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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def uniq(container):
 """ Check if all of a container's elements are unique. Successively tries first to rely that the elements are hashable, then falls back on them being sortable, and finally falls back on brute force. """


    try:
        return len(set(unbool(i) for i in container)) == len(container)
    except TypeError:
        try:
            sort = sorted(unbool(i) for i in container)
            sliced = itertools.islice(sort, 1, None)
            for i, j in zip(sort, sliced):
                if i == j:
                    return False
        except (NotImplementedError, TypeError):
            seen = []
            for e in container:
                e = unbool(e)
                if e in seen:
                    return False
                seen.append(e)
    return True