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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def list_channels(self, collection_name, experiment_name):
 """ List all channels belonging to the named experiment that is part of the named collection. Args: collection_name (string):
 Name of the parent collection. experiment_name (string):
 Name of the parent experiment. Returns: (list) Raises: requests.HTTPError on failure. """

        dont_care = 'image'
        chan = ChannelResource(
            name='', collection_name=collection_name,
            experiment_name=experiment_name, type=dont_care)
        return self._list_resource(chan)