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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def __is_exported(self, name, module):
 """ Returns `True` if and only if `pydoc` considers `name` to be a public identifier for this module where `name` was defined in the Python module `module`. If this module has an `__all__` attribute, then `name` is considered to be exported if and only if it is a member of this module's `__all__` list. If `__all__` is not set, then whether `name` is exported or not is heuristically determined. Firstly, if `name` starts with an underscore, it will not be considered exported. Secondly, if `name` was defined in a module other than this one, it will not be considered exported. In all other cases, `name` will be considered exported. """

        if hasattr(self.module, '__all__'):
            return name in self.module.__all__
        if not _is_exported(name):
            return False
        if module is None:
            return False
        if module is not None and self.module.__name__ != module.__name__:
            return name in self._declared_variables
        return True