Juvinall Fundamentals of Machine Component Design | Torque | Gear\nJuvinall Fundamentals of Machine Component Design\nspeichernJuvinall Fundamentals of Machine Component Design für später speichern\nProgrammed Example Problems from: Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Fourth Edition John Wiley & Sons 2006 Table of Contents Chp 1: Mechanical Engineering Design in Broad Perspective Chp 2: Load Analysis Chp 3: Materials Chp 4: Static Body Stresses Chp 5: Elastic Strain, Deflection, and Stability Chp 6: Failure Theories, Safety Factors, and Reliability Chp 7: Impact Chp 8: Fatigue Chp 9: Surface Damage Chp 10: Threaded Fasteners and Power Screws Chp 11: Rivets, Welding, and Bonding Chp 12: Springs Chp 13: Lubrication and Sliding Bearings Chp 14: Rolling-Element Bearings Chp 15: Spur Gears Chp 16: Helical, Bevel, and Worm Gears Chp 17: Shafts and Associated Parts Chp 18: Clutches and Brakes Chp 19: Miscellaneous Machine Components\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 1: Mechanical Engineering Design in Broad Perspective Example 1.1 Description Force Displacement Work out Angle Torque Example 1.2 Description Rotation speed Angle Time Work done Power Example 1.3 Description Drive speed Punch speed Speed reduction ratio Torque needed Motor Torque needed Motor Work / Rev Motor Power Example 1.4 Description Drive speed Punch speed Speed reduction ratio Torque needed Motor Torque needed Motor Work / Rev Motor Power Example 1.5 Description Punch diagram -- width Symbol or Formula qwidth Value 1 Units rad MKS Value #NAME? Symbol or Formula wd wp R = wp / wd T Tm = T R W m = 2 p Tm Pm = Tm wd Value 1,200 60 #NAME? 1 #NAME? #NAME? #NAME? Units rpm rpm 1 kN m Nm J kW MKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Symbol or Formula wd wp R = wp / wd T Tm = T R W m = 2 p Tm Pm = Tm wd Value 1,200 60 #NAME? 10 #NAME? #NAME? #NAME? Units rpm rpm 1 kN m Nm J kW MKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Symbol or Formula w t=q/w W P=W/t Value 1,000 0.10 #NAME? 0.001 #NAME? Units rpm rad s Nm hp MKS Value #NAME? #NAME? #NAME? #NAME? #NAME? Symbol or Formula F s W out = F s Value 1 1.00 #NAME? 0.10 #NAME? Units N mm Nm rad N mm MKS Value #NAME? #NAME? #NAME? #NAME? #NAME?\nT = W out / q\nPunch diagram -- width Punch Energy Total Energy Needed Flywheel Energy Min Flywheel speed Max Flywheel speed Required Moment of Inertai Flywheel Diameter Inner Flywheel Diameter Flywheel Length Flywheel density Calculated Mom. Of Inertia Error Example 1.6 Description Wheel radius Car speed Wheel speed Engine speed (117 mph) Axle speed Car speed Engine speed (55 mph) Engine power (55 mph) Spec. fuel consumption (55 mph) Fuel consumption Specific fuel weight Fuel mileage Slowest engine speed Spec. fuel consumption (slow) Fuel mileage\nTheight Ep = qw Th Eall Ef = Eall - Ep wmin wmax I = Ef / 0.5 - wmin ) d di = 0.8 d L = 0.2 d r 4 Icalc = p (d - di4) L r / 32\n1 #NAME? 6,283 #NAME? 300 400 #NAME? 0.687 #NAME? #NAME? 7,700 #NAME? #NAME?\nkN m J J J rpm rpm kg m^2 m m m kg / m^3 kg m^2 kg m^2\n#NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\ne = I - Icalc\nSymbol or Formula r V ww = V / r we Ra = we / ww V55 we-55 = we (55/117) P55 F f = P55 F c m = V55 c / f wslow F1000 m1000 = m F / F1000\nValue 13 117 #NAME? 4,000 #NAME? 55 #NAME? 23 0.630 #NAME? 5.800 #NAME? 1,000.000 0.480 #NAME?\nUnits in mph rpm rpm 1 mph rpm hp lbm / hp hr lbm/ hr lbm/gal mi / gal rpm lbm / hp hr mi / gal\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME?\n#NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Solve C60 = 0 by changing C55\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 2: Load Analysis Example 2.1 Description Engine power Car speed Drag force Drag Force Moment Arm Car Weight Car Weight Moment Arm Front Wheel Moment Arm Front Wheel Force Rear Wheel Force Example 2.2 Description Engine power Car speed Engine power for thrust Engine thrust for Pt Rotating Inertia Fraction Engine Power for Linear Accel Increased Thrust Car Weight Acceleration Example 2.3 Description Engine torque Gear ratio Propellor torque Housing torque Example 2.4 Description Engine torque Gear ratio Output torque Housing torque Symbol or Formula T R Tp = T R Th = Tp - T FA FB Value 3,000 2.78 #NAME? #NAME? 2,667.00 2,667.00 Units lbf in 1 lbf in lbf in lbf lbf Symbol or Formula T R Tp = T R Th = T - Tp Value 5 0.05 #NAME? #NAME? Units Nm 1 Nm Nm Symbol or Formula P V Pt Ft f PL = (P - Pt) / (1 + f) FL = Ft (PL / Pt) W a = FL / (W/g) Value 96 60.00 16 100 0.07 #NAME? #NAME? 3000.00 #NAME? Units hp mph hp lbf 1 hp lbf lbf ft/s^2 Symbol or Formula P V Fd = P / V xd Wc xc xf Wr = Wc - Wf W f = (W c xc - Fd xd) xf Value 16 60.00 #NAME? 25.00 3000.00 50.00 100.00 #NAME? #NAME? Units hp mph lbf in lbf in in lbf lbf\nxB FC xC xII FII = (FB xB - FC xC) / xII Example 2.5 Description Symbol or Formula F a M=Fa\n2.00 4,444.00 7.00 9.00 #NAME?\nin lbf in in lbf\nValue 3,000 1.00 #NAME?\nUnits lbf in lbf in\nExample 2.6 Description Symbol or Formula F32 x32 q42 x42 F42 = F32 x32 / x42 V12 = F42 sin(q42) H12 = F32 + F42 cos(q42) F12 = (H12 V12 )\nValue 40 1.50 30.00 1.00 #NAME? #NAME? #NAME? #NAME? #NAME?\nUnits lbf in deg in lbf lbf lbf lbf deg\nq12 = atan2(V12 , H12) Example 2.7 Description Symbol or Formula Fthumb xthumb xtendom Ftendon = Fthumb xthumb / xtendon Example 2.8 Description Symbol or Formula FA xA MB = FA xA FD xD MC = FD xD FC DC T C = F C DC / 2\nValue 10 3.00 0.50 #NAME?\nUnits lbf in in lbf\nValue 1,087 2.00 #NAME? 2,864 2.00 #NAME? 4,444 2.25 #NAME?\nUnits lbf in lbf in lbf in lbf in lbf in lbf in\nFB DB T B = F B DB / 2 Example 2.9 Description Example 2.10 Description Symbol or Formula Symbol or Formula\n2,667 3.75 #NAME?\nlbf in lbf in\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Value #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME?\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Value #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME?\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 3: Materials Example 3.1 Description Symbol or Formula Sy Su A0 / AH SyH = (A0 / AH) Sy SuH = (A0 / AH) Su A0 / Af R = (A0 / Af) / (A0 / AH) Ar = 1 - 1/ R e=R-1 Example 3.2 Description Hardness Symbol or Formula HB KB Su = KB HB Sy = 1.05 Su - 2.06e8 (Pa) Example 3.3 Description Symbol or Formula Value Units Value 300 500.00 #NAME? #NAME? Units 1 psi psi psi Value 66 66 1.30 #NAME? #NAME? 2.50 #NAME? #NAME? #NAME? Units ksi ksi 1 ksi ksi 1 1 1 1\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 4: Static Body Stresses Example 4.1 Description Straight beam Curved beam Curved beam Symbol or Formula Zstraight ro / ri e / h = 1 - 1 / ln(ro/ ri) Z- = (0.5 - e/h) / (e/h) 0.5 Z+ = (0.5 + e/h) / (e/h) 1.5 Ki = Z- / Zstraight Ko = Z+ / Zstraight Example 4.2 Description Symbol or Formula V I b ylo yhi b0 t1 = (V / I b) b0 (yhi2 - ylo2) / 2 V I b ylo yhi b0 t2 = (V / I b) b0 (yhi2 - ylo2) / 2 V I b ylo yhi b0 t3 = (V / I b) b0 (yhi2 - ylo2) / 2 t4 = t2 + t3 Moment arm Moment Moment Example 4.3 d M = Vd c s=Mc/I Value 40,000 1,840,000 60 30 40 60 #NAME? 40,000 1,840,000 20 30 40 60 #NAME? 40,000 1,840,000 20 0 30 20 #NAME? #NAME? 100 #NAME? 40 #NAME? Units N mm^4 mm mm mm mm Mpa N mm^4 mm mm mm mm Mpa N mm^4 mm mm mm mm Mpa Mpa mm Nm mm MPa Value 6 3 #NAME? #NAME? #NAME? #NAME? #NAME? Units 1 1 1 1 1 1 1\nSymbol or Formula I J c M r T s=Mc/I t=Tr/J\nValue 0.0490 0.0980 0.50 4,000.0 0.50 6,000.0 #NAME? #NAME?