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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def list_(formatter, value, name, option, format):
 """Repeats the items of an array. Spec: `{:[l[ist]:]item|spacer[|final_spacer[|two_spacer]]}` Example:: u'apple, banana, and coconut' u'apple and banana' """

    if not format:
        return
    if not hasattr(value, '__getitem__') or isinstance(value, string_types):
        return
    words = format.split(u'|', 4)
    num_words = len(words)
    if num_words < 2:
        # Require at least two words for item format and spacer.
        return
    num_items = len(value)
    item_format = words[0]
    # NOTE: SmartFormat.NET treats a not nested item format as the format
    # string to format each items.  For example, `x` will be treated as `{:x}`.
    # But the original tells us this behavior has been deprecated so that
    # should be removed.  So SmartFormat for Python doesn't implement the
    # behavior.
    spacer = u'' if num_words < 2 else words[1]
    final_spacer = spacer if num_words < 3 else words[2]
    two_spacer = final_spacer if num_words < 4 else words[3]
    buf = io.StringIO()
    for x, item in enumerate(value):
        if x == 0:
            pass
        elif x < num_items - 1:
            buf.write(spacer)
        elif x == 1:
            buf.write(two_spacer)
        else:
            buf.write(final_spacer)
        buf.write(formatter.format(item_format, item, index=x))
    return buf.getvalue()