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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def consume_path_sep(self, i):
 """Consume any consecutive path separators are they count as one."""


        try:
            if self.bslash_abort:
                count = -1
                c = '\\'
                while c == '\\':
                    count += 1
                    c = next(i)
                i.rewind(1)
                # Rewind one more if we have an odd number (escape): \\\*
                if count > 0 and count % 2:
                    i.rewind(1)
            else:
                c = '/'
                while c == '/':
                    c = next(i)
                i.rewind(1)
        except StopIteration:
            pass