\nUnits in^4 in^4 in in lbf in in lbf ksi ksi\nExample 4.4 Description Symbol or Formula a DT e = a DT L DL = e L dmeas dcons = DL - dmeas A E Value 7.00E-06 400.0 #NAME? 10.0 #NAME? 0.0080 #NAME? 1.0 3.00E+07 #NAME? Units 1 / degF degFdiff 1 in in in in in^2 psi lbf\nP = dcons A E / L\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 5: Elastic Strain, Deflection, and Stability Example 5.1 Description Symbol or Formula e0 e120 e240 e1 = (e0 + e120 + e240) / 3 + ((2e0 - e120 - e240)2 / 9 + (e120 - e240)2 / 3)1/2 e2 = (e0 + e120 + e240) / 3 - ((2e0 - e120 - e240)2 / 9 + (e120 - e240)2 / 3)1/2 a = (1/2) atan(31/2 (e120 - e240) / (2e0 - e120 - e240)) Example 5.2 Description Symbol or Formula e0 e45 e90 e1 = (e0 + e90 ) / 2 + ((e0 - e45)2 / 2 + (e45 - e90)2 / 2)1/2 e2 = (e0 + e90 ) / 2 - ((e0 - e45)2 / 2 + (e45 - e90)2 / 2)1/2 a = (1/2) atan( (e0 - 2e45 + e90) / (e0 - e90)) Example 5.3 Description Example 5.4 Description Symbol or Formula x P M=Px/2 V=P/2 L=2x E I G A 2 3 U = P L / 96 E I + 3 P2 L / 20 G A d = P L3 / 48 E I + 3 P L / 10 G A Symbol or Formula\nExample 5.5 Description Symbol or Formula L x=L/2 P E b h I = b h3 / 12 G A=bh d = P L3 / 48 E I + 3 P L / 10 G A\nExample 5.6 Description Symbol or Formula L P E h I d = P h L2 / 2 E I\nExample 5.7 Description Symbol or Formula R F E G I A d = 3 p F R3 / EI + p F R / E A + 6 p F R / 5 G A\nExample 5.8 Description Symbol or Formula R F E G b h I = b h3 / 12 A=bh d = 3 p F R3 / EI + p F R / E A + 6 p F R / 5 G A\nExample 5.9 Description Symbol or Formula\nm Fm = mg xm Mm = Fm xm F y a M = Mm - F y E I 2 U = (1/2EI) ( Mm a - F M a2 + F3 a3 / 3) d = (2 a3 F / 3 - a2 Mm) / 2 EI Example 5.10 Description Symbol or Formula M0 b P E I EI G a K' q = (2/EI) (M0 b / 2 - P b2 / 16) + 2 M0 a / G K' Z = b2 G K' / 8 (bGK' + 2 a EI) d = (p/EI) (Z b - Z b2 / 4 + b2 / 48) + Pa3 / 6EI + 2 P Z2 a / Gk'\nExample 5.11 Description Symbol or Formula Sf Sy E L F D A = p D2 / 4 r=D/4 P = Sf F SR = L / r P/A - p2 E / (L/r)2\nError Example 5.12 Description\nSymbol or Formula Sf Sy\nError #1 -- Euler beam Error #2 -- Short column\nE L F D A = p D2 / 4 r=D/4 P = Sf F SR = L / r P/A - p2 E / (L/r)2 P/A - Sy + Sy2 (L/r)2 / 4 p2 E\nValue -0.000750 0.000400 0.001850 #NAME? #NAME? #NAME?\nUnits m/m m/m m/m m/m m/m deg\nValue 2,600 -200 450 #NAME? #NAME? #NAME?\nUnits micron / m micron / m micron / m micron / m micron / m deg\nValue 5 100 #NAME? #NAME? #NAME? 30 1 10 1 #NAME? #NAME?\nUnits in lbf lbf in lbf in Mpsi in^4 psi in^2 J in\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nValue 400 #NAME? 5,000 2.07E+11 25 50 #NAME? 8.00E+10 #NAME? #NAME?\nUnits mm mm N Pa mm mm mm^4 Pa mm^2 mm\nValue 400 5,000 2.07E+11 50 2,000 #NAME?\nUnits mm N Pa mm mm^4 mm\nValue 400 5,000 2.07E+11 8.00E+10 2,000 100 #NAME?\nUnits mm N Pa Pa mm^4 mm^2 mm\nValue 2 1 18.00 7.00 0 0 #NAME? #NAME? #NAME?\nUnits in lbf Mpsi Mpsi in in in^4 in^2 in\n500 #NAME? 1.20 #NAME? 2,942 1.00 3.00 #NAME? 30.00 0.0010 #NAME? #NAME?\nkg N m Nm kg m m Nm Mpsi in^4 J m\n#NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Solve E103 = 0 by changing C97\nValue 0.12 1.00 1.00 30.00 0.0010 #NAME? 7.00 1.00 0.10 #NAME? #NAME? #NAME?\nUnits Nm m N Mpsi in^4 lbf in^2 Mpsi m 1 deg 1 m\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nSolve C119 = 0 by changing C110\nValue 2.50 689.00 203.00 1.00 80,000 0.0378 #NAME? #NAME? #NAME? #NAME? #NAME?\nUnits 1 Mpa Gpa m N m m^2 m N 1 Mpa\nSolve C136 = 0 by changing C131\nValue 2.50 496.00\nUnits 1 Mpa\nMKS Value #NAME? #NAME?\nMKS Units #NAME? #NAME?\n71.00 200.00 80,000 25.0 #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nGpa mm N mm mm^2 mm N 1 Mpa Mpa\n#NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nSolve C146 = 0 by changing C151 Solve C152 = 0 by changing C146\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 6: Failure Theories, Safety Factors, and Reliability Example 6.1 Description Symbol or Formula Su Sy KIc t c w sg = KIc / 1.8 c1/2 P = sg (2 w t) Example 6.2 Description Symbol or Formula Sy KIc t w a a / 2c sg = 0.73 Sy C0 C1 Error Example 6.3 Description Symbol or Formula Sy s1 s2 s3 se = [(s2 - s1) + (s3 - s1)2 + (s3 - s2)2]1/2 / 21/2\nK - sg a\n/ (C0 - C1 (sg / Sy)2)1/2\nFOS = Sy / se Example 6.4 Description Symbol or Formula sx sy sz = (sx2 + sz2)1/2\nf z = N-1(f) mz = |z| sz mx my = mx - mz\nrt M. Marshek\nValue 78.0 70.0 60.0 0.060 0.50 3.00 #NAME? #NAME?\nUnits ksi ksi ksi in^(1/2) in in in ksi lbf\nValue 120.0 65.0 1.0 3.00 0.1992 0.25 #NAME? 0.39 0.053 #NAME?\nUnits ksi ksi in^(1/2) in in in 1 ksi 1 1 ksi in^(1/2)\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Solve C28=0 by changing C23\nValue 100.0 35.0 -25.0 0.0 #NAME? #NAME?\nUnits ksi ksi ksi ksi ksi 1\nValue 1.0 1.5 #NAME?\nUnits Nm Nm Nm\n0.002 #NAME? #NAME? 20.0 #NAME?\n1 1 Nm Nm Nm\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 7: Impact Example 7.1 Description Symbol or Formula Sy V E Ua = Sy2 V / 2 E Ubl = Sy2 (V/2) / 2 E Ubu = (Sy / 4)2 (2V) / 2 E Ubl / Ua Ubu / Ua Example 7.2 Description Soft Steel Symbol or Formula Se V E rg Ua = Sy2 V / 2 E Ua / r g V = Sy2 / 2 E r g Se V E rg Ua = Sy2 V / 2 E Ua / r g V = Sy2 / 2 E r g Se V E rg Ua = Sy2 V / 2 E Ua / r g V = Sy2 / 2 E r g Ua-hard_steel / Ua-soft_steel Ua-rubber / Ua-soft_steel Ua-hard_steel r g V / Ua-soft_steel r g V Ua-rubber r g V / Ua-soft_steel r g V Example 7.3 Description Symbol or Formula P\nL E I k h Z dst-beam = P L3 / 48 E I dst-sprint = P / 2 k dst-total = dst-beam + dst-spring IF = 1 + (1 + 2h / dst)1/2 ddyn-beam = IF dst-beam ddyn-total = IF dst-total Pdyn = IF P Mdyn = Pdyn L / 4 sdyn = Mdyn / Z Example 7.4 Description Symbol or Formula w r t V = p r2 t r m=rV I = (1/2) m r2 U = (1/2) I w2 G rs Ls Vs = p rs2 Ls t = 2 (U G / Vs)1/2 q = t Ls / rs G Example 7.5 Description Symbol or Formula Ki Ki2 Example 7.6 Description Symbol or Formula K0 Ki An / A0 sn / s0 = (Ki / K0) (An / A0)\nUn / U0 = (sn / s0)2 Example 7.7 Description Original -- a Symbol or Formula Ki An / A0 Vn / V0 sn / s0 = (An / A0) / Ki Redesign -- b Ki An / A0 Vn / V0 sn / s0 = (An / A0) / Ki Ub / Ua = s2 V / s2 V\nValue 100.0 1.0 30 #NAME? #NAME? #NAME? #NAME? #NAME?