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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def locate(self, point):
 r"""Find a point on the current curve. Solves for :math:`s` in :math:`B(s) = p`. This method acts as a (partial) inverse to :meth:`evaluate`. .. note:: A unique solution is only guaranteed if the current curve has no self-intersections. This code assumes, but doesn't check, that this is true. .. image:: ../../images/curve_locate.png :align: center .. doctest:: curve-locate 0.5 True Traceback (most recent call last):
 ValueError: Parameters not close enough to one another .. testcleanup:: curve-locate import make_images make_images.curve_locate(curve, point1, point2, point3) Args: point (numpy.ndarray):
 A (``D x 1``) point on the curve, where :math:`D` is the dimension of the curve. Returns: Optional[float]: The parameter value (:math:`s`) corresponding to ``point`` or :data:`None` if the point is not on the ``curve``. Raises: ValueError: If the dimension of the ``point`` doesn't match the dimension of the current curve. """

        if point.shape != (self._dimension, 1):
            point_dimensions = " x ".join(
                str(dimension) for dimension in point.shape
            )
            msg = _LOCATE_ERROR_TEMPLATE.format(
                self._dimension, self._dimension, point, point_dimensions
            )
            raise ValueError(msg)

        return _curve_helpers.locate_point(self._nodes, point)