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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def _get_fault_dip_term(self, C, rup):
 """ Returns the fault dip term, defined in equation 24 """

        if rup.mag < 4.5:
            return C["c19"] * rup.dip
        elif rup.mag > 5.5:
            return 0.0
        else:
            return C["c19"] * (5.5 - rup.mag) * rup.dip