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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def append(self, acces, **kwargs):
 """Append acces to list. Quite slow since it checks uniqueness. kwargs may set `info` for this acces. """

        if acces.Id in set(ac.Id for ac in self):
            raise ValueError("Acces id already in list !")
        list.append(self, acces)
        if kwargs:
            self.infos[acces.Id] = kwargs