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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def get(url, max_backoff=32, verbose=False, **kwargs):
 """Adding retries to requests.get with exponential backoff. Args: url (str):
 The URL to fetch max_backoff (int):
 The number of seconds to sleep at maximums verbose (bool):
 Whether to print exceptions. Returns: Response: For successful requests return requests' response. `None` otherwise. """

    sleep_seconds = 1
    while sleep_seconds <= max_backoff:
        try:
            # you may overwrite `timeout` via `kwargs`
            response = requests.get(url, **{**{'timeout': 30}, **kwargs})
            # for 4xx, return instantly, no hope of success
            if 400 <= response.status_code < 500:
                return None
            # successfully return 2XX and 3xx
            if 200 <= response.status_code < 400:
                return response
            # for 1xx and 5xx, retry
        except RequestException as e:
            if verbose:
                print(str(e))

        time.sleep(sleep_seconds)
        sleep_seconds *= 2
    return None