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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def same_intersection(intersection1, intersection2, wiggle=0.5 ** 40):
 """Check if two intersections are close to machine precision. .. note:: This is a helper used only by :func:`verify_duplicates`, which in turn is only used by :func:`generic_intersect`. Args: intersection1 (.Intersection):
 The first intersection. intersection2 (.Intersection):
 The second intersection. wiggle (Optional[float]):
 The amount of relative error allowed in parameter values. Returns: bool: Indicates if the two intersections are the same to machine precision. """

    if intersection1.index_first != intersection2.index_first:
        return False

    if intersection1.index_second != intersection2.index_second:
        return False

    return np.allclose(
        [intersection1.s, intersection1.t],
        [intersection2.s, intersection2.t],
        atol=0.0,
        rtol=wiggle,
    )