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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def urljoin(*parts):
 """ Join terms together with forward slashes Parameters parts Returns ------- str """

    # first strip extra forward slashes (except http:// and the likes) and
    # create list
    part_list = []
    for part in parts:
        p = str(part)
        if p.endswith('//'):
            p = p[0:-1]
        else:
            p = p.strip('/')
        part_list.append(p)
    # join everything together
    url = '/'.join(part_list)
    return url