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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def afw_to_nfa_conversion(afw: dict) -> dict: """ Returns a NFA reading the same language of input AFW. Let :math:`A = (Σ, S, s^0 , ρ, F )` be an afw. Then we define the nfa :math:`A_N` such that :math:`L(A_N) = L(A)` as follows :math:`AN = (Σ, S_N , S^0_N , ρ_N , F_N )` where: • :math:`S_N = 2^S` • :math:`S^0_N= \{\{s^0 \}\}` • :math:`F_N=2^F` • :math:`(Q,a,Q') ∈ ρ_N` iff :math:`Q'` satisfies :math:`⋀_{ s∈Q} ρ(s, a)` We take an empty conjunction in the definition of :math:`ρ_N` to be equivalent to true; thus, :math:`(∅, a, ∅) ∈ ρ_N`. :param dict afw: input AFW. :return: *(dict)* representing a NFA. """


    nfa = {
        'alphabet': afw['alphabet'].copy(),
        'initial_states': {(afw['initial_state'],)},
        'states': {(afw['initial_state'],)},
        'accepting_states': set(),
        'transitions': dict()
    }

    # State of the NFA are composed by the union of more states of the AFW

    boundary = deepcopy(nfa['states'])
    possible_assignments = set(
        itertools.product([True, False], repeat=len(afw['states'])))

    while boundary:
        state = boundary.pop()
        # The state is accepting only if composed exclusively of final states
        if set(state).issubset(afw['accepting_states']):
            nfa['accepting_states'].add(state)

        for action in nfa['alphabet']:
            boolean_formula = 'True'
            # join the boolean formulas of the single states given the action
            for s in state:
                if (s, action) not in afw['transitions']:
                    boolean_formula += ' and False'
                else:
                    boolean_formula += \
                        ' and (' + \
                        afw['transitions'][s, action] + \
                        ')'

            for assignment in possible_assignments:
                mapping = dict(zip(afw['states'], assignment))

                # If the formula is satisfied
                if eval(boolean_formula, mapping):
                    # add the transition to the resulting NFA

                    evaluation = \
                        tuple(k for k in mapping if mapping[k] is True)

                    if evaluation not in nfa['states']:
                        nfa['states'].add(evaluation)
                        boundary.add(evaluation)
                    nfa['transitions'].setdefault(
                        (state, action), set()).add(evaluation)

    return nfa