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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def sql_column_like_drug(self, column_name: str) -> str: """ Returns SQL like .. code-block:: sql (column_name LIKE '%drugname1%' OR column_name LIKE '%drugname2%') for the drug names that this Drug object knows about. Args: column_name: column name, pre-escaped if necessary Returns: SQL fragment as above """

        clauses = [
            "{col} LIKE {fragment}".format(
                col=column_name,
                fragment=sql_string_literal(f))
            for f in self.sql_like_fragments
        ]
        return "({})".format(" OR ".join(clauses))