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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def generate_range(start=None, end=None, periods=None, offset=BDay()):
 """ Generates a sequence of dates corresponding to the specified time offset. Similar to dateutil.rrule except uses pandas DateOffset objects to represent time increments. Parameters start : datetime (default None) end : datetime (default None) periods : int, (default None) offset : DateOffset, (default BDay()) Notes ----- * This method is faster for generating weekdays than dateutil.rrule * At least two of (start, end, periods) must be specified. * If both start and end are specified, the returned dates will satisfy start <= date <= end. Returns ------- dates : generator object """

    from pandas.tseries.frequencies import to_offset
    offset = to_offset(offset)

    start = to_datetime(start)
    end = to_datetime(end)

    if start and not offset.onOffset(start):
        start = offset.rollforward(start)

    elif end and not offset.onOffset(end):
        end = offset.rollback(end)

    if periods is None and end < start and offset.n >= 0:
        end = None
        periods = 0

    if end is None:
        end = start + (periods - 1) * offset

    if start is None:
        start = end - (periods - 1) * offset

    cur = start
    if offset.n >= 0:
        while cur <= end:
            yield cur

            # faster than cur + offset
            next_date = offset.apply(cur)
            if next_date <= cur:
                raise ValueError('Offset {offset} did not increment date'
                                 .format(offset=offset))
            cur = next_date
    else:
        while cur >= end:
            yield cur

            # faster than cur + offset
            next_date = offset.apply(cur)
            if next_date >= cur:
                raise ValueError('Offset {offset} did not decrement date'
                                 .format(offset=offset))
            cur = next_date