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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def code(_, s, from_fenced_block = None, **kw):
 """ md code AND ``` style fenced raw code ends here"""

        lang = kw.get('lang')

        raw_code = s
        if have_pygments:
            s = style_ansi(raw_code, lang=lang)


        # outest hir is 2, use it for fenced:
        ind = ' ' * kw.get('hir', 2)
        #if from_fenced_block: ... WE treat equal.

        # shift to the far left, no matter the indent (screenspace matters):
        firstl = s.split('\n')[0]
        del_spaces = ' ' * (len(firstl) - len(firstl.lstrip()))
        s = ('\n' + s).replace('\n%s' % del_spaces, '\n')[1:]

        # we want an indent of one and low vis prefix. this does it:
        code_lines = ('\n' + s).splitlines()
        prefix = ('\n%s%s %s' % (ind, low(code_pref), col('', C, no_reset=1)))
        code = prefix.join(code_lines)
        return code + '\n' + reset_col