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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:

def has_same_unique_benchmark(self):
        "True if all suites have one benchmark with the same name"
        if any(len(suite) > 1 for suite in self.suites):
            return False
        names = self.suites[0].get_benchmark_names()
        return all(suite.get_benchmark_names() == names
                   for suite in self.suites[1:])