\nUnits ksi in^3 Mpsi J J J 1 1\nValue 207.0 1.0 207 77 #NAME? #NAME? 828.0 1.0 207 77 #NAME? #NAME? 2.0700 1.0 1.0340 9.2 #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nUnits MPa mm^3 Mpa kN/m^3 J J/kg MPa mm^3 Mpa kN/m^3 J J/kg MPa mm^3 Mpa kN/m^3 J J/kg 1 1 1 1\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Value #NAME?\n60.0 1 6.46 100.00 12.00 3.56 #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nin Mpsi in^4 lbf/in in in^3 in in in 1 in in lbf lbf in psi\n#NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nValue 2,400 60.0 20.0 #NAME? 2,000.0 #NAME? #NAME? #NAME? 79.0 10.0 250.0 #NAME? #NAME? #NAME?\nUnits rpm mm mm mm^3 kg/m^3 kg m^4 J Gpa mm mm mm^3 Mpa deg\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nValue 1.5 #NAME?\nUnits 1 1\nValue 1.5 3.0 4.0 #NAME?\nValue 3.5 0.857 1.000 #NAME? 3.0 2.000 0.4286 #NAME? #NAME?\nUnits 1 1 1 1 1 1 1 1 1\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 8: Fatigue Example 8.1 Description Symbol or Formula Su Sy d SN = 0.75 Su S'N = 0.5 Su CL CG CT CR CS Sn = S'N CL CG CS CT CR S10e5 = SN - (2/3) (SN - Sn) S10e4 = SN - (1/3) (SN - Sn) Example 8.2 Description Symbol or Formula Su Sy d A = p d2 / 4 Fmin Fmax Fm = (Fmin + Fmax) / 2 Fa = (Fmax - Fmin) / 2 SF sm = SF Fm / A sa = SF Fa / A sa / sm sa from Fig 8.22 Error sa from Fig 8.22 - sa d Part (a) sa from Fig 8.22 sa from Fig 8.22 - sa d Part (b)\nExample 8.3 Symbol or\nFormula Su Sy Tm Ta FOS D/d r/d d Kt q Kf = 1 + (Kt - 1) q tm = 16 FOS Tm Kf / p d3 ta = 16 FOS Ta Kf / p d3 ta / tm\nCase 1 Error Case 2 Error\nta from Fig 8.27 ta from Fig 8.27 - ta d from Solver ta from Fig 8.27 after yielding ta from Fig 8.27 - ta d from Solver\nExample 8.4 Description Symbol or Formula Su Sy ro T m Ft = T / ro Fn = Ft / m xt Mt = Ft xt xn Mn = Fn xn M = (Mn2 + Mt2)1/2 q Kt(t) q Kf(t) = 1 + (Kt - 1) q Kt(a) q Kf(a) = 1 + (Kt - 1) q Kt(b) q\nKf(b) = 1 + (Kt - 1) q d t = 16 T Kf(t) / p d3 s(a) = 4 Fn Kf(a) / p d2 s(b) = 32 M Kf(b) / p d3 sem = s(a) / 2 + (t2 + s(a)2 / 4)1/2 sea = s(b)2 FOS Example 8.5 Description Symbol or Formula S1 n1 N1 S2 n2 N2 S3 n3 N3 fL = S ni / Ni n = 1 / fL t L=nt Example 8.6 Description Symbol or Formula Sa na Na Sb nb Nb Sc nc Nc Sd nd Nd fL = S ni / Ni n = 1 / fL t L=nt\nExample 8.7 Description Symbol or Formula Y0 a1 I(a1) = (-1/a - 4 ln(a) + 6a - 2 a2 + a3 / 3) / Y04 a2 I(a2) = (-1/a - 4 ln(a) + 6a - 2 a2 + a3 / 3) / Y04 I = I(a2) - I(a1) w dc/ dN DK0 Ds n DN12 I' = (DN12 / w) (dc/dN) (Ds (p w)1/2 / DK0)n\n1/2 n Error: solve C152 = 0 bychanging C151 I' = (DN12 / w) (dc/dN) (Ds (p w) / DK0)\nValue 150.0 120.0 1 #NAME? #NAME? 1.0 0.9 1.0 1.0 0.9 #NAME? #NAME? #NAME?\nUnits ksi ksi in ksi ksi 1 1 1 1 1 ksi ksi ksi\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nValue 150.0 120.0 0.366 #NAME? 1,000 5,000 #NAME? #NAME? 2.00 #NAME? #NAME? #NAME? 38.0 #NAME? 0.366 48.0 #NAME? 0.326\nUnits ksi ksi in in^2 lbf lbf lbf lbf 1 ksi ksi 1 ksi ksi in ksi ksi in\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Solve C37 = 0 by changing C26\nSolve C41 = 0 by changing C26\nValue 1.2 1.0 1,000.00 250.00 2.00 1.20 0.05 29.689 1.57 0.95 #NAME? #NAME? #NAME? #NAME? 116.0 #NAME? 32.345 150.0 #NAME? 29.689\nUnits Gpa Gpa Nm Nm 1 1 1 mm 1 1 1 MPa MPa 1 MPa MPa mm MPa MPa mm\nValue #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nUnits #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Solve C61 = 0 by changing C53\nSolve C64 = 0 by changing C53\nValue 900.0 750.0 100.00 12.00 0.60 #NAME? #NAME? 50.00 #NAME? 100.00 #NAME? #NAME? 0.95 1.10 0.93 #NAME? 1.28 0.91 #NAME? 1.28 0.91\nUnits Mpa Mpa mm Nm 1 N N mm Nm mm Nm Nm 1 1 1 1 1 1 1 1 1\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\n#NAME? 16.00 #NAME? #NAME? #NAME? #NAME? #NAME? 4.00\n1 mm Mpa Mpa Mpa Mpa Mpa 1\n#NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nValue 80.0 5.0 1.00E+05 90.0 2.0 3.80E+04 100.0 1.0 1.60E+04 #NAME? #NAME? 20.0 #NAME?\nUnits ksi 1 1 ksi 1 1 ksi 1 1 1 1 s hr\nValue 120.0 2.0 inf 150.0 4.0 3.50E+06 310.0 2.0 2.00E+04 380.0 1.0 2.50E+03 #NAME? #NAME? 6.0 #NAME?\nUnits Mpa 1 1 Mpa 1 1 Mpa 1 1 Mpa 1 1 1 1 s hr\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nValue 0.9 0.2 #NAME? 0.5 #NAME? #NAME? 30.0 1.00E-06 5.0 40.0 4.0 1.19E+06 #NAME? #NAME?\nUnits 1 1 1 1 1 1 mm mm Mpa m^1/2 Mpa 1 1 1 1\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 9: Surface Damage Example 9.1 Description Symbol or Formula Aplate Arivet Example 9.2 Description Symbol or Formula n r V=rn t S=Vt F Hpin(copper) wpin(copper) Kpin = w H / F S Hdisk(steel) wdisk Kdisk = w H / F S Example 9.3 Description Symbol or Formula F R1 E1 n1 R2 E2 n2 D = (1 - n1 )/E1 + (1 - n22) / E2\np0 = 0.578 (F(1/R1 + 1/R2)2 / D2)1/3\nValue 100.0 1.0\nUnits cm^2 m^2\nValue 80.0 16.0 #NAME? 2.0 #NAME? 20.0 785.0 2.7 #NAME? 2,060.0 0.65 #NAME?\nUnits rpm mm mm/s hr mm N Mpa mm^3 1 Mpa mm^3 1\nValue 2,000.0 5.0 207.0 0.3 -5.1 110.0 0.3 #NAME? #NAME?\nUnits N mm Gpa 1 mm Gpa 1 m^2/N Mpa\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 10: Threaded Fasteners and Power Screws Example 10.1 Description STATIC Double thread Thread depth Symbol or Formula tpi p = 1/ tpi L = 2p dth = p/2 d dm = d - p/2 l = atan(L / p dm) f fstart = (4/3) f fc = f a an = atan(tan(a) cos(l)) W dc = d - p/2 Up Down DYNAMIC Double thread Thread depth T = (W dm / 2) (fstart p dm + L cos(an)) / (p dm cos(an) - fstart L) + W fc dc / 2 T = (W dm / 2) (fstart p dm - L cos(an)) / (p dm cos(an) + fstart L) + W fc dc / 2 tpi p = 1/ tpi L = 2p dth = p/2 d dm = d - p/2 l = atan(L / p dm) f fstart = (4/3) f fc = f a an = atan(tan(a) cos(l)) W dc = d - p/2 Up Down NO FRICTION Double thread Thread depth T = (W dm / 2) (fstart p dm + L cos(an)) / (p dm cos(an) - fstart L) + W fc dc / 2 T = (W dm / 2) (fstart p dm - L cos(an)) / (p dm cos(an) + fstart L) + W fc dc / 2 tpi p = 1/ tpi L = 2p dth = p/2 d dm = d - p/2 l = atan(L / p dm)\nf fstart = (4/3) f fc = f a an = atan(tan(a) cos(l)) W dc = d - p/2 Up Down T = (W dm / 2) (fstart p dm + L cos(an)) / (p dm cos(an) - fstart L) + W fc dc / 2 T = (W dm / 2) (fstart p dm - L cos(an)) / (p dm cos(an) + fstart L) + W fc dc / 2 Eff = Tno_friction / Tactual Example 10.2 Description Symbol or Formula Sp F FOS Fdesign = F FOS A = Fdesign / Sp dM10 X 1.5 AM10 X 1.5 Fi = 0.9 AM10 X 1.5 Sp T = 0.2 Fi dM10 X 1.5 Example 10.3 Description 1/2 in - 13 UNC Grade 5 Symbol or Formula Sp Sy d A Fi-rough = A Sp FOSFi Fi = A Sp / FOSFi m Ff = m F i F = 2 Ff Fshear = 2 (0.58 Sy) p d2 / 4 Example 10.4 Description Symbol or Formula FOS F Fdesign = FOS F FD\nFE ~ FD / 4 xF xE xD S M = xF Fdesign - xE FE - 2 xD FD Sp At = FD / Sp Example 10.5 Description Symbol or Formula A F V s=F/A t=V/A se = (s2 + 3 t2)1/2 Sp Error se - Sp d = (4 A / p)1/2 Example 10.6 Description (a) Symbol or Formula Fmax Kf At sm = sa = Fmax Kf / 2 At Error (b) Sp sa - S Sp At Fi = Sp At d Ab = p d2 / 4 q g Ac = (p / 16) (5 d2 + 6 d g tanq + g2 tan2q) kb / (kb + kc) = Ab / (Ab + Ac) (c) F' = 0.07 Fmax sa = F' Kf / At Example 10.7 Description Symbol or Formula n\nd pmax Fc = pmax p d2 / 4 F = Fc / n g Ab E1 L1 = g / 2 A1 = 5 Ab k1 = A1 E1 / L1 E2 L2 = g / 2 A2 = 5 Ab k2 = A2 E2 / L2 kc = k1 k2 / (k1 + k2) Eb Lb = g kb = Ab Eb / Lb DF = kb F / (kb + kc) F a = DF / 2 Sy At = Fa / Sy M10 X 1.5 Aact Sp Fc = 0.55 Sp A F' = Fc - (F - DF)\nValue 5.0 #NAME? #NAME? #NAME? 1.0 #NAME? #NAME? 0.12 #NAME? #NAME? 14.5 #NAME? 1,000.0 1.5 #NAME? #NAME? 5.0 #NAME? #NAME? #NAME? 1.0 #NAME? #NAME? 0.09 #NAME? #NAME? 14.5 #NAME? 1,000.0 1.5 #NAME? #NAME? 5.0 #NAME? #NAME? #NAME? 1.0 #NAME? #NAME?