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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def score_n2(matrix, matrix_size):
 """\ Implements the penalty score feature 2. ISO/IEC 18004:2015(E) -- 7.8.3 Evaluation of data masking results - Table 11 (page 54) ============================== ==================== =============== Feature Evaluation condition Points ============================== ==================== =============== Block of modules in same color Block size = m × n N2 ×(m-1)×(n-1) ============================== ==================== =============== N2 = 3 :param matrix: The matrix to evaluate :param matrix_size: The width (or height) of the matrix. :return int: The penalty score (feature 2) of the matrix. """

    score = 0
    for i in range(matrix_size - 1):
        for j in range(matrix_size - 1):
            bit = matrix[i][j]
            if bit == matrix[i][j + 1] and bit == matrix[i + 1][j] \
                and bit == matrix[i + 1][j + 1]:
                score += 1
    return score * 3