<SYSTEM_TASK:>
Solve the following problem using Python, implementing the functions described below, one line at a time
<END_TASK>
<USER_TASK:>
Description:
 def extra_space_exists(str1: str, str2: str) -> bool: # noqa """ Return True if a space shouldn't exist between two items """

    ls1, ls2 = len(str1), len(str2)
    if str1.isdigit():
        # 10 SM
        if str2 in ['SM', '0SM']:
            return True
        # 12 /10
        if ls2 > 2 and str2[0] == '/' and str2[1:].isdigit():
            return True
    if str2.isdigit():
        # OVC 040
        if str1 in CLOUD_LIST:
            return True
        # 12/ 10
        if ls1 > 2 and str1.endswith('/') and str1[:-1].isdigit():
            return True
        # 12/1 0
        if ls2 == 1 and ls1 > 3 and str1[:2].isdigit() and '/' in str1 and str1[3:].isdigit():
            return True
        # Q 1001
        if str1 in ['Q', 'A']:
            return True
    # 36010G20 KT
    if str2 == 'KT' and str1[-1].isdigit() \
            and (str1[:5].isdigit() or (str1.startswith('VRB') and str1[3:5].isdigit())):
        return True
    # 36010K T
    if str2 == 'T' and ls1 >= 6 \
            and (str1[:5].isdigit() or (str1.startswith('VRB') and str1[3:5].isdigit())) and str1[-1] == 'K':
        return True
    # OVC022 CB
    if str2 in CLOUD_TRANSLATIONS and str2 not in CLOUD_LIST and ls1 >= 3 and str1[:3] in CLOUD_LIST:
        return True
    # FM 122400
    if str1 in ['FM', 'TL'] and (str2.isdigit() or (str2.endswith('Z') and str2[:-1].isdigit())):
        return True
    # TX 20/10
    if str1 in ['TX', 'TN'] and str2.find('/') != -1:
        return True
    return False