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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:

def _str_iterator(self, iterator, name_callback=None, prefix="\n", left_paren='[', right_paren=']', depth=0):
        '''
        turn an iteratable value into a string representation

        iterator -- iterator -- the value to be iterated through
        name_callback -- callback -- if not None, a function that will take the key of each iteration
        prefix -- string -- what will be prepended to the generated value
        left_paren -- string -- what will open the generated value
        right_paren -- string -- what will close the generated value
        depth -- integer -- how deep into recursion we are

        return -- string
        '''
        indent = 1 if depth > 0 else 0

        s = []
        s.append('{}{}'.format(prefix, self._add_indent(left_paren, indent)))

        s_body = []

        for k, v in iterator:
            k = k if name_callback is None else name_callback(k)
            v = Value(v, depth+1)
            try:
                # TODO -- right here we should check some flag or something to
                # see if lists should render objects
                if k is None:
                    s_body.append("{}".format(v))
                else:
                    s_body.append("{}: {}".format(k, v))

            except RuntimeError as e:
                # I've never gotten this to work
                s_body.append("{}: ... Recursion error ...".format(k))

            except UnicodeError as e:
                print(v.val)
                print(type(v.val))

        s_body = ",\n".join(s_body)
        s_body = self._add_indent(s_body, indent + 1)

        s.append(s_body)
        s.append("{}".format(self._add_indent(right_paren, indent)))

        return "\n".join(s)