<SYSTEM_TASK:>
Solve the following problem using Python, implementing the functions described below, one line at a time
<END_TASK>
<USER_TASK:>
Description:
 def replace_uri(self, src, dest):
 """Replace a uri reference everywhere it appears in the graph with another one. It could appear as the subject, predicate, or object of a statement, so for each position loop through each statement that uses the reference in that position, remove the old statement, and add the replacement. """


        # NB: The hypothetical statement <src> <src> <src> will be removed
        # and re-added several times. The subject block will remove it and
        # add <dest> <src> <src>. The predicate block will remove that and
        # add <dest> <dest> <src>. The object block will then remove that
        # and add <dest> <dest> <dest>.

        # NB2: The list() call here is necessary. .triples() is a generator:
        # It calculates its matches as it progressively iterates through the
        # graph. Actively changing the graph inside the for loop while the
        # generator is in the middle of examining it risks invalidating the
        # generator and could conceivably make it Just Break, depending on
        # the implementation of .triples(). Wrapping .triples() in a list()
        # forces it to exhaust the generator, running through the entire
        # graph to calculate the list of matches before continuing to the
        # for loop.

        subject_triples = list(self.content.triples((src, None, None)))
        for s, p, o in subject_triples:
            self.content.remove((src, p, o))
            self.content.add((dest, p, o))

        predicate_triples = list(self.content.triples((None, src, None)))
        for s, p, o in predicate_triples:
            self.content.remove((s, src, o))
            self.content.add((s, dest, o))

        object_triples = list(self.content.triples((None, None, src)))
        for s, p, o in object_triples:
            self.content.remove((s, p, src))
            self.content.add((s, p, dest))