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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def is_sqlatype_binary(coltype: Union[TypeEngine, VisitableType]) -> bool: """ Is the SQLAlchemy column type a binary type? """

    # Several binary types inherit internally from _Binary, making that the
    # easiest to check.
    coltype = _coltype_to_typeengine(coltype)
    # noinspection PyProtectedMember
    return isinstance(coltype, sqltypes._Binary)