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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def _resolved_type(self):
 """Return the type for the columns, and a flag to indicate that the column has codes."""

        import datetime

        self.type_ratios = {test: (float(self.type_counts[test]) / float(self.count)) if self.count else None
                            for test, testf in tests + [(None, None)]}

        # If it is more than 5% str, it's a str

        try:
            if self.type_ratios.get(text_type,0) + self.type_ratios.get(binary_type,0) > .05:
                if self.type_counts[text_type] > 0:
                    return text_type, False

                elif self.type_counts[binary_type] > 0:
                    return binary_type, False
        except TypeError as e:
            # This is probably the result of the type being unknown
            pass


        if self.type_counts[datetime.datetime] > 0:
            num_type = datetime.datetime

        elif self.type_counts[datetime.date] > 0:
            num_type = datetime.date

        elif self.type_counts[datetime.time] > 0:
            num_type = datetime.time

        elif self.type_counts[float] > 0:
            num_type = float

        elif self.type_counts[int] > 0:
            num_type = int

        elif self.type_counts[text_type] > 0:
            num_type = text_type

        elif self.type_counts[binary_type] > 0:
            num_type = binary_type

        else:
            num_type = unknown

        if self.type_counts[binary_type] > 0 and num_type != binary_type:
            has_codes = True
        else:
            has_codes = False

        return num_type, has_codes