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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def grouper_dict(d, n):
 """Evenly divide dictionary into fixed-length piece, no filled value if chunk size smaller than fixed-length. Usage:: 6: 'F', 7: 'G', 8: 'H', 9: 'I', 10: 'J'})) [{1: 'A', 2: 'B', 3: 'C'}, {4: 'D', 5: 'E', 6: 'F'}, {7: 'G', 8: 'H', 9: 'I'}, {10: 'J'}] """

    chunk = dict()
    counter = 0
    for k, v in d.items():
        counter += 1
        chunk[k] = v
        print(counter ,chunk)
        if counter == n:
            yield chunk
            chunk = dict()
            counter = 0
    if len(chunk) > 0:
        yield chunk