\begin{definition}[Definition:Order Type]
Let $\struct {S, \preccurlyeq_1}$ and $\struct {T, \preccurlyeq_2}$ be ordered sets.
Then $S$ and $T$ '''have the same (order) type''' {{iff}} they are order isomorphic.
The '''order type''' of an  ordered set $\struct {S, \preccurlyeq}$ can be denoted $\map \ot {S, \preccurlyeq}$.
\end{definition}