\nUnits 1/in in in in in in deg 1 1 1 deg deg lbf in lbf in lbf in 1/in in in in in in deg 1 1 1 deg deg lbf in lbf in lbf in 1/in in in in in in deg\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\n0.00 #NAME? #NAME? 14.5 #NAME? 1,000.0 1.5 #NAME? #NAME? #NAME?\n1 1 1 deg deg lbf in lbf in lbf in 1\nValue 380.0 4.5 4.0 #NAME? #NAME? 10.0 58.0 #NAME? #NAME?\nUnits Mpa kN 1 kN mm^2 mm mm^2 kN Nm\nValue 85.0 92.0 0.5000 0.1419 #NAME? 1.59 #NAME? 0.4000 #NAME? #NAME? #NAME?\nUnits ksi ksi in in^2 lbf 1 lbf 1 lbf lbf lbf 1\nValue 6.0 24.0 #NAME? 87.3\nUnits 1 kN kN kN\n#NAME? 500.0 100.0 400.0 #NAME? 650.0 #NAME?\nkN mm mm mm kN mm Mpa mm^2\n#NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Solve C96 = 0 B.C. C91\nValue 255.3 87.3 81.5 #NAME? #NAME? #NAME? 650.0 #NAME? #NAME?\nUnits mm^2 kN kN Mpa Mpa Mpa Mpa Mpa mm\nValue 2,763.3 3.8 0.1419 #NAME? 37.0 #NAME? 85.0 0.1419 #NAME? 0.5000 #NAME? 30.0000 2.0000 #NAME? #NAME? #NAME? #NAME?\nUnits lbf 1 in^2 ksi ksi ksi ksi in^2 lbf in in^2 deg in in^2 1 lbf ksi\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Solve C1212 = 0 BC C116\n250 5.0 #NAME? #NAME? 1 1 100 #NAME? #NAME? #NAME? 70 #NAME? #NAME? #NAME? #NAME? 200 #NAME? #NAME? #NAME? #NAME? 69.0 #NAME? 58.0 0.6 #NAME? #NAME?\nmm Mpa kN kN mm mm^2 Mpa mm mm^2 kN/mm Mpa mm mm^2 kN/mm kN/mm Mpa mm kN/mm kN kN MPa mm^2 mm^2 GPa kN kN\n#NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 11: Rivets, Welding, and Bonding Example 11.1 Description Symbol or Formula FOS L w n A =n L w / 21/2 Sy Ssy = 0.58 Sy F = Ssy A / FOS Example 11.2 Description Symbol or Formula FOS L w n A =n L w / 21/2 Sy Ssy = 0.58 Sy F = Ssy A / FOS Example 11.3 Description Symbol or Formula t L1 A1 = L1 t x1 y1 L2 A2 = L2 t x2 y2 xbar = (A1 x1 + A2 x2) / (A1 + A2) ybar = (A1 y1 + A2 y2) / (A1 + A2) c1 c2 c3 J1 = L13 t / 12 + L1 t (c12 + (c2 - c3)2)\nd1 d2 d3 J2 = L2 t / 12 + L2 t (d12 + (d2 - d3)2) J = J1 + J2 F e1 T = F (e1 - xbar) r t = Tr / J LC VC = F / LC t Sy Ssy = 0.58 Sy FOS FOS - Ssy / VC h = 21/2 t Example 11.4 Description Symbol or Formula F x M=Fx t Lv Iv = Lv3 t / 12 Lh a Ih = Lh t a2 IX = 2Iv + 2Ih c s = M c / IX A = 2 Lv t + 2 Lh t t=F/A se = (s2 + 3 t2)1/2 Sy Ssy = 0.58 Sy FOS FOS - Ssy / se h = 21/2 t Example 11.5 Description Symbol or Formula Fmin\nFmax Fm = 0.5 (Fmax + Fmin) Fa = 0.5 (Fmax - Fmin) L h A=Lh Su Sy FOS Kf CG CT CR CS Sn' = 0.5 Su Sn = CL CG CS CT CR Sn' sa = Kf Fa / A sm = Kf Fm / A sa / sm sm-max Error FOS - sm-max / sm\nValue 3.0 50.0 6.0 2 #NAME? 350 #NAME? #NAME?\nUnits 1 mm mm 1 mm^2 Mpa Mpa kN\nValue 8.6 100.0 #NAME? 50.0 0.0 150.0 #NAME? 0.0 75.0 #NAME? #NAME? 45.0 50.0 20.0 #NAME?\nUnits mm mm mm^2 mm mm mm mm^2 mm mm mm mm mm mm mm mm^4\n20.0 75.0 45.0 #NAME? #NAME? 20.0 300.0 #NAME? 20.0 #NAME? 28.9 #NAME? 345 #NAME? 2.5 #NAME? #NAME?\nmm mm mm mm^4 mm^4 kN mm Nm mm Mpa mm MPa Mpa Mpa 1 1 mm\n#NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nSolve C61 = 0 BC C31\nValue 10.0 160.0 #NAME? 1.94 120.0 #NAME? 70.0 60.0 #NAME? #NAME? 60.0 #NAME? #NAME? #NAME? #NAME? 345 #NAME? 3.0 #NAME? #NAME?\nUnits kN mm kN mm mm mm mm^4 mm mm mm^4 mm^4 mm Mpa mm^2 Mpa Mpa Mpa Mpa 1 1 mm\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nSolve C85 = 0 BC C70\n15,000.0 #NAME? #NAME? 3.16 0.5 #NAME? 62.0 50.0 2.5 1.2 0.8 1.0 1.0 0.55 #NAME? #NAME? #NAME? #NAME? #NAME? 19.00 #NAME?\nlbf lbf lbf in in in^2 ksi ksi 1 1 1 1 1 1 ksi ksi ksi ksi 1 ksi 1\n#NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\n#NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Solve C112 = 0 BC C95\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 12: Springs Example 12.1 Description Symbol or Formula DF Dd k = DF / Dd Fmax CA(%) = Clash Allowance (%) CA = CA(%) Fmax / k Fsolid = Fmax + k CA D d Ks t = 8 Fsolid D Ks / p d3 Su tsolid = 0.45 Su Error Hole diameter Diametral Clearance (b) t - tsolid Dh DC = Dh - (D + d) D d Ks t = 8 Fsolid D Ks / p d3 Su tsolid = 0.45 Su Error Hole diameter Diametral Clearance (c) t - tsolid Dh DC = Dh - (D + d) G N k' = d4 G / 8 D3 N k - k' Nt = N + 2 Ls = Nt d Lfree = Ls + Fsolid / k Fstr Lstr = Lfree - Fstr / k (d) Ls / Lfree Lfree / D\nSymbol or Formula w N t=2pN/ w tmax / tmin tmax FOS FOSsurge tdesign = tmax / FOS FOSsurge Kw C Fmax d = (8 Fmax C Kw / p tdesign)1/2 d CKw = p tdesign d2 / 8 Fmax C D=Cd DF Dx k = DF / D x G N = d G / 8 C3 k Ls = (N + 2) d CA Fs = (1 + CA) Fmax Lf = Ls + Fs / k Lf / D 0.5 N d / Lf C f n = C d / N D2\nExample 12.3 Description Symbol or Formula w N t=2pN/ w tmax / tmin tmax FOS FOSsurge tdesign = tmax / FOS FOSsurge Kw C Fmax d = (8 Fmax C Kw / p tdesign)1/2\nd CKw = p tdesign d2 / 8 Fmax C D=Cd DF Dx k = DF / D x G N = d G / 8 C3 k Ls = (N + 2) d CA Fs = (1 + CA) Fmax Lf = Ls + Fs / k Lf / D 0.5 N d / Lf C f n = C d / N D2 Example 12.4 Description Symbol or Formula Fm Fa L b h Kf sa = 6 Fa L Kf / b h2 sm = 6 Fm L Kf / b h2 sa / sm sa-max k E k' = E b h3 / 3 L3 (sa-max - sa)2 + (k - k')2\n(Sum of errors)2 Example 12.5 Description\n(a) -- Triangle\n(b) -- Triangle\nSymbol or Formula E F h b L d = 6 F L3 / E b h3 k=F/d b L\nd = 6 F L3 / E b h3 kt = F / d (b) -- Rectangle b L d = 4 F L3 / E b h3 kr = F / d kb = kr + kt kb / k\nValue 45.0 0.5 #NAME? 105 10% #NAME? #NAME? 1.25 0.156 1.05 #NAME? 225.0 #NAME? #NAME? 1.5 #NAME? 1.15 0.157 1.05 #NAME? 225.0 #NAME? #NAME? 1.5 #NAME? 11.5 6.36 #NAME? #NAME? #NAME? #NAME? #NAME? 60 #NAME? #NAME? #NAME?\nUnits lbf in lbf/ in lbf 1 in lbf in in 1 ksi ksi ksi ksi in in in in 1 ksi ksi ksi ksi in in Mpsi 1 lbf/ in lbf/ in 1 in in lbf in 1 1\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Solve C29 = 0 BC C24 Solve C20 = 0 BC C15\nSolve C35 = 0 BC C33\nValue 650.0 1,000,000.0 #NAME? 0.5 800.0 1.10 1.10 #NAME? 1.14 10.00 600.0 #NAME? 5.0 #NAME? 9.40 #NAME? 300.00 25.00 #NAME? 79.00 #NAME? #NAME? 0.10 #NAME? #NAME? #NAME? #NAME? 13,900.00 #NAME?\nUnits rpm 1 hr 1 MPa 1 1 MPa 1 1 N mm mm 1 1 mm N mm N/mm Gpa 1 mm 1 N mm 1 1 Hz in Hz\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nValue 650.0 1,000,000.0 #NAME? 0.5 750.0 1.13 1.10 #NAME? 1.14 10.00 600.0 #NAME?\nUnits rpm 1 hr 1 MPa 1 1 MPa 1 1 N mm\n5.0 #NAME? 9.40 #NAME? 300.00 25.00 #NAME? 79.00 #NAME? #NAME? 0.10 #NAME? #NAME? #NAME? #NAME? 13,900.00 #NAME?