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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def _get_widget_id(self, package_name):
 """ returns widget_id for given package_name does not care about multiple widget ids at the moment, just picks the first :param str package_name: package to check for :return: id of first widget which belongs to the given package_name :rtype: str """

        widget_id = ""
        for app in self.get_apps_list():
            if app.package == package_name:
                widget_id = list(app.widgets.keys())[0]

        return widget_id