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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def split_iterable_as_iterable(self, values):
 """Group iterable into iterables, in the order of the keys Parameters values : iterable of length equal to keys iterable of values to be grouped Yields ------ iterable of items in values Notes ----- Memory consumption depends on the amount of sorting required Worst case, if index.sorter[-1] = 0, we need to consume the entire value iterable, before we can start yielding any output But to the extent that the keys are already sorted, the grouping is lazy """

        values = iter(enumerate(values))
        cache = dict()
        def get_value(ti):
            try:
                return cache.pop(ti)
            except:
                while True:
                    i, v = next(values)
                    if i==ti:
                        return v
                    cache[i] = v
        s = iter(self.index.sorter)
        for c in self.count:
            yield (get_value(i) for i in itertools.islice(s, int(c)))