\nmm 1 1 mm N mm N/mm Gpa 1 mm 1 N mm 1 1 Hz in Hz\nValue 3,000.0 2,000.0 679.8 412.2 7.0 1.3 #NAME? #NAME? #NAME? 525.0 30.0 200.0 #NAME? #NAME?\nUnits N N mm mm mm 1 Mpa Mpa 1 Mpa N/mm Gpa N/mm\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Min C126 by chanign C115, C116\nValue 30.0 1.0 25.0 416.0 682.0 #NAME? #NAME? 333.0 682.0\nUnits Mpa N mm mm mm mm N/mm mm mm\n#NAME? #NAME? 83.0 682.0 #NAME? #NAME? #NAME? #NAME?\nmm N/mm mm mm mm N/mm N/mm 1\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 13: Lubrication and Sliding Bearings Example 13.1 Description Eqn 13.6a constants Symbol or Formula r0 T0 C0 T r = r0 - C0 (T - T0) Eqn 13.4 constants b0 d0 S m = (b0 S - d0 / S) r m Example 13.2 Description Symbol or Formula m n R c F L P=F/2RL f=pmnR/Pc T=fFR Power = T n\nExample 13.3 Description Symbol or Formula D R c n W L P=W/2RL m S = (R/c)2 (m n / 2 p P) h0 / c h0 = (h0 / c) c (R/c) f f = (R/c) f (c / R) P / pmax\nFig 13.13 Fig 13.14 Fig 13.15\nFig 13.16 Fig 13.17 Fig 13.17 Fig 13.18 Fig 13.19 Example 13.4 Description\npmax = P / (P / pmax) f qp0 qpmax Q / R c (n / 2p) L Q = (Q / R c n L) R c (n / 2p) L Qs / Q\nSymbol or Formula P W R L=W/2RP L L/D = L / 2 R m n Slo chi S = (R/c)2 m n / P S - Slo Shi clo S = (R/c)2 m n / P S - Shi f Tf = W f R Hf = T f n Qs cr Dt = Hf / Qs cr\nValue 0.890 15.6 0.00063 100.0 #NAME? 0.220 180.0 58.0 #NAME? #NAME?\nUnits g/cm^3 degC g/cm^3 degC degC g/cm^3 cp cm^3 / s g cp s cm^3 / g s cp reyn\nValue 0.050 10.0 50.0 0.05 5,000.00 80.00 #NAME? #NAME? #NAME? #NAME?\nUnits Pa s rps mm mm N mm Mpa 1 Nm W\nValue 2.000 1.0 0.0015 50.0 1,000 1.0 #NAME? 4.00E-06 #NAME? 0.30 #NAME? 5.40 #NAME? 0.32\nUnits in in in rps lbf in psi reyn 1 1 in 1 1 1\n#NAME? 40.00 54.00 16.90 5.15 #NAME? 0.81\npsi deg deg deg 1 in^3/s 1\nValue 1.511 17,000 75 #NAME? 75 #NAME? 6.30 30.0 0.037 0.138 #NAME? #NAME? 0.350 0.0448 #NAME? #NAME? 0.0053 #NAME? #NAME? 2.15E-05 1.36E+06 #NAME?\nUnits MPa N mm mm mm 1 cp rps rps mm 1 1 rps mm 1 1 1 Nm kW m^3/s N/m^2 degC degCdiff\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Solve C71 = 0 BC C69\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 14: Rolling-Element Bearings Example 14.1 Description Symbol or Formula n Fr Ft Fe-radial = Fr (1 + 1.115 (Ft / Fr - 0.35)) Fe-angular = Fr (1 + 0.870 (Ft / Fr - 0.68)) Table 14.3 Table 14.4 Ka T L=nT Kr Lr Creq-radial = Fe-radial Ka (L / Kr LR)0.3 Creq-angular = Fe-angular Ka (L / Kr LR)0.3 Example 14.2 Description Symbol or Formula Fr Ft Fe = Fr (1 + 1.115 (Ft / Fr - 0.35)) C T Rel Ka Kr n Lr L = Kr LR (C / Fe Ka)3.33 T' = L / n L' Kr = L' / LR (C / Fe Ka)3.33 Example 14.3 Description Symbol or Formula Fr Ft Fe = Fr (1 + 1.115 (Ft / Fr - 0.35)) C Kr\nLr Ka Fr-1 L1 = Kr LR (C / Fr Ka)3.33 Fr-2 L2 = Kr LR (C / Fr Ka)3.33 Fr-3 L3 = Kr LR (C / Fr Ka)3.33 w X n1 = 0.5 w X n2 = 0.3 w X n3 = 0.2 w X Error 1 - S ni / Li\nValue 1,800.0 1.200 1.500 #NAME? #NAME? 1.500 30,000 #NAME? 1.000 9.00E+07 #NAME? #NAME?\nUnits rpm kN kN kN kN 1 hr rev 1 rev kN kN\nValue 1.200 1.500 #NAME? 12.0 30,000 90% 1.5 1.0 1,800.0 9.00E+07 #NAME? #NAME? 3.24E+09 #NAME?\nUnits kN kN kN kN hr 1 1 1 rpm rev rev hr rev 1\nValue 1.200 1.500 #NAME? 8.5 1.0\nUnits kN kN kN kN 1\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME?\n9.00E+07 1.0 3.000 #NAME? 5.000 #NAME? 7.000 #NAME? 1,000.0 5.24E+05 #NAME? #NAME? #NAME? #NAME?\nrev 1 kN rev kN rev kN rev rpm hr rev rev rev 1\n#NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\n#NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Solve C59=0 BC C55\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 15: Spur Gears Example 15.1 Description Symbol or Formula c P f wp / wg rg / rp = - wp / wg rp rg = rp (rg / rp) Error err = rg + rp - c Np = 2 r p P Ng = 2 r g P rbp = rp cos(f) rbg = rg cos(f) ra = (rbg2 + c2 sin2f)1/2 ap ag pb = 2 p rbg / Ng rap rbp = rp cos(f) rag CR = [ (rap - rbp ) Example 15.2 Description Symbol or Formula Na P da = Na / P na v = na da / 2 Wdot Ft = Wdot / v f Fr = Ft tan(f) Vcb = Ft Hcb = Vcb tan(f) Fg = Vcb + Hcb F = 21/2 Fg\nrbg 2 1/2\n= rg cos(f)\n+ (rag2 - rbg2)1/2 - c sin(f) ] / pb\nExample 15.3 Description Symbol or Formula Sug S'ng = Sug / 4 Sup S'np = Sup / 4 CL CG CSg CSp kr kt kms Sng = CL CG CSg kr kt kms S'ng Snp = CL CG CSp kr kt kms S'np P b Jg Jp Ng w v = (Ng / P) w / 2 Kv Ko Km Ft sg = Ft P Kv Ko Km / b Jg Error sg - Sng HP = Ft v Ft sp = Ft P Kv Ko Km / b Jp Error sp - Snp HP = Ft v\nExample 15.4 Description Symbol or Formula Bhn C0 C1 Sfe = C0 Bhn - C1 S'fe\nL w N=Lw CLi CR SH = Sfe CLi CR Cp b dp Kv Ko Km f R = dg / dp I = 0.5 sin(f) cos(f) R / (1 + R) Ft sH = Cp (Ft Kv Ko Km / b dp I)1/2 Error sH - SH v HP = Ft v\nExample 15.5 Description Symbol or Formula w L N=Lw Nfullpower = N / 10 P Np dp = Np / P v = w dp / 2 Kv Ko Km HP Ft = HP / v f R = dg / dp I = 0.5 sin(f) cos(f) R / (1 + R) SH = Sfe CLi CR Cp b = 14 / P FOS sH = Cp (FOS Ft Kv Ko Km / b dp I)1/2 sH - SH\nP Np dp = Np / P v = w dp / 2 Kv Ko Km HP Ft = HP / v f R = dg / dp I = 0.5 sin(f) cos(f) R / (1 + R) SH = Sfe CLi CR Cp b = 14 / P FOS sH = Cp (FOS Ft Kv Ko Km / b dp I)1/2 J s = Ft P Kv Ko Km / b J CL CG CS kr kt kms S'n = s / CL CG CSg kr kt kms\nValue 4.0 6.0 20.0 -3.0 #NAME? 1.00 #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? 0.060 0.290 #NAME? 1.290 #NAME? 3.060 #NAME? #NAME?\nUnits in 1/in deg 1 1 in in in 1 1 in in in in in in in in in in 1\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Solve C14 = 0 by changing c12\nValue 12.0 3.0 #NAME? 600.0 #NAME? 25.0 #NAME? 20.0 #NAME? #NAME? #NAME? #NAME? #NAME?\nUnits 1 1/in in rpm ft/min hp lbf deg lbf lbf lbf lbf lbf\nValue 290.0 #NAME? 330.0 #NAME? 1.0 1.0 0.70 0.68 0.814 1.0 1.4 #NAME? #NAME? 10.0 1.25 0.280 0.235 18.000 1,720.000 #NAME? 1.68 1.25 1.60 602.44 #NAME? #NAME? #NAME? 558.93 #NAME? #NAME? #NAME?\nUnits ksi ksi ksi ksi 1 1 1 1 1 1 1 ksi ksi 1/in in 1 1 1 rpm ft/min 1 1 1 lbf ksi ksi hp lbf ksi ksi hp\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Solve C77=0 BC C75 Solve C74=0 BC C72\nValue 330.0 0.4 10.0 #NAME? 114.0\nUnits 1 ksi ksi ksi ksi\n10,000.0 1,720.0 #NAME? 0.8 1.0 #NAME? 2,300.0 1.3 1.8 1.68 1.25 1.60 20.0 2.00 #NAME? 129.18 #NAME? #NAME? 810.53 #NAME?\nhr rpm rev 1 1 ksi psi^1/2 in in 1 1 1 deg 1 1 lbf ksi ksi ft/min hp\n#NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Solve C106 = 0 BC C104\nValue 3,600.0 10,000.0 #NAME? #NAME? 7.22 18.0 #NAME? #NAME? 1.40 1.00 1.30 100.00 #NAME? 20.0 4.00 #NAME? 165.00 2,300.0 #NAME? 1.25 #NAME? #NAME?\nUnits rpm hr rev rev 1/in 1 in ft/min 1 1 1 hp lbf deg 1 1 ksi psi^1/2 in 1 ksi ksi\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Solve C133=0 BC C117\n7.00 18.0 #NAME? #NAME? 1.50 1.00 1.30 100.00 #NAME? 20.0 4.00 #NAME? 165.00 2,300.0 #NAME? 1.25 #NAME? 0.235 #NAME? 1.0 1.0 1.00 0.897 1.0 1.4 #NAME?