size(num)
        else:
            num = sp.array([sp.size(i) for i in num], dtype=int)
        return num