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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def nsmallest(self, n=5, keep='first'):
 """ Return the smallest `n` elements. Parameters n : int, default 5 Return this many ascending sorted values. keep : {'first', 'last', 'all'}, default 'first' When there are duplicate values that cannot all fit in a Series of `n` elements: - ``first`` : return the first `n` occurrences in order of appearance. - ``last`` : return the last `n` occurrences in reverse order of appearance. - ``all`` : keep all occurrences. This can result in a Series of size larger than `n`. Returns ------- Series The `n` smallest values in the Series, sorted in increasing order. See Also -------- Series.nlargest: Get the `n` largest elements. Series.sort_values: Sort Series by values. Series.head: Return the first `n` rows. Notes ----- Faster than ``.sort_values().head(n)`` for small `n` relative to the size of the ``Series`` object. Examples -------- Italy 59000000 France 65000000 Brunei 434000 Malta 434000 Maldives 434000 Iceland 337000 Nauru 11300 Tuvalu 11300 Anguilla 11300 Monserat 5200 dtype: int64 The `n` smallest elements where ``n=5`` by default. Monserat 5200 Nauru 11300 Tuvalu 11300 Anguilla 11300 Iceland 337000 dtype: int64 The `n` smallest elements where ``n=3``. Default `keep` value is 'first' so Nauru and Tuvalu will be kept. Monserat 5200 Nauru 11300 Tuvalu 11300 dtype: int64 The `n` smallest elements where ``n=3`` and keeping the last duplicates. Anguilla and Tuvalu will be kept since they are the last with value 11300 based on the index order. Monserat 5200 Anguilla 11300 Tuvalu 11300 dtype: int64 The `n` smallest elements where ``n=3`` with all duplicates kept. Note that the returned Series has four elements due to the three duplicates. Monserat 5200 Nauru 11300 Tuvalu 11300 Anguilla 11300 dtype: int64 """

        return algorithms.SelectNSeries(self, n=n, keep=keep).nsmallest()