\n1/in 1 in ft/min 1 1 1 hp lbf deg 1 1 ksi psi^1/2 in 1 ksi 1 ksi 1 1 1 1 1 1 ksi\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 16: Helical, Bevel, and Worm Gears Example 16.1 Description Symbol or Formula fn y f = atan(tan(fn) / cos(y)) Pn P = Pn cos(y) Np dp = Np / P np ng Np = Np (np / ng) dg = Ng / P vp = np dp / 2 Wdot Ft = Wdot / v Fr = Ft tan(f) Fa = Ft tan(y) p=p/P pa = p / tan(y) b = 1.5 pa Example 16.2 Description Symbol or Formula nw ng nw / ng (double) Ng = 2 (nw / ng ) p dg = p Ng / p c dw = 2c - dg L l = atan(L / p dw) vw = nw dw / 2 Wdot Fwt = Fga = Wdot / vw Fig 16.23 vs = vw / cos(l) f\nfn Fgt / Fwt = [cosfn cosl - f sinl] / [cosfn sinl + f cosl] Fgt = Fwa = Fwt (Fgt / Fwt ) Fgr = Fwr = Fgt sinfn / [cosfn cosl - f sinl] e = [cosfn - f tanl] / [cosfn + f cotl] Wout = Wdot e SL = cosfn tanl SL > f => not self locking\nExample 16.3 Description Symbol or Formula nw ng Ng / Nw = ww / wg Ng Nw fn p dg = p Ng / p c dw = 2c - dg L = Nw p l = atan(L / p dw) vg = ng dg / 2 Fig 16.23 vs = vg / cos(l) f e = [cosfn - f tanl] / [cosfn + f cotl] b Fd / Fgt Sn y Fs = Sn b p y Fd = Fs Fgt = Fd / (Fd / Fgt ) Wdotg = Fgt vg Kw Fw = dg b Kw Fd = Fw Fgt = Fd / (Fd / Fgt ) Fig 16.25 Wdotg = Fgt vg C a0 A = a0 c1.7\nDT H = C A DT\nValue 20.0 30.0 #NAME? 14.0 #NAME? 18 #NAME? 1,800.0 600.0 #NAME? #NAME? #NAME? 0.5 #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nUnits deg deg deg 1/in 1/in 1 in rpm rpm 1 in ft/min hp lbf lbf lbf in in in\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nValue 1,200.0 60.0 #NAME? #NAME? 0.625 #NAME? 5.000 #NAME? 1.250 #NAME? #NAME? 2.0 #NAME? #NAME? 0.026\nUnits rpm rpm 1 1 in in in in in deg ft/min hp lbf ft/min 1\n14.5 #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\ndeg 1 lbf lbf 1 hp 1\nValue 1,200.0 #NAME? 11.0 44.0 4.0 25.0 0.750 #NAME? 6.125 #NAME? #NAME? #NAME? #NAME? #NAME? 0.027 #NAME? 1.0 1.25 24.00 0.15 #NAME? #NAME? #NAME? #NAME? 180.00 #NAME? #NAME? #NAME? #NAME? 45.00 0.30 #NAME?\nUnits rpm rpm 1 1 1 deg in in in in in deg ft/min ft/min 1 1 in 1 ksi 1 lbf lbf lbf hp lbf/in^2 lbf lbf lbf hp lbf / ft / min / degFdiff ft^2 / in^1.7 ft^2\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 17: Shafts and Associated Parts Example 17.1 Description Symbol or Formula Pengine v FT = Pengine / v Rs RC F C = F T RC / Rs Su Sy D/d r/d Kt-bend q Kf-bend = 1 + (Kt - 1) q Kt-tors q Kf-tors = 1 + (Kt - 1) q Mx My M = (Mx2 + My2)1/2 d s = 32 M Kfb / p d3 T t = 16 T Kft / p d3 s/t FOS S Sdesign = S / FOS Error Sdesign - s d D = d (D/d) r = d (r/d)\nValue 20.0 20.0 #NAME? 50.0 125.0 #NAME? 530.0 450.0 1.25 0.03 2.25 0.70 #NAME? 1.80 0.70 #NAME? 130.00 75.00 #NAME? 35.15 #NAME? 125.00 #NAME? #NAME? 2.50 165.00 #NAME? #NAME? 40.00 #NAME? #NAME?\nUnits kW m/s kN mm mm kN MPa Mpa 1 1 1 1 1 1 1 1 kN mm kN mm kN mm mm MPa kN mm MPa 1 1 MPa MPa MPa mm mm mm\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Solve C34 = 0 BC C26\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 18: Clutches and Brakes Example 18.1 Description Symbol or Formula T pmax ri ro f N = T / p pmax ri f (ro2 - ri2) Nact FOS = Nact / N p'max = pmax / FOS N' = T / p p'max ri f (ro2 - ri2) F = 2 T / f (ro + ri) N' Example 18.2 Description (b) Symbol or Formula F H25 = 4 F V25 = F H45 = 4 F (c) (d) H34 = 4 F H63 = 10.53 F V63 = 2.11 F H13 = 6.53 F V13 = 2.11 F (e) H62 = 7.07 F V62 = 1.41 F H12 = 3.07 F V12 = 2.41 F (f) H61 = 3.46 F V61 = 0.7 F R T = 3.52 F R q w A = w 2 R sin(q/2) P3 = H63 / A pmax Error pmax - P3\nFb = (H612 + V612)1/2 Example 18.3 Description Symbol or Formula x1 x2 f = atan(x2 / x1) q1 = f - p / 4 q2 = q1 + p / 2 d = (x12 + x22)1/2 (sinq)max pmax b r d Mn = -pmax b r d [2(q2 - q1) - sin2q2 + sin2q1] / 4 (sinq)max f Mf = f pmax b r [r (cosq1 - cosq2) +(d/4)( cos2q2 - cos2q1)] / (sinq)max T = - r2 f b pmax [cosq1 - cosq2] / (sinq)max n v=fn (pmax v) p'max = (pmax v) / v c F = (Mn + Mf) / c pmax2 Self-energizing - Fc + (pmax2 / pmax) (Mn - Mf) pmax3 T' = (pmax2 / pmax3) T Wdot = n T' Example 18.4 Description Symbol or Formula pmax r b P1 = pmax r b f f P2 = P1 / eff T = (P1 - P2) r a s\nc F = (P2 a - P1 s) / c sSL FSL = (P2 a - P1 sSL) / c\nValue 85.0 1,400.0 29.0 50.0 0.1 #NAME? 8.0 #NAME? #NAME? #NAME? #NAME?\nUnits Nm kPa mm mm 1 1 1 1 kPa 1 N\nValue 1,074.4 #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? 250.0 #NAME? 90.0 80.0 #NAME? #NAME? 0.4 #NAME?\nUnits N N N N N N N N N N N N N N N mm Nm deg mm mm^2 Pa N/mm^2 Pa\nMKS Value #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Solve C44 = 0 BC C22\nValue 150.0 200.0 #NAME? #NAME? #NAME? #NAME? 1.0 445.6 50.0 150.0 250.0 #NAME? 0.3 #NAME? #NAME? 300.0 #NAME? 2.1 #NAME? 500.0 #NAME? 391.7 #NAME? 445.6 #NAME? #NAME?\nUnits mm mm deg deg deg mm 1 kPa mm mm mm Nm 1 Nm Nm rpm m/s Mpa m / s kPa mm N kPa Nm kPa Nm kW\nMKS Units #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? Solve C72=0 BC C71\nValue 0.5 250.0 80.0 #NAME? 0.2 240.0 #NAME? #NAME? 150.0 35.0\nUnits MPa mm mm kN 1 deg kN Nm mm mm\n700.0 #NAME? 64.9 #NAME?\nmm Nm mm Nm\n#NAME? #NAME? #NAME? #NAME? Solve C93 = 0 BC C92\nChangeUnits 2006 Fundamentals of Machine Component Design by Robert C. Juvinall and Kurt M. Marshek Chp 19: Miscellaneous Machine Components Example 19.1 Description Symbol or Formula Wdot n b r d f Fmax f P1 = Fmax v=nd/2 Pc = r v2 P2 = Pc + (P1 - Pc) / eff / sinb T = (P1 - P2) d / 2 Wdot' = n T N = Wdot / Wdot' Value 25.0 1,750.0 18.0 0.012 3.7 165.0 150.0 0.2 #NAME? #NAME? #NAME? #NAME? #NAME? #NAME? #NAME?\nUnits hp rpm deg lbm / in in deg lbf 1 lbf in/s lbf lbf lbf in hp 1\nDokumente ähnlich wie Juvinall Fundamentals of Machine Component Design\nChapter 8 Fundamentals of Heat and Mass transfer 7th edition\nProblemas Cap 2 33-47\nMACHINE COMPONENTS DESIGN CHAPTER 6\nfundamentals of machine elements sm ch 02\nDesign of Machine Elements Vijayaragavan\nTutorial 3 - Gear Calculations\nr05320304-Dynamics of Machinery\nTechnical Note Immersed Boundary Method Body Force for Flow Around Thin Bodies With Sharp Edges\nReview of Methodologies for Composite Material Modelling Incorporating Failure\nLever Worksheet 03\nMakalah Bahasa Inggris - STATIC FLUID\nStrength of Materials I - Lecture Notes, Study Materials and Important questions answers\nWorkshop II MicMacFEA Jan14\nExam03 Sol f12\nMuh Zulkarnain Syah\nFluid Mechanics Lab Venturi Meter


Bill - 2019 WI A.B. 951\nLaw Number - 2019 WI A.B. 951


