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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def distance_strength_of_connection(A, V, theta=2.0, relative_drop=True):
 """Distance based strength-of-connection. Parameters A : csr_matrix or bsr_matrix Square, sparse matrix in CSR or BSR format V : array Coordinates of the vertices of the graph of A relative_drop : bool If false, then a connection must be within a distance of theta from a point to be strongly connected. If true, then the closest connection is always strong, and other points must be within theta times the smallest distance to be strong Returns ------- C : csr_matrix C(i,j) = distance(point_i, point_j) Strength of connection matrix where strength values are distances, i.e. the smaller the value, the stronger the connection. Sparsity pattern of C is copied from A. Notes ----- - theta is a drop tolerance that is applied row-wise - If a BSR matrix given, then the return matrix is still CSR. The strength is given between super nodes based on the BSR block size. Examples -------- """

    # Amalgamate for the supernode case
    if sparse.isspmatrix_bsr(A):
        sn = int(A.shape[0] / A.blocksize[0])
        u = np.ones((A.data.shape[0],))
        A = sparse.csr_matrix((u, A.indices, A.indptr), shape=(sn, sn))

    if not sparse.isspmatrix_csr(A):
        warn("Implicit conversion of A to csr", sparse.SparseEfficiencyWarning)
        A = sparse.csr_matrix(A)

    dim = V.shape[1]

    # Create two arrays for differencing the different coordinates such
    # that C(i,j) = distance(point_i, point_j)
    cols = A.indices
    rows = np.repeat(np.arange(A.shape[0]), A.indptr[1:] - A.indptr[0:-1])

    # Insert difference for each coordinate into C
    C = (V[rows, 0] - V[cols, 0])**2
    for d in range(1, dim):
        C += (V[rows, d] - V[cols, d])**2
    C = np.sqrt(C)
    C[C < 1e-6] = 1e-6

    C = sparse.csr_matrix((C, A.indices.copy(), A.indptr.copy()),
                          shape=A.shape)

    # Apply drop tolerance
    if relative_drop is True:
        if theta != np.inf:
            amg_core.apply_distance_filter(C.shape[0], theta, C.indptr,
                                           C.indices, C.data)
    else:
        amg_core.apply_absolute_distance_filter(C.shape[0], theta, C.indptr,
                                                C.indices, C.data)
    C.eliminate_zeros()

    C = C + sparse.eye(C.shape[0], C.shape[1], format='csr')

    # Standardized strength values require small values be weak and large
    # values be strong.  So, we invert the distances.
    C.data = 1.0 / C.data

    # Scale C by the largest magnitude entry in each row
    C = scale_rows_by_largest_entry(C)

    return C