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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def match_one_string(pattern: str, s: str, *args):
 """ Make sure you know only none or one string will be matched! If you are not sure, use `match_one_pattern` instead. :param pattern: :param s: :param args: :return: .. doctest:: 123 Pattern "\d+" not found, or more than one found in string abc! None Pattern "\d+" not found, or more than one found in string abc 123 def 456! None """

    try:
        # `match` is either an empty list or a list of string.
        match, = re.findall(pattern, s)
        if len(args) == 0:  # If no wrapper argument is given, return directly the matched string
            return match
        elif len(args) == 1:  # If wrapper argument is given, i.e., not empty, then apply wrapper to the match
            wrapper, = args
            return wrapper(match)
        else:
            raise TypeError(
                'Multiple wrappers are given! Only one should be given!')
    except ValueError:
        print("Pattern \"{0}\" not found, or more than one found in string {1}!".format(
            pattern, s))