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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def convert_idx_to_name(self, y, lens):
 """Convert label index to name. Args: y (list):
 label index list. lens (list):
 true length of y. Returns: y: label name list. Examples: [['B-LOC'], ['B-LOC', 'I-LOC'], ['B-LOC', 'B-LOC', 'B-LOC']] """

        y = [[self.id2label[idx] for idx in row[:l]]
             for row, l in zip(y, lens)]
        return y