Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0



2y$\sqrt y$

Work Step by Step

$\sqrt \frac{28y^{5}}{7y^{2}}$ = $\sqrt \frac{2.14y^{5}}{7y^{2}}$ = $\sqrt 2.2y^{3}$ = $\sqrt 4y^{2}.y$ = 2y$\sqrt y$
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