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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def find(self, query=None, func=None, labels=None, colors=None, pinned=None, archived=None, trashed=False):
 # pylint: disable=too-many-arguments """Find Notes based on the specified criteria. Args: query (Union[_sre.SRE_Pattern, str, None]):
 A str or regular expression to match against the title and text. func (Union[callable, None]):
 A filter function. labels (Union[List[str], None]):
 A list of label ids or objects to match. An empty list matches notes with no labels. colors (Union[List[str], None]):
 A list of colors to match. pinned (Union[bool, None]):
 Whether to match pinned notes. archived (Union[bool, None]):
 Whether to match archived notes. trashed (Union[bool, None]):
 Whether to match trashed notes. Return: List[gkeepapi.node.TopLevelNode]: Results. """

        if labels is not None:
            labels = [i.id if isinstance(i, _node.Label) else i for i in labels]

        return (node for node in self.all() if
            (query is None or (
                (isinstance(query, six.string_types) and (query in node.title or query in node.text)) or
                (isinstance(query, Pattern) and (
                    query.search(node.title) or query.search(node.text)
                ))
            )) and
            (func is None or func(node)) and \
            (labels is None or \
             (not labels and not node.labels.all()) or \
             (any((node.labels.get(i) is not None for i in labels)))
            ) and \
            (colors is None or node.color in colors) and \
            (pinned is None or node.pinned == pinned) and \
            (archived is None or node.archived == archived) and \
            (trashed is None or node.trashed == trashed)
        )