College Physics Problem 2.28

A powerful motorcycle can accelerate from rest to 26.8 m/s (100 km/h) in only 3.90 s.
(a) What is its average acceleration?
(b) How far does it travel in that time?


Part (a). The average acceleration of the motorcycle can be solved using the equation \overline{a}=\frac{\Delta v}{\Delta t}. Substitute the given into the equation. That is,




Part (b). The distance traveled is equal to the average velocity multiplied by the time of travel. That is,

\Delta x=v_{ave}t

\Delta x=\left(\frac{0\:m.s+26.8\:m/s}{2}\right)\left(3.90\:s\right)

\Delta x=52.26\:m

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