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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:

def filter_keys(self, **kwargs):
        "Return a set of keys filtered according to the given arguments."
        self._used_index = False
        keys = set(self.data.keys())
        for key_filter, v_filter in kwargs.items():
            if key_filter in self.indexes:
                self._used_index = True
                if v_filter not in self.indexes[key_filter]:
                    keys = set([])
                else:
                    keys = keys.intersection(
                        self.indexes[key_filter][v_filter])
            else:
                keys = keys.intersection(
                    self.simple_filter(key_filter, v_filter))
        return keys