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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def remove_index(self, index):
 """ This one takes some explanation. When we do a query with a WHERE statement, it may end up being a scan and it may end up being a query. If it is a query, we need to remove the hash and range key constraints from the expression and return that as the query_constraints. The remaining constraints, if any, are returned as the filter_constraints. """

        # We can only be doing this if all of the joining ops are AND (no OR),
        # so we don't even need to worry about OR's
        query = []
        remainder = []
        for i in range(0, len(self.pieces), 2):
            const = self.pieces[i]
            if const.hash_field == index.hash_key:
                query.append(const)
            elif index.range_key is not None and const.range_field == index.range_key:
                query.append(const)
            else:
                remainder.append(const)
        if len(query) == 1:
            query_constraints = query[0]
        else:
            query_constraints = Conjunction.and_(query)
        if not remainder:
            filter_constraints = None
        elif len(remainder) == 1:
            filter_constraints = remainder[0]
        else:
            filter_constraints = Conjunction.and_(remainder)
        return (query_constraints, filter_constraints)