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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def as_ordered_dict(self, preference_orders: List[List[str]] = None) -> OrderedDict: """ Returns Ordered Dict of Params from list of partial order preferences. Parameters preference_orders: List[List[str]], optional ``preference_orders`` is list of partial preference orders. ["A", "B", "C"] means "A" > "B" > "C". For multiple preference_orders first will be considered first. Keys not found, will have last but alphabetical preference. Default Preferences: ``[["dataset_reader", "iterator", "model", "train_data_path", "validation_data_path", "test_data_path", "trainer", "vocabulary"], ["type"]]`` """

        params_dict = self.as_dict(quiet=True)
        if not preference_orders:
            preference_orders = []
            preference_orders.append(["dataset_reader", "iterator", "model",
                                      "train_data_path", "validation_data_path", "test_data_path",
                                      "trainer", "vocabulary"])
            preference_orders.append(["type"])

        def order_func(key):
            # Makes a tuple to use for ordering.  The tuple is an index into each of the `preference_orders`,
            # followed by the key itself.  This gives us integer sorting if you have a key in one of the
            # `preference_orders`, followed by alphabetical ordering if not.
            order_tuple = [order.index(key) if key in order else len(order) for order in preference_orders]
            return order_tuple + [key]

        def order_dict(dictionary, order_func):
            # Recursively orders dictionary according to scoring order_func
            result = OrderedDict()
            for key, val in sorted(dictionary.items(), key=lambda item: order_func(item[0])):
                result[key] = order_dict(val, order_func) if isinstance(val, dict) else val
            return result

        return order_dict(params_dict, order_func)