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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def compare(self, v1, v2):
 """ Compares two values. Returns 1 if all values are withing self.tolerance of each other. """

        try:
            if len(v1) != len(v2): return 0
            for x, y in zip(v1, v2):
                if abs( x - y ) > self.tolerance:
                    return 0
            return 1
        except:
            # some patterns may not be vectors
            try:
                if abs( v1 - v2 ) > self.tolerance:
                    return 0
                else:
                    return 1
            except:
                return 0