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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def pluralize(count, item_type):
 """Pluralizes the item_type if the count does not equal one. For example `pluralize(1, 'apple')` returns '1 apple', while `pluralize(0, 'apple') returns '0 apples'. :return The count and inflected item_type together as a string :rtype string """

  def pluralize_string(x):
    if x.endswith('s'):
      return x + 'es'
    else:
      return x + 's'

  text = '{} {}'.format(count, item_type if count == 1 else pluralize_string(item_type))
  return text