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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def get_the_board( layout=BOARDS["arduino"], base_dir="/dev/", identifier="tty.usbserial" ):
 """ Helper function to get the one and only board connected to the computer running this. It assumes a normal arduino layout, but this can be overriden by passing a different layout dict as the ``layout`` parameter. ``base_dir`` and ``identifier`` are overridable as well. It will raise an IOError if it can't find a board, on a serial, or if it finds more than one. """

    from .pyfirmata import Board  # prevent a circular import

    boards = []
    for device in os.listdir(base_dir):
        if device.startswith(identifier):
            try:
                board = Board(os.path.join(base_dir, device), layout)
            except serial.SerialException:
                pass
            else:
                boards.append(board)
    if len(boards) == 0:
        raise IOError(
            "No boards found in {0} with identifier {1}".format(base_dir, identifier)
        )
    elif len(boards) > 1:
        raise IOError("More than one board found!")
    return boards[0]