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Solve the following problem using Python, implementing the functions described below, one line at a time
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Description:
 def visit_named_resource(self, _, children):
 """A resource in the query with its optional name. Arguments --------- _ (node) : parsimonious.nodes.Node. children : list - 0: for ``OPTIONAL_RESOURCE_NAME``: str, the name of the resource, or ``None`` if not set in the query. - 1: for ``RESOURCE``: an instance of a subclass of ``.resources.Resource``. Returns ------- .resources.Resource An instance of a subclass of ``.resources.Resource``, with its ``name`` field set to the name in the query if set. Example ------- <Field[bar] /> <Field[foo] .bar /> <Field[foo] .bar /> """


        name, resource = children
        if name:
            resource.name = name
        return resource