explain please formula and showing how u get the answer (life saver)

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A uniform electric field of magnitude 260V/m is directed in the positive x direction. A+11.0 µC charge moves from theorigin to the point (x, y) = (20.0 cm, 50.0 cm).
(a) What was the change in the potential energy of thischarge?
1wrong check mark J
(b) Through what potential difference did the charge move?
2wrong check mark V

Answers (1)

  • JamesD6132
    Rating:5 stars

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