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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def replace_word_tokens(string, language):
 """ Given a string and an ISO 639-2 language code, return the string with the words replaced with an operational equivalent. """

    words = mathwords.word_groups_for_language(language)

    # Replace operator words with numeric operators
    operators = words['binary_operators'].copy()
    if 'unary_operators' in words:
        operators.update(words['unary_operators'])

    for operator in list(operators.keys()):
        if operator in string:
            string = string.replace(operator, operators[operator])

    # Replace number words with numeric values
    numbers = words['numbers']
    for number in list(numbers.keys()):
        if number in string:
            string = string.replace(number, str(numbers[number]))

    # Replace scaling multipliers with numeric values
    scales = words['scales']
    end_index_characters = mathwords.BINARY_OPERATORS
    end_index_characters.add('(')

    word_matches = find_word_groups(string, list(scales.keys()))

    for match in word_matches:
        string = string.replace(match, '(' + match + ')')

    for scale in list(scales.keys()):
        for _ in range(0, string.count(scale)):
            start_index = string.find(scale) - 1
            end_index = len(string)

            while is_int(string[start_index - 1]) and start_index > 0:
                start_index -= 1

            end_index = string.find(' ', start_index) + 1
            end_index = string.find(' ', end_index) + 1

            add = ' + '
            if string[end_index] in end_index_characters:
                add = ''

            string = string[:start_index] + '(' + string[start_index:]
            string = string.replace(
                scale, '* ' + str(scales[scale]) + ')' + add,
                1
            )

    string = string.replace(') (', ') + (')

    return string