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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def noise3(self, x, y, z, repeat, base=0.0):
 		"""Tileable 3D noise. 		 		repeat specifies the integer interval in each dimension 		when the noise pattern repeats. 		 		base allows a different texture to be generated for 		the same repeat interval. 		"""

		i = int(fmod(floor(x), repeat))
		j = int(fmod(floor(y), repeat))
		k = int(fmod(floor(z), repeat))
		ii = (i + 1) % repeat
		jj = (j + 1) % repeat
		kk = (k + 1) % repeat
		if base:
			i += base; j += base; k += base
			ii += base; jj += base; kk += base

		x -= floor(x); y -= floor(y); z -= floor(z)
		fx = x**3 * (x * (x * 6 - 15) + 10)
		fy = y**3 * (y * (y * 6 - 15) + 10)
		fz = z**3 * (z * (z * 6 - 15) + 10)

		perm = self.permutation
		A = perm[i]
		AA = perm[A + j]
		AB = perm[A + jj]
		B = perm[ii]
		BA = perm[B + j]
		BB = perm[B + jj]
		
		return lerp(fz, lerp(fy, lerp(fx, grad3(perm[AA + k], x, y, z),
										  grad3(perm[BA + k], x - 1, y, z)),
								 lerp(fx, grad3(perm[AB + k], x, y - 1, z),
										  grad3(perm[BB + k], x - 1, y - 1, z))),
						lerp(fy, lerp(fx, grad3(perm[AA + kk], x, y, z - 1),
										  grad3(perm[BA + kk], x - 1, y, z - 1)),
								 lerp(fx, grad3(perm[AB + kk], x, y - 1, z - 1),
										  grad3(perm[BB + kk], x - 1, y - 1, z - 1))))