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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def treeprint(data, render_only=False, file=None, **options):
 """ Render a tree structure based on generic python containers. The keys should be titles and the values are children of the node or None if it's an empty leaf node; Primitives are valid leaf node labels too. E.g. sample = { "Leaf 1": None, "Leaf 2": "I have a label on me", "Branch A": { "Sub Leaf 1 with float label": 3.14, "Sub Branch": { "Deep Leaf": None } }, "Branch B": { "Sub Leaf 2": None } } """


    def getiter(obj):
        if isinstance(obj, collections.abc.Mapping):
            return obj.items()
        elif (isinstance(obj, collections.abc.Iterable) and
              not isinstance(obj, str)):
            return enumerate(obj)

    def cycle_check(item, seen=set()):
        item_id = id(item)
        if item_id in seen:
            raise ValueError('Cycle detected for: %s' % repr(item))
        else:
            seen.add(item_id)

    def crawl(obj, cc=cycle_check):
        cc(obj)
        objiter = getiter(obj)
        if objiter is None:
            yield TreeNode(obj)
        else:
            for key, item in objiter:
                if isinstance(item, collections.abc.Iterable) and \
                   not isinstance(item, str):
                    yield TreeNode(key, children=crawl(item))
                elif item is None:
                    yield TreeNode(key)
                else:
                    yield TreeNode(key, label=item)
    t = Tree(**options)
    render_gen = t.render(crawl(data))
    if render_only:
        return render_gen
    else:
        file = sys.stdout if file is None else file
        conv = (lambda x: x.plain()) if not file.isatty() else (lambda x: x)
        for x in render_gen:
            print(conv(x), file=file)