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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def userInformation(MoreData_presence=0):
 """USER INFORMATION Section 9.3.31"""

    a = TpPd(pd=0x3)
    b = MessageType(mesType=0x20)  # 000100000
    c = UserUser()
    packet = a / b / c
    if MoreData_presence is 1:
        d = MoreDataHdr(ieiMD=0xA0, eightBitMD=0x0)
        packet = packet / d
    return packet