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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def from_unicode(text, origin = root):
 """Convert unicode text into a Name object. Lables are encoded in IDN ACE form. @rtype: dns.name.Name object """


    if not isinstance(text, unicode):
        raise ValueError("input to from_unicode() must be a unicode string")
    if not (origin is None or isinstance(origin, Name)):
        raise ValueError("origin must be a Name or None")
    labels = []
    label = u''
    escaping = False
    edigits = 0
    total = 0
    if text == u'@':
        text = u''
    if text:
        if text == u'.':
            return Name([''])        # no Unicode "u" on this constant!
        for c in text:
            if escaping:
                if edigits == 0:
                    if c.isdigit():
                        total = int(c)
                        edigits += 1
                    else:
                        label += c
                        escaping = False
                else:
                    if not c.isdigit():
                        raise BadEscape
                    total *= 10
                    total += int(c)
                    edigits += 1
                    if edigits == 3:
                        escaping = False
                        label += chr(total)
            elif c == u'.' or c == u'\u3002' or \
                 c == u'\uff0e' or c == u'\uff61':
                if len(label) == 0:
                    raise EmptyLabel
                labels.append(encodings.idna.ToASCII(label))
                label = u''
            elif c == u'\\':
                escaping = True
                edigits = 0
                total = 0
            else:
                label += c
        if escaping:
            raise BadEscape
        if len(label) > 0:
            labels.append(encodings.idna.ToASCII(label))
        else:
            labels.append('')
    if (len(labels) == 0 or labels[-1] != '') and not origin is None:
        labels.extend(list(origin.labels))
    return Name(labels)