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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def show_all(self, as_string=True):
 """, python2 will not show flags"""

        result = []
        for item in self.container:
            pattern = str(item[0])[10:] if PY3 else item[0].pattern
            instances = item[2] or []
            value = (
                '%s "%s"' % (item[1].__name__, (item[1].__doc__ or ""))
                if callable(item[1])
                else str(item[1])
            )
            value = "%s %s" % (type(item[1]), value)
            result.append(" => ".join((pattern, ",".join(instances), value)))
        return "\n".join(result) if as_string else result