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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def _get_offset_day(self, other):
 """ Find the day in the same month as other that has the same weekday as self.weekday and is the last such day in the month. Parameters other: datetime Returns ------- day: int """

        dim = ccalendar.get_days_in_month(other.year, other.month)
        mend = datetime(other.year, other.month, dim)
        wday = mend.weekday()
        shift_days = (wday - self.weekday) % 7
        return dim - shift_days