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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def render_tree(tree, list_all=True, show_only=None, frozen=False, exclude=None):
 """Convert tree to string representation :param dict tree: the package tree :param bool list_all: whether to list all the pgks at the root level or only those that are the sub-dependencies :param set show_only: set of select packages to be shown in the output. This is optional arg, default: None. :param bool frozen: whether or not show the names of the pkgs in the output that's favourable to pip --freeze :param set exclude: set of select packages to be excluded from the output. This is optional arg, default: None. :returns: string representation of the tree :rtype: str """

    tree = sorted_tree(tree)
    branch_keys = set(r.key for r in flatten(tree.values()))
    nodes = tree.keys()
    use_bullets = not frozen

    key_tree = dict((k.key, v) for k, v in tree.items())
    get_children = lambda n: key_tree.get(n.key, [])

    if show_only:
        nodes = [p for p in nodes
                 if p.key in show_only or p.project_name in show_only]
    elif not list_all:
        nodes = [p for p in nodes if p.key not in branch_keys]

    def aux(node, parent=None, indent=0, chain=None):
        if exclude and (node.key in exclude or node.project_name in exclude):
            return []
        if chain is None:
            chain = [node.project_name]
        node_str = node.render(parent, frozen)
        if parent:
            prefix = ' '*indent + ('- ' if use_bullets else '')
            node_str = prefix + node_str
        result = [node_str]
        children = [aux(c, node, indent=indent+2,
                        chain=chain+[c.project_name])
                    for c in get_children(node)
                    if c.project_name not in chain]
        result += list(flatten(children))
        return result

    lines = flatten([aux(p) for p in nodes])
    return '\n'.join(lines)