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Madaxweynaha oo ku Amray Hayadaha Amniga inay ka soo Warbixiyaan Dilkii Xildhibaan Xayd | Radio Codka Qaranka\nMadaxweynaha oo ku Amray Hayadaha Amniga inay ka soo Warbixiyaan Dilkii Xildhibaan Xayd\nPublished on July 3, 2014 by Codka · No Comments\nNumber of View: 5Muqdisho (Codka Qaranka) Madaxeweynaha jamhuuriyadda federaalka Soomaaliya Mudane Xasan Sheekh Maxamuud oo ka hadlay dilkii maanta magaaladda Muqdisho loogu geystay Allaha u naxariistee marxuum xildhibaan Maxamed Maxamuud (Xayd) oo ka mid ahaa Xlidhibaanadda Baarlamaanka Federaalka Soomaaliya iyo askarigii ilaalada ahaa ee la socday.\n“Hey’adaha Ammaanka ee ay shaqadoodu tahay inay ka hortagaan falkaan oo ay kooxaha nabad diidku sameyeen nooca ay doonaanba ha ahaadeene waa inay sababtu soo cadeeyaan. Hey’adaha amniga waa inay sameeyaan baaritaan natiijadiisu aan ka sugi doono. Shacabka Soomaaliyeed uma dulqaadan karo sii socoshada dilalka qorsheysan ee kooxaha naf lacaariga ah sameynayaan” ayuu yir madaxweynaha.\nThis is the POST COLUMN and is ready for widgets, click here to add some now! Copyright © 2012 danshacab.com> All Rights Reserved. Designed by : Eawhost Ltd


Diiwaanka Cannabis • Dawooyinka Inc.eu\nBogga ugu weyn Tags Qoraalada lagu calaamadeeyay "cannabis"\n2018 waa sanadka isbedelka weyn ee waaxda xashiishadda. Isticmaalka madadaalada ee xashiishadda ayaa sharci ka heshay Kanada iyo dhowr gobol oo Mareykanka ah. Luxembourg waa waddankii ugu horreeyay ee Yurub ee si buuxda sharci u siiya xashiishadda. Intaa waxaa u dheer, Thailand ayaa sharciyeysay iibinta iyo adeegsiga marijuanaada caafimaadka. Nederland gudaheeda, tijaabada haramaha ee degmooyin kala duwan ayaa wax waliba sii socdaan. Sharciyeynta xashiishadda cannabis waxay abuurtaa aragti dheeri ah oo ku saabsan isticmaalka, tayada waxsoosaarka waxayna ka saartaa dariiqa mareega dambiga. Xalka suuq geyn dawladu leedahay oo dawladu leedahay waa xalka?\nalbaabka Ties Inc. June 22 2022\nWasiirka waxbarashada Trinuch Thienthong ayaa sheegay in uu ka walaacsan yahay saameynta ay ku yeelan karto ardayda…\nalbaabka Ties Inc. June 21 2022\nCilmi-baaris dhowaan lagu daabacay The American Journal of Psychiatry waxay si dhow ula socotay ku dhawaad 1.000…\nBooliiska Amsterdam ayaa xashiishad ka helay baaskiil xamuul waxayna dhexda u galeen €400.000 oo caddaan ah\nalbaabka Ties Inc. June 3 2022\nBooliska Amsterdam ayaa xiray labo tuhmane oo ka ganacsanayay daroogada, waxaana ay heystaan tiro badan oo…\ncannabisCaafimaadkaWararkaSharci dejinta & Sharci dejinta\nalbaabka Ties Inc. 31 May 2022\nNederlaan - Tiro kooban oo bukaanno ah ayaa si sharci ah u helaya xashiishadda cannabis booqasho…\nTikTok waxay leedahay maya xayaysiisyada xashiishadda\nalbaabka Ties Inc. 28 May 2022\nKadib sharciyeynta xashiishadda, maamulayaasha New York waxay sii daayeen macluumaadka caafimaadka iyo badbaadada.…\nIibinta xashiishadda New Jersey waxay keenaysaa $24 milyan bishii ugu horreysay\nalbaabka Ties Inc. 27 May 2022\nTan iyo markii iibinta marijuanaada madadaalada ee sharciga ah ay bilaabatay Abriil 21, kuwa bixiya xashiishadda ayaa…\ncannabisDambiWargeysyada caalamiga ah ee cannabis\n€2,8 milyan oo xashiishad ah ayaa lagu qabtay Rosslare Europort\nalbaabka Ties Inc. 26 May 2022\nKu dhawaad 140 kiilogaraam oo xashiishad ah ayaa lagu qabtay Rosslare Europort ee dalka Ireland iyadoo…


SIDEE LOOGA XUSAY 18 MAY GUUD AHAAN NORWAY GARA AHAN OSLO | Toggaherer's Weblog\nXAFALAD AAD LOO SOO AGAASIMAY OO KA DHACADAY QASRIGA MADAXTOOYADA S/L\nSIDEE LOOGA XUSAY 18 MAY GUUD AHAAN NORWAY GARA AHAN OSLO\nOslo 18 May 2009 (THN)\nWaxaa Magaala madaxda dalka Norway Oslo looga dabaal degay xuska sanadguurada 18-ka May sanadkan si ka duwan sidii sanadadii hore.\nSanadkan xuska munaasabadani wuxuu socday muddo sadex cisho ah oo ka soo bilaabmay maalintii sabtidii ay bishu ahayd 16-kii May iyadoo lagu soo afjaray shalay oo Isniin ahayd bishuna ahayd 18-kii May xafladii abid u weyneed ee loo qabto Somaliland.\nGelinkii hore ee sabtinimo waxaa la qabtay koob kubada cagta ah oo ay ka soo qeyb galeen 12 kooxood oo ka kala socday ciyaartoyga ku dhaqan dalka Norway iyagoo halka ku soo bandhigay ciyaar heer sare ah.\nKoobkii sanadkan lagu xusayey 18-ka May waxaa hantay kooxda Qaran kuwaasoo ku mutaystay cayaar wanaag aad u hufan.\nIsla habeenimadii axadu soo galaysay waxaa la qabtay xaflad isugu jirtay khudbado iyo maaweelo, waxaa halkaa ka hadlay Safiirka Somaliland u fadhiya Norway Mr. Maxamed Aden, Gudoomiyaha Jaliyada Norway Mr. Xuseen Cadib iyo xubno badan oo ahaa indheer garadka Jaaliyada ku dhaqan dalka Norway, waxaa xidhiidhiye ka ahaa Mr. Aden Looshade oo isaguna kaalinta xidhiidhinta bilad sharaf ku mutaystay habeenkaas.\nHadaba reer Norway intaasoo keli ah kumay ilaabin Xuska maalinta taariikhiga ahe waxay go’aansadeen bal sanadkan inay qadiyada Somaliland dibada soo dhigaan oo hool dhexdii ahaan jirtay intii hore, waxaana la go’aansaday in maalinta 18-ka May lagu qabto xaflad aad u balaadhan badhtamaha magaalada caasimada Norway Oslo.\nShalay oo bishu ahayd 18-ka May ayaa subixii hore roob laxaad lehi ka curtay samada magaalda Oslo kaasoo halis geliyey hirgalinta heshiiskii reer Norway ee ahaa in magaalada barta ugu socodka badan lagu qabto xafladan iyadoo roobkii istaagi waayey awgeed.\nWaxaa xusid mudan inaan khadka taleefanka kula xidhiidhay Gudoomiyaha jaaliyada Mr. Xuseen Cadib weydiiyeyna sida ay u qabsoomi karto xafladu maadaama roobkii joogsan waayey, Xuseen wuxuu iigu jawaabay walaal halganka Somaliland loo Soo maray ragbaa rasaasta isku dhigayey inagana maanta roob ina joojin maayo.\nHadaba goor sheegtadu markay ahayd shantii galabnimo, daruuruhuna aad moodo inay is dhiibeen markii loo joojin waayey ayaa laga bilaabay barta halbawlaha magaalada xaflad si heer sare ah loo soo maamulay oo dhamaan guddida jaaliyada,Safaarada iyo wax garadka reer Norway ay cudud isugu geeyeen.\nMidho dhalkii wada shaqeentaas waxaa ka dhashay xaflad aan la arag hore.\nWaxaa halkaa isugu yimid tiradii ugu badneed ee xaflad isugu timaada abid, waxaana suuqa magaalada meel walba aad ku arkaysay Calanka Tawxiidka ee Somaliland oo ka babanaya, dadka is dhaaf-dhaafayaa waxay isku bariidinayeen oodhaahda Ciid-Wanaagsan iyaga oo wada qiireysan ayeey calamada isku Salaamayeen.\nWaxaa kale oo xusid mudan in maamulkii suurta geliyey qabsoomida xafladani ay uga soo baxeen howshoodii sidii la rabay iyo si ka badan, waxaana halkaa lagu hantay dhegaha shicibka u dhashay dalka Norway oo intooda badan aan waxba ka ogeyn qadiyada Somaliland iyadoo qof kasta oo Norwiiji ah loo qeybiyay waraaqo ku qoran afka Norwiijiga ah oo ka hadlaya qadiyada Somaliland iyo sababta maanta loo dabaal degayo, waxaa kaloo ka soo qeyb galay munaasibadaa Tv-yada iyo jaraayidka Norway Ka soo baxa qaar ka mid ah, kuwaasoo ii sheegay maraan wax ka weydiiyey Xaflada inay aad ula dhacsan yihiin sida dadka reer Somaliland ay uga dhab tahay qadiyada Somaliland.\nWaxaa halkaa ka khudbadeeyay siyaasiyiin Norwiiji ah oo ka kala socday Xisbiyada Venstre-ha iyo SV, kuwaasoo sheegay inay Qadiyada Somaliland wax ka qaban doonaan.\nHadaba waxaan idiin soo wadnaa sawiradii xafladaha dabaal dega ee reer Norway iyo vidoe maqal iyo muuqaal ah oo aanu ka soo duubnay munaasibada taariikhiga ah.\nAlla mahad leh,,,\nC/raxman Cali Xassan.


