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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def poll(self, timeout=-1, maxevents=-1):
 """ Poll for events :param timeout: The amount of seconds to wait for events before giving up. The default value, -1, represents infinity. Note that unlike the underlying ``epoll_wait()`` timeout is a fractional number representing **seconds**. :param maxevents: The maximum number of events to report. The default is a reasonably-sized maximum, identical to the one selected by Python 3.4. :returns: A list of (fd, events) that were reported or an empty list if the timeout elapsed. :raises ValueError: If :meth:`closed()` is True :raises OSError: If the underlying ``epoll_wait(2)`` fails. The error message matches those found in the manual page. """

        if self._epfd < 0:
            _err_closed()
        if timeout != -1:
            # 1000 because epoll_wait(2) uses milliseconds
            timeout = int(timeout * 1000)
        if maxevents == -1:
            maxevents = FD_SETSIZE - 1
        events = (epoll_event * maxevents)()
        num_events = epoll_wait(
            self._epfd, cast(byref(events), POINTER(epoll_event)),
            maxevents, timeout)
        return [(events[i].data.fd, events[i].events)
                for i in range(num_events)]