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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:

def aggregate(self, other=None):
        '''collect the furthest failure from self and other.'''
        if not self.status:
            return self
        if not other:
            return self
        if not other.status:
            return other
        return Value(True, other.index, self.value + other.value, None)