Content: 15.jpg (13.86 KB)
Uploaded: 31.08.2017

Positive responses: 0
Negative responses: 0

Sold: 0
Refunds: 0

A closed container is divided into two parts by a flat partition, having a square hole with side a=400 mm, closed cover. The pressure above the liquid (kerosene) in the left part of the tank is determined by the indicator of pressure gauge RM = 0.07 MPa (abs); air pressure at the right part of figure manovacuummeter Pb = 0.02 MPa (abs). Determine the magnitude and point of application of resultant pressure force on the cover. The distance from the surface of the liquid to cover h=1300 mm.
The solution of the problem is followed by an explanation and a breakdown of the formulas. After payment you will be able to get a file made in word. Perhaps the solution of this problem according to your requirements.
No feedback yet

Similar items