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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def neclusters(l, K):
 """Partition list ``l`` in ``K`` partitions, without empty parts. [[[0, 1], [2]], [[1], [0, 2]], [[0], [1, 2]]] [[[0, 1, 2]]] """

    for c in clusters(l, K):
        if all(x for x in c):
            yield c