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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def pluralize(word) : """Pluralize an English noun."""


        rules = [
            ['(?i)(quiz)$' , '\\1zes'],
            ['^(?i)(ox)$' , '\\1en'],
            ['(?i)([m|l])ouse$' , '\\1ice'],
            ['(?i)(matr|vert|ind)ix|ex$' , '\\1ices'],
            ['(?i)(x|ch|ss|sh)$' , '\\1es'],
            ['(?i)([^aeiouy]|qu)ies$' , '\\1y'],
            ['(?i)([^aeiouy]|qu)y$' , '\\1ies'],
            ['(?i)(hive)$' , '\\1s'],
            ['(?i)(?:([^f])fe|([lr])f)$' , '\\1\\2ves'],
            ['(?i)sis$' , 'ses'],
            ['(?i)([ti])um$' , '\\1a'],
            ['(?i)(buffal|tomat)o$' , '\\1oes'],
            ['(?i)(bu)s$' , '\\1ses'],
            ['(?i)(alias|status)' , '\\1es'],
            ['(?i)(octop|vir)us$' , '\\1i'],
            ['(?i)(ax|test)is$' , '\\1es'],
            ['(?i)s$' , 's'],
            ['(?i)$' , 's']
        ]

        uncountable_words = ['equipment', 'information', 'rice', 'money', 'species', 'series', 'fish', 'sheep']

        irregular_words = {
            'person' : 'people',
            'man' : 'men',
            'child' : 'children',
            'sex' : 'sexes',
            'move' : 'moves'
        }

        lower_cased_word = word.lower();

        for uncountable_word in uncountable_words:
            if lower_cased_word[-1*len(uncountable_word):] == uncountable_word :
                return word

        for irregular in irregular_words.keys():
            match = re.search('('+irregular+')$',word, re.IGNORECASE)
            if match:
                return re.sub('(?i)'+irregular+'$', match.expand('\\1')[0]+irregular_words[irregular][1:], word)

        for rule in range(len(rules)):
            match = re.search(rules[rule][0], word, re.IGNORECASE)
            if match :
                groups = match.groups()
                for k in range(0,len(groups)) :
                    if groups[k] == None :
                        rules[rule][1] = rules[rule][1].replace('\\'+str(k+1), '')

                return re.sub(rules[rule][0], rules[rule][1], word)

        return word