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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def _get_aggregated_info(self):
 """ Keeps track of aggregated info in a dictionary called self.aggregated_info """

        agg_results = {}
        for key in self.aggregated_info['occurrences']:
            agg_results[key] = {
                'occurrences': self.aggregated_info['occurrences'].get(key),
                'coverage': (float(self.aggregated_info['occurrences']
                                   .get(key))/float(self.get_metadata('items_count')))*100
            }
        return agg_results