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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def py2round(value):
 """Round values as in Python 2, for Python 3 compatibility. All x.5 values are rounded away from zero. In Python 3, this has changed to avoid bias: when x is even, rounding is towards zero, when x is odd, rounding is away from zero. Thus, in Python 3, round(2.5) results in 2, round(3.5) is 4. Python 3 also returns an int; Python 2 returns a float. """

    if value > 0:
        return float(floor(float(value)+0.5))
    else:
        return float(ceil(float(value)-0.5))