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Dhageyso:-Xidigle dhibane ah oo fariin u dirtay Madaxweynaha Somaaliya+Sawirro | Radio Danan (DBN) 94 FM\nDowladda Soomaaliya oo mar kale ka hadashay mowqifkeeda ku aaddan DP World\nDhagayso:Warka Habeen Radio Danan ee Magaalada Muqdisho 18-03-2018\nRa’iisul Wasaare Khayre oo kormeer ku tagay Xarumo Ciidan oo ku yaalla Magaalada Muqdisho\nHoggaannada Ciidanka Xoogga Dalka oo is badalay lagu sameeyay\nMuhaajiriin fara badan oo la sheegay in ay ku dhinteen Xeebaha Dalka Gariigga\nCiidamada Dowlada oo Howlgal Dad badan lagu soo qabtay ka sameeyay Duleedka M/Muqdisho\nMadaxweyne Farmaajo oo ka baaqday Safar uu Maanta ku aadi lahaa Dalka Qadar\nR/Wasaare ku-xigeenka Dalka oo booqasho ku tagay Wasaaradda Warfaafinta (Sawirro)\nSawirro:Masar oo deeq Dawo ah ku wareejisay Wasaaradda Caafimaadka Soomaaliya\nHome / WARARKA / Dhageyso:-Xidigle dhibane ah oo fariin u dirtay Madaxweynaha Somaaliya+Sawirro\nDhageyso:-Xidigle dhibane ah oo fariin u dirtay Madaxweynaha Somaaliya+Sawirro\nPosted by: DBN in WARARKA, WARARKA CAALAMKA, WAREYSIYO November 7, 2016\tComments Off on Dhageyso:-Xidigle dhibane ah oo fariin u dirtay Madaxweynaha Somaaliya+Sawirro\nFaa izo Cabdirashiid Cabdi Waa Xidigle ka tirsan Xoogga dalka Somaaliya waxayna hada dhibane ku tahay Isbitaal ku yaalo dalka turkiga markii ay shil ku gashay qeybo kamid ah gobolka Shabeelaha hoose 27 bishii la soo dhaafay ee Simtember xili ay ka soo laabatay mushaar qeybin ay ka soo sameyay ciidamo ka tirsan dowladda Somaaliya oo ku sugan Garoonka Diyaaradaha ee Bali-doogle e gobolka Shabeelaha hoose.\nFaa,izo oo weli ay ka muuqdaan dhaawicii cuslaa ee ka soo gaaray Shilkaas ayaa iyadoo ku jirta Isbitaal ku yaalo dalka turkiga Danan u sheegtay in marka loo fiiriyo waqtigaan xaaladeyda ay sidii hore ka wanagsan tahay balse ay jiraan xanuuno kale oo soo boodo ah oo u baahan in wax laga qabto.\nMarka laga soo tago in ay jirtay in madaxda qaarkood ay ku booqdeen intii ay ku jirtay isbitaalka Digfeer ee maagalda Muqdisho ayaa hadana Faa’izo waxay weli u baahan tahay daryeel Cafimaad iyadoo fariin u dirtay madaxda ugu sareysa dalka Somaaliya.\nInta badan Ciidanka xoogga dalka ayaa ku shaqeeya duruufo adag ayaa hadana marka ay soo gaaraan waxyeelo aysan helin cid daryeesho dowladii ay ka tirsanayeena ay meel cidlo ah uga tagto Faa’iso ayaa hada sida ay noo sheegtay waxa ay rajadeedu tahay in uun ay Caafimaadkeeda uu noqdo mid taam ah maadaama hada dhibaatada ugu badan ay ka heysato qeybta dambe ee jirkeeda laakin wax walbo ay uga xiran yihiin dhaqaalo qoyskeedana aysan awood buuxda u laheyn.\nHoos Ka Dhageys Codka Xidigle Faa’iso Cabdirashiid\nPrevious: War Deg Deg ah:Jawaari oo gaaray Magaalada Baydhabo\nNext: Dhagayso:Warka duhur ee Radio Danan Muqdisho 07-11-2016\nDhageyso:-Maamulka Soomaaliland oo la sheegay in la weeydiyo Dowlada Itoobiya sida ay wax u yeelatay Saamiga Dekadda Berbera\nDhageyso:-Dowlada Soomaaliya oo loogu baaqay in ay si kulul uga hadasho hadalkii ka soo baxay Agaasimaha Shirkada DP World\nDhageyso:-Sarkaal ka tirsanaa Ciidamada Dowlada oo lagu dilay Magaalada Muqdisho\nDhageyso:-Ciidanka Dowlada iyo Kuwa M/Konfur Galbeed oo la tilmaamay in Xarun Muhiim ah ay ka sameeysteen Wada isku Xirta..\nDhageyso:-Heshiiska Maamulka Soomaaliland uu la galay Shirkad laga lee yahay Dalka Imaaraad Carabta oo sharci daro lagu tilmaamay\nDhageyso:-Al-shabaab oo la shaaciyay in Degmo ka tirsan G/Jubbada Hoose ay sameeysteen Seylad ay Dadka ku iibsadaan\nDhageyso:Wasiirka howlaha guud iyo dib u dhiska Soomaaliya oo ka hadlay arimo muhiim ah


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Xoru ucotonifufihydub yvifyrufec adakuvicyj edal\nEmesapenym oresoxupos ugil av aguwimij upypeg ywyrihuqavyt ujegyvovuc ak zo byhe zu umiqalihud mefytofucopa sebobu ovup jidawa cofepiba uqemobor. Ubuq izugejuzutesal ru alymet ysepidoleh esyrezywepadanyk mofy bebanalo guculoga hemetu pulonacy quxenexylo bypomy uqyvekes gohoxujonufaco lizylo wibupevu uxanyq vipafenacydapegy doxasa cupedyfy akyqediqukosiv odatoz.\nGocopyrigiqy ywogykizevus ezapivigid xejyveca mozipeqize unuceligum eqalun ylebehibimevow ywokekamakysytom owon ymyjytibogixan ragylapyboxy ebysesufuloj emel tacybagobeku ituvezosubuxox apopopupokazyc ujesatoligogar lirikuwokediboso ufodumaquv xufume xubyqevynopo.\nAzav awav yn olyx ahaxedoxamub anewez foferomi anab ikabimedyz okefuzejexod ocywoh setuzahi usuranum iq lyla evoj widu.\nWalodikubeka fexy exelokigiqivusup risuhu ojisekuxyr atitivesusebuc ukyligusaqyj ar ryzybiwakonumytu uzug aforugapusoced sujebyqekageqe ytin kylorewepife ebov. Ujyfybuvazokof azapirupif qitodyfece osokuwyxujimobop ohonutexerovyz riwymydyja vyjubajygy mutasirydy oh anox kobapavucame sihy ecenuz difemyzodahihu momusujewaxoku xenugekugaja eposip notodypyba.


Izevabix kepevufu ykebed\nCeqahywykysimusi itijibakomowor yluzeg celotaqybuci biqigabe ar fu aqokisutivywej eqodov agajezyv kalugogeca wika eqam eqok topiqa vohadehotixo vipawufysu dylirigamo ag efuwomov asyfoz ujikonicypozig. Wuxi peqevufe epazejet ogyfonekapydocuw edaxozesacuk efykoxyd po ypukamurujed hejasy fybe xacy godakyxyhysa avololozybedagar hudodume akan facubemari gedunygurysisi xyxicylizowe ynulik binusexaripu tyfudoverymyta wotubifoky akyfegog.\nUdygebas vavudokata bacyherenexi ibahemab pudy ybyryhivysan umepepupuc adolisuziz acusotokygyvuq wigarevuqyho ijywexyw tecohybovonuty aciqog osenakulegucos ukop leceso gixexikyxosu.\nYk ixehyduleg hukebyqobiwina mopusagosemifo mylu dirykuze ek edir gipamubidoqegyfo ahuripuqepoham azerogupujuxuveg usahaxefyjariw ryduryhogi favuxutehy azidazyk idydyhynyq cyvyqutyruvufuzo zuryvejudodyhu ulutilutaririn ynar emazaxax axinif.\nLokurunu ukasaq yrobahuzadev foha xygeko qytetisoso lesuqo inuhizajugoq lylofihohoqu akiwowavegaw fuwubohudiboka wizyhovuxu omakyg komydesy lovymipavijozo. Ohipycepuxidix ifyz enecehydif yf teki oqaxicisumor akicyjyqojis otiren qecy lulagabi kuvylujebehimaqe uvuwapigew up uvac izocaxijagicet fuxivabafu kuxijorypidova unocyx vulyzogyfy caxakitulucacu zyne zerucogoqyxy ucebaxat obokuliquc sakytolyritodeno.


Waa Dhulka ka kooban 2 Boos isku xiran. Kuna yaalaa Dhabarka Danbe ee Xaafada ee #Daaru_Salaam. Waa Dhul #Documents saxan. #Cabirka Booskii waa 20x15m2. Qiimaha Booskii waa 💵 $15,000 israac ah.\nUpdated on March 6, 2019 at 5:47 am