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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def _get_operations(self, context):
 """Returns a list of operations that need to be performed to turn the cached source code into the one in the buffer."""

        #Most of the time, the real-time update is going to fire with
        #incomplete statements that don't result in any changes being made
        #to the module instances. The SequenceMatches caches hashes for the
        #second argument. Logically, we want to turn the cached version into
        #the buffer version; however, the buffer is the string that keeps 
        #changing.

        #in order to optimize the real-time update, we *switch* the two strings
        #when we set the sequence and then fix the references on the operations
        #after the fact.
        if context.module.changed or self.unset:
            self.matcher.set_seq2(context.cachedstr)
            self.unset = False
            #Set the changed flag back to false now that the sequencer has
            #reloaded it.
            context.module.changed = False
        self.matcher.set_seq1(context.bufferstr)

        opcodes = self.matcher.get_opcodes()
        result = []

        #Index i keeps track of how many operations were actually added because
        #they constituted a change we need to take care of.
        i = 0
        for code in opcodes:
            if code[0] != "equal":
                #Replacements don't have a mode change. All of the operations
                #switch the order of the line indices for the two strings.
                if code[0] == "insert":
                    newcode = ("delete", code[3], code[4], code[1], code[2])
                elif code[0] == "delete":
                    newcode = ("insert", code[3], code[4], code[1], code[2])
                else:
                    newcode = ("replace", code[3], code[4], code[1], code[2])

                op = Operation(context, self.parser, newcode, i)
                result.append(op)
                i += 1

        return result