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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:

def intersect(self, second_iterable, selector=identity):
        '''Returns those elements which are both in the source sequence and in
        the second_iterable.

        Note: This method uses deferred execution.

        Args:
            second_iterable: Elements are returned if they are also in the
                sequence.

            selector: An optional single argument function which is used to
                project the elements in the source and second_iterables prior
                to comparing them. If omitted the identity function will be
                used.

        Returns:
            A sequence containing all elements in the source sequence  which
            are also members of the second sequence.

        Raises:
            ValueError: If the Queryable has been closed.
            TypeError: If the second_iterable is not in fact iterable.
            TypeError: If the selector is not callable.
        '''
        if self.closed():
            raise ValueError("Attempt to call intersect() on a "
                             "closed Queryable.")

        if not is_iterable(second_iterable):
            raise TypeError("Cannot compute intersect() with second_iterable "
               "of non-iterable {0}".format(str(type(second_iterable))[7: -1]))

        if not is_callable(selector):
            raise TypeError("intersect() parameter selector={0} is "
                            "not callable".format(repr(selector)))

        return self._create(self._generate_intersect_result(second_iterable,
                                                            selector))