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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:

def _to_dict(xmltree):
    '''
    Converts an XML ElementTree to a dictionary that only contains items.
    This is the default behavior in version 2017.7. This will default to prevent
    unexpected parsing issues on modules dependant on this.
    '''
    # If this object has no children, the for..loop below will return nothing
    # for it, so just return a single dict representing it.
    if not xmltree.getchildren():
        name = _conv_name(xmltree.tag)
        return {name: xmltree.text}

    xmldict = {}
    for item in xmltree:
        name = _conv_name(item.tag)

        if name not in xmldict:
            if item.getchildren():
                xmldict[name] = _to_dict(item)
            else:
                xmldict[name] = item.text
        else:
            # If a tag appears more than once in the same place, convert it to
            # a list. This may require that the caller watch for such a thing
            # to happen, and behave accordingly.
            if not isinstance(xmldict[name], list):
                xmldict[name] = [xmldict[name]]
            xmldict[name].append(_to_dict(item))
    return xmldict