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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def _select_most_recent_symbols_chunk(self, sid_group):
 """Retrieve the most recent symbol for a set of sids. Parameters sid_group : iterable[int] The sids to lookup. The length of this sequence must be less than or equal to SQLITE_MAX_VARIABLE_NUMBER because the sids will be passed in as sql bind params. Returns ------- sel : Selectable The sqlalchemy selectable that will query for the most recent symbol for each sid. Notes ----- This is implemented as an inner select of the columns of interest ordered by the end date of the (sid, symbol) mapping. We then group that inner select on the sid with no aggregations to select the last row per group which gives us the most recently active symbol for all of the sids. """

        cols = self.equity_symbol_mappings.c

        # These are the columns we actually want.
        data_cols = (cols.sid,) + tuple(cols[name] for name in symbol_columns)

        # Also select the max of end_date so that all non-grouped fields take
        # on the value associated with the max end_date. The SQLite docs say
        # this:
        #
        # When the min() or max() aggregate functions are used in an aggregate
        # query, all bare columns in the result set take values from the input
        # row which also contains the minimum or maximum. Only the built-in
        # min() and max() functions work this way.
        #
        # See https://www.sqlite.org/lang_select.html#resultset, for more info.
        to_select = data_cols + (sa.func.max(cols.end_date),)

        return sa.select(
            to_select,
        ).where(
            cols.sid.in_(map(int, sid_group))
        ).group_by(
            cols.sid,
        )